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{"id":26619,"date":"2018-04-13T13:20:43","date_gmt":"2018-04-13T06:20:43","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=26619"},"modified":"2018-04-13T13:20:43","modified_gmt":"2018-04-13T06:20:43","slug":"bai-tap-trac-nghiem-giai-tich-12-on-tap-cuoi-nam-phan-6","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/bai-tap-trac-nghiem-giai-tich-12-on-tap-cuoi-nam-phan-6\/","title":{"rendered":"B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: \u00d4n t\u1eadp cu\u1ed1i n\u0103m (Ph\u1ea7n 6)"},"content":{"rendered":"

C\u00e2u 34:<\/b>\u00a0Cho<\/p>\n

\"\"<\/p>\n

Kh\u0103\u0309ng \u0111i\u0323nh na\u0300o sai?<\/p>\n

\"\"<\/p>\n

C\u00e2u 35:<\/b>\u00a0Bi\u00ea\u0301n \u0111\u00f4\u0309i<\/p>\n

\"\"<\/p>\n

Khi \u0111o\u0301, f(t) la\u0300 ha\u0300m na\u0300o trong ca\u0301c ha\u0300m s\u00f4\u0301 sau?<\/p>\n

A. f(t) = 2t2<\/sup>\u00a0– 2t\u00a0\u00a0\u00a0B. f(t) = t2<\/sup>\u00a0+ t\u00a0\u00a0\u00a0 C. f(t) = t2<\/sup>\u00a0– t \u00a0\u00a0\u00a0D. f(t) = 2t2<\/sup>\u00a0+ 2t<\/p>\n

C\u00e2u 36:<\/b>\u00a0Di\u00ea\u0323n ti\u0301ch hi\u0300nh gi\u01a1\u0301i ha\u0323n b\u01a1\u0309i \u0111\u01b0\u01a1\u0300ng cong y = x2<\/sup>\u00a0+ 1 ti\u00ea\u0301p tuy\u00ea\u0301n v\u01a1\u0301i \u0111\u01b0\u01a1\u0300ng cong na\u0300y ta\u0323i M(2; 5) va\u0300 tru\u0323c la\u0300:<\/p>\n

A. 0 \u00a0\u00a0\u00a0B. -8\/3 \u00a0\u00a0\u00a0C. 8\/3 \u00a0\u00a0\u00a0 D. K\u00ea\u0301t qua\u0309 kha\u0301c.<\/p>\n

C\u00e2u 37:<\/b>\u00a0Th\u00ea\u0309 ti\u0301ch v\u00e2\u0323t tro\u0300n xoay khi quay hi\u0300nh ph\u0103\u0309ng gi\u01a1\u0301i ha\u0323n b\u01a1\u0309i ca\u0301c \u0111\u01b0\u01a1\u0300ng y = 4\/x, y = 0, x = 1, x = 4 quanh tru\u0323c Ox la\u0300:<\/p>\n

A. 6\u03c0\u00a0\u00a0\u00a0 B. 4\u03c0 \u00a0\u00a0\u00a0 C. 12\u03c0 \u00a0\u00a0\u00a0D. 8\u03c0<\/p>\n

C\u00e2u 38:<\/b>\u00a0Th\u00ea\u0309 ti\u0301ch v\u00e2\u0323t tro\u0300n xoay khi quay hi\u0300nh ph\u0103\u0309ng gi\u01a1\u0301i ha\u0323n b\u01a1\u0309i ca\u0301c \u0111\u01b0\u01a1\u0300ng<\/p>\n

\"B\u00e0i<\/p>\n

quanh tru\u0323c Ox la\u0300:<\/p>\n

A. \u03c0(e2<\/sup>\u00a0+ e)\u00a0\u00a0\u00a0B. \u03c0(e2<\/sup>\u00a0– e) \u00a0\u00a0\u00a0C. \u03c0e2<\/sup> \u00a0\u00a0\u00a0 D. \u03c0e<\/p>\n

