2<\/sub>\u00a0. Kho\u1ea3ng c\u00e1ch nh\u1ecf nh\u1ea5t c\u1ee7a \u0111o\u1ea1n th\u1eb3ng MN l\u00e0:<\/p>\n![\"\"](\"https:\/\/lop12.edu.vn\/wp-content\/uploads\/2018\/04\/on-tap-cuoi-nam-5-1.png\")
<\/p>\n
C\u00e2u 34:<\/b>\u00a0Trong kh\u00f4ng gian Oxyz, cho hai \u0111i\u1ec3m A(3;2;1), M(3;0;0) v\u00e0 m\u1eb7t ph\u1eb3ng (P) c\u00f3 ph\u01b0\u01a1ng tr\u00ecnh l\u00e0: x + y + z – 3 = 0 . Vi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh c\u1ee7a \u0111\u01b0\u1eddng th\u1eb3ng d \u0111i qua \u0111i\u1ec3m M, n\u1eb1m trong m\u1eb7t ph\u1eb3ng (P) sao cho kho\u1ea3ng c\u00e1ch t\u1eeb A \u0111\u1ebfn \u0111\u01b0\u1eddng th\u1eb3ng d nh\u1ecf nh\u1ea5t<\/p>\n
A. x = -3 – t, y = t, z = 0 \u00a0\u00a0\u00a0C. x = 3 – t, y = t, z = 0<\/p>\n
B. x = 3 + t, y = 2t, z = 2t \u00a0\u00a0\u00a0D. x = -1 + 3t, y = 1, z = 0<\/p>\n
C\u00e2u 35:<\/b>\u00a0Cho m\u1ed9t \u0111\u1ed3 ch\u01a1i h\u00ecnh kh\u1ed1i ch\u00f3p S.ABC c\u00f3 SA, SB, SC \u0111\u00f4i m\u1ed9t vu\u00f4ng g\u00f3c v\u1edbi nhau v\u00e0 SA = SB = SC = 6cm. Trong t\u1ea5t c\u1ea3 c\u00e1c kh\u1ed1i c\u1ea7u c\u00f3 th\u1ec3 ch\u1ee9a \u0111\u1ed3 ch\u01a1i \u0111\u00f3 th\u00ec kh\u1ed1i c\u1ea7u c\u00f3 b\u00e1n k\u00ednh nh\u1ecf nh\u1ea5t l\u00e0:<\/p>\n
A. \u221a6 (cm)\u00a0\u00a0\u00a0B. 2\u221a6 (cm) \u00a0\u00a0\u00a0C. 3\u221a3 (cm)\u00a0\u00a0\u00a0D. 3\u221a6 (cm)<\/p>\n
C\u00e2u 36:<\/b>\u00a0Trong kh\u00f4ng gian Oxyz, cho c\u00e1c \u0111i\u1ec3m A(1;1;0), B(0;1;1). T\u00ecm tr\u00ean m\u1eb7t ph\u1eb3ng xOz t\u1ecda \u0111\u1ed9 \u0111i\u1ec3m C \u0111\u1ec3 OABC l\u00e0 m\u1ed9t t\u1ee9 di\u1ec7n \u0111\u1ec1u<\/p>\n
A. C(0;0;1)\u00a0\u00a0\u00a0B. C(1;0;0)\u00a0\u00a0\u00a0C. C(1;0;1)\u00a0\u00a0\u00a0D. C(2;0;2)<\/p>\n
C\u00e2u 37:<\/b>\u00a0Trong kh\u00f4ng gian Oxyz, cho m\u1eb7t c\u1ea7u (S) c\u00f3 ph\u01b0\u01a1ng tr\u00ecnh x2<\/sup>\u00a0+ y2<\/sup>\u00a0+ z2<\/sup>\u00a0= 1. Vi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh m\u1eb7t ph\u1eb3ng (P) \u0111i qua<\/p>\n![\"\"](\"https:\/\/lop12.edu.vn\/wp-content\/uploads\/2018\/04\/on-tap-cuoi-nam-5-2.png\")
<\/p>\n
v\u00e0 ti\u1ebfp x\u00fac v\u1edbi (S)<\/p>\n
A. \u221a3x + 4z – 2 = 0\u00a0\u00a0\u00a0C. y + \u221a3z = 0<\/p>\n
B. \u221a3y + z – 2 = 0 \u00a0\u00a0\u00a0D. x + \u221a3y + z – 2 = 0<\/p>\n
H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0110\u00e1p \u00e1n<\/b><\/p>\n\n\n\n| 31-B<\/td>\n | 32-A<\/td>\n | 33-B<\/td>\n | 34-C<\/td>\n | 35-B<\/td>\n | 36-C<\/td>\n | 37-B<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n C\u00e2u 34:<\/b><\/p>\n \u0110\u01b0\u1eddng th\u1eb3ng d c\u1ea7n t\u00ecm \u0111i qua h\u00ecnh chi\u1ebfu vu\u00f4ng g\u00f3c H c\u1ee7a A tr\u00ean m\u1eb7t ph\u1eb3ng (P)<\/p>\n C\u00e2u 35:<\/b><\/p>\n X\u00e9t m\u1eb7t c\u1ea7u t\u00e2m I, l\u00e0 t\u00e2m c\u1ee7a tam gi\u00e1c \u0111\u1ec1u ABC, v\u00e0 c\u00f3 b\u00e1n