C\u00e2u 1:<\/b>\u00a0Trong kh\u00f4ng gian Oxyz, cho hai vect\u01a1\u00a0u\u2192<\/i>\u00a0= (x; y; z),\u00a0u’\u2192<\/i>\u00a0= (x’; y’; z’) . Trong c\u00e1c kh\u1eb3ng \u0111\u1ecbnh sau \u0111\u00e2y, kh\u1eb3ng \u0111\u1ecbnh n\u00e0o sai?<\/p>\n

<\/p>\n

C\u00e2u 2:<\/b>\u00a0Trong kh\u00f4ng gian Oxyz, cho ba vect\u01a1<\/p>\n

<\/p>\n

T\u1ecda \u0111\u1ed9 c\u1ee7a vect\u01a1:<\/p>\n

<\/p>\n

A. (-3;4;4)\u00a0\u00a0\u00a0B. (-3;4;-2)\u00a0\u00a0\u00a0C. (9;4;4)\u00a0\u00a0\u00a0D. \u0110\u00e1p \u00e1n kh\u00e1c<\/p>\n

C\u00e2u 3:<\/b>\u00a0Trong kh\u00f4ng gian Oxyz, cho \u0111i\u1ec3m M(x_{0<\/sub>; y0<\/sub>; z0<\/sub>) v\u1edbi x0<\/sub>, y0<\/sub>, z0<\/sub>\u00a0\u2260 0. G\u1ecdi M1<\/sub>, M2<\/sub>, M3<\/sub>\u00a0l\u1ea7n l\u01b0\u1ee3t l\u00e0 h\u00ecnh chi\u1ebfu vu\u00f4ng g\u00f3c c\u1ee7a \u0111i\u1ec3m M tr\u00ean c\u00e1c tr\u1ee5c Ox, Oy, Oz. Trong c\u00e1c kh\u1eb3ng \u0111\u1ecbnh sau, kh\u1eb3ng \u0111\u1ecbnh n\u00e0o sai?<\/p>\n}

<\/p>\n

B. M_{1<\/sub>(x0<\/sub>; 0; 0), M2<\/sub>(0; y0<\/sub>; 0), M3<\/sub>(0; 0; z0<\/sub>)<\/p>\n}

C. OM \u2264 OM_{1<\/sub>\u00a0+ OM2<\/sub>\u00a0+ OM3<\/sub><\/p>\n}

D. M\u1eb7t ph\u1eb3ng (M_{1<\/sub>M2<\/sub>M3<\/sub>) \u0111i qua \u0111i\u1ec3m M<\/p>\n}

C\u00e2u 4:<\/b>\u00a0Trong kh\u00f4ng gian Oxyz, cho hai \u0111i\u1ec3m A(1; 3; 1), B(0; 1; 2). V\u1edbi nh\u1eefng gi\u00e1 tr\u1ecb n\u00f2a c\u1ee7a m th\u00ec \u0111i\u1ec3m C(0;0;m) n\u1eb1m tr\u00ean \u0111\u01b0\u1eddng th\u1eb3ng AB<\/p>\n

A. m = 1\u00a0\u00a0\u00a0B. m = 2\u00a0\u00a0\u00a0C. m = 0\u00a0\u00a0\u00a0D. Kh\u00f4ng t\u1ed3n t\u1ea1i m<\/p>\n

C\u00e2u 5:<\/b>\u00a0Trong kh\u00f4ng gian Oxyz, cho h\u00ecnh h\u1ed9p ch\u1eef nh\u1eadt ABCD.A’B’C’D’ c\u00f3 A(1; 0; 0), B(2; 0; 0), D(1; 2; 0), A'(1; 0; 2). G\u1ecdi I l\u00e0 t\u00e2m c\u1ee7a h\u00ecnh h\u1ed9p. Trong c\u00e1c kh\u1eb3ng \u0111\u1ecbnh sau \u0111\u00e2y, kh\u1eb3ng \u0111\u1ecbnh n\u00e0o sai?<\/p>\n

<\/p>\n

C\u00e2u 6:<\/b>\u00a0Trong kh\u00f4ng gian Oxyz, cho m\u1eb7t c\u1ea7u (S) \u0111i qua b\u1ed1n \u0111i\u1ec3m O, A(-4;0;0), B(0;2;0), C(0;0;-4). Ph\u01b0\u01a1ng tr\u00ecnh c\u1ee7a m\u1eb7t c\u1ea7u (S) l\u00e0:<\/p>\n

A. x^{2<\/sup>\u00a0+ y2<\/sup>\u00a0+ z2<\/sup>\u00a0+ 2x – y + 2z = 0 \u00a0\u00a0\u00a0C. x2<\/sup>\u00a0+ y2<\/sup>\u00a0+ z2<\/sup>\u00a0– 4x + 2y – 4z = 0<\/p>\n}

B. x^{2<\/sup>\u00a0+ y2<\/sup>\u00a0+ z2<\/sup>\u00a0+ 4x + 2y + 4z = 0\u00a0\u00a0\u00a0D. x2<\/sup>\u00a0+ y2<\/sup>\u00a0+ z2<\/sup>\u00a0+ 4x – 2y + 4z = 0<\/p>\n}

C\u00e2u 7:<\/b>\u00a0Trong kh\u00f4ng gian Oxyz, cho m\u1eb7t ph\u1eb3ng (P) \u0111i qua \u0111i\u1ec3m M(1;2;3) v\u00e0 ch\u1ee9a tr\u1ee5c Ox. Ph\u01b0\u01a1ng tr\u00ecnh c\u1ee7a m\u1eb7t ph\u1eb3ng (P) l\u00e0:<\/p>\n

A. x + 2y + 3z – 14 = 0\u00a0\u00a0\u00a0C. 2x – y = 0<\/p>\n

B. 3y – 2z = 0\u00a0\u00a0\u00a0D. 3x – z = 0<\/p>\n

H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0110\u00e1p \u00e1n<\/b><\/p>\n\n\n\n

1-C<\/td>\n

2-B<\/td>\n

3-D<\/td>\n

4-D<\/td>\n

5-B<\/td>\n

6-D<\/td>\n

7-B<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n","protected":false},"excerpt":{"rendered":" C\u00e2u 1:\u00a0Trong kh\u00f4ng gian Oxyz, cho hai vect\u01a1\u00a0u\u2192\u00a0= (x; y; z),\u00a0u’\u2192\u00a0= (x’; y’; z’) . Trong c\u00e1c kh\u1eb3ng \u0111\u1ecbnh sau \u0111\u00e2y, kh\u1eb3ng \u0111\u1ecbnh n\u00e0o sai? C\u00e2u 2:\u00a0Trong kh\u00f4ng gian Oxyz, cho ba vect\u01a1 T\u1ecda \u0111\u1ed9 c\u1ee7a vect\u01a1: A. (-3;4;4)\u00a0\u00a0\u00a0B. (-3;4;-2)\u00a0\u00a0\u00a0C. (9;4;4)\u00a0\u00a0\u00a0D. \u0110\u00e1p \u00e1n kh\u00e1c C\u00e2u 3:\u00a0Trong kh\u00f4ng gian Oxyz, cho \u0111i\u1ec3m M(x0; y0; z0) v\u1edbi […]<\/p>\n","protected":false},"author":3,"featured_media":27178,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[157],"tags":[1450,1448],"yoast_head":"\n