C\u00e2u 34:<\/b>\u00a0Cho<\/p>\n
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Kh\u0103\u0309ng \u0111i\u0323nh na\u0300o sai?<\/p>\n
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C\u00e2u 35:<\/b>\u00a0Bi\u00ea\u0301n \u0111\u00f4\u0309i<\/p>\n
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Khi \u0111o\u0301, f(t) la\u0300 ha\u0300m na\u0300o trong ca\u0301c ha\u0300m s\u00f4\u0301 sau?<\/p>\n
A. f(t) = 2t2<\/sup>\u00a0– 2t\u00a0\u00a0\u00a0B. f(t) = t2<\/sup>\u00a0+ t\u00a0\u00a0\u00a0 C. f(t) = t2<\/sup>\u00a0– t \u00a0\u00a0\u00a0D. f(t) = 2t2<\/sup>\u00a0+ 2t<\/p>\n C\u00e2u 36:<\/b>\u00a0Di\u00ea\u0323n ti\u0301ch hi\u0300nh gi\u01a1\u0301i ha\u0323n b\u01a1\u0309i \u0111\u01b0\u01a1\u0300ng cong y = x2<\/sup>\u00a0+ 1 ti\u00ea\u0301p tuy\u00ea\u0301n v\u01a1\u0301i \u0111\u01b0\u01a1\u0300ng cong na\u0300y ta\u0323i M(2; 5) va\u0300 tru\u0323c la\u0300:<\/p>\n A. 0 \u00a0\u00a0\u00a0B. -8\/3 \u00a0\u00a0\u00a0C. 8\/3 \u00a0\u00a0\u00a0 D. K\u00ea\u0301t qua\u0309 kha\u0301c.<\/p>\n C\u00e2u 37:<\/b>\u00a0Th\u00ea\u0309 ti\u0301ch v\u00e2\u0323t tro\u0300n xoay khi quay hi\u0300nh ph\u0103\u0309ng gi\u01a1\u0301i ha\u0323n b\u01a1\u0309i ca\u0301c \u0111\u01b0\u01a1\u0300ng y = 4\/x, y = 0, x = 1, x = 4 quanh tru\u0323c Ox la\u0300:<\/p>\n A. 6\u03c0\u00a0\u00a0\u00a0 B. 4\u03c0 \u00a0\u00a0\u00a0 C. 12\u03c0 \u00a0\u00a0\u00a0D. 8\u03c0<\/p>\n C\u00e2u 38:<\/b>\u00a0Th\u00ea\u0309 ti\u0301ch v\u00e2\u0323t tro\u0300n xoay khi quay hi\u0300nh ph\u0103\u0309ng gi\u01a1\u0301i ha\u0323n b\u01a1\u0309i ca\u0301c \u0111\u01b0\u01a1\u0300ng<\/p>\n <\/p>\n quanh tru\u0323c Ox la\u0300:<\/p>\n A. \u03c0(e2<\/sup>\u00a0+ e)\u00a0\u00a0\u00a0B. \u03c0(e2<\/sup>\u00a0– e) \u00a0\u00a0\u00a0C. \u03c0e2<\/sup> \u00a0\u00a0\u00a0 D. \u03c0e<\/p>\n C\u00e2u 39:<\/b>\u00a0Ph\u00e2\u0300n th\u01b0\u0323c va\u0300 ph\u00e2\u0300n a\u0309o cu\u0309a s\u00f4\u0301 ph\u01b0\u0301c z tho\u0309a ma\u0303n\u00a0z\u2212<\/i>\u00a0= (1 + 2i)2<\/sup>\u00a0+ (1 – 2i)3<\/sup>\u00a0la\u0300<\/p>\n A. 14 va\u0300 6i\u00a0\u00a0\u00a0 B. \u201314 va\u0300 6 \u00a0\u00a0\u00a0C. 14 va\u0300 \u2013 6 \u00a0\u00a0\u00a0D. \u201314 va\u0300 \u20136.