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{"id":25916,"date":"2018-04-09T17:43:26","date_gmt":"2018-04-09T10:43:26","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=25916"},"modified":"2018-04-09T17:43:26","modified_gmt":"2018-04-09T10:43:26","slug":"de-kiem-tra-hoc-ki-1-vat-li-12","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/de-kiem-tra-hoc-ki-1-vat-li-12\/","title":{"rendered":"\u0110\u1ec1 ki\u1ec3m tra h\u1ecdc k\u00ec 1 V\u1eadt L\u00ed 12"},"content":{"rendered":"

C\u00e2u 1:<\/b>\u00a0M\u1ea1ch \u0111i\u1ec7n xoay chi\u1ec1u g\u1ed5m R, L, C m\u1eafc n\u1ed1i ti\u1ebfp c\u00f3 h\u1ec7 s\u1ed1 c\u00f4ng su\u1ea5t b\u1eb1ng 1 khi<\/p>\n

\"\"<\/p>\n

C\u00e2u 2:<\/b>\u00a0T\u1ed1c \u0111\u1ed9 truy\u1ec1n s\u00f3ng \u00e2m l\u1edbn nh\u1ea5t trong m\u00f4i tr\u01b0\u1eddng<\/p>\n

A. Ch\u1ea5t r\u1eafn \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. Ch\u1ea5t l\u1ecfng<\/p>\n

C. Ch\u1ea5t khi \u1edf \u00e1p su\u1ea5t th\u1ea5p \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. Ch\u1ea5t kh\u00ed \u1edf \u00e1p su\u1ea5t cao<\/p>\n

C\u00e2u 3:<\/b>\u00a0Ph\u01b0\u01a1ng tr\u00ecnh n\u00e0o d\u01b0\u1edbi \u0111\u00e2y l\u00e0 ph\u01b0\u01a1ng tr\u00ecnh s\u00f3ng?<\/p>\n

\"\"<\/p>\n

C\u00e2u 4:<\/b>\u00a0S\u00f3ng ngang truy\u1ec1n \u0111\u01b0\u1ee3c trong c\u00e1c m\u00f4i tr\u01b0\u1eddng<\/p>\n

A. Ch\u1ea5t r\u1eafn \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. Ch\u1ea5t l\u1ecfng<\/p>\n

C. Ch\u1ea5t kh\u00ed \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. Ch\u1ea5t r\u1eafn, ch\u1ea5t l\u1ecfng v\u00e0 ch\u1ea5t kh\u00ed<\/p>\n

C\u00e2u 5:<\/b>\u00a0M\u1ed9t con l\u1eafc \u0111\u01a1n dao \u0111\u1ed9ng v\u1edbi bi\u00ean \u0111\u1ed9 nh\u1ecf. Kho\u1ea3ng th\u1eddi gian gi\u1eefa hai l\u1ea7n li\u00ean ti\u1ebfp qu\u1ea3 c\u1ea7u c\u1ee7a con l\u1eafc \u1edf v\u1ecb tr\u00ed cao nh\u1ea5t l\u00e0 1 s. Chu k\u00ec dao \u0111\u1ed9ng c\u1ee7a con l\u1eafc l\u00e0<\/p>\n

A. 1 s \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 0,5 s \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. 2 s \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 4 s<\/p>\n

\n
<\/div>\n<\/div>\n

C\u00e2u 6:<\/b>\u00a0M\u1ed9t ch\u1ea5t \u0111i\u1ec3m dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a theo ph\u01b0\u01a1lng tr\u00ecnh x = \u2013 4cos5\u03c0t (cm). Bi\u00ean \u0111\u1ed9, chu k\u00ec v\u00e0 pha ban \u0111\u1ea7u c\u1ee7a dao \u0111\u1ed9ng l\u1ea7n l\u01b0\u1ee3t l\u00e0<\/p>\n

A. \u2013 4 cm ; 0,4 s ; 0\u00a0 \u00a0 \u00a0 \u00a0 \u00a04 cm ; 0,4 s ; 0<\/p>\n

C. 4 cm ; 2,5 s ; \u03c0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 4 cm ; 0,4 s ; \u03c0<\/p>\n

C\u00e2u 7:<\/b>\u00a0M\u1ed9t con l\u1eafc l\u00f2 xo dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a. L\u00f2 xo c\u00f3 \u0111\u1ed9 c\u1ee9ng k = 40 N\/m. Khi qu\u1ea3 c\u1ea7u con l\u1eafc qua v\u1ecb tr\u00ed c\u00f3 li \u0111\u1ed9 x = \u2013 2 cm th\u00ec th\u1ebf n\u0103ng c\u1ee7a con l\u1eafc l\u00e0<\/p>\n

