C\u00e2u 41:<\/b>\u00a0Th\u01b0\u0323c hi\u00ea\u0323n phe\u0301p ti\u0301nh<\/p>\n
<\/p>\n
A. T = 1 + i\u00a0\u00a0\u00a0B. T = 1 – i\u00a0\u00a0\u00a0C. T = -1 + i\u00a0\u00a0\u00a0D. T = -1 – i<\/p>\n
C\u00e2u 42:<\/b>\u00a0Ca\u0301c s\u00f4\u0301 th\u01b0\u0323c x, y tho\u0309a ma\u0303n: (x + 2y) + (2x – y)i = 6 + 7i. Gia\u0301 tri\u0323 bi\u00ea\u0309u th\u01b0\u0301c T = x + y b\u0103\u0300ng:<\/p>\n
A. 4 \u00a0\u00a0\u00a0B. 5\u00a0\u00a0\u00a0C. 6 \u00a0\u00a0\u00a0D. 7.<\/p>\n
C\u00e2u 43:<\/b>\u00a0Ph\u01b0\u01a1ng tri\u0300nh z2<\/sup>\u00a0– 8z + 20 = 0 co\u0301 hai nghi\u00ea\u0323m la\u0300<\/p>\n A. 8 \u00b1 4i\u00a0\u00a0\u00a0B. -8 \u00b1 4i \u00a0\u00a0\u00a0C. -4 \u00b1 2i\u00a0\u00a0\u00a0D. 4 \u00b1 2i<\/p>\n C\u00e2u 44:<\/b>\u00a0S\u00f4\u0301 ph\u01b0\u0301c z = a + bi co\u0301 ph\u00e2\u0300n th\u01b0\u0323c, ph\u00e2\u0300n a\u0309o la\u0300 ca\u0301c s\u00f4\u0301 nguy\u00ean va\u0300 tho\u0309a ma\u0303n: z3<\/sup>\u00a0= 2 + 11i. Gia\u0301 tri\u0323 bi\u00ea\u0309u th\u01b0\u0301c T = a + b la\u0300<\/p>\n A. 2 \u00a0\u00a0\u00a0B. 3 \u00a0\u00a0\u00a0 C. 4 \u00a0\u00a0\u00a0D. 5<\/p>\n C\u00e2u 45:<\/b>\u00a0T\u00e2\u0323p h\u01a1\u0323p ca\u0301c \u0111i\u00ea\u0309m bi\u00ea\u0309u di\u00ea\u0303n s\u00f4\u0301 ph\u01b0\u0301c z tho\u0309a ma\u0303n |i(z – 1) + 2| = |3 – 4i| la\u0300<\/p>\n A. \u0110\u01b0\u01a1\u0300ng tro\u0300n t\u00e2m I(1; 2) ba\u0301n ki\u0301nh R = 5<\/p>\n B. \u0110\u01b0\u01a1\u0300ng tro\u0300n t\u00e2m I(1; -2) ba\u0301n ki\u0301nh R = 5<\/p>\n C. \u0110\u01b0\u01a1\u0300ng tro\u0300n t\u00e2m I(-1; 2) ba\u0301n ki\u0301nh R = 5<\/p>\n D. \u0110\u01b0\u01a1\u0300ng tro\u0300n t\u00e2m I(-1; -2) ba\u0301n ki\u0301nh R = 5<\/p>\n C\u00e2u 46:<\/b>\u00a0Cho s\u00f4\u0301 ph\u01b0\u0301c z tho\u0309a ma\u0303n |z\u2212<\/i>\u00a0+ 1 – i| = |z|. Gia\u0301 tri\u0323 nho\u0309 nh\u00e2\u0301t cu\u0309a m\u00f4\u0111un cu\u0309a z la\u0300<\/p>\n <\/p>\n H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0110\u00e1p \u00e1n<\/b><\/p>\n C\u00e2u 41:<\/b><\/p>\n Ta c\u00f3<\/p>\n <\/p>\n C\u00e2u 42:<\/b><\/p>\n Ta c\u00f3: (x + 2y) + (2x – y)i = 6 + 7i<\/p>\n <\/p>\n V\u1eady: T = 4 + 1 = 5<\/p>\n C\u00e2u 44:<\/b><\/p>\n Ta c\u00f3: z3<\/sup>\u00a0= a3<\/sup>\u00a0+ 3a2<\/sup>bi + 3ab2<\/sup>i2<\/sup>\u00a0+ b3<\/sup>i3<\/sup>\u00a0= a3<\/sup>\u00a0– 3ab2<\/sup>\u00a0+ (3a2<\/sup>b – b3<\/sup>)i<\/p>\n T\u1eeb gi\u1ea3 thi\u1ebft ta c\u00f3:<\/p>\n <\/p>\n T\u1eeb ph\u01b0\u01a1ng tr\u00ecnh th\u1ee9 nh\u1ea5t ta c\u00f3: a(a2<\/sup>\u00a0– 3b2<\/sup>). V\u00ec a,b nguy\u00ean n\u00ean a l\u00e0 \u01b0\u1edbc c\u1ee7a 2.