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{"id":27113,"date":"2018-04-17T11:02:18","date_gmt":"2018-04-17T04:02:18","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=27113"},"modified":"2018-04-17T11:02:18","modified_gmt":"2018-04-17T04:02:18","slug":"bai-tap-trac-nghiem-hinh-hoc-12-on-tap-cuoi-nam-phan-2","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/bai-tap-trac-nghiem-hinh-hoc-12-on-tap-cuoi-nam-phan-2\/","title":{"rendered":"B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m H\u00ecnh h\u1ecdc 12: \u00d4n t\u1eadp cu\u1ed1i n\u0103m (ph\u1ea7n 2)"},"content":{"rendered":"

C\u00e2u 9:<\/b>\u00a0Cho h\u00ecnh ch\u00f3p S.ABCD c\u00f3 SA \u22a5 (ABCD) , \u0111\u00e1y ABCD l\u00e0 h\u00ecnh ch\u1eef nh\u1eadt. SA = 2AD = 2a . G\u00f3c gi\u1eefa mp(SBC) v\u00e0 m\u1eb7t \u0111\u00e1y l\u00e0 45o<\/sup>\u00a0. G\u1ecdi M l\u00e0 trung \u0111i\u1ec3m c\u1ee7a BC. Kho\u1ea3ng c\u00e1ch t\u1eeb M \u0111\u1ebfn mp(SBD) l\u00e0:<\/p>\n

\"\"<\/p>\n

C\u00e2u 10:<\/b>\u00a0Cho h\u00ecnh ch\u00f3p S.ABCD c\u00f3 \u0111\u00e1y ABCD l\u00e0 h\u00ecnh b\u00ecnh h\u00e0nh. G\u1ecdi M, N l\u1ea7n l\u01b0\u1ee3t l\u00e0 trung \u0111i\u1ec3m c\u1ee7a SA, SC. Bi\u1ebft th\u1ec3 t\u00edch c\u1ee7a kh\u1ed1i ch\u00f3p S.BMN l\u00e0 a3<\/sup>\u00a0. T\u00ednh th\u1ec3 t\u00edch kh\u1ed1i ch\u00f3p S.ABCD<\/p>\n

A. a3<\/sup>\u00a0\u00a0\u00a0B. 4a3<\/sup>\u00a0\u00a0\u00a0C. 8a3<\/sup>\u00a0\u00a0\u00a0\u00a0D. 16a3<\/sup><\/p>\n

C\u00e2u 11:<\/b>\u00a0Cho h\u00ecnh ch\u00f3p S.ABC c\u00f3 \u2220ASB = \u2220BSC = \u2220CSA = 60o<\/sup>, SA = 2SB = 3SC = 3a Th\u1ec3 t\u00edch kh\u1ed1i ch\u00f3p S.ABC l\u00e0 :<\/p>\n

\"\"<\/p>\n

C\u00e2u 12:<\/b>\u00a0Cho h\u00ecnh ch\u00f3p S.ABC c\u00f3 h\u00ecnh chi\u1ebfu vu\u00f4ng g\u00f3c c\u1ee7a S l\u00ean m\u1eb7t \u0111\u00e1y l\u00e0 t\u00e2m O c\u1ee7a \u0111\u01b0\u1eddng tr\u00f2n ngo\u1ea1i ti\u1ebfp tam gi\u00e1c ABC. Bi\u1ebft SB = a v\u00e0 g\u00f3c gi\u1eefa c\u1ea1nh b\u00ean SA v\u00e0 m\u1eb7t \u0111\u00e1y b\u1eb1ng 60o<\/sup>\u00a0. Di\u1ec7n t\u00edch c\u1ee7a m\u1eb7t c\u1ea7u ngo\u1ea1i ti\u1ebfp h\u00ecnh ch\u00f3p S.ABC l\u00e0 :<\/p>\n

