C\u00e2u 1:<\/b>\u00a0M\u1ed9t v\u1eadt tham gia \u0111\u1ed3ng th\u1eddi hai dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a c\u00f9ng ph\u01b0\u01a1ng, c\u00f9ng t\u1ea7n s\u1ed1 c\u00f3 bi\u00ean \u0111\u1ed9 l\u1ea7n l\u01b0\u1ee3t l\u00e0: A1<\/sub>\u00a0= 3 cm v\u00e0 A2<\/sub>\u00a0= 4 cm. Bi\u00ean \u0111\u1ed9 c\u1ee7a dao \u0111\u1ed9ng t\u1ed5ng h\u1ee3p kh\u00f4ng th\u1ec3 nh\u1eadn gi\u00e1 tr\u1ecb<\/p>\n A. 5,7 cm \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 1,0 cm \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. 7,5 cm \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 5,0 cm.<\/p>\n C\u00e2u 2:<\/b>\u00a0M\u1ed9t v\u1eadt th\u1ef1c hi\u1ec7n \u0111\u1ed3ng th\u1eddi hai dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a c\u00f9ng ph\u01b0\u01a1ng, c\u00f9ng t\u1ea7n s\u1ed1 c\u00f3 ph\u01b0\u01a1ng tr\u00ecnh:<\/p>\n <\/p>\n \u1eadn t\u1ed1c c\u1ee7a v\u1eadt t\u1ea1i th\u1eddi \u0111i\u1ec3m t = 2 s l\u00e0<\/p>\n A. -10\u03c0 (cm\/s) \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 10\u03c0 (cm\/s) \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. \u03c0 (cm\/s) \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. \u2013\u03c0 (cm\/s).<\/p>\n C\u00e2u 3:<\/b>\u00a0Dao \u0111\u1ed9ng t\u1ed5ng h\u1ee3p c\u1ee7a hai dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a c\u00f9ng ph\u01b0\u01a1ng, c\u00f9ng t\u1ea7n s\u1ed1:<\/p>\n <\/p>\n l\u00e0 dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a c\u00f3 bi\u00ean \u0111\u1ed9 v\u00e0 pha ban \u0111\u1ea7u l\u00e0:<\/p>\n A. 13 cm; \u03c0\/6 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 17 cm; \u03c0\/12 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. 21 cm; 0,306 rad \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 19 cm; \u03c0\/8<\/p>\n C\u00e2u 4:<\/b>\u00a0Hai giao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a c\u00f9ng ph\u01b0\u01a1ng, c\u00f9ng t\u1ea7n s\u1ed1, ng\u01b0\u1ee3c pha nhau, c\u00f3 bi\u00ean \u0111\u1ed9 l\u00e0 A1<\/sub>\u00a0v\u00e0 A2<\/sub>\u00a0v\u1edbi A2<\/sub>=3A1<\/sub>, th\u00ec dao \u0111\u1ed9ng t\u1ed5ng h\u1ee3p c\u00f3 bi\u00ean \u0111\u1ed9 A l\u00e0<\/p>\n A. A1<\/sub> \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 2A1<\/sub> \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. 3A1<\/sub> \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 4A1<\/sub><\/p>\n C\u00e2u 5:<\/b>\u00a0Hai dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a c\u00f9ng ph\u01b0\u01a1ng, c\u00f9ng t\u1ea7n s\u1ed1, c\u00f9ng pha, c\u00f3 bi\u00ean \u0111\u1ed9 l\u00e0 A1<\/sub>\u00a0v\u00e0 A2<\/sub>\u00a0v\u1edbi A2<\/sub>=4A1<\/sub>\u00a0th\u00ec dao \u0111\u1ed9ng t\u1ed5ng h\u1ee3p c\u00f3 bi\u00ean \u0111\u1ed9 A l\u00e0<\/p>\n A. 5A1<\/sub> \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 2A1<\/sub> \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. 