C\u00e2u 9:<\/b>\u00a0T\u00ednh ch\u1ea5t gi\u1ed1ng nhau gi\u1eefa tia R\u01a1n \u2013 ghen v\u00e0 tia t\u1eed ngo\u1ea1i l\u00e0<\/p>\n

A. b\u1ecb h\u1ea5p th\u1ee5 b\u1edfi th\u1ee7y tinh v\u00e0 n\u01b0\u1edbc<\/p>\n

B. l\u00e0m ph\u00e1t quang m\u1ed9t s\u1ed1 ch\u1ea5t<\/p>\n

C. c\u00f3 t\u00ednh \u0111\u00e2m xuy\u00ean m\u1ea1nh<\/p>\n

D. \u0111\u1ec1u b\u1ecb l\u1ec7ch trong \u0111i\u1ec7n tr\u01b0\u1eddng<\/p>\n

C\u00e2u 10:<\/b>\u00a0Trong b\u1ed1n lo\u1ea1i tia d\u01b0\u1edbi \u0111\u00e2y, tia n\u00e0o x\u1ebfp th\u1ee9 hai v\u1ec1 kh\u1ea3 n\u0103ng \u0111\u00e2m xuy\u00ean?<\/p>\n

A. Tia gamma \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. Tia h\u1ed3ng ngo\u1ea1i<\/p>\n

C. Tia R\u01a1n \u2013 ghen \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. Tia t\u1eed ngo\u1ea1i<\/p>\n

C\u00e2u 11:<\/b>\u00a0T\u00ecm ph\u00e1t bi\u1ec3u sai<\/p>\n

C\u00e1c b\u1ee9c x\u1ea1 \u0111i\u1ec7n t\u1eeb c\u00f3 b\u01b0\u1edbc s\u00f3ng t\u1eeb 5.10^{-7<\/sup>\u00a0m \u0111\u1ebfn 10-9<\/sup>\u00a0m \u0111\u1ec1u c\u00f3 t\u00ednh ch\u1ea5t chung l\u00e0<\/p>\n}

A. c\u00f3 t\u00e1c d\u1ee5ng l\u00ean k\u00ednh \u1ea3nh<\/p>\n

B. kh\u00f4ng nh\u00ecn th\u1ea5y<\/p>\n

C. c\u00f3 t\u00e1c d\u1ee5ng sinh h\u1ecdc<\/p>\n

D. c\u00f3 kh\u1ea3 n\u0103ng g\u00e2y hi\u1ec7u \u1ee9ng quang \u0111i\u1ec7n<\/p>\n

C\u00e2u 12:<\/b>\u00a0Tia X v\u00e0 tia t\u1eed ngo\u1ea1i kh\u00f4ng c\u00f3 chung t\u00ednh ch\u1ea5t n\u00e0o sau \u0111\u00e2y?<\/p>\n

A. kh\u00f4ng mang \u0111i\u1ec7n \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0B. c\u00f3 kh\u1ea3 n\u0103ng sinh l\u00ed<\/p>\n

C. t\u00e1c d\u1ee5ng m\u1ea1nh l\u00ean kinh \u1ea3nh \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. b\u1ecb n\u01b0\u1edbc h\u1ea5p th\u1ee5 m\u1ea1nh<\/p>\n

C\u00e2u 13:<\/b>\u00a0M\u1ed9t b\u1ee9c x\u1ea1 trong kh\u00f4ng kh\u00ed c\u00f3 b\u01b0\u1edbc s\u00f3ng \u03bb = 0,48 \u03bcm. Khi b\u1ee9c xja n\u00e0y chi\u1ebfu v\u00e0o trong n\u01b0\u1edbc c\u00f3 chi\u1ebft su\u1ea5t n = 1,5 th\u00ec b\u01b0\u1edbc s\u00f3ng c\u1ee7a n\u00f3 l\u00e0<\/p>\n

A. 0,48 \u03bcm \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 0,36 \u03bcm<\/p>\n

C. 0,32 \u03bcm \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 0,72 \u03bcm<\/p>\n

C\u00e2u 14:<\/b>\u00a0Cho l\u0103ng k\u00ednh th\u1ee7y tinh c\u00f3 g\u00f3c chi\u1ebft quang A=6\u00b0. Chi\u1ebft su\u1ea5t c\u1ee7a l\u0103ng k\u00ednh ph\u1ee5 thu\u1ed9c v\u00e0o v\u00e0o b\u01b0\u1edbc s\u00f3ng \u03bb theo c\u00f4ng th\u1ee9c n=1,620+0,2\/\u03bb^{2<\/sup>\u00a0v\u1edbi \u03bb t\u00ednh ra \u03bcm. Chi\u1ebfu ch\u00f9m s\u00e1ng g\u1ed3m hai b\u1ee9c x\u1ea1 c\u00f3 b\u01b0\u1edbc s\u00f3ng \u03bb_{1<\/sub>\u00a0= 0,43 \u03bcm v\u00e0 \u03bb2<\/sub>\u00a0= 0,46 \u03bcm t\u1edbi l\u0103ng k\u00ednh tr\u00ean v\u1edbi g\u00f3c t\u1edbi nh\u1ecf. G\u00f3c l\u1ec7ch gi\u1eefa hai tia l\u00f3 l\u00e0<\/p>\n}}