\"\"<\/p>\n

C\u00e2u 13:<\/b>\u00a0Cho h\u00ecnh ch\u00f3p S.ABCD c\u00f3 \u0111\u00e1y ABCD l\u00e0 h\u00ecnh ch\u1eef nh\u1eadt, SA = AB = 2AD = 2a. Hai m\u1eb7t ph\u1eb3ng (SAB) v\u00e0 (SAD) c\u00f9ng vu\u00f4ng g\u00f3c v\u1edbi \u0111\u00e1y. B\u00e1n k\u00ednh c\u1ee7a m\u1eb7t c\u1ea7u ngo\u1ea1i t\u00e2m B c\u1eaft SC theo m\u1ed9t d\u00e2y c\u00f3 \u0111\u1ed9 d\u00e0i 2a\/3 l\u00e0 :<\/p>\n

\"\"<\/p>\n

C\u00e2u 14:<\/b>\u00a0H\u00ecnh n\u00f3n c\u00f3 thi\u1ebft di\u1ec7n c\u1eaft b\u1edfi m\u1eb7t ph\u1eb3ng qua tr\u1ee5c l\u00e0 m\u1ed9t tam gi\u00e1c vu\u00f4ng v\u00e0 c\u00f3 di\u1ec7n t\u00edch xung quanh l\u00e0 \u221a2 . \u0110\u1ed9 d\u00e0i \u0111\u01b0\u1eddng cao c\u1ee7a h\u00ecnh n\u00f3n l\u00e0 :<\/p>\n

A. \u221a2 \u00a0\u00a0\u00a0B. 1\u00a0\u00a0\u00a0C. 1\/\u221a2 \u00a0\u00a0\u00a0D. 2<\/p>\n

C\u00e2u 15:<\/b>\u00a0B\u1ea1n Nam cao 1,8m tham gia tr\u00f2 ch\u01a1i nh\u00e0 b\u00f3ng. B\u1ea1n Nam ph\u1ea3i \u0111\u1ee9ng th\u1eb3ng trong qu\u1ea3 b\u00f3ng h\u00ecnh c\u1ea7u v\u00e0 l\u0103n tr\u00ean c\u1ecf. \u0110\u1ec3 Nam c\u00f3 th\u1ec3 \u0111\u1ee9ng \u0111\u01b0\u1ee3c trong qu\u1ea3 b\u00f3ng th\u00ec Nam ph\u1ea3i ch\u1ecdn qu\u1ea3 b\u00f3ng c\u00f3 th\u1ec3 t\u00edch \u00edt nh\u1ea5t l\u00e0 bao nhi\u00eau trong c\u00e1c k\u1ebft qu\u1ea3 sau:<\/p>\n

A. \u03c0(m3<\/sup>)\u00a0\u00a0\u00a0B. 7,776\u03c0(m3<\/sup>)\u00a0\u00a0\u00a0C. 2,916\u03c0(m3<\/sup>)\u00a0\u00a0\u00a0D. 0,648\u03c0(m3<\/sup>)<\/p>\n

C\u00e2u 16:<\/b>\u00a0Cho h\u00ecnh tr\u1ee5 c\u00f3 th\u1ec3 t\u00edch b\u1eb1ng 2\u03c0 v\u00e0 c\u00f3 thi\u1ebft di\u1ec7n c\u1eaft b\u1edfi m\u1eb7t ph\u1eb3ng qua tr\u1ee5c l\u00e0 h\u00ecnh vu\u00f4ng. Di\u1ec7n t\u00edch xung quanh c\u1ee7a kh\u1ed1i tr\u1ee5 l\u00e0:<\/p>\n

A. \u03c0\u00a0\u00a0\u00a0B. 2\u03c0\u00a0\u00a0\u00a0C. 4\u03c0\/3\u00a0\u00a0\u00a0D. 4\u03c0<\/p>\n

H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0110\u00e1p \u00e1n<\/b><\/p>\n\n\n\n
9-A<\/td>\n10-C<\/td>\n11-A<\/td>\n12-B<\/td>\n13-C<\/td>\n14-B<\/td>\n15-A<\/td>\n16-D<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

C\u00e2u 9:<\/b><\/p>\n

T\u1eeb gi\u1ea3 thi\u1ebft ta c\u00f3 :<\/p>\n

\"\"<\/p>\n

=> AB = SA = 2a => VS.BDM<\/sub>\u00a0= (1\/4)VS.ABCD<\/sub>\u00a0= a3<\/sup>\/3<\/p>\n