A. \u2013 0,016 J \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 0,008 J \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. \u2013 0,80 J \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 0,016 J<\/p>\n

C\u00e2u 8:<\/b>\u00a0M\u1ed9t con l\u1eafc l\u00f2 xo treo th\u1eb3ng \u0111\u1ee9ng. Qu\u1ea3 c\u1ea7u con l\u1eafc c\u00f3 kh\u1ed5i l\u01b0\u1ee3ng 100g. Khi c\u00e2n b\u1eb1ng, l\u00f2 xo d\u00e3n ra m\u1ed9t \u0111o\u1ea1n b\u1eb1ng 4 cm so v\u1edbi chi\u1ec1u d\u00e0i t\u1ef1 nhi\u00ean c\u1ee7a n\u00f3. Cho con l\u1eafc dao \u0111\u1ed9ng theo ph\u01b0\u01a1ng th\u1eb3ng \u0111\u1ee9ng. L\u1ea5y g=\u03c02<\/sup>\u00a0(m\/s2<\/sup>). Chu k\u00ec dao \u0111\u1ed9ng c\u1ec9a con l\u1eafc b\u1eb1ng<\/p>\n

A. 4 s \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 0,4 s \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. 0,07 s \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 1 s<\/p>\n

C\u00e2u 9:<\/b>\u00a0M\u1ed9t con l\u1eafc \u0111\u01a1n c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng m = 100 g v\u00e0 chi\u1ec1u d\u00e0i l = 1,4 m. Con l\u1eafc dao \u0111\u1ed9ng nh\u1ecf t\u1ea1i m\u1ed9t n\u01a1i c\u00f3 gia t\u1ed1c r\u01a1i t\u1ef1 do l\u00e0 g = 9,8 m\/s2<\/sup>. Chu k\u00ec dao \u0111\u1ed9ng c\u1ee7a con l\u1eafc b\u1eb1ng<\/p>\n

A. 2,37 s \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 16,6 s \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. 0,63 s \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 20 s<\/p>\n

C\u00e2u 10:<\/b>\u00a0Hai ngu\u1ed3n ph\u00e1t s\u00f3ng k\u1ebft h\u1ee3p l\u00e0 hai ngu\u1ed3n c\u00f3<\/p>\n

A. Pha dao \u0111\u1ed9ng b\u1eb1ng nhau.<\/p>\n

B. C\u00f9ng bi\u00ean \u0111\u1ed9 dao \u0111\u1ed9ng.<\/p>\n

C. C\u00f9ng t\u1ea7n s\u1ed1 giao \u0111\u1ed9ng<\/p>\n

D. C\u00f9ng t\u1ea7n s\u1ed1 dao \u0111\u1ed9ng v\u00e0 c\u00f3 hi\u1ec7u s\u1ed1 pha dao \u0111\u1ed9ng kh\u00f4ng \u0111\u1ed5i<\/p>\n

C\u00e2u 11:<\/b>\u00a0Hai ngu\u1ed3n ph\u00e1t s\u00f3ng c\u00f3 c\u00f9ng t\u1ea7n s\u1ed1, n\u1eb1m t\u1ea1i hai \u0111i\u1ec3m S1<\/sub>\u00a0v\u00e0 S2<\/sub>. T\u1ea1i c\u00e1c \u0111i\u1ec3m n\u1eb1m tr\u00ean \u0111\u01b0\u1eddng trung tr\u1ef1c c\u1ee7a S1<\/sub>S2<\/sub>\u00a0s\u1ebd lu\u00f4n lu\u00f4n c\u00f3 c\u1ef1c \u0111\u1ea1i giao thoa n\u1ebfu hi\u1ec7u s\u1ed1 pha dao \u0111\u1ed9ng c\u1ee7a hai ngu\u1ed3n b\u1eb1ng<\/p>\n

A. \u03c0\/2 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. \u03a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. 3\u03c0\/2 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 2\u03c0<\/p>\n