<\/p>\n C\u00e2u 40:<\/b>\u00a0Th\u01b0\u0323c hi\u00ea\u0323n phe\u0301p ti\u0301nh T = 3i(5 + 2i) + (2 – 5i)(3 + 7i) ta co\u0301:<\/p>\n A. T = 35 + 14i\u00a0\u00a0\u00a0B. T = 35 – 24i \u00a0\u00a0\u00a0C. T = -35 + 14i\u00a0\u00a0\u00a0D. T = -35 – 14i<\/p>\n H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0110\u00e1p \u00e1n<\/b><\/p>\n C\u00e2u 34:<\/b><\/p>\n D\u1ec5 th\u1ea5y B, C, D l\u00e0 c\u00e1c kh\u1eb3ng \u0111\u1ecbnh \u0111\u00fang, c\u00f2n kh\u1eb3ng \u0111\u1ecbnh A sai v\u00ec \u0111\u1ed5i bi\u1ebfn m\u00e0 kh\u00f4ng \u0111\u1ed5i c\u1eadn<\/p>\n C\u00e2u 35:<\/b><\/p>\n Ta c\u00f3:<\/p>\n <\/p>\n C\u00e2u 36:<\/b><\/p>\n Ph\u01b0\u01a1ng tr\u00ecnh ti\u1ebfp tuy\u1ebfn v\u1edbi y = x2<\/sup>\u00a0+ 1 t\u1ea1i M(2 ;5) l\u00e0 :<\/p>\n y = y'(2)(x – 2) + 5 => y = 4(x – 2) + 5 = 4x – 3<\/p>\n X\u00e9t PT : x2<\/sup>\u00a0+ 1 = 4x – 3 => x = 2 . Ta c\u00f3<\/p>\n <\/p>\n C\u00e2u 37:<\/b><\/p>\n <\/p>\n C\u00e2u 38:<\/b><\/p>\n <\/p>\n C\u00e2u 39:<\/b><\/p>\n Ta c\u00f3:\u00a0z\u2212<\/i>\u00a0= (1 + 2i)2<\/sup>\u00a0+ (1 – 2i)3<\/sup>\u00a0= 1 + 4i – 4 + 1 – 6i – 12 + 8i = -14 + 6i<\/p>\n Suy ra z = -14 – 6i. V\u1eady ph\u1ea7n th\u1ef1c v\u00e0 ph\u1ea7n \u1ea3o c\u1ee7a z l\u00e0: -14 v\u00e0 – 6<\/p>\n C\u00e2u 40:<\/b><\/p>\n Ta c\u00f3: T = 15i + 6i2<\/sup>\u00a0+ 6 + 14i – 15i – 35i2<\/sup>\u00a0= 15i – 6 + 6 + 14i – 15i + 35 = 35 + 14i<\/p>\n","protected":false},"excerpt":{"rendered":" C\u00e2u 34:\u00a0Cho Kh\u0103\u0309ng \u0111i\u0323nh na\u0300o sai? C\u00e2u 35:\u00a0Bi\u00ea\u0301n \u0111\u00f4\u0309i Khi \u0111o\u0301, f(t) la\u0300 ha\u0300m na\u0300o trong ca\u0301c ha\u0300m s\u00f4\u0301 sau? A. f(t) = 2t2\u00a0– 2t\u00a0\u00a0\u00a0B. f(t) = t2\u00a0+ t\u00a0\u00a0\u00a0 C. f(t) = t2\u00a0– t \u00a0\u00a0\u00a0D. f(t) = 2t2\u00a0+ 2t C\u00e2u 36:\u00a0Di\u00ea\u0323n ti\u0301ch hi\u0300nh gi\u01a1\u0301i ha\u0323n b\u01a1\u0309i \u0111\u01b0\u01a1\u0300ng cong y = x2\u00a0+ 1 ti\u00ea\u0301p tuy\u00ea\u0301n v\u01a1\u0301i […]<\/p>\n","protected":false},"author":3,"featured_media":26620,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[157],"tags":[1447,1446],"yoast_head":"\n\n\n
\n 34-A<\/td>\n 35-A<\/td>\n 36-C<\/td>\n 37-C<\/td>\n 38-C<\/td>\n 39-D<\/td>\n 40-A<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n