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{"id":27370,"date":"2018-04-17T17:45:12","date_gmt":"2018-04-17T10:45:12","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=27370"},"modified":"2018-04-17T17:45:12","modified_gmt":"2018-04-17T10:45:12","slug":"chuong-2-bai-tap-trac-nghiem-giai-tich-12-phuong-trinh-mu-va-phuong-trinh-logarit-phan-5","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/chuong-2-bai-tap-trac-nghiem-giai-tich-12-phuong-trinh-mu-va-phuong-trinh-logarit-phan-5\/","title":{"rendered":"Ch\u01b0\u01a1ng 2 – B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: Ph\u01b0\u01a1ng tr\u00ecnh m\u0169 v\u00e0 ph\u01b0\u01a1ng tr\u00ecnh l\u00f4garit (Ph\u1ea7n 5)"},"content":{"rendered":"

C\u00e2u 17:<\/b>\u00a0M\u1ed9t qu\u1ea7n th\u1ec3 vi khu\u1ea9n b\u1eaft \u0111\u1ea7u t\u1eeb 100 c\u00e1 th\u1ec3 v\u00e0 c\u1ee9 sau 3 gi\u1edd th\u00ec s\u1ed1 c\u00e1 th\u1ec3 l\u1ea1i t\u0103ng g\u1ea5p \u0111\u00f4i. B\u1edfi v\u1eady, s\u1ed1 c\u00e1 th\u1ec3 vi khu\u1ea9n \u0111\u01b0\u1ee3c bi\u1ec3u th\u1ecb theo th\u1eddi gian t (t\u00ednh b\u1eb1ng gi\u1edd) b\u1eb1ng c\u00f4ng th\u1ee9c<\/p>\n

\"\"<\/p>\n

H\u1ecfi sau bao l\u00e2u th\u00ec qu\u1ea7n th\u1ec3 n\u00e0y \u0111\u1ea1t \u0111\u1ebfn 50000 c\u00e1 th\u1ec3 (l\u00e0m tr\u00f2n k\u1ebft qu\u1ea3 \u0111\u1ebfn h\u00e0ng ph\u1ea7n m\u01b0\u1eddi) ?<\/p>\n

A. 36,8 gi\u1edd\u00a0\u00a0\u00a0B. 30,2 gi\u1edd \u00a0\u00a0\u00a0C. 26,9 gi\u1edd \u00a0\u00a0\u00a0D. 18,6 gi\u1edd<\/p>\n

C\u00e2u 18:<\/b>\u00a0Khi \u0111\u00e8n flash c\u1ee7a m\u1ed9t m\u00e1y \u1ea3nh t\u1eaft th\u00ec ngay l\u1eadp t\u1ee9c ngu\u1ed3n \u0111i\u1ec7n t\u1eeb pin s\u1ebd x\u1ea1c cho t\u1ee5 \u0111i\u1ec7n c\u1ee7a n\u00f3. L\u01b0\u1ee3ng \u0111i\u1ec7n t\u00edch trong t\u1ee5 x\u00e1c \u0111\u1ecbnh b\u1edfi c\u00f4ng th\u1ee9c<\/p>\n

\"\"<\/p>\n

trong \u0111\u00f3 Q0<\/sub>\u00a0l\u00e0 \u0111i\u1ec7n t\u00edch t\u1ed1i \u0111a m\u00e0 t\u1ee5 c\u00f3 th\u1ec3 t\u00edch \u0111\u01b0\u1ee3c, th\u1eddi gian t t\u00ednh b\u1eb1ng gi\u00e2y. H\u1ecfi sau bao l\u00e2u th\u00ec t\u1ee5 t\u00edch \u0111\u01b0\u1ee3c 90% \u0111i\u1ec7n t\u00edch t\u1ed1i \u0111a ?<\/p>\n

A. 3,2 gi\u00e2y\u00a0\u00a0\u00a0B. 4,6 gi\u00e2y \u00a0\u00a0\u00a0C. 4,8 gi\u00e2y \u00a0\u00a0\u00a0D. 9,2 gi\u00e2y<\/p>\n