C\u00e2u 12:<\/b>\u00a0C\u00f3 hai ngu\u1ed3n ph\u00e1t s\u00f3ng k\u1ebft h\u1ee3p c\u00f9ng pha. T\u1ea1i \u0111i\u1ec3m M s\u1ebd c\u00f3 c\u1ef1c ti\u1ec3u giao thoa n\u1ebfu hi\u1ec7u \u0111\u01b0\u1eddng \u0111i t\u1eeb \u0111i\u1ec3m \u0111\u00f3 \u0111\u1ebfn hai ngu\u1ed3n b\u1eb1ng<\/p>\n

\"\"<\/p>\n

C\u00e2u 13:<\/b>\u00a0Khi n\u00f3i v\u1ec1 dao \u0111\u1ed9ng c\u01a1 c\u01b0\u1ee1ng b\u1ee9c, ph\u00e1t bi\u1ec3u n\u00e0o sau \u0111\u00e2y l\u00e0 sai?<\/p>\n

A. T\u1ea7n s\u1ed1 c\u1ee7a dao \u0111\u1ed9ng c\u01b0\u1ee1ng b\u1ee9c b\u1eb1ng t\u1ea7n s\u1ed1 c\u1ee7a l\u1ef1c c\u01b0\u1ee1ng b\u1ee9c<\/p>\n

B. Bi\u00ean \u0111\u1ed9 c\u1ee7a dao \u0111\u1ed9ng c\u01b0\u1ee1ng b\u1ee9c ph\u1ee5 thu\u1ed9c v\u00e0o bi\u00ean \u0111\u1ed9 c\u1ee7a l\u1ef1c c\u01b0\u1ee1ng b\u1ee9c<\/p>\n

C. Bi\u00ean \u0111\u1ecd c\u1ee7a dao \u0111\u1ed9ng c\u01b0\u1ee1ng b\u1ee9c c\u00e0ng l\u1edbn khi t\u1ea7n s\u1ed1 c\u1ee7a l\u1ef1c c\u01b0\u1ee1ng b\u1ee9c c\u00e0ng g\u1ea7n t\u1ea7n s\u1ed1 ri\u00eang c\u1ee7a h\u1ec7 dao \u0111\u1ed9ng<\/p>\n

D. T\u1ea7n s\u1ed1 c\u1ee7a dao \u0111\u1ed9ng c\u01b0\u1ee1ng b\u1ee9c l\u1edbn h\u01a1n t\u1ea7n s\u1ed1 c\u1ee7a l\u1ef1c c\u01b0\u1ee1ng b\u1ee9c<\/p>\n

C\u00e2u 14:<\/b>\u00a0M\u1ed9t s\u00f3ng c\u01a1 truy\u1ec1n d\u1ecdc theo tr\u1ee5c Ox c\u00f3 ph\u01b0\u01a1ng tr\u00ecnh u = 5cos(6\u03c0t \u2013 \u03c0x) (cm), v\u1edbi t \u0111o b\u1eb1ng s, x \u0111o b\u1eb1ng m. T\u1ed1c \u0111\u1ed9 truy\u1ec1n s\u00f3ng l\u00e0<\/p>\n

A. 3 m\/s \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 60 m\/s \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. 6 m\/s \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 30 m\/s<\/p>\n

C\u00e2u 15:<\/b><\/p>\n

\"\"<\/p>\n

A. 0,50 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 0,71 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. 1,00 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 0,86<\/p>\n

C\u00e2u 16:<\/b>\u00a0M\u1ed9t s\u00f3ng \u00e2m truy\u1ec1n trong m\u1ed9t m\u00f4i tr\u01b0\u1eddng. Bi\u1ebft c\u01b0\u1eddng \u0111\u1ed9 \u00e2m t\u1ea1i m\u1ed9t \u0111i\u1ec3m g\u1ea5p 100 l\u1ea7n c\u01b0\u1eddng \u0111\u1ed9 \u00e2m chu\u1ea9n. M\u1ee9c c\u01b0\u1eddng \u0111\u1ed9 \u00e2m t\u1ea1i \u0111i\u1ec3m \u0111\u00f3 l\u00e0<\/p>\n

A. 50 dB \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 20 dB \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. 100 dB \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 10 dB<\/p>\n

