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{"id":26384,"date":"2018-04-10T17:45:10","date_gmt":"2018-04-10T10:45:10","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=26384"},"modified":"2018-04-10T17:45:10","modified_gmt":"2018-04-10T10:45:10","slug":"bai-tap-trac-nghiem-vat-li-12-con-lac-lo-xo-phan-1","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/bai-tap-trac-nghiem-vat-li-12-con-lac-lo-xo-phan-1\/","title":{"rendered":"B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m V\u1eadt L\u00ed 12: Con l\u1eafc l\u00f2 xo (ph\u1ea7n 1)"},"content":{"rendered":"

C\u00e2u 1:<\/b>\u00a0T\u00ecm ph\u00e1t bi\u1ec3u sai v\u1ec1 con l\u1eafc l\u00f2 xo dao \u0111\u1ed9ng tr\u00ean m\u1eb7t ph\u1eb3ng n\u1eb1m ngang.<\/p>\n

A. V\u1eadt c\u00f3 gia t\u1ed1c b\u1eb1ng 0 khi l\u00f2 xo c\u00f3 \u0111\u1ed9 d\u00e0i t\u1ef1 nhi\u00ean.<\/p>\n

B. V\u1eadt c\u00f3 gia t\u1ed1c c\u1ef1c \u0111\u1ea1i khi \u0111\u1ed9 l\u1edbn v\u1eadn t\u1ed1c c\u1ef1c ti\u1ec3u.<\/p>\n

C. V\u1eadt c\u00f3 \u0111\u1ed9 l\u1edbn v\u1eadn t\u1ed1c nh\u1ecf nh\u1ea5t khi l\u00f2 xo kh\u00f4ng bi\u1ebfn d\u1ea1ng.<\/p>\n

D. V\u1eadt \u0111\u1ed5i chi\u1ec1u chuy\u1ec3n \u0111\u1ed9ng khi l\u00f2 xo bi\u1ebfn d\u1ea1ng l\u1edbn nh\u1ea5t.<\/p>\n

C\u00e2u 2:<\/b>\u00a0M\u1ed9t con l\u1eafc l\u00f2 xo dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a. Mu\u1ed1n t\u1ea7n s\u1ed1 t\u0103ng l\u00ean ba l\u1ea7n th\u00ec<\/p>\n

A. T\u0103ng k ba l\u1ea7n, gi\u1ea3m m ch\u00edn l\u1ea7n.<\/p>\n

B. T\u0103ng k ba l\u1ea7n, gi\u1ea3m m ba l\u1ea7n.<\/p>\n

C. Gi\u1ea3m k b l\u1ea7n, t\u0103ng m ba l\u1ea7n.<\/p>\n

D. Gi\u1ea3m k ba l\u1ea7n, t\u0103ng m ch\u00edn l\u1ea7n.<\/p>\n

C\u00e2u 3:<\/b>\u00a0T\u1ea1i n\u01a1i c\u00f3 gia t\u1ed1c tr\u1ecdng tr\u01b0\u1eddng g = 9,81 m\/s2<\/sup>, m\u1ed9t v\u1eadt n\u1eb7ng khi treo v\u00e0o m\u1ed9t l\u00f2 xo l\u00e0m l\u00f2 xo d\u00e3n ra \u0394l = 2,4 cm. Chu k\u00ec dao \u0111\u1ed9ng c\u1ee7a con l\u1eafc l\u00f2 xo n\u00e0y l\u00e0<\/p>\n

A. 0,18 s \u00a0\u00a0\u00a0\u00a0\u00a0 B. 0,31 s \u00a0\u00a0\u00a0\u00a0\u00a0C. 0,22 s \u00a0\u00a0\u00a0\u00a0\u00a0D. 0,90 s<\/p>\n

C\u00e2u 4:<\/b>\u00a0M\u1ed9t con l\u1eafc l\u00f2 xo dao \u0111\u1ed9ng tr\u00ean m\u1eb7t ph\u1eb3ng n\u1eb1m ngang c\u00f3 qu\u1ea3 n\u1eb7ng kh\u1ed1i l\u01b0\u1ee3ng m = 100 g v\u00e0 \u0111\u1ed9 c\u1ee9ng l\u00f2 xo k = 100 N\/m. L\u1ea5y g\u1ea7n \u0111\u00fang \u03c02<\/sup>\u00a0\u2248 10. K\u00e9o qu\u1ea3 n\u1eb7ng ra c\u00e1ch v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng +5 cm r\u1ed3i th\u1ea3 tay nh\u1eb9. Ph\u01b0\u01a1ng tr\u00ecnh dao \u0111\u1ed9ng c\u1ee7a con l\u1eafc l\u00e0<\/p>\n