M\u1eb7t kh\u00e1c ta c\u00f3 :<\/p>\n

SB = 2a\u221a2; SD = a\u221a5; BD = a\u221a5 => S\u0394SBD<\/sub>\u00a0= a2<\/sup>\u221a6<\/p>\n

\"\"<\/p>\n

C\u00e2u 10:<\/b><\/p>\n

Theo t\u1ec9 s\u1ed1 th\u1ec3 t\u00edch ta c\u00f3 :<\/p>\n

\"\"<\/p>\n

C\u00e2u 11:<\/b><\/p>\n

G\u1ecdi A\u2019,B\u2019 l\u1ea7n l\u01b0\u1ee3t thu\u1ed9c c\u00e1c c\u1ea1nh SA, SB sao cho SA’ = SB’ = a. Khi \u0111\u00f3 SA\u2019B\u2019C\u2019 l\u00e0 t\u1ee9 di\u1ec7n \u0111\u1ec1u c\u1ea1nh b\u1eb1ng a. Theo c\u00f4ng th\u1ee9c t\u1ec9 s\u1ed1 th\u1ec3 t\u00edch ta c\u00f3 :<\/p>\n

\"\"<\/p>\n

C\u00e2u 12:<\/b><\/p>\n

T\u1eeb gi\u1ea3 thi\u1ebft ta c\u00f3 SO l\u00e0 tr\u1ee5c c\u1ee7a \u0111\u01b0\u1eddng tr\u00f2n ngo\u1ea1i ti\u1ebfp tam gi\u00e1c ABC v\u00e0 SA=SB=a. Trong m\u1eb7t ph\u1eb3ng (SAO), trung tr\u1ef1c c\u1ee7a c\u1ea1nh SA c\u1eaft SO t\u1ea1i I th\u00ec I l\u00e0 t\u00e2m c\u1ee7a m\u1eb7t c\u1ea7u ngo\u1ea1i ti\u1ebfp h\u00ecnh ch\u00f3p. Khi \u0111\u00f3 ta t\u00ednh \u0111\u01b0\u1ee3c :<\/p>\n

\"\"<\/p>\n

C\u00e2u 13:<\/b><\/p>\n

T\u1eeb gi\u1ea3 thi\u1ebft ta c\u00f3 SA \u22a5 (ABCD), theo \u0111\u1ecbnh l\u00ed ba \u0111\u01b0\u1eddng vu\u00f4ng g\u00f3c ta c\u00f3 tam gi\u00e1c SBC vu\u00f4ng t\u1ea1i B. G\u1ecdi S(B,r) l\u00e0 m\u1eb7t c\u1ea7u t\u00e2m B c\u1eaft SC theo m\u1ed9t d\u00e2y c\u00f3 \u0111\u1ed9 d\u00e0i 2a\/3. Khi \u0111\u00f3 ta t\u00ednh \u0111\u01b0\u1ee3c:<\/p>\n

\"\"<\/p>\n

C\u00e2u 14:<\/b><\/p>\n

T\u1eeb gi\u1ea3 thi\u1ebft ta c\u00f3 : 2\u03b1 = 90o<\/sup>\u00a0=> \u03b1 = 45o<\/sup>\u00a0=> h = r; l = r\u221a2<\/p>\n

Di\u1ec7n t\u00edch xung quanh c\u1ee7a h\u00ecnh n\u00f3n l\u00e0 : Sxq<\/sub>\u00a0= \u03c0rl = \u03c0r2<\/sup>\u221a2 = \u03c0\u221a2 => r = 1 => h = 1<\/p>\n

C\u00e2u 15:<\/b><\/p>\n

B\u1ea1n Nam cao 1,8m n\u00ean \u0111\u01b0\u1eddng k\u00ednh c\u1ee7a qu\u1ea3 b\u00f3ng kh\u00f4ng nh\u1ecf h\u01a1n 1,8m hay b\u00e1n k\u00ednh kh\u00f4ng nh\u1ecf h\u01a1n 0,9m. Do \u0111\u00f3 th\u1ec3 t\u00edch qu\u1ea3 b\u00f3ng th\u1ecfa m\u00e3n \u0111i\u1ec1u ki\u1ec7n l\u00e0 :<\/p>\n

