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I = x2.sinx + x.cosx – 2sinx + C \u00a0\u00a0\u00a0B. I = x2.sinx + 2x.cosx – 2sinx + C C. I = x.sinx + 2x.cosx + C […]\" \/>\n<meta property=\"og:url\" content=\"https:\/\/lop12.edu.vn\/chuong-3-bai-tap-trac-nghiem-giai-tich-12-on-tap-chuong-3-phan-1\/\" \/>\n<meta property=\"og:site_name\" content=\"Lop12.edu.vn - C\u1ed9ng \u0111\u1ed3ng h\u1ecdc sinh l\u1edbp 12 l\u1edbn nh\u1ea5t t\u1ea1i Vi\u1ec7t Nam\" \/>\n<meta property=\"article:published_time\" content=\"2018-04-16T05:26:16+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/lop12.edu.vn\/wp-content\/uploads\/2018\/04\/bai-tap-trac-nghiem-on-tap-chuong-3-phan-1.png\" \/>\n\t<meta property=\"og:image:width\" content=\"147\" \/>\n\t<meta property=\"og:image:height\" content=\"59\" \/>\n\t<meta property=\"og:image:type\" content=\"image\/png\" \/>\n<meta name=\"author\" content=\"H\u00e0 Trang\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"H\u00e0 Trang\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"1 minute\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"WebPage\",\"@id\":\"https:\/\/lop12.edu.vn\/chuong-3-bai-tap-trac-nghiem-giai-tich-12-on-tap-chuong-3-phan-1\/\",\"url\":\"https:\/\/lop12.edu.vn\/chuong-3-bai-tap-trac-nghiem-giai-tich-12-on-tap-chuong-3-phan-1\/\",\"name\":\"Ch\u01b0\u01a1ng 3 - B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: \u00d4n t\u1eadp ch\u01b0\u01a1ng 3 (Ph\u1ea7n 1)\",\"isPartOf\":{\"@id\":\"https:\/\/lop12.edu.vn\/#website\"},\"datePublished\":\"2018-04-16T05:26:16+00:00\",\"dateModified\":\"2018-04-16T05:26:16+00:00\",\"author\":{\"@id\":\"https:\/\/lop12.edu.vn\/#\/schema\/person\/2da855e5d06b553ac0065157cc261a45\"},\"breadcrumb\":{\"@id\":\"https:\/\/lop12.edu.vn\/chuong-3-bai-tap-trac-nghiem-giai-tich-12-on-tap-chuong-3-phan-1\/#breadcrumb\"},\"inLanguage\":\"en-US\",\"potentialAction\":[{\"@type\":\"ReadAction\",\"target\":[\"https:\/\/lop12.edu.vn\/chuong-3-bai-tap-trac-nghiem-giai-tich-12-on-tap-chuong-3-phan-1\/\"]}]},{\"@type\":\"BreadcrumbList\",\"@id\":\"https:\/\/lop12.edu.vn\/chuong-3-bai-tap-trac-nghiem-giai-tich-12-on-tap-chuong-3-phan-1\/#breadcrumb\",\"itemListElement\":[{\"@type\":\"ListItem\",\"position\":1,\"name\":\"Home\",\"item\":\"https:\/\/lop12.edu.vn\/\"},{\"@type\":\"ListItem\",\"position\":2,\"name\":\"Ch\u01b0\u01a1ng 3 – B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: \u00d4n t\u1eadp ch\u01b0\u01a1ng 3 (Ph\u1ea7n 1)\"}]},{\"@type\":\"WebSite\",\"@id\":\"https:\/\/lop12.edu.vn\/#website\",\"url\":\"https:\/\/lop12.edu.vn\/\",\"name\":\"Lop12.edu.vn - C\u1ed9ng \u0111\u1ed3ng h\u1ecdc sinh l\u1edbp 12\",\"description\":\"\",\"potentialAction\":[{\"@type\":\"SearchAction\",\"target\":{\"@type\":\"EntryPoint\",\"urlTemplate\":\"https:\/\/lop12.edu.vn\/?s={search_term_string}\"},\"query-input\":\"required name=search_term_string\"}],\"inLanguage\":\"en-US\"},{\"@type\":\"Person\",\"@id\":\"https:\/\/lop12.edu.vn\/#\/schema\/person\/2da855e5d06b553ac0065157cc261a45\",\"name\":\"H\u00e0 Trang\",\"image\":{\"@type\":\"ImageObject\",\"inLanguage\":\"en-US\",\"@id\":\"https:\/\/lop12.edu.vn\/#\/schema\/person\/image\/\",\"url\":\"https:\/\/secure.gravatar.com\/avatar\/545a8100db1147f314111301d261dc33?s=96&d=mm&r=g\",\"contentUrl\":\"https:\/\/secure.gravatar.com\/avatar\/545a8100db1147f314111301d261dc33?s=96&d=mm&r=g\",\"caption\":\"H\u00e0 Trang\"},\"url\":\"https:\/\/lop12.edu.vn\/author\/trangvth2\/\"}]}<\/script>\n","yoast_head_json":{"title":"Ch\u01b0\u01a1ng 3 - B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: \u00d4n t\u1eadp ch\u01b0\u01a1ng 3 (Ph\u1ea7n 1)","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/lop12.edu.vn\/chuong-3-bai-tap-trac-nghiem-giai-tich-12-on-tap-chuong-3-phan-1\/","og_locale":"en_US","og_type":"article","og_title":"Ch\u01b0\u01a1ng 3 - B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: \u00d4n t\u1eadp ch\u01b0\u01a1ng 3 (Ph\u1ea7n 1)","og_description":"C\u00e2u 1:\u00a0H\u1ecd nguy\u00ean h\u00e0m c\u1ee7a h\u00e0m s\u1ed1 C\u00e2u 2:\u00a0Trong nh\u1eefng ph\u00e1t bi\u1ec3u sau, ph\u00e1t bi\u1ec3u n\u00e0o l\u00e0 sai? 