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{"id":27126,"date":"2018-04-17T11:05:53","date_gmt":"2018-04-17T04:05:53","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=27126"},"modified":"2018-04-17T11:05:53","modified_gmt":"2018-04-17T04:05:53","slug":"bai-tap-trac-nghiem-hinh-hoc-12-on-tap-cuoi-nam-phan-1","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/bai-tap-trac-nghiem-hinh-hoc-12-on-tap-cuoi-nam-phan-1\/","title":{"rendered":"B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m H\u00ecnh h\u1ecdc 12: \u00d4n t\u1eadp cu\u1ed1i n\u0103m (ph\u1ea7n 1)"},"content":{"rendered":"

C\u00e2u 1:<\/b>\u00a0M\u1ed9t h\u00ecnh ch\u00f3p c\u00f3 40 c\u1ea1nh. H\u00ecnh ch\u00f3p \u0111\u00f3 c\u00f3 bao nhi\u00eau m\u1eb7t?<\/p>\n

A. 20\u00a0\u00a0\u00a0B. 21\u00a0\u00a0\u00a0C. 22\u00a0\u00a0\u00a0D. 40<\/p>\n

C\u00e2u 2:<\/b>\u00a0Trong s\u1ed1 c\u00e1c m\u1ec7nh \u0111\u1ec1 sau \u0111\u00e2y, m\u1ec7nh \u0111\u1ec1 n\u00e0o \u0111\u00fang?<\/p>\n

A. S\u1ed1 c\u1ea1nh c\u1ee7a m\u1ed9t h\u00ecnh \u0111a di\u1ec7n lu\u00f4n l\u00e0 m\u1ed9t s\u1ed1 ch\u1eb5n<\/p>\n

B. S\u1ed1 m\u1eb7t c\u1ee7a m\u1ed9t h\u00ecnh \u0111a di\u1ec7n lu\u00f4n l\u00e0 m\u1ed9t s\u1ed1 ch\u1eb5n<\/p>\n

C. S\u1ed1 \u0111\u1ec9nh c\u1ee7a m\u1ed9t h\u00ecnh l\u0103ng tr\u1ee5 lu\u00f4n l\u00e0 m\u1ed9t s\u1ed1 ch\u1eb5n<\/p>\n

D. S\u1ed1 c\u1ea1nh c\u1ee7a m\u1ed9t h\u00ecnh l\u0103ng tr\u1ee5 lu\u00f4n l\u00e0 m\u1ed9t s\u1ed1 ch\u1eb5n<\/p>\n

C\u00e2u 3:<\/b>\u00a0Trong c\u00e1c m\u1ec7nh \u0111\u1ec1 sau \u0111\u00e2y, m\u1ec7nh \u0111\u1ec1 n\u00e0o sai?<\/p>\n

A. T\u1ed3n t\u1ea1i c\u00e1c kh\u1ed1i \u0111a di\u1ec7n \u0111\u1ec1u lo\u1ea1i (3;4)<\/p>\n

B. T\u1ed3n t\u1ea1i c\u00e1c kh\u1ed1i \u0111a di\u1ec7n \u0111\u1ec1u lo\u1ea1i (5;3)<\/p>\n

C. T\u1ed3n t\u1ea1i c\u00e1c kh\u1ed1i \u0111a di\u1ec7n \u0111\u1ec1u lo\u1ea1i (3;5)<\/p>\n

D. T\u1ed3n t\u1ea1i c\u00e1c kh\u1ed1i \u0111a di\u1ec7n \u0111\u1ec1u lo\u1ea1i (4;4)<\/p>\n

C\u00e2u 4:<\/b>\u00a0Trong c\u00e1c m\u1ec7nh \u0111\u1ec1 sau \u0111\u00e2y, m\u1ec7nh \u0111\u1ec1 n\u00e0o \u0111\u00fang?<\/p>\n

A. Trong m\u1ed9t h\u00ecnh \u0111a di\u1ec7n \u0111\u1ec1u, s\u1ed1 \u0111\u1ec9nh lu\u00f4n l\u1edbn h\u01a1n s\u1ed1 m\u1eb7t<\/p>\n

B. T\u1ed3n t\u1ea1i m\u1ed9t h\u00ecnh \u0111a di\u1ec7n \u0111\u1ec1u c\u00f3 s\u1ed1 \u0111\u1ec9nh b\u1eb1ng s\u1ed1 m\u1eb7t<\/p>\n

C. Trong m\u1ed9t h\u00ecnh \u0111a di\u1ec7n \u0111\u1ec1u, s\u1ed1 \u0111\u1ec9nh lu\u00f4n b\u1eb1ng s\u1ed1 m\u1eb7t<\/p>\n

D. Trong m\u1ed9t h\u00ecnh \u0111a di\u1ec7n \u0111\u1ec1u, s\u1ed1 \u0111\u1ec9nh lu\u00f4n nh\u1ecf h\u01a1n s\u1ed1 m\u1eb7t<\/p>\n