\"\"<\/p>\n

C\u00e2u 16:<\/b><\/p>\n

T\u1eeb gi\u1ea3 thi\u1ebft ta c\u00f3 : h = 2r; V = \u03c0r2<\/sup>h = 2\u03c0 => r = 1, h = 2 => Sxq<\/sub>\u00a0= 2\u03c0rh = 4\u03c0<\/p>\n","protected":false},"excerpt":{"rendered":"

C\u00e2u 9:\u00a0Cho h\u00ecnh ch\u00f3p S.ABCD c\u00f3 SA \u22a5 (ABCD) , \u0111\u00e1y ABCD l\u00e0 h\u00ecnh ch\u1eef nh\u1eadt. SA = 2AD = 2a . G\u00f3c gi\u1eefa mp(SBC) v\u00e0 m\u1eb7t \u0111\u00e1y l\u00e0 45o\u00a0. G\u1ecdi M l\u00e0 trung \u0111i\u1ec3m c\u1ee7a BC. Kho\u1ea3ng c\u00e1ch t\u1eeb M \u0111\u1ebfn mp(SBD) l\u00e0: C\u00e2u 10:\u00a0Cho h\u00ecnh ch\u00f3p S.ABCD c\u00f3 \u0111\u00e1y ABCD l\u00e0 h\u00ecnh b\u00ecnh […]<\/p>\n","protected":false},"author":3,"featured_media":27114,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[157],"tags":[1450,1448],"yoast_head":"\nB\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m H\u00ecnh h\u1ecdc 12: \u00d4n t\u1eadp cu\u1ed1i n\u0103m (ph\u1ea7n 2)<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/bai-tap-trac-nghiem-hinh-hoc-12-on-tap-cuoi-nam-phan-2\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m H\u00ecnh h\u1ecdc 12: \u00d4n t\u1eadp cu\u1ed1i n\u0103m (ph\u1ea7n 2)\" \/>\n<meta property=\"og:description\" content=\"C\u00e2u 9:\u00a0Cho h\u00ecnh ch\u00f3p S.ABCD c\u00f3 SA \u22a5 (ABCD) , \u0111\u00e1y ABCD l\u00e0 h\u00ecnh ch\u1eef nh\u1eadt. SA = 2AD = 2a . G\u00f3c gi\u1eefa mp(SBC) v\u00e0 m\u1eb7t \u0111\u00e1y l\u00e0 45o\u00a0. G\u1ecdi M l\u00e0 trung \u0111i\u1ec3m c\u1ee7a BC. Kho\u1ea3ng c\u00e1ch t\u1eeb M \u0111\u1ebfn mp(SBD) l\u00e0: C\u00e2u 10:\u00a0Cho h\u00ecnh ch\u00f3p S.ABCD c\u00f3 \u0111\u00e1y ABCD l\u00e0 h\u00ecnh b\u00ecnh […]\" \/>\n<meta property=\"og:url\" content=\"https:\/\/lop12.edu.vn\/bai-tap-trac-nghiem-hinh-hoc-12-on-tap-cuoi-nam-phan-2\/\" \/>\n<meta property=\"og:site_name\" content=\"Lop12.edu.vn - C\u1ed9ng \u0111\u1ed3ng h\u1ecdc sinh l\u1edbp 12 l\u1edbn nh\u1ea5t t\u1ea1i Vi\u1ec7t Nam\" \/>\n<meta property=\"article:published_time\" content=\"2018-04-17T04:02:18+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/lop12.edu.vn\/wp-content\/uploads\/2018\/04\/on-tap-cuoi-nam-2.png\" \/>\n\t<meta property=\"og:image:width\" content=\"209\" \/>\n\t<meta property=\"og:image:height\" content=\"104\" \/>\n\t<meta property=\"og:image:type\" content=\"image\/png\" \/>\n<meta name=\"author\" content=\"H\u00e0 Trang\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"H\u00e0 Trang\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"4 minutes\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"WebPage\",\"@id\":\"https:\/\/lop12.edu.vn\/bai-tap-trac-nghiem-hinh-hoc-12-on-tap-cuoi-nam-phan-2\/\",\"url\":\"https:\/\/lop12.edu.vn\/bai-tap-trac-nghiem-hinh-hoc-12-on-tap-cuoi-nam-phan-2\/\",\"name\":\"B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m