C\u00e2u 39:<\/b>\u00a0Ph\u00e2\u0300n th\u01b0\u0323c va\u0300 ph\u00e2\u0300n a\u0309o cu\u0309a s\u00f4\u0301 ph\u01b0\u0301c z tho\u0309a ma\u0303n\u00a0z\u2212<\/i>\u00a0= (1 + 2i)2<\/sup>\u00a0+ (1 – 2i)3<\/sup>\u00a0la\u0300<\/p>\n

A. 14 va\u0300 6i\u00a0\u00a0\u00a0 B. \u201314 va\u0300 6 \u00a0\u00a0\u00a0C. 14 va\u0300 \u2013 6 \u00a0\u00a0\u00a0D. \u201314 va\u0300 \u20136.<\/p>\n

C\u00e2u 40:<\/b>\u00a0Th\u01b0\u0323c hi\u00ea\u0323n phe\u0301p ti\u0301nh T = 3i(5 + 2i) + (2 – 5i)(3 + 7i) ta co\u0301:<\/p>\n

A. T = 35 + 14i\u00a0\u00a0\u00a0B. T = 35 – 24i \u00a0\u00a0\u00a0C. T = -35 + 14i\u00a0\u00a0\u00a0D. T = -35 – 14i<\/p>\n

H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0110\u00e1p \u00e1n<\/b><\/p>\n\n\n\n
34-A<\/td>\n35-A<\/td>\n36-C<\/td>\n37-C<\/td>\n38-C<\/td>\n39-D<\/td>\n40-A<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

C\u00e2u 34:<\/b><\/p>\n

D\u1ec5 th\u1ea5y B, C, D l\u00e0 c\u00e1c kh\u1eb3ng \u0111\u1ecbnh \u0111\u00fang, c\u00f2n kh\u1eb3ng \u0111\u1ecbnh A sai v\u00ec \u0111\u1ed5i bi\u1ebfn m\u00e0 kh\u00f4ng \u0111\u1ed5i c\u1eadn<\/p>\n

C\u00e2u 35:<\/b><\/p>\n

Ta c\u00f3:<\/p>\n

\"\"<\/p>\n

C\u00e2u 36:<\/b><\/p>\n

Ph\u01b0\u01a1ng tr\u00ecnh ti\u1ebfp tuy\u1ebfn v\u1edbi y = x2<\/sup>\u00a0+ 1 t\u1ea1i M(2 ;5) l\u00e0 :<\/p>\n

y = y'(2)(x – 2) + 5 => y = 4(x – 2) + 5 = 4x – 3<\/p>\n

X\u00e9t PT : x2<\/sup>\u00a0+ 1 = 4x – 3 => x = 2 . Ta c\u00f3<\/p>\n

\"\"<\/p>\n

C\u00e2u 37:<\/b><\/p>\n

\"\"<\/p>\n

C\u00e2u 38:<\/b><\/p>\n

\"\"<\/p>\n

C\u00e2u 39:<\/b><\/p>\n

Ta c\u00f3:\u00a0z\u2212<\/i>\u00a0= (1 + 2i)2<\/sup>\u00a0+ (1 – 2i)3<\/sup>\u00a0= 1 + 4i – 4 + 1 – 6i – 12 + 8i = -14 + 6i<\/p>\n

Suy ra z = -14 – 6i. V\u1eady ph\u1ea7n th\u1ef1c v\u00e0 ph\u1ea7n \u1ea3o c\u1ee7a z l\u00e0: -14 v\u00e0 – 6<\/p>\n

C\u00e2u 40:<\/b><\/p>\n

Ta c\u00f3: T = 15i + 6i2<\/sup>\u00a0+ 6 + 14i – 15i – 35i2<\/sup>\u00a0= 15i – 6 + 6 + 14i – 15i + 35 = 35 + 14i<\/p>\n","protected":false},"excerpt":{"rendered":"