A. 0,68\u00b0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 0,82\u00b0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. 0,14\u00b0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 2,1\u00b0<\/p>\n

C\u00e2u 15:<\/b>\u00a0Tr\u00ean \u0111o\u1ea1n th\u1eb3ng d\u00e0i 9,6 mm n\u1eb1m vu\u00f4ng g\u00f3c v\u1edbi c\u00e1c v\u00e2n s\u00e1ng tr\u00ean m\u00e0n \u1ea3nh c\u1ee7a m\u1ed9t th\u00ed nghi\u1ec7m Y \u2013 \u00e2ng c\u00f3 13 v\u00e2n s\u00e1ng, trong \u0111\u00f3 c\u00f3 2 v\u00e2n s\u00e1ng \u1edf hai \u0111\u1ea7u. Ngu\u1ed3n ph\u00e1t \u00e1nh s\u00e1ng c\u00f3 b\u01b0\u1edbc s\u00f3ng 0,6 \u03bcm. T\u1ec9 s\u1ed1 c\u00e1c kho\u1ea3ng c\u00e1ch a\/D trong th\u00ed nghi\u1ec7m n\u00e0y l\u00e0<\/p>\n

A. 2,5.10^{-3<\/sup>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 7,5.10-4<\/sup><\/p>\n}

C. 4,5.10^{-4<\/sup>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 1,3.10-4<\/sup><\/p>\n}

H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0111\u00e1p \u00e1n<\/b><\/p>\n\n\n\n\n

C\u00e2u<\/td>\n	9<\/td>\n	10<\/td>\n	11<\/td>\n	12<\/td>\n	13<\/td>\n	14<\/td>\n	15<\/td>\n<\/tr>\n
\u0110\u00e1p \u00e1n<\/td>\n	B<\/td>\n	C<\/td>\n	B<\/td>\n	D<\/td>\n	C<\/td>\n	B<\/td>\n	B<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n C\u00e2u 11:<\/b>\u00a0B<\/p>\n C\u00e1c b\u1ee9c x\u1ea1 c\u00f3 b\u01b0\u1edbc s\u00f3ng t\u1eeb 5.10-7<\/sup>m \u0111\u1ebfn 10-9<\/sup>m bao g\u1ed3m c\u1ea3 \u00e1nh s\u00e1ng nh\u00ecn th\u1ea5y, \u0111\u00f3 l\u00e0 b\u1ee9c x\u1ea1 nh\u00ecn th\u1ea5y \u0111\u01b0\u1ee3c<\/p>\n C\u00e2u 14:<\/b>\u00a0B<\/p>\n M\u1ed7i tia qua l\u0103ng k\u00ednh b\u1ecb l\u1ec7ch D = A(n \u2013 1) n\u00ean g\u00f3c t\u1ea1o b\u1edfi hai tia l\u00f3 l\u00e0<\/p>\n <\/p>\n C\u00e2u 15:<\/b>\u00a0B<\/p>\n Kho\u1ea3ng v\u00e2n l\u00e0:<\/p>\n <\/p>\n","protected":false},"excerpt":{"rendered":" C\u00e2u 9:\u00a0T\u00ednh ch\u1ea5t gi\u1ed1ng nhau gi\u1eefa tia R\u01a1n \u2013 ghen v\u00e0 tia t\u1eed ngo\u1ea1i l\u00e0 A. b\u1ecb h\u1ea5p th\u1ee5 b\u1edfi th\u1ee7y tinh v\u00e0 n\u01b0\u1edbc B. l\u00e0m ph\u00e1t quang m\u1ed9t s\u1ed1 ch\u1ea5t C. c\u00f3 t\u00ednh \u0111\u00e2m xuy\u00ean m\u1ea1nh D. \u0111\u1ec1u b\u1ecb l\u1ec7ch trong \u0111i\u1ec7n tr\u01b0\u1eddng C\u00e2u 10:\u00a0Trong b\u1ed1n lo\u1ea1i tia d\u01b0\u1edbi \u0111\u00e2y, tia n\u00e0o x\u1ebfp th\u1ee9 […]<\/p>\n","protected":false},"author":3,"featured_media":25813,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[158],"tags":[1443,1442],"yoast_head":"\n