C\u00e2u 20:<\/b>\u00a0T\u00ednh nguy\u00ean h\u00e0m<\/p>\n

<\/p>\n

C\u00e2u 21:<\/b>\u00a0M\u1ed9t \u00f4 t\u00f4 \u0111ang ch\u1ea1y v\u1edbi v\u1eadn t\u1ed1c 10m\/s th\u00ec ng\u01b0\u1eddi l\u00e1i \u0111\u1ea1p phanh, t\u1eeb th\u1eddi \u0111i\u1ec3m \u0111\u00f3, \u00f4 t\u00f4 chuy\u1ec3n \u0111\u1ed9ng ch\u1eadm d\u1ea7n \u0111\u1ec1u v\u1edbi v\u1eadn t\u1ed1c v(t) = -5t + 10(m\/s), trong \u0111\u00f3 t l\u00e0 kho\u1ea3ng th\u1eddi gian t\u00ednh b\u1eb1ng gi\u00e2y , k\u1ec3 t\u1eeb l\u00fac b\u1eaft \u0111\u1ea7u \u0111\u1ea1p phanh .H\u1ecfi t\u1eeb l\u00fac \u0111\u1ea1p phanh \u0111\u1ebfn khi d\u1eebng h\u1eb3n, \u00f4 t\u00f4 c\u00f2n di chuy\u1ec3n bao nhi\u00eau m\u00e9t?<\/p>\n

A.0,2m \u00a0\u00a0\u00a0 B.2m \u00a0\u00a0\u00a0 C.10m \u00a0\u00a0\u00a0 D.20m.<\/p>\n

C\u00e2u 22:<\/b>\u00a0T\u00ecm m \u0111\u1ec3<\/p>\n

<\/p>\n

l\u00e0 nghi\u1ec7m ph\u01b0\u01a1ng tr\u00ecnh: mt^{3<\/sup>\u00a0+ 3t2<\/sup>\u00a0+ m – 3<\/p>\n}

A. m = 2 \u00a0\u00a0\u00a0B. m = -1 \u00a0\u00a0\u00a0 C. m = 4 \u00a0\u00a0\u00a0D. Gi\u00e1 tr\u1ecb kh\u00e1c.<\/p>\n

C\u00e2u 23:<\/b>\u00a0Cho parabol (P): y^{2<\/sup>\u00a0= 2x v\u00e0 \u0111\u01b0\u1eddng tr\u00f2n ( C ): x2<\/sup>\u00a0+ y2<\/sup>\u00a0= 8 . (P) chia ( C ) th\u00e0nh hai ph\u1ea7n . T\u00ecm t\u1ec9 s\u1ed1 di\u1ec7n t\u00edch c\u1ee7a hai ph\u1ea7n \u0111\u00f3.<\/p>\n}

<\/p>\n

C\u00e2u 24:<\/b>\u00a0T\u00ednh di\u1ec7n t\u00edch h\u00ecnh ph\u1eb3ng gi\u1edbi h\u1ea1n b\u1edfi \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1<\/p>\n

<\/p>\n

v\u00e0 \u0111\u01b0\u1eddng th\u1eb3ng y = x+2.<\/p>\n

A. 1\/12 \u00a0\u00a0\u00a0 B. 1\/6\u00a0\u00a0\u00a0 C. 1\/3 \u00a0\u00a0\u00a0 D. 1\/2<\/p>\n

C\u00e2u 25:<\/b>\u00a0T\u00ednh th\u1ec3 t\u00edch h\u00ecnh tr\u00f2ng xoay khi quay quanh tr\u1ee5c Ox m\u1ed9t h\u00ecnh ph\u1eb3ng gi\u1edbi h\u1ea1n b\u1edfi \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1<\/p>\n

<\/p>\n

tr\u1ee5c Ox, hai \u0111\u01b0\u1eddng th\u1eb3ng x = 1 v\u00e0 x = 3.<\/p>\n

<\/p>\n

H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0110\u00e1p \u00e1n<\/b><\/p>\n\n\n\n

19-B<\/td>\n

20-C<\/td>\n

21-C<\/td>\n

22-B<\/td>\n

23-D<\/td>\n

24-B<\/td>\n

25-C<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n","protected":false},"excerpt":{"rendered":" C\u00e2u 19:\u00a0Nguy\u00ean h\u00e0m c\u1ee7a h\u00e0m s\u1ed1 C\u00e2u 20:\u00a0T\u00ednh nguy\u00ean h\u00e0m C\u00e2u 21:\u00a0M\u1ed9t \u00f4 t\u00f4 \u0111ang ch\u1ea1y v\u1edbi v\u1eadn t\u1ed1c 10m\/s th\u00ec ng\u01b0\u1eddi l\u00e1i \u0111\u1ea1p phanh, t\u1eeb th\u1eddi \u0111i\u1ec3m \u0111\u00f3, \u00f4 t\u00f4 chuy\u1ec3n \u0111\u1ed9ng ch\u1eadm d\u1ea7n \u0111\u1ec1u v\u1edbi v\u1eadn t\u1ed1c v(t) = -5t + 10(m\/s), trong \u0111\u00f3 t l\u00e0 kho\u1ea3ng th\u1eddi gian t\u00ednh b\u1eb1ng gi\u00e2y , […]<\/p>\n","protected":false},"author":3,"featured_media":26858,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[157],"tags":[1447,1446],"yoast_head":"\n