C\u00e2u 19:<\/b>\u00a0Chi\u1ec1u d\u00e0i (t\u00ednh b\u1eb1ng xentimet) c\u1ee7a m\u1ed9t lo\u00e0i c\u00e1 b\u01a1n \u1edf Th\u00e1i B\u00ecnh D\u01b0\u01a1ng theo tu\u1ed5i c\u1ee7a n\u00f3 (k\u00ed hi\u1ec7u l\u00e0 t, t\u00ednh b\u1eb1ng n\u0103m) \u0111\u01b0\u1ee3c \u01b0\u1edbc l\u01b0\u1ee3ng b\u1edfi c\u00f4ng th\u1ee9c f(t) = 200(1 – 0,956e0,18t<\/sup>). M\u1ed9t con c\u00e1 b\u01a1n thu\u1ed9c lo\u00e0i n\u00e0y c\u00f3 chi\u1ec1u d\u00e0i 140cm. H\u00e3y \u01b0\u1edbc l\u01b0\u1ee3ng tu\u1ed5i c\u1ee7a n\u00f3.<\/p>\n

A. 2,79 n\u0103m\u00a0\u00a0\u00a0B. 6,44 n\u0103m \u00a0\u00a0\u00a0C. 7,24 n\u0103m \u00a0\u00a0\u00a0D. 12,54 n\u0103m<\/p>\n

C\u00e2u 20:<\/b>\u00a0C\u00f3 m\u1ed9t d\u1ecbch c\u00fam trong m\u1ed9t khu v\u1ef1c qu\u00e2n \u0111\u1ed9i v\u00e0 s\u1ed1 ng\u01b0\u1eddi l\u00ednh \u1edf \u0111\u00f3 m\u1eafc b\u1ec7nh c\u00fam sau t ng\u00e0y (k\u1ec3 t\u1eeb ng\u00e0y d\u1ecbch c\u00fam b\u00f9ng ph\u00e1t) \u0111\u01b0\u1ee3c \u01b0\u1edbc l\u01b0\u1ee3ng b\u1eb1ng c\u00f4ng th\u1ee9c<\/p>\n

\"\"<\/p>\n

trong \u0111\u00f3 k l\u00e0 m\u1ed9t h\u1eb1ng s\u1ed1. Bi\u1ebft r\u1eb1ng c\u00f3 40 ng\u01b0\u1eddi l\u00ednh m\u1eafc b\u1ec7nh c\u00fam sau 7 ng\u00e0y. T\u00ecm gi\u00e1 tr\u1ecb c\u1ee7a h\u1eb1ng s\u1ed1 k.<\/p>\n

A. 0,33\u00a0\u00a0\u00a0B. 2,31 \u00a0\u00a0\u00a0C. 1,31 \u00a0\u00a0\u00a0D. -2,31<\/p>\n

C\u00e2u 21:<\/b>\u00a0N\u1ebfu log(log(log(logx))) = 0 th\u00ec x = 10k<\/sup>\u00a0. T\u00ecm gi\u00e1 tr\u1ecb c\u1ee7a k<\/p>\n

A. 10 \u00a0\u00a0\u00a0B. 100 \u00a0\u00a0\u00a0C. 103<\/sup>\u00a0\u00a0\u00a0\u00a0D. 1010<\/sup><\/p>\n

C\u00e2u 22:<\/b>\u00a0Gi\u1ea3i ph\u01b0\u01a1ng tr\u00ecnh log3<\/sub>x = (-2 + log2<\/sub>100)(log3<\/sub>\u221a2)<\/p>\n

A. x = 5 \u00a0\u00a0\u00a0B. x = 3\u221a2\u00a0\u00a0\u00a0C. x = 24<\/sup>\u00a0\u00a0\u00a0\u00a0D. x = 50<\/p>\n

C\u00e2u 23:<\/b>\u00a0T\u00ecm t\u1eadp h\u1ee3p c\u00e1c nghi\u1ec7m c\u1ee7a ph\u01b0\u01a1ng tr\u00ecnh<\/p>\n

\"\"<\/p>\n

H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0110\u00e1p \u00e1n<\/b><\/p>\n\n\n\n
17-C<\/td>\n18-B<\/td>\n19-B<\/td>\n20-A<\/td>\n21-D<\/td>\n22-A<\/td>\n23-B<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

