C\u00e2u 9:<\/b>\u00a0M\u1ed9t con l\u1eafc \u0111\u01a1n g\u1ed3m v\u1eadt n\u1eb7ng c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng m= 400 g v\u00e0 \u0111\u1ed9 d\u00e0i d\u00e2y treo l = 2 m. G\u00f3c l\u1ec7ch c\u1ef1c \u0111\u1ea1i c\u1ee7a d\u00e2y so v\u1edbi \u0111\u01b0\u1eddng th\u1eb3ng \u0111\u1ee9ng \u03b1_{o<\/sub>\u00a0= 9\u00b0. L\u1ea5y g = 9,8 m\/s^{2<\/sup>. C\u01a1 n\u0103ng v\u00e0 v\u1eadn t\u1ed1c v\u1eadt n\u1eb7ng khi \u0111\u00f3 \u1edf v\u1ecb tr\u00ed th\u1ea5p nh\u1ea5t l\u00e0<\/p>\n}}

A.W = 0,61 J; v = 2 m\/s. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0B. W = 0,096 J; v = 0,69 m\/s.<\/p>\n

C. W = 9,6 J; v = 0,70 m\/s. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0D. W = 0,96 J; v = 0,78 m\/s.<\/p>\n

C\u00e2u 10:<\/b>\u00a0M\u1ed9t con l\u1eafc \u0111\u01a1n d\u00e0i l_{1<\/sub>\u00a0dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a v\u1edbi chu k\u00ec T1<\/sub>\u00a0= 0,9 s. Con l\u1eafc \u0111\u01a1n th\u1ee9 hai d\u00e0i l2<\/sub>\u00a0c\u00f3 chu k\u00ec T2<\/sub>\u00a0= 1,2 s. Con l\u1eafc \u0111\u01a1n d\u00e0i l3<\/sub>\u00a0= l1<\/sub>\u00a0+ l2<\/sub>\u00a0c\u00f3 chu k\u00ec T3<\/sub>\u00a0b\u1eb1ng<\/p>\n}

A. 1,6 s \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0B. 1,5 s \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0C. 1,4 s \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0D. 2,1 s.<\/p>\n

C\u00e2u 11:<\/b>\u00a0M\u1ed9t con l\u1eafc \u0111\u01a1n c\u00f3 chi\u1ec1u d\u00e0i 20 cm. \u1ede th\u1eddi \u0111i\u1ec3m t = 0 t\u1ea1i v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng ng\u01b0\u1eddi ta truy\u1ec1n cho con l\u1eafc v\u1eadn t\u1ed1c 28 cm\/s theo chi\u1ec1u d\u01b0\u01a1ng c\u1ee7a tr\u1ee5c t\u1ecda \u0111\u1ed9. L\u1ea5y<\/p>\n

<\/p>\n

C\u00e2u 12:<\/b>\u00a0Con l\u1eafc \u0111\u01a1n dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a t\u1ea1i m\u1ed9t \u0111\u1ecba \u0111i\u1ec3m tr\u00ean m\u1eb7t \u0111\u1ea5t. Khi chi\u1ec1u d\u00e0i d\u00e2y treo l\u00e0 l_{1<\/sub>\u00a0th\u00ec chu k\u00ec dao \u0111\u1ed9ng c\u1ee7a con l\u1eafc l\u00e0 T1<\/sub>, c\u00f2n khi chi\u1ec1u d\u00e0i d\u00e2y treo l\u00e0 l2<\/sub>\u00a0th\u00ec chu k\u00ec dao \u0111\u1ed9ng c\u1ee7a con l\u1eafc l\u00e0 T2<\/sub>. \u0110\u1ec3 chu k\u00ec dao \u0111\u1ed9ng c\u1ee7a con l\u1eafc T= (T1<\/sub>+T2<\/sub>)\/2 th\u00ec chi\u1ec1u d\u00e0i d\u00e2y treo con l\u1eafc ph\u1ea3i l\u00e0<\/p>\n}

<\/p>\n

C\u00e2u 13:<\/b>\u00a0M\u1ed9t con l\u1eafc \u0111\u01a1n dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a v\u1edbi bi\u00ean \u0111\u1ed9 g\u00f3c \u03b1_{o<\/sub>= 8\u00b0. Khi \u0111\u1ed9ng n\u0103ng c\u1ee7a con l\u1eafc g\u1ea5p 2 l\u1ea7n th\u1ebf n\u0103ng th\u00ec li \u0111\u1ed9c g\u00f3c \u03b1 b\u1eb1ng<\/p>\n}

A. \u00b13\u00b089 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0B. \u00b14\u00b008 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0C. \u00b14\u00b062 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0D. \u00b15\u00b021<\/p>\n

C\u00e2u 14:<\/b>\u00a0Khi \u0111\u01b0a con l\u1eafc \u0111\u01a1n t\u1eeb m\u1eb7t \u0111\u1ea5t l\u00ean \u0111\u1ed9 cao b\u1eb1ng b\u00e1n k\u00ednh Tr\u00e1i \u0110\u1ea5t, v\u00e0 gi\u1ea3m chi\u1ec1u d\u00e0i d\u00e2y treo b\u1ed1n l\u1ea7n (trong \u0111i\u1ec1u ki\u1ec7n nhi\u1ec7t \u0111\u1ed9 kh\u00f4ng \u0111\u1ed5i), th\u00ec chu k\u00ec dao \u0111\u1ed9ng nh\u1ecf c\u1ee7a con l\u1eafc s\u1ebd<\/p>\n

A. kh\u00f4ng \u0111\u1ed5i \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0B. t\u0103ng 2 l\u1ea7n \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0C. t\u0103ng \u221a2 l\u1ea7n \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0D. gi\u1ea3m 4 l\u1ea7n<\/p>\n

