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{"id":26311,"date":"2018-04-10T17:01:10","date_gmt":"2018-04-10T10:01:10","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=26311"},"modified":"2018-04-10T17:01:10","modified_gmt":"2018-04-10T10:01:10","slug":"bai-tap-trac-nghiem-vat-li-12-chuong-1-phan-2","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/bai-tap-trac-nghiem-vat-li-12-chuong-1-phan-2\/","title":{"rendered":"B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m V\u1eadt L\u00ed 12: Ch\u01b0\u01a1ng 1 (ph\u1ea7n 2)"},"content":{"rendered":"

C\u00e2u 8:<\/b>\u00a0Hai con l\u1eafc l\u00f2 xo gi\u1ed1ng nhau treo v\u00e0o hai \u0111i\u1ec3m tr\u00ean c\u00f9ng gi\u00e1 \u0111\u1ee1 n\u1eb1m ngang. Ch\u1ecdn tr\u1ee5c t\u1ecda \u0111\u1ed9 Ox c\u00f3 ph\u01b0\u01a1ng th\u1eb3ng \u0111\u1ee9ng, chi\u1ec1u h\u01b0\u1edbng xu\u1ed1ng d\u01b0\u1edbi th\u00ec ph\u01b0\u01a1ng tr\u00ecnh dao \u0111\u1ed9ng c\u1ee7a hai con l\u1eafc l\u00e0 x1<\/sub>=4cos\u206120t v\u00e0 x2<\/sub>=4\u221a3 cos\u2061(20t+\u03c0\/2) v\u1edbi x \u0111o b\u1eb1ng cm, t \u0111o b\u1eb1ng s. Bi\u1ebft l\u00f2 xo c\u00f3 \u0111\u1ed9 c\u1ee9ng k = 0,5 N\/cm, gia t\u1ed1c tr\u1ecdng tr\u01b0\u1eddng g = 10 m\/s2<\/sup>. L\u1ef1c c\u1ef1c \u0111\u1ea1i do hai con l\u1eafc t\u00e1c d\u1ee5ng l\u00ean gi\u00e1 \u0111\u1ee1 l\u00e0<\/p>\n

A. 4,5 N. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0B. 6,5 N \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0C. 2,5 N. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0D. 1,5 N.<\/p>\n

C\u00e2u 9:<\/b>\u00a0Hai con l\u1eafc \u0111\u01a1n dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a t\u1ea1i c\u00f9ng m\u1ed9t n\u01a1i tr\u00ean Tr\u00e1i \u0110\u1ea5t, c\u00f3 c\u01a1 n\u0103ng b\u1eb1ng nhau. Qu\u1ea3 n\u1eb7ng c\u1ee7a ch\u00fang c\u00f3 c\u00f9ng kh\u1ed1i l\u01b0\u1ee3ng. Chi\u1ec1u d\u00e0i d\u00e2y treo con l\u1eafc th\u1ee9 nh\u1ea5t b\u1eb1ng 1,5 l\u1ea7n chi\u1ec1u d\u00e0i d\u00e2y treo con l\u1eafc th\u1ee9 hai (l1<\/sub>=1,5l2<\/sub>). Quan h\u1ec7 gi\u1eefa bi\u00ean \u0111\u1ed9 g\u00f3c c\u1ee7a hai con l\u1eafc \u0111\u00f3 l\u00e0<\/p>\n

\"\"<\/p>\n

C\u00e2u 10:<\/b>\u00a0M\u1ed9t con l\u1eafc \u0111\u01a1n g\u1ed3m v\u1eadt n\u1eb7ng kh\u1ed1i l\u01b0\u1ee3ng m = 100g, d\u00e2y treo d\u00e0i l = 80 cm, \u0111\u1eb7t t\u1ea1i n\u01a1i c\u00f3 g = 10 m\/s2<\/sup>. K\u00e9o d\u00e2y treo cho v\u1eadt l\u1ec7ch kh\u1ecfi v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng m\u1ed9t \u0111o\u1ea1n A r\u1ed3i th\u1ea3 kh\u00f4ng v\u1eadn t\u1ed1c \u0111\u1ea7u, con l\u1eafc dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a v\u1edbi c\u01a1 n\u0103ng W=8,1.10-4<\/sup>\u00a0J . Bi\u00ean \u0111\u1ed9 dao \u0111\u1ed9ng A c\u1ee7a con l\u1eafc l\u00e0<\/p>\n

A. 2,4 cm \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0B. 3,6 cm \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0C. 4,8 cm \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0D. 7,2 cm.<\/p>\n

C\u00e2u 11:<\/b>\u00a0Ph\u00e1t bi\u1ec3u n\u00e0o sau \u0111\u00e2y l\u00e0 sai khi n\u00f3i v\u1ec1 hi\u1ec7n t\u01b0\u1ee3ng c\u1ed9ng h\u01b0\u1edfng?<\/p>\n