C\u00e2u 17:<\/b>\u00a0M\u1ed9t con l\u1eafc l\u00f2 xo g\u1ed3m v\u1eadt nh\u1ecf g\u1eafn v\u1edbi l\u00f2 xo nh\u1eb9 dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a theo ph\u01b0\u01a1ng ngang. L\u1ef1c k\u00e9o v\u1ec1 t\u00e1c d\u1ee5ng v\u00e0o v\u1eadt lu\u00f4n<\/p>\n

A. C\u00f9ng chi\u1ec1u v\u1edbi chi\u1ec1u chuy\u1ec3n \u0111\u1ed9ng c\u1ee7a v\u1eadt<\/p>\n

B. H\u01b0\u1edbng v\u1ec1 v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng<\/p>\n

C. C\u00f9ng chi\u1ec1u v\u1edbi chi\u1ec1u bi\u1ebfn d\u1ea1ng c\u1ee7a l\u00f2 xo<\/p>\n

D. H\u01b0\u1edbng v\u1ec1 v\u1ecb tr\u00ed bi\u00ean<\/p>\n

C\u00e2u 18:<\/b>\u00a0S\u00f3ng truy\u1ec1n tr\u00ean m\u1ed9t s\u1ee3i d\u00e2y c\u00f3 m\u1ed9t \u0111\u1ea7u c\u1ed1 \u0111\u1ecbnh, m\u1ed9t \u0111\u1ea7u t\u1ef1 do. Mu\u1ed1n c\u00f3 s\u00f3ng d\u1eebng tr\u00ean d\u00e2y th\u00ec chi\u1ec1u d\u00e0i c\u1ee7a s\u1ee3i d\u00e2y ph\u1ea3i b\u1eb1ng<\/p>\n

A. M\u1ed9t s\u1ed1 ch\u1eb5n l\u1ea7n m\u1ed9t ph\u1ea7n t\u01b0 b\u01b0\u1edbc s\u00f3ng<\/p>\n

B. M\u1ed9t s\u1ed1 l\u1ebb l\u1ea7n n\u1eeda b\u01b0\u1edbc s\u00f3ng<\/p>\n

C. M\u1ed9t s\u1ed1 l\u1ebb l\u1ea7n m\u1ed9t ph\u1ea7n t\u01b0 b\u01b0\u1edbc s\u00f3ng<\/p>\n

D. M\u1ed9t s\u1ed1 nguy\u00ean l\u1ea7n b\u01b0\u1edbc s\u00f3ng<\/p>\n

C\u00e2u 19:<\/b>\u00a0\u0110\u1eb7t \u0111i\u1ec7n \u00e1p u=100cos100\u03c0t (V) v\u00e0o hai \u0111\u1ea7u cu\u1ed9n c\u1ea3m thu\u1ea7n c\u00f3 \u0111\u1ed9 t\u1ef1 c\u1ea3m 1\/2\u03c0 (H). Bi\u1ec3u th\u1ee9c c\u1ee7a c\u01b0\u1eddng \u0111\u1ed9 d\u00f2ng \u0111i\u1ec7n qua cu\u1ed9n c\u1ea3m l\u00e0<\/p>\n

\"\"<\/p>\n

C\u00e2u 20:<\/b>\u00a0\u0110\u1eb7t \u0111i\u1ec7n \u00e1p xoay chi\u1ec1u u=Uo<\/sub>cos100\u03c0t (V) v\u00e0o hai \u0111\u1ea7u \u0111\u1ecdna m\u1ea1ch AB m\u1eafc n\u1ed1i ti\u1ebfp g\u1ed3m \u0111i\u1ec7n tr\u1edf thu\u1ea7n 100 \u03a9, t\u1ee5 \u0111i\u1ec7n c\u00f3 \u0111i\u1ec7n dung 10-4<\/sup>\/\u03c0 (F) v\u00e0 cu\u1ed9n c\u1ea3m thu\u1ea7n c\u00f3 \u0111\u1ed9 t\u1ef1 c\u1ea3m thay \u0111\u1ed5i \u0111\u01b0\u1ee3c. \u0111\u1ec3 \u0111i\u1ec7n \u00e1p gi\u1eefa hai \u0111\u1ea7u \u0111i\u1ec7n tr\u1edf tr\u1ec5 pha \u03c0\/4 so v\u1edbi \u0111i\u1ec7n \u00e1p gi\u1eefa hai \u0111\u1ea7u \u0111o\u1ea1n m\u1ea1ch AB th\u00ec \u0111\u1ed9 t\u1ef1 c\u1ea3m c\u1ee7a cu\u1ed9n c\u1ea3m b\u1eb1ng<\/p>\n