H\u00ecnh h\u1ecdc 12: \u00d4n t\u1eadp cu\u1ed1i n\u0103m (ph\u1ea7n 2)\",\"isPartOf\":{\"@id\":\"https:\/\/lop12.edu.vn\/#website\"},\"datePublished\":\"2018-04-17T04:02:18+00:00\",\"dateModified\":\"2018-04-17T04:02:18+00:00\",\"author\":{\"@id\":\"https:\/\/lop12.edu.vn\/#\/schema\/person\/2da855e5d06b553ac0065157cc261a45\"},\"breadcrumb\":{\"@id\":\"https:\/\/lop12.edu.vn\/bai-tap-trac-nghiem-hinh-hoc-12-on-tap-cuoi-nam-phan-2\/#breadcrumb\"},\"inLanguage\":\"en-US\",\"potentialAction\":[{\"@type\":\"ReadAction\",\"target\":[\"https:\/\/lop12.edu.vn\/bai-tap-trac-nghiem-hinh-hoc-12-on-tap-cuoi-nam-phan-2\/\"]}]},{\"@type\":\"BreadcrumbList\",\"@id\":\"https:\/\/lop12.edu.vn\/bai-tap-trac-nghiem-hinh-hoc-12-on-tap-cuoi-nam-phan-2\/#breadcrumb\",\"itemListElement\":[{\"@type\":\"ListItem\",\"position\":1,\"name\":\"Home\",\"item\":\"https:\/\/lop12.edu.vn\/\"},{\"@type\":\"ListItem\",\"position\":2,\"name\":\"B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m H\u00ecnh h\u1ecdc 12: \u00d4n t\u1eadp cu\u1ed1i n\u0103m (ph\u1ea7n 2)\"}]},{\"@type\":\"WebSite\",\"@id\":\"https:\/\/lop12.edu.vn\/#website\",\"url\":\"https:\/\/lop12.edu.vn\/\",\"name\":\"Lop12.edu.vn - C\u1ed9ng \u0111\u1ed3ng h\u1ecdc sinh l\u1edbp 12\",\"description\":\"\",\"potentialAction\":[{\"@type\":\"SearchAction\",\"target\":{\"@type\":\"EntryPoint\",\"urlTemplate\":\"https:\/\/lop12.edu.vn\/?s={search_term_string}\"},\"query-input\":\"required name=search_term_string\"}],\"inLanguage\":\"en-US\"},{\"@type\":\"Person\",\"@id\":\"https:\/\/lop12.edu.vn\/#\/schema\/person\/2da855e5d06b553ac0065157cc261a45\",\"name\":\"H\u00e0 Trang\",\"image\":{\"@type\":\"ImageObject\",\"inLanguage\":\"en-US\",\"@id\":\"https:\/\/lop12.edu.vn\/#\/schema\/person\/image\/\",\"url\":\"https:\/\/secure.gravatar.com\/avatar\/545a8100db1147f314111301d261dc33?s=96&d=mm&r=g\",\"contentUrl\":\"https:\/\/secure.gravatar.com\/avatar\/545a8100db1147f314111301d261dc33?s=96&d=mm&r=g\",\"caption\":\"H\u00e0 Trang\"},\"url\":\"https:\/\/lop12.edu.vn\/author\/trangvth2\/\"}]}<\/script>\n<!-- \/ Yoast SEO plugin. -->","yoast_head_json":{"title":"B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m H\u00ecnh h\u1ecdc 12: \u00d4n t\u1eadp cu\u1ed1i n\u0103m (ph\u1ea7n 2)","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/lop12.edu.vn\/bai-tap-trac-nghiem-hinh-hoc-12-on-tap-cuoi-nam-phan-2\/","og_locale":"en_US","og_type":"article","og_title":"B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m H\u00ecnh h\u1ecdc 12: \u00d4n t\u1eadp cu\u1ed1i n\u0103m (ph\u1ea7n 2)","og_description":"C\u00e2u 9:\u00a0Cho h\u00ecnh ch\u00f3p S.ABCD c\u00f3 SA \u22a5 (ABCD) , \u0111\u00e1y ABCD l\u00e0 h\u00ecnh ch\u1eef nh\u1eadt. 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