1. \u0110\u1ecbnh ngh\u0129a<\/b><\/p>\n

Cho h\u00e0m s\u1ed1 f(x) x\u00e1c \u0111\u1ecbnh tr\u00ean K (K l\u00e0 kho\u1ea3ng, \u0111o\u1ea1n ho\u1eb7c n\u1eeda kho\u1ea3n c\u1ee7a R ). H\u00e0m s\u1ed1 F(x) \u0111\u01b0\u1ee3c g\u1ecdi l\u00e0 nguy\u00ean h\u00e0m c\u1ee7a h\u00e0m s\u1ed1 f(x) tr\u00ean K n\u1ebfu F'(x) = f(x), \u2200x \u2208 K.<\/p>\n

2. C\u00e1c \u0111\u1ecbnh l\u00ed<\/b><\/p>\n

– N\u1ebfu F(x) l\u00e0 m\u1ed9t nguy\u00ean h\u00e0m c\u1ee7a f(x) tr\u00ean K th\u00ec v\u1edbi m\u1ed7i h\u1eb1ng s\u1ed1 C, h\u00e0m s\u1ed1 G(x) = F(x) + C c\u0169ng l\u00e0 m\u1ed9t nguy\u00ean h\u00e0m c\u1ee7a f(x) tr\u00ean K.<\/p>\n

– N\u1ebfu F(x) l\u00e0 m\u1ed9t nguy\u00ean h\u00e0m c\u1ee7a f(x) tr\u00ean K th\u00ec m\u1ecdi nguy\u00ean h\u00e0m c\u1ee7a f(x) tr\u00ean K \u0111\u1ec1u c\u00f3 d\u1ea1ng F(x) + C , C l\u00e0 h\u1eb1ng s\u1ed1.<\/p>\n

H\u1ecd t\u1ea5t c\u1ea3 c\u00e1c nguy\u00ean h\u00e0m c\u1ee7a f(x) tr\u00ean K k\u00ed hi\u1ec7u l\u00e0:<\/p>\n

<\/p>\n

– M\u1ecdi h\u00e0m s\u1ed1 f(x) lien t\u1ee5c tr\u00ean K \u0111\u1ec1u c\u00f3 nguy\u00ean h\u00e0m tr\u00ean K.<\/p>\n

3. B\u1ea3ng nguy\u00ean h\u00e0m c\u1ee7a m\u1ed9t s\u1ed1 h\u00e0m s\u1ed1 th\u01b0\u1eddng g\u1eb7p<\/b><\/p>\n

1. \u222b0dx=C, \u222bdx= \u222b1dx=x+C ;<\/p>\n

<\/p>\n

4. V\u1edbi k l\u00e0 h\u1eb1ng s\u1ed1 kh\u00e1c 0<\/p>\n

<\/p>\n

4. C\u00e1c ph\u01b0\u01a1ng ph\u00e1p t\u00ecm nguy\u00ean h\u00e0m<\/b><\/p>\n

– Ph\u01b0\u01a1ng ph\u00e1p bi\u1ebfn \u0111\u1ed5i s\u1ed1<\/p>\n

\u0110\u1ecbnh l\u00ed. N\u1ebfu \u222bf(u)du=F(u)+C v\u00e0 u = u(x) l\u00e0 h\u00e0m s\u1ed1 c\u00f3 \u0111\u1ea1o h\u00e0m li\u00ean t\u1ee5c th\u00ec \u222bf(u(x)).u'(x)dx=F(u(x))+C .<\/p>\n

H\u1ec7 qu\u1ea3. N\u1ebfu u = ax+b, a\u22600 th\u00ec ta c\u00f3<\/p>\n

<\/p>\n

– Ph\u01b0\u01a1ng ph\u00e1p l\u1ea5y nguy\u00ean h\u00e0m t\u1eebng ph\u1ea7n<\/p>\n

\u0110\u1ecbnh l\u00ed. N\u1ebfu hai h\u00e0m s\u1ed1 u = u(x) v\u00e0 v\u00e0 v = v(x) c\u00f3 \u0111\u1ea1o h\u00e0m li\u00ean t\u1ee5c tr\u00ean K th\u00ec:<\/p>\n

\u222bu(x)v'(x)dx=u(x)v(x)-\u222bu'(x)v(x)dx hay \u222budv=vu-\u222bvdu .<\/p>\n","protected":false},"excerpt":{"rendered":"

1. \u0110\u1ecbnh ngh\u0129a Cho h\u00e0m s\u1ed1 f(x) x\u00e1c \u0111\u1ecbnh tr\u00ean K (K l\u00e0 kho\u1ea3ng, \u0111o\u1ea1n ho\u1eb7c n\u1eeda kho\u1ea3n c\u1ee7a R ). H\u00e0m s\u1ed1 F(x) \u0111\u01b0\u1ee3c g\u1ecdi l\u00e0 nguy\u00ean h\u00e0m c\u1ee7a h\u00e0m s\u1ed1 f(x) tr\u00ean K n\u1ebfu F'(x) = f(x), \u2200x \u2208 K. 2. C\u00e1c \u0111\u1ecbnh l\u00ed – N\u1ebfu F(x) l\u00e0 m\u1ed9t nguy\u00ean h\u00e0m c\u1ee7a f(x) […]<\/p>\n","protected":false},"author":3,"featured_media":27148,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[157],"tags":[1447,1446],"yoast_head":"\n