\"\"<\/p>\n

C\u00e2u 21:<\/b>\u00a0R\u00f4to c\u1ee7a m\u1ed9t m\u00e1y ph\u00e1t \u0111i\u1ec7n xoay chi\u1ec1u m\u1ed9t pha l\u00e0 nam ch\u00e2m c\u00f3 b\u1ed1n c\u1eb7p c\u1ef1c (4 c\u1ef1c t\u1eeb Nam v\u00e0 4 c\u1ef1c t\u1eeb B\u1eafc). Khi r\u00f4to quay v\u1edbi t\u1ed1c \u0111\u1ed9 900 v\u00f2ng\/ph\u00fat th\u00ec su\u1ea5t \u0111i\u1ec7n \u0111\u1ed9ng do m\u00e1y t\u1ea1o ra c\u00f3 t\u1ea7n s\u1ed1 l\u00e0<\/p>\n

A. 60 Hz \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 100 Hz \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. 120 Hz \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 50 Hz<\/p>\n

C\u00e2u 22:<\/b>\u00a0Tr\u00ean m\u1eb7t n\u01b0\u1edbc c\u00f3 hai ngu\u1ed3n k\u1ebft h\u1ee3p A, B dao \u0111\u1ed9ng theo ph\u01b0\u01a1ng th\u1eb3ng \u0111\u1ee9ng v\u1edbi ph\u01b0\u01a1ng tr\u00ecnh uA<\/sub>= uB<\/sub>=2cos20\u03c0t (nm). T\u1ed1c \u0111\u1ed9 truy\u1ec1n s\u00f3ng l\u00e0 30 m\/s. Coi bi\u00ean \u0111\u1ed9 s\u00f3ng kh\u00f4ng \u0111\u1ed5i trong qu\u00e1 tr\u00ecnh truy\u1ec1n s\u00f3ng. Ph\u1ea7n t\u1eed M \u1edf m\u1eb7t n\u01b0\u1edbc c\u00e1ch hai ngu\u1ed3n l\u1ea7n l\u01b0\u1ee3t l\u00e0 10,5 cm v\u00e0 13,5 cm c\u00f3 bi\u00ean \u0111\u1ed9 dao \u0111\u1ed9ng l\u00e0<\/p>\n

A. 4 mm \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 2 mm \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. 1 mm \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 0<\/p>\n

C\u00e2u 23:<\/b>\u00a0M\u1ed9t ch\u1ea5t \u0111i\u1ec3m dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a theo tr\u1ee5c Ox v\u1edbi ph\u01b0\u01a1ng tr\u00ecnh x = 10cos2\u03c0t (cm). Qu\u00e3ng \u0111\u01b0\u1eddng \u0111i \u0111\u01b0\u1ee3c c\u1ee7a ch\u1ea5t \u0111i\u1ec3m trong m\u1ed9t chu k\u00ec dao \u0111\u1ed9ng l\u00e0<\/p>\n

A. 10 cm \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 30 cm \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. 40 cm \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 20 cm<\/p>\n

C\u00e2u 24:<\/b>\u00a0Cu\u1ed9n s\u01a1 c\u1ea5o v\u00e0 cu\u1ed9n th\u1ee9 c\u1ea5p c\u1ee7a m\u1ed9t m\u00e1y bi\u1ebfn \u00e1p l\u00ed t\u01b0\u1edfng c\u00f3 s\u1ed1 v\u00f2ng d\u00e2y l\u1ea7n l\u01b0\u1ee3t l\u00e0 N1<\/sub>\u00a0v\u00e0 N2<\/sub>. Bi\u1ebft N1<\/sub>=10N2<\/sub>. \u0110\u1eb7t v\u00e0o hai \u0111\u1ea7u cu\u1ed9n s\u01a1 c\u1ea5p m\u1ed9t \u0111i\u1ec7n \u00e1p xoay chi\u1ec1u u=Uo<\/sub>cos\u03c9t th\u00ec \u0111i\u1ec7n \u00e1p hi\u1ec7u d\u1ee5ng gi\u1eefa hai \u0111\u1ea7u cu\u1ed9n th\u1ee9 c\u1ea5p \u0111\u1ec3 h\u1edf l\u00e0<\/p>\n

