C\u00e2u 8:<\/b>\u00a0D\u1ee5ng c\u1ee5 n\u00e0o sau \u0111\u00e2y c\u00f3 nguy\u00ean t\u1eafc ho\u1ea1t \u0111\u1ed9ng d\u1ef1a v\u00e0o hi\u1ec7n t\u01b0\u1ee3ng quang \u0111i\u1ec7n trong?<\/p>\n

A. T\u1ebf b\u00e0o quang \u0111i\u1ec7n<\/p>\n

B. M\u00e1y quang ph\u1ed5<\/p>\n

C. \u0110i\u00f4t ph\u00e1t quang<\/p>\n

D. Quang \u0111i\u1ec7n tr\u1edf<\/p>\n

C\u00e2u 9:<\/b>\u00a0T\u00ecm ph\u00e1t bi\u1ec3u sai<\/p>\n

A. Hi\u1ec7n t\u01b0\u1ee3ng giao thoa \u00e1nh s\u00e1ng ch\u1ee9ng t\u1ecf \u00e1nh s\u00e1ng c\u00f3 t\u00ednh ch\u1ea5t s\u00f3ng<\/p>\n

B. Hi\u1ec7n t\u01b0\u1ee3ng quang \u0111i\u1ec7n ch\u1ee9ng t\u1ecf \u00e1nh s\u00e1ng c\u00f3 t\u00ednh ch\u1ea5t h\u1ea1t<\/p>\n

C. Photon \u00e1nh s\u00e1ng kh\u00f4ng th\u1ec3 hi\u1ec7n t\u00ednh ch\u1ea5t s\u00f3ng khi truy\u1ec1n trong ch\u00e2n kh\u00f4ng<\/p>\n

D. Photon \u00e1nh s\u00e1ng lu\u00f4n mang \u0111\u1ed3ng th\u1eddi c\u1ea3 t\u00ednh ch\u1ea5t s\u00f3ng v\u00e0 t\u00ednh ch\u1ea5t h\u1ea1t<\/p>\n

C\u00e2u 10:<\/b>\u00a0M\u1ed9t qu\u1ea3 c\u1ea7u kim lo\u1ea1i \u0111\u01b0\u1ee3c \u0111\u1eb7t c\u00f4 l\u1ea5p v\u1ec1 \u0111i\u1ec7n v\u00e0 c\u00e1ch xa c\u00e1c v\u1eadt d\u1eabn kh\u00e1c. Chi\u1ebfu l\u1ea7n l\u01b0\u1ee3t v\u00e0o qu\u1ea3 c\u1ea7u hai b\u1ee9c x\u1ea1 c\u00f3 b\u01b0\u1edbc s\u00f3ng \u03bb_{1<\/sub>\u00a0v\u00e0 \u03bb2<\/sub>\u00a0(\u03bb1<\/sub>\u00a0< \u03bb2<\/sub>) th\u00ec \u0111\u1ec1u x\u1ea3y ra hi\u1ec7n t\u01b0\u1ee3ng quang \u0111i\u1ec7n v\u00e0 \u0111i\u1ec7n th\u1ebf c\u1ef1c \u0111\u1ea1i m\u00e0 qu\u1ea3 c\u1ea7u \u0111\u1ea1t \u0111\u01b0\u1ee3c t\u01b0\u01a1ng \u1ee9ng l\u00e0 V1<\/sub>,V2<\/sub>. N\u1ebfu chi\u1ebfu \u0111\u1ed3ng th\u1eddi hai b\u1ee9c x\u1ea1 \u0111i\u1ec7n t\u1eeb n\u00f3i tr\u00ean v\u00e0o qu\u1ea3 c\u1ea7u th\u00ec \u0111i\u1ec7n th\u1ebf c\u1ef1c \u0111\u1ea1i c\u1ee7a qu\u1ea3 c\u1ea7u l\u00e0<\/p>\n}

<\/p>\n

C\u00e2u 11:<\/b>\u00a0T\u1ed1c \u0111\u1ed9 c\u1ee7a \u00ealectron trong nguy\u00ean t\u1eed hi\u0111r\u00f4 tr\u00ean qu\u1ef9 \u0111\u1ea1o c\u00f3 s\u1ed1 l\u01b0\u1ee3ng t\u1eed n c\u00f3 gi\u00e1 tr\u1ecb<\/p>\n