k\u00ednh r = 2\u221a6, b\u1eb1ng b\u00e1n k\u00ednh \u0111\u01b0\u1eddng tr\u00f2n ngo\u1ea1i ti\u1ebfp tam gi\u00e1c ABC. Do kho\u1ea3ng c\u00e1ch OI = 2\u221a3 < r = 2\u221a6 n\u00ean m\u1eb7t c\u1ea7u S(I,r) ch\u1ee9a h\u00ecnh ch\u00f3p S.ABC. \u0110\u00e1p \u00e1n \u0111\u00fang l\u00e0 B<\/p>\n L\u01b0u \u00fd. L\u1ed7i th\u01b0\u1eddng g\u1eb7p l\u00e0 ch\u1ecdn \u0111\u00e1p \u00e1n C v\u00ec \u0111\u00f3 l\u00e0 b\u00e1n k\u00ednh m\u1eb7t c\u1ea7u ngo\u1ea1i ti\u1ebfp h\u00ecnh ch\u00f3p S.ABC.<\/p>\n C\u00e2u 36:<\/b><\/p>\n D\u1ef1ng h\u00ecnh l\u1eadp ph\u01b0\u01a1ng c\u1ea1nh b\u1eb1ng 1, nh\u1eadn O, A, B, C l\u00e0m c\u00e1c \u0111\u1ec9nh.<\/p>\n C\u00e2u 37:<\/b><\/p>\n M thu\u1ed9c (S) n\u00ean<\/p>\n ![\"\"](\"https:\/\/lop12.edu.vn\/wp-content\/uploads\/2018\/04\/on-tap-cuoi-nam-5-3.png\") <\/p>\n
l\u00e0 m\u1ed9t vect\u01a1 ph\u00e1p tuy\u1ebfn c\u1ee7a (P).<\/p>\n","protected":false},"excerpt":{"rendered":" C\u00e2u 31:\u00a0Trong kh\u00f4ng gian Oxyz, cho b\u1ed1n \u0111i\u1ec3m A(1;0;0), B(0;-2;0), C(0;0;2), M(1;1;4). T\u00ednh kho\u1ea3ng c\u00e1ch t\u1eeb M \u0111\u1ebfn m\u1eb7t ph\u1eb3ng (ABC) A. 0\u00a0\u00a0\u00a0B. \u221a6\/2\u00a0\u00a0\u00a0C. 1\/2\u00a0\u00a0\u00a0D. 2 C\u00e2u 32:\u00a0Trong kh\u00f4ng gian Oxyz, cho hai m\u1eb7t ph\u1eb3ng (P): 2x – y – 2z + 7 = 0, (Q): 2x – y – 2z + 1 = 0. […]<\/p>\n","protected":false},"author":3,"featured_media":26779,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[157],"tags":[1450,1448],"yoast_head":"\n B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m H\u00ecnh h\u1ecdc 12: \u00d4n t\u1eadp cu\u1ed1i n\u0103m (ph\u1ea7n 5)<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/bai-tap-trac-nghiem-hinh-hoc-12-on-tap-cuoi-nam-phan-5\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m H\u00ecnh h\u1ecdc 12: \u00d4n t\u1eadp cu\u1ed1i n\u0103m (ph\u1ea7n 5)\" \/>\n<meta property=\"og:description\" content=\"C\u00e2u 31:\u00a0Trong kh\u00f4ng gian Oxyz, cho b\u1ed1n \u0111i\u1ec3m A(1;0;0), B(0;-2;0), C(0;0;2), M(1;1;4). T\u00ednh kho\u1ea3ng c\u00e1ch t\u1eeb M \u0111\u1ebfn m\u1eb7t ph\u1eb3ng (ABC) A. 0\u00a0\u00a0\u00a0B. \u221a6\/2\u00a0\u00a0\u00a0C. 1\/2\u00a0\u00a0\u00a0D. 2 C\u00e2u 32:\u00a0Trong kh\u00f4ng gian Oxyz, cho hai m\u1eb7t ph\u1eb3ng (P): 2x – y – 2z + 7 = 0, (Q): 2x – y – 2z + 1 = 0. 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T\u00ednh kho\u1ea3ng c\u00e1ch t\u1eeb M \u0111\u1ebfn m\u1eb7t ph\u1eb3ng (ABC) A. 0\u00a0\u00a0\u00a0B. \u221a6\/2\u00a0\u00a0\u00a0C. 1\/2\u00a0\u00a0\u00a0D. 2 C\u00e2u 32:\u00a0Trong kh\u00f4ng gian Oxyz, cho hai m\u1eb7t ph\u1eb3ng (P): 2x – y – 2z + 7 = 0, (Q): 2x – y – 2z + 1 = 0. 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![\"\"](\"https:\/\/lop12.edu.vn\/wp-content\/uploads\/2018\/04\/on-tap-cuoi-nam-5.png\")
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