\"\"<\/p>\n

C\u00e2u 25:<\/b>\u00a0T\u1ea1i c\u00f9ng m\u1ed9t n\u01a1i tr\u00ean Tr\u00e1i \u0110\u1ea5t, con l\u1eafc \u0111\u01a1n c\u00f3 chi\u1ec1u d\u00e0i l dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a v\u1edbi chu k\u00ec 2 s, con l\u1eafc \u0111\u01a1n c\u00f3 chi\u1ec1u d\u00e0i 2l dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a v\u1edbi chu k\u00ec l\u00e0<\/p>\n

A. 2 s \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 2\u221a2 s \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. \u221a2 s \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 4 s<\/p>\n

C\u00e2u 26:<\/b>\u00a0Ph\u00e1t bi\u1ec3u n\u00e0o sau \u0111\u00e2y l\u00e0 sai khi n\u00f3i v\u1ec1 \u0111o\u1ea1n m\u1ea1ch \u0111i\u1ec7n xoay chi\u1ec1u ch\u1ec9 c\u00f3 t\u1ee5 \u0111i\u1ec7n?<\/p>\n

A. H\u1ec7 s\u1ed1 c\u00f4ng su\u1ea5t c\u1ee7a \u0111o\u1ea1n m\u1ea1ch b\u1eb1ng 0<\/p>\n

B. C\u00f4ng su\u1ea5t ti\u00eau th\u1ee5 c\u1ee7a \u0111o\u1ea1n m\u1ea1ch kh\u00e1c 0<\/p>\n

C. T\u1ea7n s\u1ed1 g\u00f3c c\u1ee7a d\u00f2ng \u0111i\u1ec7n c\u00e0ng l\u1edbn th\u00ec dung kh\u00e1ng c\u1ee7a \u0111o\u1ea1n m\u1ea1ch c\u00e0ng nh\u1ecf<\/p>\n

D. \u0110i\u1ec7n \u00e1p gi\u1eefa hai b\u1ea3n t\u1ef1 \u0111i\u1ec7n tr\u1ec5 pha \u03c0\/2 so v\u1edbi c\u01b0\u1eddng \u0111\u1ed9 d\u00f2ng \u0111i\u1ec7n qua \u0111o\u1ea1n m\u1ea1ch<\/p>\n

C\u00e2u 27:<\/b>\u00a0\u0110\u1eb7t \u0111i\u1ec7n \u00e1p xoay chi\u1ec1u u=200\u221a2 cos100\u03c0t (V) v\u00e0o hai \u0111\u1ea7u m\u1ed9t \u0111o\u1ea1n m\u1ea1ch AB g\u1ed3m \u0111i\u1ec7n tr\u1edf thu\u1ea7n 100 \u03a9, cu\u1ed9n c\u1ea3m thu\u1ea7n v\u00e0 t\u1ee5 \u0111i\u1ec7n m\u1eafc n\u1ed1i ti\u1ebfp. Khi \u0111\u00f3, \u0111i\u1ec7n \u00e1p hai \u0111\u1ea7u t\u1ee5 \u0111i\u1ec7n l\u00e0<\/p>\n

\"\"<\/p>\n

C\u00f4ng su\u1ea5t ti\u00eau th\u1ee5 c\u1ee7a \u0111o\u1ea1n m\u1ea1ch AB b\u1eb1ng<\/p>\n

A. 200 W \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 100 W \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. 400 W \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 300 W<\/p>\n

C\u00e2u 28:<\/b>\u00a0Cho hai dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a c\u00f9ng ph\u01b0\u01a1ng c\u00f3 ph\u01b0\u01a1ng tr\u00ecnh l\u1ea7n l\u01b0\u1ee3t l\u00e0 x1<\/sub>=A1<\/sub>cos\u03c9t v\u00e0 x2<\/sub>=A2<\/sub>cos(\u03c9t+\u03c0\/2). Bi\u00ean \u0111\u1ed9 dao \u0111\u1ed9ng t\u1ed5ng h\u1ee3p c\u1ee7a hai dao \u0111\u1ed9ng n\u00e0y l\u00e0<\/p>\n