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I = x.sinx + 2x.cosx + C […]","og_url":"https:\/\/lop12.edu.vn\/chuong-3-bai-tap-trac-nghiem-giai-tich-12-on-tap-chuong-3-phan-1\/","og_site_name":"Lop12.edu.vn - C\u1ed9ng \u0111\u1ed3ng h\u1ecdc sinh l\u1edbp 12 l\u1edbn nh\u1ea5t t\u1ea1i Vi\u1ec7t Nam","article_published_time":"2018-04-16T05:26:16+00:00","og_image":[{"width":147,"height":59,"url":"https:\/\/lop12.edu.vn\/wp-content\/uploads\/2018\/04\/bai-tap-trac-nghiem-on-tap-chuong-3-phan-1.png","type":"image\/png"}],"author":"H\u00e0 Trang","twitter_card":"summary_large_image","twitter_misc":{"Written by":"H\u00e0 Trang","Est. reading time":"1 minute"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/lop12.edu.vn\/chuong-3-bai-tap-trac-nghiem-giai-tich-12-on-tap-chuong-3-phan-1\/","url":"https:\/\/lop12.edu.vn\/chuong-3-bai-tap-trac-nghiem-giai-tich-12-on-tap-chuong-3-phan-1\/","name":"Ch\u01b0\u01a1ng 3 - B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: \u00d4n t\u1eadp ch\u01b0\u01a1ng 3 (Ph\u1ea7n 1)","isPartOf":{"@id":"https:\/\/lop12.edu.vn\/#website"},"datePublished":"2018-04-16T05:26:16+00:00","dateModified":"2018-04-16T05:26:16+00:00","author":{"@id":"https:\/\/lop12.edu.vn\/#\/schema\/person\/2da855e5d06b553ac0065157cc261a45"},"breadcrumb":{"@id":"https:\/\/lop12.edu.vn\/chuong-3-bai-tap-trac-nghiem-giai-tich-12-on-tap-chuong-3-phan-1\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/lop12.edu.vn\/chuong-3-bai-tap-trac-nghiem-giai-tich-12-on-tap-chuong-3-phan-1\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/lop12.edu.vn\/chuong-3-bai-tap-trac-nghiem-giai-tich-12-on-tap-chuong-3-phan-1\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/lop12.edu.vn\/"},{"@type":"ListItem","position":2,"name":"Ch\u01b0\u01a1ng 3 – B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: \u00d4n t\u1eadp ch\u01b0\u01a1ng 3 (Ph\u1ea7n 1)"}]},{"@type":"WebSite","@id":"https:\/\/lop12.edu.vn\/#website","url":"https:\/\/lop12.edu.vn\/","name":"Lop12.edu.vn - C\u1ed9ng \u0111\u1ed3ng h\u1ecdc sinh l\u1edbp 12","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/lop12.edu.vn\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/lop12.edu.vn\/#\/schema\/person\/2da855e5d06b553ac0065157cc261a45","name":"H\u00e0 Trang","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/lop12.edu.vn\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/545a8100db1147f314111301d261dc33?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/545a8100db1147f314111301d261dc33?s=96&d=mm&r=g","caption":"H\u00e0 Trang"},"url":"https:\/\/lop12.edu.vn\/author\/trangvth2\/"}]}},"_links":{"self":[{"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/posts\/26912"}],"collection":[{"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/users\/3"}],"replies":[{"embeddable":true,"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/comments?post=26912"}],"version-history":[{"count":1,"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/posts\/26912\/revisions"}],"predecessor-version":[{"id":26923,"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/posts\/26912\/revisions\/26923"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/media\/26922"}],"wp:attachment":[{"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/media?parent=26912"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/categories?post=26912"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/tags?post=26912"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}

