C\u00e2u 1:<\/b>\u00a0Di\u1ec7n t\u00edch h\u00ecnh ph\u1eb3ng gi\u1edbi h\u1ea1n b\u1edfi y = x2<\/sup>\u00a0– x + 3 v\u00e0 y = 2x + 1 l\u00e0:<\/p>\n <\/p>\n C\u00e2u 2:<\/b>\u00a0Cho \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 y = f(x). Di\u1ec7n t\u00edch h\u00ecnh ph\u1eb3ng ( ph\u1ea7n g\u1ea1ch s\u1ecdc ) l\u00e0:<\/p>\n <\/p>\n <\/p>\n C\u00e2u 3:<\/b>\u00a0Di\u1ec7n t\u00edch h\u00ecnh ph\u1eb3ng gi\u1edbi h\u1ea1n b\u1edfi \u0111\u1ed3 th\u1ecb hai h\u00e0m s\u1ed1 y = \u221a6 v\u00e0 y = 6 – x v\u00e0 tr\u1ee5c t\u00f9ng l\u00e0:<\/p>\n <\/p>\n C\u00e2u 4:<\/b>\u00a0Di\u1ec7n t\u00edch h\u00ecnh ph\u1eb3ng gi\u1edbi h\u1ea1n b\u1edfi \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 y = x + 1\/x , tr\u1ee5c ho\u00e0nh, \u0111\u01b0\u1eddng th\u1eb3ng x = -1 v\u00e0 \u0111\u01b0\u1eddng th\u1eb3ng x = -2 l\u00e0:<\/p>\n <\/p>\n C\u00e2u 5:<\/b>\u00a0T\u00ednh di\u1ec7n t\u00edch h\u00ecnh ph\u1eb3ng gi\u1edbi h\u1ea1n b\u1edfi \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 y = ex<\/sup>\u00a0– e-x<\/sup>\u00a0, tr\u1ee5c ho\u00e0nh, \u0111\u01b0\u1eddng th\u1eb3ng x = -1 v\u00e0 \u0111\u01b0\u1eddng th\u1eb3ng x = 1.<\/p>\n <\/p>\n C\u00e2u 6:<\/b>\u00a0T\u00ednh di\u1ec7n t\u00edch h\u00ecnh ph\u1eb3ng gi\u1edbi h\u1ea1n b\u1edfi \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 y = \u221ax – x v\u00e0 tr\u1ee5c ho\u00e0nh.<\/p>\n <\/p>\n H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0110\u00e1p \u00e1n<\/b><\/p>\n C\u00e2u 1:<\/b><\/p>\n Ta c\u00f3: x2<\/sup>\u00a0– x + 3 = 2x + 1 <=> x2<\/sup>\u00a0– 3x + 2 = 0 <=> x = 2 ho\u1eb7c x = 1<\/p>\n <\/p>\n C\u00e2u 3:<\/b><\/p>\n X\u00e9t ph\u01b0\u01a1ng tr\u00ecnh ho\u00e0nh \u0111\u1ed9 giao \u0111i\u1ec3m \u221a = 6 – x => x = 4. Khi \u0111\u00f3 di\u1ec7n t\u00edch gi\u1edbi h\u1ea1n \u0111\u01b0\u1ee3c t\u00ednh b\u1edfi:<\/p>\n <\/p>\n C\u00e2u 4:<\/b><\/p>\n Di\u1ec7n t\u00edch gi\u1edbi h\u1ea1n \u0111\u01b0\u1ee3c t\u00ednh b\u1edfi<\/p>\n <\/p>\n C\u00e2u 5:<\/b><\/p>\n Di\u1ec7n t\u00edch h\u00ecnh ph\u1eb3ng \u0111\u01b0\u1ee3c t\u00ednh b\u1edfi<\/p>\n <\/p>\n C\u00e2u 6:<\/b><\/p>\n X\u00e9t ph\u01b0\u01a1ng tr\u00ecnh<\/p>\n <\/p>\n Khi \u0111\u00f3 di\u1ec7n t\u00edch h\u00ecnh ph\u1eb3ng \u0111\u01b0\u1ee3c t\u00ednh b\u1edfi<\/p>\n <\/p>\n","protected":false},"excerpt":{"rendered":" C\u00e2u 1:\u00a0Di\u1ec7n t\u00edch h\u00ecnh ph\u1eb3ng gi\u1edbi h\u1ea1n b\u1edfi y = x2\u00a0– x + 3 v\u00e0 y = 2x + 1 l\u00e0: C\u00e2u 2:\u00a0Cho \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 y = f(x). Di\u1ec7n t\u00edch h\u00ecnh ph\u1eb3ng ( ph\u1ea7n g\u1ea1ch s\u1ecdc ) l\u00e0: C\u00e2u 3:\u00a0Di\u1ec7n t\u00edch h\u00ecnh ph\u1eb3ng gi\u1edbi h\u1ea1n b\u1edfi \u0111\u1ed3 th\u1ecb hai h\u00e0m s\u1ed1 y = […]<\/p>\n","protected":false},"author":3,"featured_media":26940,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[157],"tags":[1447,1446],"yoast_head":"\n\n\n
\n 1-C<\/td>\n 2-C<\/td>\n 3-D<\/td>\n 4-C<\/td>\n 5-C<\/td>\n 6-B<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n