C\u00e2u 20:<\/b>\u00a0Ti\u0300m mi\u00ea\u0300n xa\u0301c \u0111i\u0323nh cu\u0309a ha\u0300m s\u00f4\u0301<\/p>\n
<\/p>\n
A. D = (1; +\u221e)\\{ee<\/sup>}\u00a0\u00a0\u00a0B. D = (0; +\u221e)\\{e}<\/p>\n C. D = (ee<\/sup>; +\u221e)\u00a0\u00a0\u00a0D. D = (1; +\u221e)\\{e}<\/p>\n C\u00e2u 21:<\/b>\u00a0Nga\u0300y 15 tha\u0301ng 2 n\u0103m 2010 \u00f4ng A g\u01b0\u0309i va\u0300o ng\u00e2n ha\u0300ng 500 tri\u00ea\u0323u \u0111\u00f4\u0300ng v\u01a1\u0301i hi\u0300nh th\u01b0\u0301c la\u0303i ke\u0301p va\u0300 la\u0303i su\u00e2\u0301t 10,3% m\u00f4\u0323t n\u0103m. Ta\u0323i th\u01a1\u0300i \u0111i\u00ea\u0309m \u0111o\u0301 \u00f4ng A d\u01b0\u0323 ti\u0301nh se\u0303 ru\u0301t h\u00ea\u0301t ti\u00ea\u0300n ra va\u0300o 15 tha\u0301ng 2 n\u0103m 2013. N\u00ea\u0301u trong khoa\u0309ng th\u01a1\u0300i gian \u0111o\u0301 la\u0303i su\u00e2\u0301t kh\u00f4ng thay \u0111\u00f4\u0309i thi\u0300 s\u00f4\u0301 ti\u00ea\u0300n ma\u0300 \u00f4ng A ru\u0301t \u0111\u01b0\u01a1\u0323c la\u0300 bao nhi\u00eau? La\u0300m tro\u0300n k\u00ea\u0301t qua\u0309 \u0111\u00ea\u0301n ha\u0300ng nghi\u0300n.<\/p>\n A. 608305000 \u0111\u00f4\u0300ng. \u00a0\u00a0\u00a0 B. 665500000 \u0111\u00f4\u0300ng.<\/p>\n C. 670960000 \u0111\u00f4\u0300ng. \u00a0\u00a0\u00a0D. 740069000 \u0111\u00f4\u0300ng.<\/p>\n C\u00e2u 22:<\/b>\u00a0Ti\u0300m gia\u0301 tri\u0323 l\u01a1\u0301n nh\u00e2\u0301t cu\u0309a ha\u0300m s\u00f4\u0301 y = x2<\/sup>e-x<\/sup>\u00a0tr\u00ean \u0111oa\u0323n [-1; 4]<\/p>\n <\/p>\n C\u00e2u 23:<\/b>\u00a0Ti\u0300m t\u00e2\u0323p nghi\u00ea\u0323m cu\u0309a ph\u01b0\u01a1ng tri\u0300nh log(x + 3) + log(x – 1) = log(x2<\/sup>\u00a0– 2x -3)<\/p>\n A. \u2205 \u00a0\u00a0\u00a0B. {0} \u00a0\u00a0\u00a0 C. R \u00a0\u00a0\u00a0D. (1; +\u221e)<\/p>\n C\u00e2u 24:<\/b>\u00a0Bi\u00ea\u0301t r\u1eb1ng logM<\/sub>N = logN<\/sub>M va\u0300 N \u2260 . Ti\u0301nh gia\u0301 tri\u0323 cu\u0309a MN.<\/p>\n A. -1 \u00a0\u00a0\u00a0B. 1 \u00a0\u00a0\u00a0C. 2\u00a0\u00a0\u00a0D. 10<\/p>\n C\u00e2u 25:<\/b>\u00a0Bi\u00ea\u0301t:<\/p>\n <\/p>\n Khi \u0111o\u0301 ap<\/sup>\u00a0b\u0103\u0300ng<\/p>\n A. loga<\/sub>b\u00a0\u00a0\u00a0B. alogb<\/sub>a<\/sup>\u00a0\u00a0\u00a0C. logb<\/sub>a\u00a0\u00a0\u00a0D. b<\/p>\n C\u00e2u 26:<\/b>\u00a0Gia\u0309 s\u01b0\u0309 x la\u0300 nghi\u00ea\u0323m cu\u0309a ph\u01b0\u01a1ng tri\u0300nh logx<\/sub>25 – logx<\/sub>4 = logx<\/sub>\u221ax.