{"id":26912,"date":"2018-04-16T12:26:16","date_gmt":"2018-04-16T05:26:16","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=26912"},"modified":"2018-04-16T12:26:16","modified_gmt":"2018-04-16T05:26:16","slug":"chuong-3-bai-tap-trac-nghiem-giai-tich-12-on-tap-chuong-3-phan-1","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/chuong-3-bai-tap-trac-nghiem-giai-tich-12-on-tap-chuong-3-phan-1\/","title":{"rendered":"Ch\u01b0\u01a1ng 3 – B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: \u00d4n t\u1eadp ch\u01b0\u01a1ng 3 (Ph\u1ea7n 1)"},"content":{"rendered":"

C\u00e2u 1:<\/b>\u00a0H\u1ecd nguy\u00ean h\u00e0m c\u1ee7a h\u00e0m s\u1ed1<\/p>\n

$\"B\u00e0i$ $\"\"$ <\/p>\n

C\u00e2u 2:<\/b>\u00a0Trong nh\u1eefng ph\u00e1t bi\u1ec3u sau, ph\u00e1t bi\u1ec3u n\u00e0o l\u00e0 sai?<\/p>\n

$\"\"$ <\/p>\n

C\u00e2u 3:<\/b>\u00a0T\u00ecm nguy\u00ean h\u00e0m c\u1ee7a h\u00e0m s\u1ed1<\/p>\n

$\"\"$ <\/p>\n

C\u00e2u 4:<\/b><\/p>\n

$\"\"$ <\/p>\n

A. I = x^{2<\/sup>.sinx + x.cosx – 2sinx + C \u00a0\u00a0\u00a0B. I = x^{2<\/sup>.sinx + 2x.cosx – 2sinx + C<\/p>\n}}

C. I = x.sinx + 2x.cosx + C \u00a0\u00a0\u00a0D. I = 2x.cosx + sinx + C<\/p>\n

C\u00e2u 5:<\/b><\/p>\n

$\"\"$ <\/p>\n

A. I = ln^{3<\/sup>x – 2ln^{2<\/sup>x + 2lnx + C \u00a0\u00a0\u00a0B. I = -ln^{3<\/sup>x – 2ln^{2<\/sup>x + 2lnx + C<\/p>\n}}}}