A. \u0110i\u1ec1u ki\u1ec7n x\u1ea3y ra hi\u1ec7n t\u01b0\u1ee3ng c\u1ed9ng h\u01b0\u1edfng l\u00e0 h\u1ec7 ph\u1ea3i dao \u0111\u1ed9ng c\u01b0\u1ee1ng b\u1ee9c d\u01b0\u1edbi t\u00e1c d\u1ee5ng c\u1ee7a ngo\u1ea1i l\u1ef1c bi\u1ebfn thi\u00ean tu\u1ea7n ho\u00e0n c\u00f3 t\u1ea7n s\u1ed1 ngo\u1ea1i l\u1ef1c f b\u1eb1ng t\u1ea7n s\u1ed1 ri\u00eang c\u1ee7a h\u1ec7 fo<\/sub>.<\/p>\n

B. Bi\u00ean \u0111\u1ed9 c\u1ed9ng h\u01b0\u1edfng kh\u00f4ng ph\u1ee5 thu\u1ed9c v\u00e0o l\u1ef1c c\u1ea3n c\u1ee7a m\u00f4i tr\u01b0\u1eddng.<\/p>\n

C. Hi\u1ec7n t\u01b0\u1ee3ng \u0111\u1eb7c bi\u1ec7t x\u1ea3y ra trong dao \u0111\u1ed9ng c\u01b0\u1ee1ng b\u1ee9c l\u00e0 hi\u1ec7n t\u01b0\u1ee3ng c\u1ed9ng h\u01b0\u1edfng.<\/p>\n

D. Khi c\u1ed9ng h\u01b0\u1edfng, bi\u00ean \u0111\u1ed9 c\u1ee7a dao \u0111\u1ed9ng c\u01b0\u1ee1ng b\u1ee9c t\u0103ng \u0111\u1ed9t ng\u1ed9t v\u00e0 \u0111\u1ea1t gi\u00e1 tr\u1ecb c\u1ef1c \u0111\u1ea1i.<\/p>\n

C\u00e2u 12:<\/b>\u00a0Ch\u1ecdn ph\u00e1t bi\u1ec3u \u0111\u00fang khi n\u00f3i v\u1ec1 dao \u0111\u1ed9ng c\u01b0\u1ee1ng b\u1ee9c.<\/p>\n

A. T\u1ea7n s\u1ed1 c\u1ee7a dao \u0111\u1ed9ng c\u01b0\u1ee1ng b\u1ee9c l\u00e0 t\u1ea7n s\u1ed1 c\u1ee7a ngo\u1ea1i l\u1ef1c tu\u1ea7n ho\u00e0n.<\/p>\n

B. T\u1ea7n s\u1ed1 c\u1ee7a dao \u0111\u1ed9ng c\u01b0\u1ee1ng b\u1ee9c c\u0169ng l\u00e0 t\u1ea7n s\u1ed1 ri\u00eang c\u1ee7a h\u1ec7.<\/p>\n

C. Bi\u00ean \u0111\u1ed9 c\u1ee7a dao \u0111\u1ed9ng c\u01b0\u1ee1ng b\u1ee9c l\u00e0 bi\u00ean \u0111\u1ed9 c\u1ee7a ngo\u1ea1i l\u1ef1c tu\u1ea7n ho\u00e0n.<\/p>\n

D. Bi\u00ean \u0111\u1ed9 c\u1ee7a dao \u0111\u1ed9ng c\u01b0\u1ee1ng b\u1ee9c ch\u1ec9 ph\u1ee5 thu\u1ed9c v\u00e0o t\u1ea7n s\u1ed1 c\u1ee7a ngo\u1ea1i l\u1ef1c tu\u1ea7n ho\u00e0n.<\/p>\n

C\u00e2u 13:<\/b>\u00a0M\u1ed9t dao \u0111\u1ed9ng t\u1eaft d\u1ea7n c\u00f3 bi\u00ean \u0111\u1ed9 gi\u1ea3m 2% sau m\u1ed7i chu k\u00ec. Sau 5 chu k\u00ec ph\u1ea7n c\u01a1 n\u0103ng dao \u0111\u1ed9ng c\u00f2n l\u1ea1i l\u00e0<\/p>\n

A. 70% \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0B. 75% \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0C. 78,1% \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0D. 81,5%.<\/p>\n