C\u00e2u 5:<\/b>\u00a0Cho h\u00ecnh ch\u00f3p t\u1ee9 gi\u00e1c \u0111\u1ec1u S.ABCD, c\u1ea1nh \u0111\u00e1y l\u00e0 a, SA = 2a. Th\u1ec3 t\u00edch kh\u1ed1i ch\u00f3p l\u00e0:<\/p>\n

\"\"<\/p>\n

C\u00e2u 6:<\/b>\u00a0Cho h\u00ecnh ch\u00f3p S.ABCD c\u00f3 \u0111\u00e1y l\u00e0 h\u00ecnh vu\u00f4ng c\u1ea1nh a. M\u1eb7t b\u00ean (SAD) l\u00e0 tam gi\u00e1c c\u00e2n t\u1ea1i \u0111\u1ec9nh S v\u00e0 n\u1eb1m trong m\u1eb7t ph\u1eb3ng vu\u00f4ng g\u00f3c v\u1edbi \u0111\u00e1y. G\u00f3c gi\u1eefa c\u1ea1nh b\u00ean SB v\u00e0 m\u1eb7t \u0111\u00e1y l\u00e0 60o<\/sup>\u00a0. T\u00ednh th\u1ec3 t\u00edch kh\u1ed1i ch\u00f3p S.ABCD<\/p>\n

\"\"<\/p>\n

C\u00e2u 7:<\/b>\u00a0Cho l\u0103ng tr\u1ee5 ABC.A’B’C’ c\u00f3 \u0111\u1ed9 d\u00e0i c\u1ea1nh b\u00ean b\u1eb1ng 2a, \u0111\u00e1y ABC l\u00e0 tam gi\u00e1c \u0111\u1ec1u c\u1ea1nh a v\u00e0 h\u00ecnh chi\u1ebfu vu\u00f4ng g\u00f3c c\u1ee7a \u0111\u1ec9nh A\u2019 tr\u00ean m\u1eb7t ph\u1eb3ng (ABC) l\u00e0 trung \u0111i\u1ec3m c\u1ea1nh BC. Th\u1ec3 t\u00edch kh\u1ed1i ch\u00f3p A.BCC\u2019B\u2019 l\u00e0:<\/p>\n

\"\"<\/p>\n

C\u00e2u 8:<\/b>\u00a0Cho h\u00ecnh ch\u00f3p S.ABC c\u00f3 \u0111\u00e1y ABC l\u00e0 tam gi\u00e1c vu\u00f4ng t\u1ea1i \u0111\u1ec9nh A v\u00e0 AB = AC, SA = SB = SC = 3a. G\u00f3c gi\u1eefa m\u1eb7t ph\u1eb3ng (SAB) v\u00e0 m\u1eb7t ph\u1eb3ng (ABC) l\u00e0 60o<\/sup>\u00a0. G\u1ecdi G l\u00e0 tr\u1ecdng t\u00e2m c\u1ee7a tam gi\u00e1c SAB. Th\u1ec3 t\u00edch kh\u1ed1i ch\u00f3p S.GBC l\u00e0:<\/p>\n

\"\"<\/p>\n

H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0110\u00e1p \u00e1n<\/b><\/p>\n\n\n\n
1-B<\/td>\n2-C<\/td>\n3-D<\/td>\n4-B<\/td>\n5-D<\/td>\n6-D<\/td>\n7-D<\/td>\n8-B<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

C\u00e2u 1:<\/b><\/p>\n

G\u1ecdi h\u00ecnh ch\u00f3p \u0111\u00e3 cho l\u00e0 h\u00ecnh ch\u00f3p n \u2013 gi\u00e1c, khi \u0111\u00f3 s\u1ed1 c\u1ea1nh c\u1ee7a h\u00ecnh ch\u00f3p l\u00e0 2n=40. Suy ra n=20 v\u00e0 do \u0111\u00f3 s\u1ed1 m\u1eb7t c\u1ee7a h\u00ecnh ch\u00f3p l\u00e0 n+1=21<\/p>\n

C\u00e2u 2:<\/b><\/p>\n

H\u00ecnh l\u0103ng tr\u1ee5 tam gi\u00e1c c\u00f3 9 c\u1ea1nh n\u00ean m\u1ec7nh \u0111\u1ec1 A v\u00e0 D sai. H\u00ecnh ch\u00f3p t\u1ee9 gi\u00e1c c\u00f3 5 m\u1eb7t n\u00ean m\u1ec7nh \u0111\u1ec1 B sai. L\u0103ng tr\u1ee5 n-gi\u00e1c c\u00f3 2n \u0111\u1ec9nh n\u00ean \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 C.<\/p>\n

C\u00e2u 3:<\/b><\/p>\n

Trong b\u1ea3ng ph\u00e2n lo\u1ea1i 5 kh\u1ed1i \u0111a di\u1ec7n \u0111\u1ec1u ta kh\u00f4ng th\u1ea5y c\u00f3 kh\u1ed1i \u0111a di\u1ec7n \u0111\u1ec1u lo\u1ea1i (4 ;4)<\/p>\n