A. x = 5cos(\u03c0t) (cm). \u00a0\u00a0\u00a0\u00a0\u00a0 B. x = 10cos(10\u03c0t) (cm).<\/p>\n

C. x = 5cos(\u03c0t+\u03c0\/2) (cm).\u00a0\u00a0\u00a0\u00a0\u00a0 D. x = 5cos(10\u03c0t) (cm).<\/p>\n

C\u00e2u 5:<\/b>\u00a0M\u1ed9t con l\u1eafc l\u00f2 xo c\u00f3 qu\u1ea3 n\u1eb7ng kh\u1ed1i l\u01b0\u1ee3ng m v\u00e0 l\u00f2 xo \u0111\u1ed9 c\u1ee9ng k th\u00ec chu k\u00ec dao \u0111\u1ed9ng T = 0,5 s. \u0110\u1ec3 c\u00f3 t\u1ea7n s\u1ed1 dao \u0111\u1ed9ng c\u1ee7a con l\u1eafc f = 1 Hz th\u00ec ph\u1ea3i thay qu\u1ea3 n\u1eb7ng m b\u1eb1ng qu\u1ea3 n\u1eb7ng c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng m\u2019 l\u00e0<\/p>\n

A. 4m \u00a0\u00a0\u00a0\u00a0\u00a0 B. 16m \u00a0\u00a0\u00a0\u00a0\u00a0 C. 2m \u00a0\u00a0\u00a0\u00a0\u00a0 D. m\/2<\/p>\n

C\u00e2u 6:<\/b>\u00a0V\u1eadt m1<\/sub>\u00a0g\u1eafn v\u1edbi m\u1ed9t l\u00f2 xo dao \u0111\u1ed9ng v\u1edbi chu k\u00ec T1<\/sub>\u00a0= 0,9 s. V\u1eadt m2<\/sub>\u00a0g\u1eafn v\u1edbi l\u00f2 xo \u0111\u00f3 th\u00ec dao \u0111\u1ed9ng v\u1edbi chu k\u00ec T2<\/sub>\u00a0= 1,2 s. G\u1eafn \u0111\u1ed3ng th\u1eddi c\u1ea3 hai v\u1eadt m1<\/sub>, m2<\/sub>\u00a0v\u1edbi l\u00f2 xo n\u00f3i tr\u00ean th\u00ec h\u1ec7 v\u1eadt s\u1ebd dao \u0111\u1ed9ng v\u1edbi chu k\u00ec<\/p>\n

A. T12<\/sub>\u00a0= 1,5 s \u00a0\u00a0\u00a0\u00a0\u00a0 B. T12<\/sub>\u00a0= 1,2 s \u00a0\u00a0\u00a0\u00a0\u00a0 C. T12<\/sub>\u00a0= 0,3 s \u00a0\u00a0\u00a0\u00a0\u00a0 D. T12<\/sub>\u00a0= 5,14 s<\/p>\n

C\u00e2u 7:<\/b>\u00a0M\u1ed9t con l\u1eafc l\u00f2 xo th\u1eb3ng \u0111\u1ee9ng dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a v\u1edbi chu k\u00ec \u03c0\/5 (s). Trong qu\u00e1 tr\u00ecnh dao \u0111\u1ed9ng \u0111\u1ed9 d\u00e0i c\u1ee7a con l\u1eafc bi\u1ebfn thi\u00ean t\u1eeb 20 cm \u0111\u1ebfn 30 cm. L\u1ea5y g = 10 m\/s2<\/sup>.<\/p>\n

A. 35 cm \u00a0\u00a0\u00a0\u00a0\u00a0 B. 15 cm \u00a0\u00a0\u00a0\u00a0\u00a0C. 45 cm \u00a0\u00a0\u00a0\u00a0\u00a0 D. 40 cm<\/p>\n

C\u00e2u 8:<\/b>\u00a0M\u1ed9t v\u1eadt kh\u1ed1i l\u01b0\u1ee3ng m = 288 g \u0111\u01b0\u1ee3c treo v\u00e0o m\u1ed9t \u0111\u1ea7u l\u00f2 xo th\u00ec con l\u1eafc dao \u0111\u1ed9ng v\u1edbi t\u1ea7n s\u1ed1 f1<\/sub>\u00a0= 6,5 Hz. G\u1eafn th\u00eam v\u00e0o m m\u1ed9t v\u1eadt nh\u1ecf kh\u1ed1i l\u01b0\u1ee3ng \u0394m b\u1eb1ng<\/p>\n