3A1<\/sub> \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 4A1<\/sub><\/p>\n C\u00e2u 6:<\/b>\u00a0Hai dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a c\u00f9ng ph\u01b0\u01a1ng, c\u00f3 c\u00e1c ph\u01b0\u01a1ng tr\u00ecnh dao \u0111\u1ed9ng t\u01b0\u01a1ng \u1ee9ng l\u00e0:<\/p>\n <\/p>\n Dao \u0111\u1ed9ng t\u1ed5ng h\u1ee3p c\u00f3 ph\u01b0\u01a1ng tr\u00ecnh l\u00e0<\/p>\n <\/p>\n C\u00e2u 7:<\/b>\u00a0Hai dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a c\u00f9ng ph\u01b0\u01a1ng c\u00f3 c\u00e1c ph\u01b0\u01a1ng tr\u00ecnh c\u00f3 c\u00e1c ph\u01b0\u01a1ng tr\u00ecnh l\u1ea7n l\u01b0\u1ee3t l\u00e0:<\/p>\n <\/p>\n Bi\u00ean \u0111\u1ed9 dao \u0111\u1ed9ng t\u1ed5ng h\u1ee3p l\u00e0<\/p>\n A. 4,5 cm. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 6 cm. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. 3,5 cm \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 3 cm.<\/p>\n C\u00e2u 8:<\/b>\u00a0M\u1ed9t v\u1eadt tham gia \u0111\u1ed3ng th\u1eddi hai dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a c\u00f9ng ph\u01b0\u01a1ng, c\u00f9ng t\u1ea7n s\u1ed1, c\u00f3 c\u00e1c ph\u01b0\u01a1ng tr\u00ecnh dao \u0111\u1ed9ng th\u00e0nh ph\u1ea7n l\u1ea7n l\u01b0\u1ee3t l\u00e0:<\/p>\n <\/p>\n Khi v\u1eadt qua li \u0111\u1ed9 x = 4 cm th\u00ec v\u1eadn t\u1ed1c dao \u0111\u1ed9ng t\u1ed5ng h\u1ee3p c\u1ee7a v\u1eadt l\u00e0 60 cm\/s\/ T\u1ea7n s\u1ed1 g\u00f3c dao \u0111\u1ed9ng t\u1ed5ng h\u1ee3p c\u1ee7a v\u1eadt l\u00e0<\/p>\n A. 6 rad\/s \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 10 rad\/s \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. 40 rad\/s \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 20 rad\/s.<\/p>\n C\u00e2u 9:<\/b>\u00a0M\u1ed9t v\u1eadt c\u00f3 th\u1ec3 tham gia \u0111\u1ed3ng th\u1eddi hai dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a c\u00f9ng ph\u01b0\u01a1ng, c\u00f9ng t\u1ea7n s\u1ed1 nh\u01b0ng ng\u01b0\u1ee3c pha nhau. N\u1ebfu ch\u1ec9 tham gia dao \u0111\u1ed9ng th\u1ee9 nh\u1ea5t, n\u0103ng l\u01b0\u1ee3ng dao \u0111\u1ed9ng c\u1ee7a v\u1eadt l\u00e0 W1<\/sub>. N\u1ebfu ch\u1ec9 tham gia dao \u0111\u1ed9ng th\u1ee9 hai, n\u0103ng l\u01b0\u1ee3ng dao \u0111\u1ed9ng c\u1ee7a v\u1eadt l\u00e0 W2<\/sub>=2,25W1<\/sub>. Khi tham gia \u0111\u1ed3ng th\u1eddi hai giao \u0111\u1ed9ng, n\u0103ng l\u01b0\u1ee3ng giao \u0111\u1ed9ng c\u1ee7a v\u1eadt l\u00e0<\/p>\n A. 1,5W1<\/sub> \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. W1<\/sub> \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. 