C\u00e2u 15:<\/b>\u00a0M\u1ed9t con l\u1eafc \u0111\u01a1n d\u00e0i l dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a v\u1edbi chu k\u00ec T = 2 s. C\u1eaft d\u00e2y treo con l\u1eafc th\u00e0nh hai \u0111o\u1ea1n l_{1<\/sub>\u00a0v\u00e0 l2<\/sub>. Con l\u1eafc \u0111\u01a1n c\u00f3 \u0111\u1ed9 d\u00e0i l1<\/sub>\u00a0th\u00ec chu k\u00ec T1<\/sub>\u00a0= 1,6 s, con l\u1eafc \u0111\u01a1n c\u00f3 \u0111\u1ed9 d\u00e0i l2<\/sub>\u00a0th\u00ec chu k\u00ec T2<\/sub>\u00a0l\u00e0<\/p>\n}

A. 1,2 s \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0B. 1,4 s \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0C. 1,8 s \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0D. 0,4 s<\/p>\n

C\u00e2u 16:<\/b>\u00a0Ng\u01b0\u1eddi ta \u0111\u01b0a m\u1ed9t con l\u1eafc \u0111\u01a1n t\u1eeb m\u1eb7t \u0111\u1ea5t l\u00ean \u0111\u1ed9 cao h = 8 km. Bi\u1ebft b\u00e1n k\u00ednh Tr\u00e1i \u0110\u1ea5t R = 6400 km. \u0110\u1ec3 chu k\u00ec dao \u0111\u1ed9ng c\u1ee7a con l\u1eafc kh\u00f4ng thay \u0111\u1ed5i, chi\u1ec1u d\u00e0i con l\u1eafc thay \u0111\u1ed5i m\u1ed9t l\u01b0\u1ee3ng so v\u1edbi chi\u1ec1u d\u00e0i ban \u0111\u1ea7u l\u00e0<\/p>\n

A. t\u0103ng 0,40% \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0B. gi\u1ea3m 0,25% \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0C. gi\u1ea3m 0,47% \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0D. t\u0103ng 0,47%<\/p>\n

H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0111\u00e1p \u00e1n<\/b><\/p>\n\n\n\n\n

C\u00e2u<\/td>\n	9<\/td>\n	10<\/td>\n	11<\/td>\n	12<\/td>\n	13<\/td>\n	14<\/td>\n	15<\/td>\n	16<\/td>\n<\/tr>\n
\u0110\u00e1p \u00e1n<\/td>\n	B<\/td>\n	B<\/td>\n	C<\/td>\n	B<\/td>\n	C<\/td>\n	A<\/td>\n	A<\/td>\n	B<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n C\u00e2u 9:<\/b>\u00a0B<\/p>\n Ch\u1ecdn g\u1ed1c th\u1ebf n\u0103ng t\u1ea1i v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng ta c\u00f3 :<\/p>\n W=mghmax<\/sub>=mgl(1-cos\u03b1o<\/sub>)\u22480,096 J<\/p>\n <\/p>\n C\u00e2u 10:<\/b>\u00a0B<\/p>\n T\u1eeb c\u00f4ng th\u1ee9c t\u00ednh chu k\u00ec dao \u0111\u1ed9ng suy ra :<\/p>\n l3<\/sub>=l1<\/sub>+l2<\/sub>\u00a0\u21d2 T3<\/sub>2<\/sup>=T1<\/sub>2<\/sup>+T2<\/sub>2<\/sup>=2,25 \u21d2 T3<\/sub>=1,5 s<\/p>\n C\u00e2u 11:<\/b>\u00a0C<\/p>\n <\/p>\n C\u00e2u 12:<\/b>\u00a0B<\/p>\n <\/p>\n C\u00e2u 13:<\/b>\u00a0C<\/p>\n <\/p>\n C\u00e2u 14:<\/b>\u00a0A<\/p>\n <\/p>\n C\u00e2u 15:<\/b>\u00a0A<\/p>\n T\u1eeb c\u00f4ng th\u1ee9c t\u00ednh chu k\u00ec dao \u0111\u1ed9ng c\u1ee7a con l\u1eafc \u0111\u01a1n suy ra :<\/p>\n l2<\/sub>=l-l1<\/sub>\u00a0\u21d2 T2<\/sub>2<\/sup>=T2<\/sup>-T1<\/sub>2<\/sup>=1,44 \u21d2T2<\/sub>=1,2 s<\/p>\n C\u00e2u 16:<\/b>\u00a0B<\/p>\n <\/p>\n","protected":false},"excerpt":{"rendered":" C\u00e2u 9:\u00a0M\u1ed9t con l\u1eafc \u0111\u01a1n g\u1ed3m v\u1eadt n\u1eb7ng c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng m= 400 g v\u00e0 \u0111\u1ed9 d\u00e0i d\u00e2y treo l = 2 m. G\u00f3c l\u1ec7ch c\u1ef1c \u0111\u1ea1i c\u1ee7a d\u00e2y so v\u1edbi \u0111\u01b0\u1eddng th\u1eb3ng \u0111\u1ee9ng \u03b1o\u00a0= 9\u00b0. L\u1ea5y g = 9,8 m\/s2. C\u01a1 n\u0103ng v\u00e0 v\u1eadn t\u1ed1c v\u1eadt n\u1eb7ng khi \u0111\u00f3 \u1edf v\u1ecb tr\u00ed th\u1ea5p nh\u1ea5t […]<\/p>\n","protected":false},"author":3,"featured_media":26347,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[158],"tags":[1445,1444],"yoast_head":"\n