<\/p>\n <\/p>\n H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0110\u00e1p \u00e1n<\/b><\/p>\n C\u00e2u 20:<\/b><\/p>\n \u0110i\u1ec1u ki\u1ec7n<\/p>\n <\/p>\n V\u1eady mi\u1ec1n x\u00e1c \u0111\u1ecbnh c\u1ee7a h\u00e0m s\u1ed1 l\u00e0 D = (1; +\u221e)\\{ee<\/sup>}<\/p>\n C\u00e2u 21:<\/b><\/p>\n S\u1ed1 ti\u1ec1n \u00f4ng A r\u00fat \u0111\u01b0\u1ee3c : 500000000.(1 + 0,103)3<\/sup>\u00a0= 670959863 \u2248 970960000 (\u0111\u1ed3ng)<\/p>\n C\u00e2u 22:<\/b><\/p>\n y’ = 2xe-x<\/sup>\u00a0– x2<\/sup>e-x<\/sup>\u00a0= xe-x<\/sup>(2 – x); y’ = 0 <=> x = 0 ho\u1eb7c x = 2<\/p>\n y(-1) = e, y(0) = 0, y(2) = 4\/e2<\/sup>, y(4) = 16\/e4<\/sup><\/p>\n <\/p>\n C\u00e2u 23:<\/b><\/p>\n \u0110i\u1ec1u ki\u1ec7n x > 3. Khi \u0111\u00f3: log(x + 3) + log(x – 1) = log(x2<\/sup>\u00a0– 2x – 3)<\/p>\n <=> log[(x + 3)(x – 1)] = log(x2<\/sup>\u00a0– 2x – 3) <=> x2<\/sup>\u00a0+ 2x – 3 = x2<\/sup>\u00a0– 2x + 3<\/p>\n <=> 4x = 0 <=> x = 0 (lo\u1ea1i).<\/p>\n V\u1eady ph\u01b0\u01a1ng tr\u00ecnh v\u00f4 nghi\u1ec7m<\/p>\n C\u00e2u 24:<\/b><\/p>\n logM<\/sub>N = logN<\/sub>M<\/p>\n <\/p>\n C\u00e2u 25:<\/b><\/p>\n <\/p>\n plogb<\/sub>a = logb<\/sub>(logb<\/sub>a) => logb<\/sub>ap<\/sup>\u00a0= logb<\/sub>(logb<\/sub>a)<\/p>\n => ap<\/sup>\u00a0= logb<\/sub>a<\/p>\n C\u00e2u 26:<\/b><\/p>\n \u0110i\u1ec1u ki\u1ec7n 9 < x \u2260 1<\/p>\n logx<\/sub>25 – logx<\/sub>4 = logx<\/sub>\u221ax<\/p>\n <\/p>\n","protected":false},"excerpt":{"rendered":" C\u00e2u 20:\u00a0Ti\u0300m mi\u00ea\u0300n xa\u0301c \u0111i\u0323nh cu\u0309a ha\u0300m s\u00f4\u0301 A. D = (1; +\u221e)\\{ee}\u00a0\u00a0\u00a0B. D = (0; +\u221e)\\{e} C. D = (ee; +\u221e)\u00a0\u00a0\u00a0D. D = (1; +\u221e)\\{e} C\u00e2u 21:\u00a0Nga\u0300y 15 tha\u0301ng 2 n\u0103m 2010 \u00f4ng A g\u01b0\u0309i va\u0300o ng\u00e2n ha\u0300ng 500 tri\u00ea\u0323u \u0111\u00f4\u0300ng v\u01a1\u0301i hi\u0300nh th\u01b0\u0301c la\u0303i ke\u0301p va\u0300 la\u0303i su\u00e2\u0301t 10,3% m\u00f4\u0323t n\u0103m. Ta\u0323i th\u01a1\u0300i […]<\/p>\n","protected":false},"author":3,"featured_media":26646,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[157],"tags":[1447,1446],"yoast_head":"\n\n\n
\n 20-A<\/td>\n 21-C<\/td>\n 22-A<\/td>\n 23-A<\/td>\n 24-B<\/td>\n 25-C<\/td>\n 26-D<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n