0,25W1<\/sub> \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 0,5W1<\/sub><\/p>\n C\u00e2u 10:<\/b>\u00a0M\u1ed9t v\u1eadt th\u1ef1c hi\u1ec7n dao \u0111\u1ed9ng t\u1ed5ng h\u1ee3p c\u1ee7a hai dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a c\u00f3 c\u00f9ng t\u1ea7n s\u1ed1, dao \u0111\u1ed9ng c\u00f9ng ph\u01b0\u01a1ng v\u00e0 c\u00f3 c\u01a1 n\u0103ng l\u00e0 W. N\u1ebfu ch\u1ec9 th\u1ef1c hi\u1ec7n t\u1eebng dao \u0111\u1ed9ng th\u00e0nh ph\u1ea7n, v\u1eadt c\u00f3 c\u01a1 n\u0103ng t\u01b0\u01a1ng \u1ee9ng l\u00e0 W1<\/sub>\u00a0v\u00e0 W2<\/sub>. \u0110\u1ed9 l\u1ec7ch pha c\u1ee7a hai dao \u0111\u1ed9ng \u0111\u01b0\u1ee3c x\u00e1c \u0111\u1ecbnh b\u1eb1ng c\u00f4ng th\u1ee9c<\/p>\n <\/p>\n H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0111\u00e1p \u00e1n<\/b><\/p>\n C\u00e2u 1:<\/b>\u00a0C<\/p>\n Theo ph\u01b0\u01a1ng ph\u00e1p gi\u1ea3n \u0111\u1ed3 Fre \u2013 nen :<\/p>\n <\/p>\n Theo t\u00ednh ch\u1ea5t c\u1ee7a tam gi\u00e1c ta c\u00f3 :<\/p>\n |A1<\/sub>-A2<\/sub>\u00a0| \u2264 A \u2264 |A1<\/sub>+A2<\/sub>\u00a0| ,<\/p>\n do \u0111\u00f3 ta c\u00f3 : 1 \u2264A \u22647<\/p>\n V\u1eady A kh\u00f4ng th\u1ec3 b\u1eb1ng 7,5 cm<\/p>\n C\u00e2u 2:<\/b>\u00a0B<\/p>\n <\/p>\n C\u00e2u 3:<\/b>\u00a0C<\/p>\n <\/p>\n C\u00e2u 4:<\/b>\u00a0B<\/p>\n Hai dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a c\u00f9ng ph\u01b0\u01a1ng, c\u00f9ng t\u1ea7n s\u1ed1, ng\u01b0\u1ee3c pha nhau, n\u00ean dao \u0111\u1ed9ng t\u1ed5ng h\u1ee3p c\u00f3 bi\u00ean \u0111\u1ed9 A=A2<\/sub>-A1<\/sub>=2A1<\/sub><\/p>\n C\u00e2u 5:<\/b>\u00a0A<\/p>\n Hai dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a c\u00f9ng ph\u01b0\u01a1ng, c\u00f9ng t\u1ea7n s\u1ed1, c\u00f9ng pha n\u00ean dao \u0111\u1ed9ng t\u1ed5ng h\u1ee3p c\u00f3 bi\u00ean \u0111\u1ed9 A=A2<\/sub>+A1<\/sub>=5A1<\/sub><\/p>\n C\u00e2u 6:<\/b>\u00a0A<\/p>\n <\/p>\n C\u00e2u 7:<\/b>\u00a0B<\/p>\n x1<\/sub>\u00a0v\u00e0 x2<\/sub>\u00a0c\u00f9ng pha n\u00ean A=A1<\/sub>+A2<\/sub>=1,5+4,5=6 cm<\/p>\n C\u00e2u 8:<\/b>\u00a0D<\/p>\n <\/p>\n C\u00e2u 9:<\/b>\u00a0C<\/p>\n <\/p>\n C\u00e2u 10:<\/b>\u00a0D<\/p>\n <\/p>\n","protected":false},"excerpt":{"rendered":" C\u00e2u 1:\u00a0M\u1ed9t v\u1eadt tham gia \u0111\u1ed3ng th\u1eddi hai dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a c\u00f9ng ph\u01b0\u01a1ng, c\u00f9ng t\u1ea7n s\u1ed1 c\u00f3 bi\u00ean \u0111\u1ed9 l\u1ea7n l\u01b0\u1ee3t l\u00e0: A1\u00a0= 3 cm v\u00e0 A2\u00a0= 4 cm. Bi\u00ean \u0111\u1ed9 c\u1ee7a dao \u0111\u1ed9ng t\u1ed5ng h\u1ee3p kh\u00f4ng th\u1ec3 nh\u1eadn gi\u00e1 tr\u1ecb A. 5,7 cm \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 1,0 cm \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. 7,5 cm \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. […]<\/p>\n","protected":false},"author":3,"featured_media":26323,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[158],"tags":[1445,1444],"yoast_head":"\n\n\n
\n C\u00e2u<\/td>\n 1<\/td>\n 2<\/td>\n 3<\/td>\n 4<\/td>\n 5<\/td>\n 6<\/td>\n 7<\/td>\n 8<\/td>\n 9<\/td>\n 10<\/td>\n<\/tr>\n \n \u0110\u00e1p \u00e1n<\/td>\n C<\/td>\n B<\/td>\n C<\/td>\n B<\/td>\n A<\/td>\n A<\/td>\n B<\/td>\n D<\/td>\n C<\/td>\n D<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n