<\/p>\n N\u1ebfu a=1 th\u00ec 1 – 3b2<\/sup>\u00a0= 2. Suy ra b2<\/sup>\u00a0= -1\/3 \u2209 Z (lo\u1ea1i)<\/p>\n N\u1ebfu a=-1 th\u00ec b = \u00b11 , kh\u00f4ng th\u1ecfa m\u00e3n ph\u01b0\u01a1ng tr\u00ecnh th\u1ee9 hai c\u1ee7a h\u1ec7.<\/p>\n N\u1ebfu a=-2 th\u00ec b2<\/sup>\u00a0= 5\/3 \u2209 Z (lo\u1ea1i).<\/p>\n N\u1ebfu a=2 th\u00ec b = \u00b11 . K\u1ebft h\u1ee3p v\u1edbi ph\u01b0\u01a1ng tr\u00ecnh th\u1ee9 hai ta c\u00f3: a = 2, b = 1<\/p>\n V\u1eady T = 3<\/p>\n C\u00e2u 45:<\/b><\/p>\n \u0110\u1eb7t z = a + bi (a, b \u2208 R). Ta c\u00f3: i(z – 1) + 2 = i(a + bi – 1) + 2 = 2 – b + (a – b)i<\/p>\n <\/p>\n Do \u0111\u00f3: |i(z – 1) + 2| = |3 – 4i| <=> (a – 1)2<\/sup>\u00a0+ (b – 2)2<\/sup>\u00a0= 25<\/p>\n T\u1eadp h\u1ee3p c\u00e1c \u0111i\u1ec3m M(a,b) bi\u1ec3u di\u1ec5n c\u1ee7a s\u1ed1 ph\u1ee9c z l\u00e0 \u0111\u01b0\u1eddng tr\u00f2n t\u00e2m I(1;2), b\u00e1n k\u00ednh l\u00e0 R=5<\/p>\n C\u00e2u 46:<\/b><\/p>\n Cho s\u1ed1 ph\u1ee9c z th\u1ecfa m\u00e3n: |z\u2212<\/i>\u00a0+ 1 – i| = |z|<\/p>\n \u0110\u1eb7t z = a + bi (a, b \u2208 R) . Ta c\u00f3:\u00a0z\u2212<\/i>\u00a0+ 1 – i = a – bi + 1 – i = a + 1 – (b + 1)i<\/p>\n T\u1eeb gi\u1ea3 thi\u1ebft ta c\u00f3 : (a + 1)2<\/sup>\u00a0+ (b + 1)2<\/sup>\u00a0= a2<\/sup>\u00a0+ b2<\/sup>\u00a0<=> a + b + 1 = 0 <=> b = -1 -1<\/p>\n Khi \u0111\u00f3 |z|2<\/sup>\u00a0= a2<\/sup>\u00a0+ b2<\/sup>\u00a0= a2<\/sup>\u00a0+ ( -1 – a)2<\/sup>\u00a0= 2a2<\/sup>\u00a0+ 2a + 1<\/p>\n <\/p>\n","protected":false},"excerpt":{"rendered":" C\u00e2u 41:\u00a0Th\u01b0\u0323c hi\u00ea\u0323n phe\u0301p ti\u0301nh A. T = 1 + i\u00a0\u00a0\u00a0B. T = 1 – i\u00a0\u00a0\u00a0C. T = -1 + i\u00a0\u00a0\u00a0D. T = -1 – i C\u00e2u 42:\u00a0Ca\u0301c s\u00f4\u0301 th\u01b0\u0323c x, y tho\u0309a ma\u0303n: (x + 2y) + (2x – y)i = 6 + 7i. Gia\u0301 tri\u0323 bi\u00ea\u0309u th\u01b0\u0301c T = x + y b\u0103\u0300ng: […]<\/p>\n","protected":false},"author":3,"featured_media":26611,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[157],"tags":[1447,1446],"yoast_head":"\n\n\n
\n 40-A<\/td>\n 41-D<\/td>\n 42-B<\/td>\n 43-D<\/td>\n 44-B<\/td>\n 45-A<\/td>\n 46-D<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n