C\u00e2u 1:<\/b>\u00a0Ch\u1ecdn ph\u00e1t bi\u1ec3u \u0111\u00fang.<\/p>\n
A. C\u00f3 hai cu\u1ed9n day m\u1eafc n\u1ed1i ti\u1ebfp, cu\u1ed9n d\u00e2y n\u00e0o c\u00f3 h\u1ec7 s\u1ed1 c\u00f4ng su\u1ea5t l\u1edbn h\u01a1n th\u00ec c\u00f4ng su\u1ea5t s\u1ebd l\u1edbn h\u01a1n.<\/p>\n
B. H\u1ec7 s\u1ed1 c\u00f4ng su\u1ea5t c\u1ee7a \u0111o\u1ea1n m\u1ea1ch cos\u03c6=0,5 ch\u1ee9ng t\u1ecf c\u01b0\u1eddng \u0111\u1ed9 d\u00f2ng \u0111i\u1ec7n trong m\u1ea1ch tr\u1ec5 pha \u03c0\/3 so v\u1edbi \u0111i\u1ec7n \u00e1p gi\u1eefa hai \u0111\u1ea7u \u0111o\u1ea1n m\u1ea1ch.<\/p>\n
C. H\u1ec7 s\u1ed1 c\u00f4ng su\u1ea5t c\u1ee7a \u0111o\u1ea1n m\u1ea1ch cos\u03c6=\u221a3\/2 ch\u1ee9ng t\u1ecf c\u01b0\u1eddng \u0111\u1ed9 d\u00f2ng \u0111i\u1ec7n trong m\u1ea1ch s\u1edbm pha \u03c0\/6 so v\u1edbi \u0111i\u1ec7n \u00e1p gi\u1eefa hai \u0111\u1ea7u \u0111o\u1ea1n m\u1ea1ch.<\/p>\n
D. H\u1ec7 s\u1ed1 c\u00f4ng su\u1ea5t c\u1ee7a \u0111o\u1ea1n m\u1ea1ch R, L, C m\u1eafc n\u1ed1i ti\u1ebfp ph\u1ee5 thu\u1ed9c t\u1ea7n s\u1ed1 d\u00f2ng \u0111i\u1ec7n trong m\u1ea1ch.<\/p>\n
C\u00e2u 2:<\/b>\u00a0\u0110\u1eb7t v\u00e0o 2 \u0111\u1ea7u \u0111o\u1ea1n m\u1ea1ch g\u1ed3m R, L, C m\u1eafc n\u1ed1i ti\u1ebfp m\u1ed9t \u0111i\u1ec7n \u00e1p xoay chi\u1ec1u u=Uo<\/sub>\u00a0cos\u03c9t th\u00ec c\u01b0\u1eddng \u0111\u1ed9 d\u00f2ng \u0111i\u1ec7n trong m\u1ea1ch c\u00f3 bi\u1ec3u th\u1ee9c i=Io<\/sub>\u00a0sin(\u03c9t+\u03c0\/6). C\u00f4ng su\u1ea5t \u0111i\u1ec7n ti\u00eau th\u1ee5 c\u1ee7a \u0111o\u1ea1n m\u1ea1ch l\u00e0<\/p>\n <\/p>\n C\u00e2u 3:<\/b>\u00a0\u0110\u1eb7t m\u1ed9t \u0111i\u1ec7n \u00e1p xoay chi\u1ec1u v\u00e0o hai \u0111\u1ea7u m\u1ed9t m\u1ea1ch \u0111i\u1ec7n g\u1ed3m m\u1ed9t \u0111i\u1ec7n tr\u1edf R = 12 \u03a9 v\u00e0 m\u1ed9t cu\u1ed9n c\u1ea3m thu\u1ea7n L m\u1eafc n\u1ed1i ti\u1ebfp. \u0110i\u1ec7n \u00e1p hi\u1ec7u d\u1ee5ng hai \u0111\u1ea7u \u0111o\u1ea1n m\u1ea1ch l\u00e0 26 V, hai \u0111\u1ea7u cu\u1ed9n c\u1ea3m thu\u1ea7n l\u00e0 10 V. C\u00f4ng su\u1ea5t ti\u00eau th\u1ee5 c\u1ee7a \u0111o\u1ea1n m\u1ea1ch l\u00e0<\/p>\n A. 12 W \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 48 W \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. 