A. 12 g \u00a0\u00a0\u00a0\u00a0\u00a0 B. 32 g \u00a0\u00a0\u00a0\u00a0\u00a0 C. 50 g \u00a0\u00a0\u00a0\u00a0\u00a0 D. 60 g<\/p>\n

H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0111\u00e1p \u00e1n<\/b><\/p>\n\n\n\n\n
C\u00e2u<\/td>\n1<\/td>\n2<\/td>\n3<\/td>\n4<\/td>\n5<\/td>\n6<\/td>\n7<\/td>\n8<\/td>\n<\/tr>\n
\u0110\u00e1p \u00e1n<\/td>\nC<\/td>\nB<\/td>\nB<\/td>\nD<\/td>\nA<\/td>\nA<\/td>\nB<\/td>\nC<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

C\u00e2u 1:<\/b>\u00a0C<\/p>\n

Khi l\u00f2 xo kh\u00f4ng bi\u1ebfn d\u1ea1ng v\u1eadt \u0111i qua v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng v\u00e0 v\u1eadt c\u00f3 \u0111\u1ed9 l\u1edbn v\u1eadn t\u1ed1c (t\u1ed1c \u0111\u1ed9) l\u1edbn nh\u1ea5t.<\/p>\n

C\u00e2u 2:<\/b>\u00a0B<\/p>\n

\"\"<\/p>\n

C\u00e2u 3:<\/b>\u00a0B<\/p>\n

Khi m \u1edf v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng ta c\u00f3 h\u1ec7 th\u1ee9c c\u00e2n b\u1eb1ng tr\u1ecdng l\u1ef1c v\u00e0 l\u1ef1c \u0111\u00e0n h\u1ed3i:<\/p>\n

k\u0394l = mg<\/p>\n

\"\"<\/p>\n

C\u00e2u 4:<\/b>\u00a0D<\/p>\n

\"\"<\/p>\n

C\u00e2u 5:<\/b>\u00a0A<\/p>\n

\"\"<\/p>\n

C\u00e2u 6:<\/b>\u00a0A<\/p>\n

\"\"<\/p>\n

C\u00e2u 7:<\/b>\u00a0B<\/p>\n

\"\"<\/p>\n

C\u00e2u 8:<\/b>\u00a0C<\/p>\n

\"\"<\/p>\n","protected":false},"excerpt":{"rendered":"

C\u00e2u 1:\u00a0T\u00ecm ph\u00e1t bi\u1ec3u sai v\u1ec1 con l\u1eafc l\u00f2 xo dao \u0111\u1ed9ng tr\u00ean m\u1eb7t ph\u1eb3ng n\u1eb1m ngang. A. V\u1eadt c\u00f3 gia t\u1ed1c b\u1eb1ng 0 khi l\u00f2 xo c\u00f3 \u0111\u1ed9 d\u00e0i t\u1ef1 nhi\u00ean. B. V\u1eadt c\u00f3 gia t\u1ed1c c\u1ef1c \u0111\u1ea1i khi \u0111\u1ed9 l\u1edbn v\u1eadn t\u1ed1c c\u1ef1c ti\u1ec3u. C. V\u1eadt c\u00f3 \u0111\u1ed9 l\u1edbn v\u1eadn t\u1ed1c nh\u1ecf nh\u1ea5t […]<\/p>\n","protected":false},"author":3,"featured_media":26385,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[158],"tags":[1445,1444],"yoast_head":"\nB\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m V\u1eadt L\u00ed 12: Con l\u1eafc l\u00f2 xo (ph\u1ea7n 1)<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/bai-tap-trac-nghiem-vat-li-12-con-lac-lo-xo-phan-1\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m V\u1eadt L\u00ed 12: Con l\u1eafc l\u00f2 xo (ph\u1ea7n 1)\" \/>\n<meta property=\"og:description\" content=\"C\u00e2u 1:\u00a0T\u00ecm ph\u00e1t bi\u1ec3u sai v\u1ec1 con l\u1eafc l\u00f2 xo dao \u0111\u1ed9ng tr\u00ean m\u1eb7t ph\u1eb3ng n\u1eb1m ngang. 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