D\u01b0\u1edbi \u0111\u00e2y l\u00e0 \u0110\u1ec1 thi th\u1eed THPT qu\u1ed1c gia M\u00f4n To\u00e1n n\u0103m 2016 (S\u01b0u t\u1ea7m). Ch\u00fac c\u00e1c b\u1ea1n h\u1ecdc sinh \u00f4n t\u1eadp th\u1eadt t\u1ed1t \u0111\u1ec3 chu\u1ea9n b\u1ecb cho k\u1ef3 thi quan tr\u1ecdng n\u00e0y!<\/p>\n

C\u00e2u 1 (1,0 \u0111i\u1ec3m).<\/strong> Kh\u1ea3o s\u00e1t s\u1ef1 bi\u1ebfn thi\u00ean v\u00e0 v\u1ebd \u0111\u1ed3 th\u1ecb c\u1ee7a h\u00e0m s\u1ed1 y = -x^{3<\/sup> + 3x \u2013 2.<\/p>\n}

C\u00e2u 2 (1,0 \u0111i\u1ec3m).<\/strong> T\u00ecm gi\u00e1 tr\u1ecb l\u1edbn nh\u1ea5t v\u00e0 gi\u00e1 tr\u1ecb nh\u1ecf nh\u1ea5t c\u1ee7a h\u00e0m s\u1ed1:<\/p>\n

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C\u00e2u 3 (1,0 \u0111i\u1ec3m).<\/strong><\/p>\n

a) Gi\u1ea3i ph\u01b0\u01a1ng tr\u00ecnh: cos2x \u2013 5sinx + 2 = 0<\/p>\n

b) Gi\u1ea3i b\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh: log_{0,5<\/sub>x + 2log0,25<\/sub>(x \u2013 1) + log2<\/sub>6 \u2265 0<\/p>\n}

C\u00e2u 4 (1,0 \u0111i\u1ec3m).<\/strong> T\u00ednh t\u00edch ph\u00e2n:<\/p>\n

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C\u00e2u 5 (1,0 \u0111i\u1ec3m).<\/strong> Trong kh\u00f4ng gian Oxyz, cho c\u00e1c \u0111i\u1ec3m A(1;-1;2); B(3;1;0) v\u00e0 m\u1eb7t ph\u1eb3ng (P) c\u00f3 ph\u01b0\u01a1ng tr\u00ecnh: x \u2013 2y \u2013 4z + 8 = 0. T\u00ecm t\u1ecda \u0111\u1ed9 \u0111i\u1ec3m C n\u1eb1m trong m\u1eb7t ph\u1eb3ng (P) sao cho CA = CB v\u00e0 m\u1eb7t ph\u1eb3ng (ABC) vu\u00f4ng g\u00f3c v\u1edbi m\u1eb7t ph\u1eb3ng (P).<\/p>\n

C\u00e2u 6 (1,0 \u0111i\u1ec3m).<\/strong><\/p>\n

a) T\u00ecm s\u1ed1 h\u1ea1ng kh\u00f4ng ch\u1ee9a x trong khai tri\u1ec3n nh\u1ecb th\u1ee9c:<\/p>\n

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b) T\u1eeb c\u00e1c ch\u1eef s\u1ed1 1, 3, 4, 5, 6, 7 l\u1eadp c\u00e1c s\u1ed1 t\u1ef1 nhi\u00ean g\u1ed3m 4 ch\u1eef s\u1ed1 kh\u00e1c nhau. Ch\u1ecdn ng\u1eabu nhi\u00ean m\u1ed9t s\u1ed1 b\u1ea5t k\u00ec trong c\u00e1c s\u1ed1 l\u1eadp \u0111\u01b0\u1ee3c. T\u00ednh x\u00e1c su\u1ea5t \u0111\u1ec3 s\u1ed1 \u0111\u01b0\u1ee3c ch\u1ecdn l\u00e0 s\u1ed1 ch\u1eb5n.<\/p>\n

C\u00e2u 7 (1,0 \u0111i\u1ec3m).<\/strong> Cho h\u00ecnh ch\u00f3p S.ABCD c\u00f3 \u0111\u00e1y ABCD l\u00e0 h\u00ecnh vu\u00f4ng c\u1ea1nh a. G\u1ecdi M l\u00e0 trung \u0111i\u1ec3m CD, SH vu\u00f4ng g\u00f3c v\u1edbi m\u1eb7t ph\u1eb3ng (ABCD) v\u1edbi H l\u00e0 giao \u0111i\u1ec3m c\u1ee7a AC v\u1edbi BM. G\u00f3c gi\u1eefa (SCD) v\u00e0 (ABCD) b\u1eb1ng 60^{o<\/sup>. T\u00ednh th\u1ec3 t\u00edch kh\u1ed1i ch\u00f3p S.ABCD v\u00e0 kho\u1ea3ng c\u00e1ch gi\u1eefa hai \u0111\u01b0\u1eddng th\u1eb3ng AB v\u00e0 SM theo a.<\/p>\n}

C\u00e2u 8 (1,0 \u0111i\u1ec3m).<\/strong> Trong m\u1eb7t ph\u1eb3ng v\u1edbi h\u1ec7 to\u1ea1 \u0111\u1ed9 Oxy, cho tam gi\u00e1c ABC, g\u1ecdi D l\u00e0 \u0111i\u1ec3m \u0111\u1ed1i x\u1ee9ng v\u1edbi C qua A. \u0110i\u1ec3m H(2; -5) l\u00e0 h\u00ecnh chi\u1ebfu vu\u00f4ng g\u00f3c c\u1ee7a \u0111i\u1ec3m B tr\u00ean AD, \u0111i\u1ec3m K(-1; -1) l\u00e0 h\u00ecnh chi\u1ebfu vu\u00f4ng g\u00f3c c\u1ee7a \u0111i\u1ec3m D tr\u00ean AB, \u0111\u01b0\u1eddng tr\u00f2n (T) ngo\u1ea1i ti\u1ebfp tam gi\u00e1c ABD c\u00f3 ph\u01b0\u01a1ng tr\u00ecnh (x \u2013 1)^{2<\/sup> + (y + 2)2<\/sup> = 25. T\u00ecm t\u1ecda \u0111\u1ed9 c\u00e1c \u0111\u1ec9nh c\u1ee7a tam gi\u00e1c ABC, bi\u1ebft \u0111i\u1ec3m A c\u00f3 ho\u00e0nh \u0111\u1ed9 d\u01b0\u01a1ng.<\/p>\n}

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\u0110\u00c1P \u00c1N \u0110\u1ec0 THI<\/strong><\/p>\n

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D\u01b0\u1edbi \u0111\u00e2y l\u00e0 \u0110\u1ec1 thi th\u1eed THPT qu\u1ed1c gia M\u00f4n To\u00e1n n\u0103m 2016 (S\u01b0u t\u1ea7m). Ch\u00fac c\u00e1c b\u1ea1n h\u1ecdc sinh \u00f4n t\u1eadp th\u1eadt t\u1ed1t \u0111\u1ec3 chu\u1ea9n b\u1ecb cho k\u1ef3 thi quan tr\u1ecdng n\u00e0y! C\u00e2u 1 (1,0 \u0111i\u1ec3m). Kh\u1ea3o s\u00e1t s\u1ef1 bi\u1ebfn thi\u00ean v\u00e0 v\u1ebd \u0111\u1ed3 th\u1ecb c\u1ee7a h\u00e0m s\u1ed1 y = -x3 + 3x \u2013 […]<\/p>\n","protected":false},"author":2,"featured_media":17791,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[28],"tags":[],"yoast_head":"\n