\"\"<\/p>\n

C\u00e2u 29:<\/b>\u00a0M\u1ed9t con l\u1eafc l\u00f2 xo g\u1ed3m m\u1ed9t v\u1eadt nh\u1ecf kh\u1ed1i l\u01b0\u1ee3ng 100 g g\u1eafn v\u1edbi m\u1ed9t l\u00f2 xo nh\u1eb9. Con l\u1eafc dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a theo ph\u01b0\u01a1ng ngang v\u1edbi ph\u01b0\u01a1ng tr\u00ecnh x = 10 cos10\u03c0t (cm). M\u1ed1c th\u1ebf n\u0103ng \u1edf v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng. L\u1ea5y \u03c02<\/sup>=10. C\u01a1 n\u0103ng c\u1ee7a con l\u1eafc b\u1eb1ng<\/p>\n

A. 0,10 J \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 0,05 J \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. 1,00 J \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 0,50 J<\/p>\n

C\u00e2u 30:<\/b>\u00a0M\u1ed9t con l\u1eafc l\u00f2 xo g\u1ed3m m\u1ed9t v\u1eadt nh\u1ecf c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng 200 g v\u00e0 m\u1ed9t l\u00f2 xo nh\u1eb9 c\u00f3 \u0111\u1ed9 c\u1ee9ng 80 N\/m. Con l\u1eafc dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a theo ph\u01b0\u01a1ng n\u1eb1m ngang v\u1edbi bi\u00ean \u0111\u1ed9 4 cm. \u0110\u1ed9 l\u1edbn v\u1eadn t\u1ed1c c\u1ee7a v\u1eadt khi v\u1eadt \u1edf v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng l\u00e0<\/p>\n

A. 100 cm\/s \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 40 cm\/s<\/p>\n

C. 80 cm\/s \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 60 cm\/s<\/p>\n

 <\/p>\n","protected":false},"excerpt":{"rendered":"

C\u00e2u 1:\u00a0M\u1ea1ch \u0111i\u1ec7n xoay chi\u1ec1u g\u1ed5m R, L, C m\u1eafc n\u1ed1i ti\u1ebfp c\u00f3 h\u1ec7 s\u1ed1 c\u00f4ng su\u1ea5t b\u1eb1ng 1 khi C\u00e2u 2:\u00a0T\u1ed1c \u0111\u1ed9 truy\u1ec1n s\u00f3ng \u00e2m l\u1edbn nh\u1ea5t trong m\u00f4i tr\u01b0\u1eddng A. Ch\u1ea5t r\u1eafn \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. Ch\u1ea5t l\u1ecfng C. Ch\u1ea5t khi \u1edf \u00e1p su\u1ea5t th\u1ea5p \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. Ch\u1ea5t kh\u00ed \u1edf \u00e1p su\u1ea5t cao C\u00e2u […]<\/p>\n","protected":false},"author":3,"featured_media":25917,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[158],"tags":[1443,1442],"yoast_head":"\n\u0110\u1ec1 ki\u1ec3m tra h\u1ecdc k\u00ec 1 V\u1eadt L\u00ed 12<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/de-kiem-tra-hoc-ki-1-vat-li-12\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"\u0110\u1ec1 ki\u1ec3m tra h\u1ecdc k\u00ec 1 V\u1eadt L\u00ed 12\" \/>\n<meta property=\"og:description\" content=\"C\u00e2u 1:\u00a0M\u1ea1ch \u0111i\u1ec7n xoay chi\u1ec1u g\u1ed5m R, L, C m\u1eafc n\u1ed1i ti\u1ebfp c\u00f3 h\u1ec7 s\u1ed1 c\u00f4ng su\u1ea5t b\u1eb1ng 1 khi C\u00e2u 2:\u00a0T\u1ed1c \u0111\u1ed9 truy\u1ec1n s\u00f3ng \u00e2m l\u1edbn nh\u1ea5t trong m\u00f4i tr\u01b0\u1eddng A. Ch\u1ea5t r\u1eafn \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. Ch\u1ea5t l\u1ecfng C. Ch\u1ea5t khi \u1edf \u00e1p su\u1ea5t th\u1ea5p \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 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