24 W \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 16 W<\/p>\n C\u00e2u 4:<\/b>\u00a0\u0110\u1eb7t \u0111i\u1ec7n \u00e1p xoay chi\u1ec1u c\u00f3 bi\u1ec3u th\u1ee9c u=30cos100\u03c0t (V) v\u00e0o hai \u0111\u1ea7u \u0111o\u1ea1n m\u1ea1ch g\u1ed3m \u0111i\u1ec7n tr\u1edf thu\u1ea7n R = 30 \u03a9, m\u1eafc n\u1ed1i ti\u1ebfp v\u1edbi cu\u1ed9n c\u1ea3m thu\u1ea7n th\u00ec c\u00f4ng su\u1ea5t ti\u00eau th\u1ee5 tr\u00ean \u0111o\u1ea1n m\u1ea1ch l\u00e0 7,5 W. Bi\u1ec3u th\u1ee9c c\u1ee7a c\u01b0\u1eddng \u0111\u1ed9 d\u00f2ng \u0111i\u1ec7n qua \u0111o\u1ea1n m\u1ea1ch l\u00e0<\/p>\n <\/p>\n C\u00e2u 5:<\/b><\/p>\n <\/p>\n A. 100 V \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 100\u221a3 V \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. 120 V \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 100\u221a2 V<\/p>\n C\u00e2u 6:<\/b>\u00a0Cho m\u1ea1ch \u0111i\u1ec7n c\u00f3 R, L, C m\u1eafc n\u1ed1i ti\u1ebfp. \u0110i\u1ec7n \u00e1p gi\u1eefa hai \u0111\u1ea7u \u0111o\u1ea1n m\u1ea1ch l\u00e0 u=50\u221a2 cos100\u03c0t (V). \u0110i\u1ec7n \u00e1p hi\u1ec7u d\u1ee5ng gi\u1eefa hai \u0111\u1ea7u cu\u1ed9n c\u1ea3m thu\u1ea7n l\u00e0 UL<\/sub>=35 V v\u00e0 gi\u1eefa hai \u0111\u1ea7u t\u1ee5 \u0111i\u1ec7n l\u00e0 UC<\/sub>=75 V. H\u1ec7 s\u1ed1 c\u00f4ng su\u1ea5t c\u1ee7a m\u1ea1ch \u0111i\u1ec7n n\u00e0y l\u00e0<\/p>\n A. cos\u03c6=0,6 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. cos\u03c6=0,7<\/p>\n C. cos\u03c6=0,8 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. cos\u03c6=0,9<\/p>\n C\u00e2u 7:<\/b>\u00a0M\u1ed9t \u0111o\u1ea1n m\u1ea1ch m\u1eafc n\u1ed1i ti\u1ebfp g\u1ed3m m\u1ed9t cu\u1ed9n d\u00e2y c\u00f3 \u0111i\u1ec7n tr\u1edf thu\u1ea7n r=10\u221a3 \u03a9 v\u00e0 \u0111\u1ed9 t\u1ef1 c\u1ea3m L = 0,191 H, t\u1ee5 \u0111i\u1ec7n c\u00f3 \u0111i\u1ec7n dung C= 1\/4\u03c0 (mF), \u0111i\u1ec7n tr\u1edf R c\u00f3 gi\u00e1 tr\u1ecb thay \u0111\u1ed5i \u0111\u01b0\u1ee3c. \u0110\u1eb7t v\u00e0o hai \u0111\u1ea7u \u0111o\u1ea1n m\u1ea1ch \u0111i\u1ec7n \u00e1p u=200\u221a2 cos100\u03c0t (V). Thay \u0111\u1ed5i gi\u00e1 tr\u1ecb c\u1ee7a R \u0111\u1ec3 c\u00f4ng su\u1ea5t ti\u00eau th\u1ee5 tr\u00ean R \u0111\u1ea1t c\u1ef1c \u0111\u1ea1i. C\u00f4ng su\u1ea5t c\u1ef1c \u0111\u1ea1i \u0111\u00f3 c\u00f3 gi\u00e1 tr\u1ecb b\u1eb1ng<\/p>\n A. 200 W \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 457 W \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. 168 W \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 630 W<\/p>\n C\u00e2u 8:<\/b>\u00a0M\u1ed9t \u0111o\u1ea1n m\u1ea1ch xoay chi\u1ec1u AB c\u00f3 \u0111i\u1ec7n tr\u1edf R v\u00e0 cu\u1ed9n c\u1ea3m thu\u1ea7n ZL<\/sub>\u00a0m\u1eafc n\u1ed1i ti\u1ebfp. Bi\u1ebft ZL<\/sub>=3R. N\u1ebfu m\u1eafc th\u00eam m\u1ed9t t\u1ee5 \u0111i\u1ec7n c\u00f3 ZC<\/sub>=R th\u00ec h\u1ec7 s\u1ed1 c\u00f4ng su\u1ea5t c\u1ee7a \u0111o\u1ea1n m\u1ea1ch AB s\u1ebd<\/p>\n A. t\u0103ng 2 l\u1ea7n \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. gi\u1ea3m 2 l\u1ea7n<\/p>\n C. t\u0103ng \u221a2 l\u1ea7n \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. g\u1ec9\u1ea3m \u221a2 l\u1ea7n<\/p>\n C\u00e2u 9:<\/b>\u00a0Trong m\u1ed9t \u0111o\u1ea1n m\u1ea1ch R, L, C m\u1eafc n\u1ed1i ti\u1ebfp c\u00f3 \u0111i\u1ec7n tr\u1edf R thay \u0111\u1ed5i \u0111\u01b0\u1ee3c. Khi \u0111i\u1ec7n tr\u1edf c\u00f3 gi\u00e1 tr\u1ecb l\u00e0 30 \u03a9 ho\u1eb7c 120 \u03a9 th\u00ec c\u00f4ng su\u1ea5t ti\u00eau th\u1ee5 c\u1ee7a \u0111o\u1ea1n m\u1ea1ch b\u1eb1ng nhau. Mu\u1ed1n c\u00f4ng su\u1ea5t ti\u00eau th\u1ee5 tr\u00ean \u0111o\u1ea1n m\u1ea1ch c\u1ef1c \u0111\u1ea1i c\u1ea7n \u0111i\u1ec1u ch\u1ec9nh b\u1eb1ng nhau. Mu\u1ed1n c\u00f4ng su\u1ea5t ti\u00eau th\u1ee5 tr\u00ean \u0111o\u1ea1n m\u1ea1ch c\u1ef1c \u0111\u1ea1i c\u1ea7n \u0111i\u1ec1u ch\u1ec9nh \u0111i\u1ec7n tr\u1edf \u0111\u1ea1t gi\u00e1 tr\u1ecb l\u00e0<\/p>\n A. 75 \u03a9 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 48 \u03a9 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. 25 \u03a9 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 60 \u03a9<\/p>\n H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0111\u00e1p \u00e1n<\/b><\/p>\n C\u00e2u 1:<\/b>\u00a0D<\/p>\n <\/p>\n C\u00e2u 2:<\/b>\u00a0C<\/p>\n <\/p>\n C\u00e2u 3:<\/b>\u00a0B<\/p>\n <\/p>\n C\u00e2u 4:<\/b>\u00a0A<\/p>\n <\/p>\n C\u00e2u 5:<\/b>\u00a0D<\/p>\n <\/p>\n C\u00e2u 6:<\/b>\u00a0A<\/p>\n <\/p>\n C\u00e2u 7:<\/b>\u00a0B<\/p>\n <\/p>\n C\u00e2u 8:<\/b>\u00a0C<\/p>\n <\/p>\n C\u00e2u 9:<\/b>\u00a0D<\/p>\n <\/p>\n","protected":false},"excerpt":{"rendered":" C\u00e2u 1:\u00a0Ch\u1ecdn ph\u00e1t bi\u1ec3u \u0111\u00fang. A. C\u00f3 hai cu\u1ed9n day m\u1eafc n\u1ed1i ti\u1ebfp, cu\u1ed9n d\u00e2y n\u00e0o c\u00f3 h\u1ec7 s\u1ed1 c\u00f4ng su\u1ea5t l\u1edbn h\u01a1n th\u00ec c\u00f4ng su\u1ea5t s\u1ebd l\u1edbn h\u01a1n. B. H\u1ec7 s\u1ed1 c\u00f4ng su\u1ea5t c\u1ee7a \u0111o\u1ea1n m\u1ea1ch cos\u03c6=0,5 ch\u1ee9ng t\u1ecf c\u01b0\u1eddng \u0111\u1ed9 d\u00f2ng \u0111i\u1ec7n trong m\u1ea1ch tr\u1ec5 pha \u03c0\/3 so v\u1edbi \u0111i\u1ec7n \u00e1p gi\u1eefa hai […]<\/p>\n","protected":false},"author":3,"featured_media":25982,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[158],"tags":[1443,1442],"yoast_head":"\n\n\n
\n C\u00e2u<\/td>\n 1<\/td>\n 2<\/td>\n 3<\/td>\n 4<\/td>\n 5<\/td>\n 6<\/td>\n 7<\/td>\n 8<\/td>\n 9<\/td>\n<\/tr>\n \n \u0110\u00e1p \u00e1n<\/td>\n D<\/td>\n C<\/td>\n B<\/td>\n A<\/td>\n D<\/td>\n A<\/td>\n B<\/td>\n C<\/td>\n D<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n