C\u00e2u 19:\u00a0<\/strong>Trong kh\u00f4ng gian Oxyz, cho hai \u0111i\u1ec3m A(-1;0;2), B(1;-1;-2). Ph\u01b0\u01a1ng tr\u00ecnh c\u1ee7a m\u1eb7t ph\u1eb3ng (P) \u0111i qua A v\u00e0 vu\u00f4ng g\u00f3c v\u1edbi \u0111\u01b0\u1eddng th\u1eb3ng AB l\u00e0:<\/p>\n A. 2x – y – 4z + 10 = 0 \u00a0\u00a0\u00a0C. x – y – 2z + 5 = 0<\/p>\n B. 2x – y – 4z – 10 = 0 \u00a0\u00a0\u00a0D. 2x – y – 3z – 8 = 0<\/p>\n C\u00e2u 20:<\/b>\u00a0Trong kh\u00f4ng gian Oxyz, l\u1eadp ph\u01b0\u01a1ng tr\u00ecnh c\u1ee7a m\u1eb7t c\u1ea7u (S) c\u00f3 b\u00e1n k\u00ednh b\u1eb1ng 5 v\u00e0 ti\u1ebfp x\u00fac v\u1edbi m\u1eb7t ph\u1eb3ng (P): 3x – 4y – 4 = 0 t\u1ea1i \u0111i\u1ec3m A(4;2;1)<\/p>\n A. (x – 7)2<\/sup>\u00a0+ (y + 2)2<\/sup>\u00a0+ (z – 1)2<\/sup>\u00a0= 25<\/p>\n B. (x – 7)2<\/sup>\u00a0+ (y + 2)2<\/sup>\u00a0+ (z – 1)2<\/sup>\u00a0ho\u1eb7c (x – 1)2<\/sup>\u00a0+ (y – 6)2<\/sup>\u00a0+ (z – 1)2<\/sup>\u00a0= 25<\/p>\n C. (x + 7)2<\/sup>\u00a0+ (y – 2)2<\/sup>\u00a0+ (z + 1)2<\/sup>\u00a0= 25<\/p>\n D. (x + 7)2<\/sup>\u00a0+ (y – 2)2<\/sup>\u00a0+ (z + 1)2<\/sup>\u00a0ho\u1eb7c (x + 1)2<\/sup>\u00a0+ (y + 6)2<\/sup>\u00a0+ (z + 1)2<\/sup>\u00a0= 25<\/p>\n C\u00e2u 21:<\/b>\u00a0V\u1ecb tr\u00ed t\u01b0\u01a1ng \u0111\u1ed1i c\u1ee7a hai \u0111\u01b0\u1eddng th\u1eb3ng<\/p>\n <\/p>\n A. C\u1eaft nhau\u00a0\u00a0\u00a0B. song song\u00a0\u00a0\u00a0C. ch\u00e9o nhau\u00a0\u00a0\u00a0 D. tr\u00f9ng nhau<\/p>\n C\u00e2u 22:<\/b>\u00a0Trong kh\u00f4ng gian Oxyz, t\u1ecda \u0111\u1ed9 \u0111i\u1ec3m N \u0111\u1ed1i x\u1ee9ng v\u1edbi \u0111i\u1ec3m M(-5 ;2 ;-3) qua m\u1eb7t ph\u1eb3ng (P) : 2x – 2y + z – 1 = 0 l\u00e0 :<\/p>\n A. N(3 ;-6 ;1)\u00a0\u00a0\u00a0C. N(3 ;-2 ;-5)<\/p>\n B. N(-13 ;14 ;-7)\u00a0\u00a0\u00a0D. \u0110\u00e1p \u00e1n kh\u00e1c<\/p>\n C\u00e2u 23:<\/b>\u00a0Trong kh\u00f4ng gian Oxyz, cho ba \u0111i\u1ec3m A(0 ;2 ;-4), B(-3 ;5 ;2), C(6 ;-1 ;-1). T\u00ecm t\u1ecda \u0111\u1ed9 c\u1ee7a \u0111i\u1ec3m M thu\u1ed9c m\u1eb7t ph\u1eb3ng (Oxy) sao cho bi\u1ec3u th\u1ee9c MA2<\/sup>\u00a0+ MB2<\/sup>\u00a0+ MC2<\/sup>\u00a0\u0111\u1ea1t gi\u00e1 tr\u1ecb nh\u1ecf nh\u1ea5t<\/p>\n A. (1;2;-1)\u00a0\u00a0\u00a0B. (3;6;0)\u00a0\u00a0\u00a0C. (1;2;0)\u00a0\u00a0\u00a0D. (0;0;0)<\/p>\n C\u00e2u 24:<\/b>\u00a0Trong kh\u00f4ng gian Oxyz, cho m\u1eb7t ph\u1eb3ng (P) \u0111i qua \u0111i\u1ec3m M(-1;-1;-1) v\u00e0 c\u1eaft c\u00e1c tr\u1ee5c t\u1ecda \u0111\u1ed9 Ox, Oy, Oz l\u1ea7n l\u01b0\u1ee3t t\u1ea1i c\u00e1c \u0111i\u1ec3m A, B, C (kh\u00e1c O) sao cho O, A, B, C l\u00e0 b\u1ed1n \u0111\u1ec9nh c\u1ee7a m\u1ed9t h\u00ecnh ch\u00f3p \u0111\u1ec1u. S\u1ed1 m\u1eb7t ph\u1eb3ng (P) th\u1ecfa m\u00e3n b\u00e0i to\u00e1n l\u00e0:<\/p>\n A. 8\u00a0\u00a0\u00a0B. 6\u00a0\u00a0\u00a0C. 3\u00a0\u00a0\u00a0D. 4<\/p>\n C\u00e2u 25:<\/b>\u00a0Trong kh\u00f4ng gian Oxyz, cho b\u1ed1n \u0111i\u1ec3m A(3;4;0), B(1;2;0), C(2;0;1), D(-1;1;3). H\u1ecfi c\u00f3 bao nhi\u00eau m\u1eb7t ph\u1eb3ng (P) \u0111i qua A \u0111\u1ed3ng th\u1eddi (P) c\u00e1ch \u0111\u1ec1u ba \u0111i\u1ec3m B, C, D?<\/p>\n A. 0\u00a0\u00a0\u00a0B. 4\u00a0\u00a0\u00a0C. 1\u00a0\u00a0\u00a0D. V\u00f4 s\u1ed1<\/p>\n H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0110\u00e1p \u00e1n<\/b><\/p>\n <\/p>\n","protected":false},"excerpt":{"rendered":" C\u00e2u 19:\u00a0Trong kh\u00f4ng gian Oxyz, cho hai \u0111i\u1ec3m A(-1;0;2), B(1;-1;-2). Ph\u01b0\u01a1ng tr\u00ecnh c\u1ee7a m\u1eb7t ph\u1eb3ng (P) \u0111i qua A v\u00e0 vu\u00f4ng g\u00f3c v\u1edbi \u0111\u01b0\u1eddng th\u1eb3ng AB l\u00e0: A. 2x – y – 4z + 10 = 0 \u00a0\u00a0\u00a0C. x – y – 2z + 5 = 0 B. 2x – y – 4z – 10 […]<\/p>\n","protected":false},"author":3,"featured_media":26761,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[157],"tags":[1449,1448],"yoast_head":"\n\n\n
\n 19-A<\/td>\n 20-B<\/td>\n 21-A<\/td>\n 22-A<\/td>\n 23-C<\/td>\n 24-D<\/td>\n 25-B<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n