C\u00e2u 14:<\/b>\u00a0M\u1ed9t ch\u1ea5t \u0111i\u1ec3m dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a kh\u00f4ng ma s\u00e1t theo tr\u1ee5c Ox. Bi\u1ebft r\u1eb1ng trong qu\u00e1 tr\u00ecnh kh\u1ea3o s\u00e1t v\u1eadt ch\u01b0a \u0111\u1ed5i chi\u1ec1u chuy\u1ec3n \u0111\u1ed9ng. Khi v\u1eeba r\u1eddi kh\u1ecfi v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng m\u1ed9t \u0111o\u1ea1n s th\u00ec \u0111\u1ed9ng n\u0103ng c\u1ee7a ch\u1ea5t \u0111i\u1ec3m l\u00e0 13,95 mJ. \u0110i ti\u1ebfp m\u1ed9t \u0111o\u1ea1n s n\u1eefa th\u00ec \u0111\u1ed9ng n\u0103ng c\u1ee7a ch\u1ea5t \u0111i\u1ec3m ch\u1ec9 c\u00f2n 12,6 mJ. N\u1ebfu ch\u1ea5t \u0111i\u1ec3m \u0111i th\u00eam m\u1ed9t \u0111o\u1ea1n s n\u1eefa th\u00ec \u0111\u1ed9ng n\u0103ng c\u1ee7a n\u00f3 l\u00e0<\/p>\n

A. 6,68 mJ \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0B. 11,25 mJ \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0C. 10,35 mJ \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0D. 8,95 mJ.<\/p>\n

H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0111\u00e1p \u00e1n<\/b><\/p>\n\n\n\n\n
C\u00e2u<\/td>\n8<\/td>\n9<\/td>\n10<\/td>\n11<\/td>\n12<\/td>\n13<\/td>\n14<\/td>\n<\/tr>\n
\u0110\u00e1p \u00e1n<\/td>\nB<\/td>\nD<\/td>\nB<\/td>\nB<\/td>\nA<\/td>\nD<\/td>\nC<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

C\u00e2u 8:<\/b>\u00a0B<\/p>\n

\"\"<\/p>\n

C\u00e2u 9:<\/b>\u00a0D<\/p>\n

\"\"<\/p>\n

C\u00e2u 10:<\/b>\u00a0B<\/p>\n

\"\"<\/p>\n

C\u00e2u 13:<\/b>\u00a0D<\/p>\n

\"\"<\/p>\n

C\u00e2u 14:<\/b>\u00a0C<\/p>\n

\"\"<\/p>\n","protected":false},"excerpt":{"rendered":"

C\u00e2u 8:\u00a0Hai con l\u1eafc l\u00f2 xo gi\u1ed1ng nhau treo v\u00e0o hai \u0111i\u1ec3m tr\u00ean c\u00f9ng gi\u00e1 \u0111\u1ee1 n\u1eb1m ngang. Ch\u1ecdn tr\u1ee5c t\u1ecda \u0111\u1ed9 Ox c\u00f3 ph\u01b0\u01a1ng th\u1eb3ng \u0111\u1ee9ng, chi\u1ec1u h\u01b0\u1edbng xu\u1ed1ng d\u01b0\u1edbi th\u00ec ph\u01b0\u01a1ng tr\u00ecnh dao \u0111\u1ed9ng c\u1ee7a hai con l\u1eafc l\u00e0 x1=4cos\u206120t v\u00e0 x2=4\u221a3 cos\u2061(20t+\u03c0\/2) v\u1edbi x \u0111o b\u1eb1ng cm, t \u0111o b\u1eb1ng s. Bi\u1ebft […]<\/p>\n","protected":false},"author":3,"featured_media":26312,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[158],"tags":[1445,1444],"yoast_head":"\nB\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m V\u1eadt L\u00ed 12: Ch\u01b0\u01a1ng 1 (ph\u1ea7n 2)<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/bai-tap-trac-nghiem-vat-li-12-chuong-1-phan-2\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"B\u00e0i t\u1eadp tr\u1eafc nghi\u1ec7m V\u1eadt L\u00ed 12: Ch\u01b0\u01a1ng 1 (ph\u1ea7n 2)\" \/>\n<meta property=\"og:description\" content=\"C\u00e2u 8:\u00a0Hai con l\u1eafc l\u00f2 xo gi\u1ed1ng nhau treo v\u00e0o hai \u0111i\u1ec3m tr\u00ean c\u00f9ng gi\u00e1 \u0111\u1ee1 n\u1eb1m ngang. 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Ch\u1ecdn tr\u1ee5c t\u1ecda \u0111\u1ed9 Ox c\u00f3 ph\u01b0\u01a1ng th\u1eb3ng \u0111\u1ee9ng, chi\u1ec1u h\u01b0\u1edbng xu\u1ed1ng d\u01b0\u1edbi th\u00ec ph\u01b0\u01a1ng tr\u00ecnh dao \u0111\u1ed9ng c\u1ee7a hai con l\u1eafc l\u00e0 x1=4cos\u206120t v\u00e0 x2=4\u221a3 cos\u2061(20t+\u03c0\/2) v\u1edbi x \u0111o b\u1eb1ng cm, t \u0111o b\u1eb1ng s. 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