C\u00e2u 34:\u00a0Cho Kh\u0103\u0309ng \u0111i\u0323nh na\u0300o sai? C\u00e2u 35:\u00a0Bi\u00ea\u0301n \u0111\u00f4\u0309i Khi \u0111o\u0301, f(t) la\u0300 ha\u0300m na\u0300o trong ca\u0301c ha\u0300m s\u00f4\u0301 sau? A. f(t) = 2t2\u00a0– 2t\u00a0\u00a0\u00a0B. f(t) = t2\u00a0+ t\u00a0\u00a0\u00a0 C. f(t) = t2\u00a0– t \u00a0\u00a0\u00a0D. f(t) = 2t2\u00a0+ 2t C\u00e2u 36:\u00a0Di\u00ea\u0323n ti\u0301ch hi\u0300nh gi\u01a1\u0301i ha\u0323n b\u01a1\u0309i \u0111\u01b0\u01a1\u0300ng cong y = x2\u00a0+ 1 ti\u00ea\u0301p tuy\u00ea\u0301n v\u01a1\u0301i […]<\/p>\n","protected":false},"author":3,"featured_media":26620,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[157],"tags":[1447,1446],"yoast_head":"\nB\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: \u00d4n t\u1eadp cu\u1ed1i n\u0103m (Ph\u1ea7n 6)<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/bai-tap-trac-nghiem-giai-tich-12-on-tap-cuoi-nam-phan-6\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: \u00d4n t\u1eadp cu\u1ed1i n\u0103m (Ph\u1ea7n 6)\" \/>\n<meta property=\"og:description\" content=\"C\u00e2u 34:\u00a0Cho Kh\u0103\u0309ng \u0111i\u0323nh na\u0300o sai? C\u00e2u 35:\u00a0Bi\u00ea\u0301n \u0111\u00f4\u0309i Khi \u0111o\u0301, f(t) la\u0300 ha\u0300m na\u0300o trong ca\u0301c ha\u0300m s\u00f4\u0301 sau? A. f(t) = 2t2\u00a0– 2t\u00a0\u00a0\u00a0B. f(t) = t2\u00a0+ t\u00a0\u00a0\u00a0 C. f(t) = t2\u00a0– t \u00a0\u00a0\u00a0D. f(t) = 2t2\u00a0+ 2t C\u00e2u 36:\u00a0Di\u00ea\u0323n ti\u0301ch hi\u0300nh gi\u01a1\u0301i ha\u0323n b\u01a1\u0309i \u0111\u01b0\u01a1\u0300ng cong y = x2\u00a0+ 1 ti\u00ea\u0301p tuy\u00ea\u0301n v\u01a1\u0301i […]\" \/>\n<meta property=\"og:url\" content=\"https:\/\/lop12.edu.vn\/bai-tap-trac-nghiem-giai-tich-12-on-tap-cuoi-nam-phan-6\/\" \/>\n<meta property=\"og:site_name\" content=\"Lop12.edu.vn - C\u1ed9ng \u0111\u1ed3ng h\u1ecdc sinh l\u1edbp 12 l\u1edbn nh\u1ea5t t\u1ea1i Vi\u1ec7t Nam\" \/>\n<meta property=\"article:published_time\" content=\"2018-04-13T06:20:43+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/lop12.edu.vn\/wp-content\/uploads\/2018\/04\/1-175.png\" \/>\n\t<meta property=\"og:image:width\" content=\"243\" \/>\n\t<meta property=\"og:image:height\" content=\"57\" \/>\n\t<meta property=\"og:image:type\" content=\"image\/png\" \/>\n<meta name=\"author\" content=\"H\u00e0 Trang\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"H\u00e0 Trang\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"2 minutes\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"WebPage\",\"@id\":\"https:\/\/lop12.edu.vn\/bai-tap-trac-nghiem-giai-tich-12-on-tap-cuoi-nam-phan-6\/\",\"url\":\"https:\/\/lop12.edu.vn\/bai-tap-trac-nghiem-giai-tich-12-on-tap-cuoi-nam-phan-6\/\",\"name\":\"B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: \u00d4n t\u1eadp cu\u1ed1i n\u0103m (Ph\u1ea7n 6)\",\"isPartOf\":{\"@id\":\"https:\/\/lop12.edu.vn\/#website\"},\"datePublished\":\"2018-04-13T06:20:43+00:00\",\"dateModified\":\"2018-04-13T06:20:43+00:00\",\"author\":{\"@id\":\"https:\/\/lop12.edu.vn\/#\/schema\/person\/2da855e5d06b553ac0065157cc261a45\"},\"breadcrumb\":{\"@id\":\"https:\/\/lop12.edu.vn\/bai-tap-trac-nghiem-giai-tich-12-on-tap-cuoi-nam-phan-6\/#breadcrumb\"},\"inLanguage\":\"en-US\",\"potentialAction\":[{\"@type\":\"ReadAction\",\"target\":[\"https:\/\/lop12.edu.vn\/bai-tap-trac-nghiem-giai-tich-12-on-tap-cuoi-nam-phan-6\/\"]}]},{\"@type\":\"BreadcrumbList\",\"@id\":\"https:\/\/lop12.edu.vn\/bai-tap-trac-nghiem-giai-tich-12-on-tap-cuoi-nam-phan-6\/#breadcrumb\",\"itemListElement\":[{\"@type\":\"ListItem\",\"position\":1,\"name\":\"Home\",\"item\":\"https:\/\/lop12.edu.vn\/\"},{\"@type\":\"ListItem\",\"position\":2,\"name\":\"B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: \u00d4n t\u1eadp cu\u1ed1i n\u0103m (Ph\u1ea7n 6)\"}]},{\"@type\":\"WebSite\",\"@id\":\"https:\/\/lop12.edu.vn\/#website\",\"url\":\"https:\/\/lop12.edu.vn\/\",\"name\":\"Lop12.edu.vn - C\u1ed9ng \u0111\u1ed3ng h\u1ecdc sinh l\u1edbp 12\",\"description\":\"\",\"potentialAction\":[{\"@type\":\"SearchAction\",\"target\":{\"@type\":\"EntryPoint\",\"urlTemplate\":\"https:\/\/lop12.edu.vn\/?s={search_term_string}\"},\"query-input\":\"required name=search_term_string\"}],\"inLanguage\":\"en-US\"},{\"@type\":\"Person\",\"@id\":\"https:\/\/lop12.edu.vn\/#\/schema\/person\/2da855e5d06b553ac0065157cc261a45\",\"name\":\"H\u00e0 Trang\",\"image\":{\"@type\":\"ImageObject\",\"inLanguage\":\"en-US\",\"@id\":\"https:\/\/lop12.edu.vn\/#\/schema\/person\/image\/\",\"url\":\"https:\/\/secure.gravatar.com\/avatar\/545a8100db1147f314111301d261dc33?s=96&d=mm&r=g\",\"contentUrl\":\"https:\/\/secure.gravatar.com\/avatar\/545a8100db1147f314111301d261dc33?s=96&d=mm&r=g\",\"caption\":\"H\u00e0 Trang\"},\"url\":\"https:\/\/lop12.edu.vn\/author\/trangvth2\/\"}]}<\/script>\n<!-- \/ Yoast SEO plugin. -->","yoast_head_json":{"title":"B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: \u00d4n t\u1eadp cu\u1ed1i n\u0103m (Ph\u1ea7n 6)","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/lop12.edu.vn\/bai-tap-trac-nghiem-giai-tich-12-on-tap-cuoi-nam-phan-6\/","og_locale":"en_US","og_type":"article","og_title":"B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m Gi\u1ea3i t\u00edch 12: \u00d4n t\u1eadp cu\u1ed1i n\u0103m (Ph\u1ea7n 6)","og_description":"C\u00e2u 34:\u00a0Cho Kh\u0103\u0309ng \u0111i\u0323nh na\u0300o sai? C\u00e2u 35:\u00a0Bi\u00ea\u0301n \u0111\u00f4\u0309i Khi \u0111o\u0301, f(t) la\u0300 ha\u0300m na\u0300o trong ca\u0301c ha\u0300m s\u00f4\u0301 sau? 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