C\u00e2u 4:<\/b><\/p>\n

Nh\u00ecn v\u00e0o b\u1ea3ng ph\u00e2n lo\u1ea1i 5 h\u00ecnh \u0111a di\u1ec7n \u0111\u1ec1u ta c\u00f3 \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 B<\/p>\n

C\u00e2u 5:<\/b><\/p>\n

G\u1ecdi O l\u00e0 t\u00e2m c\u1ee7a \u0111\u00e1y, khi \u0111\u00f3 ta c\u00f3 SO \u22a5 (ABCD). Ta t\u00ednh \u0111\u01b0\u1ee3c<\/p>\n

\"\"<\/p>\n

C\u00e2u 6:<\/b><\/p>\n

G\u1ecdi H l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AD, khi \u0111\u00f3 t\u1eeb gi\u1ea3 thi\u1ebft ta c\u00f3 SH \u22a5 (ABCD) . Ta c\u00f3 :<\/p>\n

\"\"<\/p>\n

C\u00e2u 7:<\/b><\/p>\n

G\u1ecdi H l\u00e0 trung \u0111i\u1ec3m c\u1ee7a BC, khi \u0111\u00f3 t\u1eeb gi\u1ea3 thi\u1ebft ta c\u00f3 A’H \u22a5 (ABC). Ta c\u00f3:<\/p>\n

A’H = a\u221a3 => VA.BCC’B’<\/sub>\u00a0= VABC.A’B’C’<\/sub>\u00a0– VA’.ABC<\/sub><\/p>\n

\"\"<\/p>\n

C\u00e2u 8:<\/b><\/p>\n

G\u1ecdi H l\u00e0 ch\u00e2n \u0111\u01b0\u1eddng vu\u00f4ng g\u00f3c h\u1ea1 t\u1eeb \u0111\u1ec9nh S l\u00ean m\u1eb7t ph\u1eb3ng (ABC), khi \u0111\u00f3 ta ch\u1ee9ng minh \u0111\u01b0\u1ee3c H l\u00e0 trung \u0111i\u1ec3m c\u1ee7a BC. G\u1ecdi M l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AB khi \u0111\u00f3 t\u1eeb gi\u1ea3 thi\u1ebft ta c\u00f3 :<\/p>\n

\"\"<\/p>\n

\u0110\u1eb7t AB = x ta t\u00ednh \u0111\u01b0\u1ee3c :<\/p>\n

\"\"<\/p>\n","protected":false},"excerpt":{"rendered":"

C\u00e2u 1:\u00a0M\u1ed9t h\u00ecnh ch\u00f3p c\u00f3 40 c\u1ea1nh. H\u00ecnh ch\u00f3p \u0111\u00f3 c\u00f3 bao nhi\u00eau m\u1eb7t? A. 20\u00a0\u00a0\u00a0B. 21\u00a0\u00a0\u00a0C. 22\u00a0\u00a0\u00a0D. 40 C\u00e2u 2:\u00a0Trong s\u1ed1 c\u00e1c m\u1ec7nh \u0111\u1ec1 sau \u0111\u00e2y, m\u1ec7nh \u0111\u1ec1 n\u00e0o \u0111\u00fang? A. S\u1ed1 c\u1ea1nh c\u1ee7a m\u1ed9t h\u00ecnh \u0111a di\u1ec7n lu\u00f4n l\u00e0 m\u1ed9t s\u1ed1 ch\u1eb5n B. S\u1ed1 m\u1eb7t c\u1ee7a m\u1ed9t h\u00ecnh \u0111a di\u1ec7n lu\u00f4n l\u00e0 m\u1ed9t […]<\/p>\n","protected":false},"author":3,"featured_media":27127,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[157],"tags":[1450,1448],"yoast_head":"\nB\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m H\u00ecnh h\u1ecdc 12: \u00d4n t\u1eadp cu\u1ed1i n\u0103m (ph\u1ea7n 1)<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/bai-tap-trac-nghiem-hinh-hoc-12-on-tap-cuoi-nam-phan-1\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m H\u00ecnh h\u1ecdc 12: \u00d4n t\u1eadp cu\u1ed1i n\u0103m (ph\u1ea7n 1)\" \/>\n<meta property=\"og:description\" content=\"C\u00e2u 1:\u00a0M\u1ed9t h\u00ecnh ch\u00f3p c\u00f3 40 c\u1ea1nh. H\u00ecnh ch\u00f3p \u0111\u00f3 c\u00f3 bao nhi\u00eau m\u1eb7t? A. 20\u00a0\u00a0\u00a0B. 21\u00a0\u00a0\u00a0C. 22\u00a0\u00a0\u00a0D. 40 C\u00e2u 2:\u00a0Trong s\u1ed1 c\u00e1c m\u1ec7nh \u0111\u1ec1 sau \u0111\u00e2y, m\u1ec7nh \u0111\u1ec1 n\u00e0o \u0111\u00fang? A. S\u1ed1 c\u1ea1nh c\u1ee7a m\u1ed9t h\u00ecnh \u0111a di\u1ec7n lu\u00f4n l\u00e0 m\u1ed9t s\u1ed1 ch\u1eb5n B. 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