C\u00e2u 8:<\/b>\u00a0Gi\u1ea3i b\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh log5<\/sub>(2x – 4) < log5<\/sub>(x + 3)<\/p>\n A. 2 < x < 7 \u00a0\u00a0\u00a0B. -3 < x < 7 \u00a0\u00a0\u00a0C. -3 < x < 2 \u00a0\u00a0\u00a0D. x < 7<\/p>\n C\u00e2u 9:<\/b>\u00a0Gi\u1ea3i b\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh ln(xx<\/sup>\u00a0– 2x – 2) < 0<\/p>\n A. -1 \u2265 x \u2265 3 \u00a0\u00a0\u00a0C. x \u221e[-1; 1 – \u221a3) \u222a (1 + \u221a3)<\/p>\n B. -1 – \u221a3 < x < 1 + \u221a3 \u00a0\u00a0\u00a0 D. x \u221e (1 + \u221a3), 3]<\/p>\n C\u00e2u 10:<\/b>\u00a0Gi\u1ea3i b\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh<\/p>\n <\/p>\n C\u00e2u 11:<\/b>\u00a0Gi\u1ea3i b\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh logx + log(x + 9) > 11<\/p>\n A. 0 < x < 3\u00a0\u00a0\u00a0C. x < 1 ho\u1eb7c x > 2<\/p>\n B. x < 0 ho\u1eb7c x > 3\u00a0\u00a0\u00a0D. 0 < x < 1 ho\u1eb7c 2 < x < 3<\/p>\n C\u00e2u 12:<\/b>\u00a0Gi\u1ea3i b\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh 3log2<\/sub>(x2\u00a0– 3x + 2)<\/sup>\u00a0> 3<\/p>\n A. 0 < x < 3 \u00a0\u00a0\u00a0C. x < 1 ho\u1eb7c x > 2<\/p>\n B. x < 0 ho\u1eb7c x > 3 \u00a0\u00a0\u00a0D. 0 < x < 1 ho\u1eb7c 2 < x < 3<\/p>\n C\u00e2u 13:<\/b>\u00a0T\u00ecm mi\u1ec1n x\u00e1c \u0111\u1ecbnh c\u1ee7a h\u00e0m s\u1ed1 y = ln(lnx)<\/p>\n A. D = (e; +\u221e) \u00a0\u00a0\u00a0B. D = [e; \u221e)\u00a0\u00a0\u00a0C. D = (0; +\u221e) \u00a0\u00a0\u00a0D. D = (1; +\u221e)<\/p>\n C\u00e2u 14:<\/b>\u00a0T\u00ecm kho\u1ea3ng \u0111\u1ed3ng bi\u1ebfn c\u1ee7a h\u00e0m s\u1ed1 y = xlnx<\/p>\n A. (0; 1\/e) \u00a0\u00a0\u00a0B. (0; e)\u00a0\u00a0\u00a0C. (1\/e; +\u221e)\u00a0\u00a0\u00a0D. (e; +\u221e)<\/p>\n H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0110\u00e1p \u00e1n<\/b><\/p>\n C\u00e2u 8:<\/b><\/p>\n log5<\/sub>(2x – 4) < log5<\/sub>(x + 3)<\/p>\n <\/p>\n C\u00e2u 9:<\/b><\/p>\n \u0110i\u1ec1u ki\u1ec7n<\/p>\n <\/p>\n Khi \u0111\u00f3 BPT <=> x2<\/sup>\u00a0– 2x – 2 \u2264 e0<\/sup>\u00a0= 1 <=> x2<\/sup>\u00a0– 2x – 3 \u2264 0 <=> -1 \u2264 x \u2264 3<\/p>\n K\u1ebft h\u1ee3p \u0111\u01b0\u1ee3c t\u1eadp nghi\u1ec7m: (1 + \u221a3; 3)<\/p>\n C\u00e2u 10:<\/b><\/p>\n log1\/5<\/sub>(2x2<\/sup>\u00a0+ 5x + 1) < 0 <=> 2x2<\/sup>\u00a0+ 5x + 1 > 1 (do 0 < 1\/5 < 1)<\/p>\n <=> 2x2<\/sup>\u00a0+ 5x > 0 <=> x < -2\/5 ho\u1eb7c x > 0<\/p>\n C\u00e2u 11:<\/b><\/p>\n \u0110i\u1ec1u ki\u1ec7n x > 0. Khi \u0111\u00f3 b\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh \u0111\u00e3 cho t\u01b0\u01a1ng \u0111\u01b0\u01a1ng v\u1edbi<\/p>\n log[x(x + 9)] > 1 <=> x(x + 9) > 10 <=> x2<\/sup>\u00a0+ 9x – 10 > 0<\/p>\n <=> x < -10 ho\u1eb7c x > 1 <=> x > 1 (do x > 0)<\/p>\n C\u00e2u 12:<\/b><\/p>\n 3log2<\/sub>(x2\u00a0– 3x + 2)<\/sup>\u00a0> 3 7lt;=> log2<\/sub>(x2<\/sup>\u00a0– 3x + 2) > 1 <=> x2<\/sup>\u00a0– 3 + 2 > 2<\/p>\n <=> x2<\/sup>\u00a0– 3x > 0 <=> x < 0 ho\u1eb7c x> 3<\/p>\n C\u00e2u 13:<\/b><\/p>\n \u0110i\u1ec1u ki\u1ec7n ln > 0 <=> x > e0<\/sup>\u00a0= 1<\/p>\n C\u00e2u 14:<\/b><\/p>\n T\u1eadp x\u00e1c \u0111\u1ecbnh: (0; +\u221e). y’ = lnx + 1 > 0 <=> lnx > -1 <=> x > 1\/e<\/p>\n","protected":false},"excerpt":{"rendered":" C\u00e2u 8:\u00a0Gi\u1ea3i b\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh log5(2x – 4) < log5(x + 3) A. 2 < x < 7 \u00a0\u00a0\u00a0B. -3 < x < 7 \u00a0\u00a0\u00a0C. -3 < x < 2 \u00a0\u00a0\u00a0D. x < 7 C\u00e2u 9:\u00a0Gi\u1ea3i b\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh ln(xx\u00a0– 2x – 2) < 0 A. -1 \u2265 x \u2265 3 \u00a0\u00a0\u00a0C. x \u221e[-1; 1 […]<\/p>\n","protected":false},"author":3,"featured_media":27322,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[157],"tags":[1447,1446],"yoast_head":"\n\n\n
\n 8-A<\/td>\n 9-D<\/td>\n 10-B<\/td>\n 11-A<\/td>\n 12-B<\/td>\n 13-D<\/td>\n 14-C<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n