C. I = ln^{3<\/sup>x + 2ln^{2<\/sup>x + 2lnx + C \u00a0\u00a0\u00a0D. I = ln^{3<\/sup>x – 2ln^{2<\/sup>x – 2lnx + C<\/p>\n}}}}

C\u00e2u 6:<\/b><\/p>\n

$\"\"$ <\/p>\n

H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0110\u00e1p \u00e1n<\/b><\/p>\n\n\n\n
1-D<\/td>\n 2-C<\/td>\n 3-C<\/td>\n 4-B<\/td>\n 5-A<\/td>\n 6-D<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n
C\u00e2u 1:<\/b><\/p>\n
$\"\"$ <\/p>\n
C\u00e2u 3:<\/b><\/p>\n
$\"\"$ <\/p>\n
C\u00e2u 5:<\/b><\/p>\n
\u0110\u1eb7t: t = lnx => dt = dx\/x .<\/p>\n
Ta c\u00f3: I = \u222b(3t^{2<\/sup>\u00a0– 4t + 2)dt = t^{3<\/sup>\u00a0– 2t^{2<\/sup>\u00a0+ 2t + C = ln^{3<\/sup>x – 2ln^{2<\/sup>x + 2lnx + C<\/p>\n}}}}}
C\u00e2u 6:<\/b><\/p>\n
$\"\"$ <\/p>\n","protected":false},"excerpt":{"rendered":"
C\u00e2u 1:\u00a0H\u1ecd nguy\u00ean h\u00e0m c\u1ee7a h\u00e0m s\u1ed1 C\u00e2u 2:\u00a0Trong nh\u1eefng ph\u00e1t bi\u1ec3u sau, ph\u00e1t bi\u1ec3u n\u00e0o l\u00e0 sai? C\u00e2u 3:\u00a0T\u00ecm nguy\u00ean h\u00e0m c\u1ee7a h\u00e0m s\u1ed1 C\u00e2u 4: A. I = x2.sinx + x.cosx – 2sinx + C \u00a0\u00a0\u00a0B. I = x2.sinx + 2x.cosx – 2sinx + C C. I = x.sinx + 2x.cosx + C […]<\/p>\n","protected":false},"author":3,"featured_media":26922,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[157],"tags":[1447,1446],"yoast_head":"\nCh\u01b0\u01a1ng 3 - B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: \u00d4n t\u1eadp ch\u01b0\u01a1ng 3 (Ph\u1ea7n 1)<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/chuong-3-bai-tap-trac-nghiem-giai-tich-12-on-tap-chuong-3-phan-1\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Ch\u01b0\u01a1ng 3 - B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: \u00d4n t\u1eadp ch\u01b0\u01a1ng 3 (Ph\u1ea7n 1)\" \/>\n<meta property=\"og:description\" content=\"C\u00e2u 1:\u00a0H\u1ecd nguy\u00ean h\u00e0m c\u1ee7a h\u00e0m s\u1ed1 C\u00e2u 2:\u00a0Trong nh\u1eefng ph\u00e1t bi\u1ec3u sau, ph\u00e1t bi\u1ec3u n\u00e0o l\u00e0 sai? C\u00e2u 3:\u00a0T\u00ecm nguy\u00ean h\u00e0m c\u1ee7a h\u00e0m s\u1ed1 C\u00e2u 4: A. I = x2.sinx + x.cosx – 2sinx + C \u00a0\u00a0\u00a0B. I = x2.sinx + 2x.cosx – 2sinx + C C. 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