A. T\u1ec9 l\u1ec7 thu\u1eadn v\u1edbi n<\/p>\n

B. T\u1ec9 l\u1ec7 ngh\u1ecbch v\u1edbi n<\/p>\n

C. T\u1ec9 l\u1ec7 thu\u1eadn v\u1edbi \u221an<\/p>\n

D. T\u1ec9 l\u1ec7 ngh\u1ecbch v\u1edbi \u221an<\/p>\n

C\u00e2u 12:<\/b>\u00a0M\u1ed9t quang \u00ealectron c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng m v\u00e0 \u0111i\u1ec7n t\u00edch \u2013 e, sau khi b\u1ee9t ra kh\u1ecfi b\u1ec1 m\u1eb7t kim lo\u1ea1i c\u00f3 t\u1ed1c \u0111\u1ed9 ban \u0111\u1ea7u c\u1ef1c \u0111\u1ea1i v_{o<\/sub>max, n\u00f3 bay th\u1eb3ng v\u00e0o t\u1eeb tr\u01b0\u1eddng \u0111\u1ec1u c\u00f3 c\u1ea3m \u1ee9ng t\u1eeb B, theo h\u01b0\u1edbng vu\u00f4ng g\u00f3c v\u1edbi \u0111\u01b0\u1eddng s\u1ee9c t\u1eeb. Qu\u1ef9 \u0111\u1ea1o c\u1ee7a \u00ealectron trong t\u1eeb tr\u01b0\u1eddng l\u00e0 \u0111\u01b0\u1eddng tr\u00f2n c\u00f3 b\u00e1n k\u00ednh<\/p>\n}

<\/p>\n

C\u00e2u 13:<\/b>\u00a0M\u1ed9t quang \u00ealectron khi bay v\u00e0o t\u1eeb tr\u01b0\u1eddng \u0111\u1ec1u c\u00f3 c\u1ea3m \u1ee9ng t\u1eeb B =10^{-4<\/sup>\u00a0theo ph\u01b0\u01a1ng vu\u00f4ng g\u00f3c v\u1edbi c\u00e1c \u0111\u01b0\u1eddng s\u1ee9c t\u1eeb c\u00f3 b\u00e1n k\u00ednh qu\u1ef9 \u0111\u1ea1o l\u00e0 23,32 cm. T\u1ed1c \u0111\u1ed9 c\u1ee7a \u00ealectron khi bay v\u00e0o t\u1eeb tr\u01b0\u1eddng l\u00e0<\/p>\n}

A. 4,1.10^{6<\/sup>\u00a0m\/s<\/p>\n}

B. 4,1.10^{5<\/sup>\u00a0m\/s<\/p>\n}

C. 4,1.10^{5<\/sup>\u00a0mm\/s<\/p>\n}

D. 6,2.10^{5<\/sup>\u00a0m\/s<\/p>\n}

C\u00e2u 14:<\/b>\u00a0Trong quang ph\u1ed5 c\u1ee7a nguy\u00ean t\u1eed hi\u0111r\u00f4, n\u1ebfu bi\u1ebft b\u01b0\u1edbc s\u00f3ng \u03bb_{21<\/sub>\u00a0c\u1ee7a b\u1ee9c x\u1ea1 ph\u00e1t ra \u1ee9ng v\u1edbi s\u1ef1 chuy\u1ec3n \u00ealectron t\u1eeb qu\u1ef9 \u0111\u1ea1o L sang qu\u1ef9 \u0111\u1ea1o K v\u00e0 b\u01b0\u1edbc s\u00f3ng \u03bb32<\/sub>\u00a0c\u1ee7a b\u1ee9c x\u1ea1 ph\u00e1t ra \u1ee9ng v\u1edbi s\u1ef1 chuy\u1ec3n \u00ealectron t\u1eeb qu\u1ef9 \u0111\u1ea1o M s\u00e1ng qu\u1ef9 \u0111\u1ea1o K s\u1ebd l\u00e0<\/p>\n}

<\/p>\n

H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0111\u00e1p \u00e1n<\/b><\/p>\n\n\n\n\n

C\u00e2u<\/td>\n	8<\/td>\n	9<\/td>\n	10<\/td>\n	11<\/td>\n	12<\/td>\n	13<\/td>\n	14<\/td>\n<\/tr>\n
\u0110\u00e1p \u00e1n<\/td>\n	D<\/td>\n	C<\/td>\n	C<\/td>\n	B<\/td>\n	A<\/td>\n	A<\/td>\n	C<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n C\u00e2u 11:<\/b><\/p>\n <\/p>\n C\u00e2u 12:<\/b><\/p>\n <\/p>\n C\u00e2u 13:<\/b><\/p>\n <\/p>\n","protected":false},"excerpt":{"rendered":" C\u00e2u 8:\u00a0D\u1ee5ng c\u1ee5 n\u00e0o sau \u0111\u00e2y c\u00f3 nguy\u00ean t\u1eafc ho\u1ea1t \u0111\u1ed9ng d\u1ef1a v\u00e0o hi\u1ec7n t\u01b0\u1ee3ng quang \u0111i\u1ec7n trong? A. T\u1ebf b\u00e0o quang \u0111i\u1ec7n B. M\u00e1y quang ph\u1ed5 C. \u0110i\u00f4t ph\u00e1t quang D. Quang \u0111i\u1ec7n tr\u1edf C\u00e2u 9:\u00a0T\u00ecm ph\u00e1t bi\u1ec3u sai A. Hi\u1ec7n t\u01b0\u1ee3ng giao thoa \u00e1nh s\u00e1ng ch\u1ee9ng t\u1ecf \u00e1nh s\u00e1ng c\u00f3 t\u00ednh ch\u1ea5t s\u00f3ng […]<\/p>\n","protected":false},"author":3,"featured_media":25775,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[158],"tags":[1443,1442],"yoast_head":"\n