C\u00e2u 17:<\/b><\/p>\n

\"\"<\/p>\n

<=> t\/3 = log2<\/sub>500 <=> t = 3log2<\/sub>500 \u2248 26,9 (gi\u1edd)<\/p>\n

C\u00e2u 18:<\/b><\/p>\n

Ta c\u00f3: Q0<\/sub>(1 – e-1\/2<\/sup>) = 0,9Q0<\/sub>\u00a0<=> e-1\/2<\/sup>\u00a0= 0,1 <=> t = -2ln0,1 \u2248 4,6 (gi\u00e2y)<\/p>\n

C\u00e2u 19:<\/b><\/p>\n

f(t) = 200(1 – 0,956e-0,18t<\/sup>) = 140<\/p>\n

\"\"<\/p>\n

C\u00e2u 20:<\/b><\/p>\n

Ta c\u00f3:<\/p>\n

\"\"<\/p>\n

C\u00e2u 21:<\/b><\/p>\n

log(log(log(logx))) = 0 <=> log(log(logx)) = 1 <=> log(logx) = 10 <=> logx = 1010<\/sup>\u00a0<=> x = 101010<\/sup>\u00a0=> k = 1010<\/sup><\/p>\n

C\u00e2u 22:<\/b><\/p>\n

log3<\/sub>\u00a0= (-2 + log2<\/sub>100)(log3<\/sub>\u221a2) <=> x = 3(-2 + log2<\/sub>100)(log3<\/sub>\u221a2)<\/sup>\u00a0= (3log3<\/sub>\u221a2<\/sup>)-2 + log2<\/sub>100<\/sup><\/p>\n

= \u221a2-2 + log2<\/sub>100<\/sup><\/p>\n

\"\"<\/p>\n

C\u00e2u 23:<\/b><\/p>\n

L\u1ea5y l\u00f4garit c\u01a1 s\u1ed1 10 hai v\u1ebf ph\u01b0\u01a1ng tr\u00ecnh ta \u0111\u01b0\u1ee3c<\/p>\n

(logx)(logx) = 3logx – log100 <=> (logx)2<\/sup>\u00a0– 3logx + 2 = 0<\/p>\n

\"\"<\/p>\n","protected":false},"excerpt":{"rendered":"

C\u00e2u 17:\u00a0M\u1ed9t qu\u1ea7n th\u1ec3 vi khu\u1ea9n b\u1eaft \u0111\u1ea7u t\u1eeb 100 c\u00e1 th\u1ec3 v\u00e0 c\u1ee9 sau 3 gi\u1edd th\u00ec s\u1ed1 c\u00e1 th\u1ec3 l\u1ea1i t\u0103ng g\u1ea5p \u0111\u00f4i. B\u1edfi v\u1eady, s\u1ed1 c\u00e1 th\u1ec3 vi khu\u1ea9n \u0111\u01b0\u1ee3c bi\u1ec3u th\u1ecb theo th\u1eddi gian t (t\u00ednh b\u1eb1ng gi\u1edd) b\u1eb1ng c\u00f4ng th\u1ee9c H\u1ecfi sau bao l\u00e2u th\u00ec qu\u1ea7n th\u1ec3 n\u00e0y \u0111\u1ea1t \u0111\u1ebfn […]<\/p>\n","protected":false},"author":3,"featured_media":27371,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[157],"tags":[1447,1446],"yoast_head":"\nCh\u01b0\u01a1ng 2 - B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: Ph\u01b0\u01a1ng tr\u00ecnh m\u0169 v\u00e0 ph\u01b0\u01a1ng tr\u00ecnh l\u00f4garit (Ph\u1ea7n 5)<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/chuong-2-bai-tap-trac-nghiem-giai-tich-12-phuong-trinh-mu-va-phuong-trinh-logarit-phan-5\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Ch\u01b0\u01a1ng 2 - B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: Ph\u01b0\u01a1ng tr\u00ecnh m\u0169 v\u00e0 ph\u01b0\u01a1ng tr\u00ecnh l\u00f4garit (Ph\u1ea7n 5)\" \/>\n<meta property=\"og:description\" content=\"C\u00e2u 17:\u00a0M\u1ed9t qu\u1ea7n th\u1ec3 vi khu\u1ea9n b\u1eaft \u0111\u1ea7u t\u1eeb 100 c\u00e1 th\u1ec3 v\u00e0 c\u1ee9 sau 3 gi\u1edd th\u00ec s\u1ed1 c\u00e1 th\u1ec3 l\u1ea1i t\u0103ng g\u1ea5p \u0111\u00f4i. 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