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{"id":2575,"date":"2016-04-16T11:20:16","date_gmt":"2016-04-16T11:20:16","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=2575"},"modified":"2016-11-12T02:22:10","modified_gmt":"2016-11-12T02:22:10","slug":"nhung-cau-hoi-kho-trong-de-thi-hoa-2","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/nhung-cau-hoi-kho-trong-de-thi-hoa-2\/","title":{"rendered":"Nh\u1eefng c\u00e2u h\u1ecfi kh\u00f3 trong \u0111\u1ec1 thi H\u00f3a"},"content":{"rendered":"
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\u0110\u1ec1 thi THPT qu\u1ed1c gia H\u00f3a h\u1ecdc th\u01b0\u1eddng c\u00f3 50 c\u00e2u h\u1ecfi. M\u1ee9c \u0111\u1ed9 c\u00e2u h\u1ecfi s\u1ebd t\u0103ng d\u1ea7n t\u1eeb d\u1ec5 \u0111\u1ebfn kh\u00f3. Nh\u1eefng c\u00e2u h\u1ecfi kh\u00f3 th\u01b0\u1eddng l\u00e0 nh\u1eefng c\u00e2u \u0111\u1ec3 ph\u00e2n lo\u1ea1i th\u00ed sinh kh\u00e1 – gi\u1ecfi. D\u01b0\u1edbi \u0111\u00e2y l\u00e0 nh\u1eefng d\u1ea1ng c\u00e2u h\u1ecfi kh\u00f3 m\u00e0 th\u00ed sinh s\u1ebd g\u1eb7p trong \u0111\u1ec1 thi THPT qu\u1ed1c gia. M\u1eddi th\u00ed sinh th\u1eed s\u1ee9c!<\/h5>\n
1. <\/span><\/span>H\u1ed7n h\u1ee3p X g\u1ed3m 3 este \u0111\u01a1n ch\u1ee9c, t\u1ea1o th\u00e0nh t\u1eeb c\u00f9ng m\u1ed9t ancol Y v\u1edbi 3 axit cacboxylic (ph\u00e2n t\u1eed ch\u1ec9 c\u00f3 nh\u00f3m -COOH); trong \u0111\u00f3, c\u00f3 hai axit no l\u00e0 \u0111\u1ed3ng \u0111\u1eb3ng k\u1ebf ti\u1ebfp nhau v\u00e0 m\u1ed9t axit kh\u00f4ng no (c\u00f3 \u0111\u1ed3ng ph\u00e2n h\u00ecnh h\u1ecdc,ch\u1ee9a m\u1ed9t li\u00ean k\u1ebft \u0111\u00f4i C=C trong ph\u00e2n t\u1eed). Th\u1ee7y ph\u00e2n ho\u00e0n to\u00e0n 5,88gam X b\u1eb1ng dung d\u1ecbch NaOH, thu \u0111\u01b0\u1ee3c h\u1ed7n h\u1ee3p mu\u1ed1i v\u00e0 m gam ancol Y. Cho m gam Y v\u00e0o b\u00ecnh \u0111\u1ef1ng Na d\u01b0, sau ph\u1ea3n \u1ee9ng thu \u0111\u01b0\u1ee3c 896 ml kh\u00ed (\u0111ktc)v\u00e0 kh\u1ed1i l\u01b0\u1ee3ng b\u00ecnh t\u0103ng 2,48gam. M\u1eb7t kh\u00e1c, n\u1ebfu \u0111\u1ed1t ch\u00e1y ho\u00e0n to\u00e0n 5,88gam X th\u00ec thu \u0111\u01b0\u1ee3c CO2 v\u00e0 3,96 gam H2O. Ph\u1ea7n tr\u0103m kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a este kh\u00f4ng no trong X l\u00e0<\/b><\/h5>\n
<\/div>\n<\/div>\n
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    \n
  • \n

    A)<\/span>40,82%.<\/b><\/p>\n<\/li>\n

  • \n

    B)<\/span>29,25%.<\/b><\/p>\n<\/li>\n

  • \n

    C)<\/span>34,01%.<\/b><\/p>\n<\/li>\n

  • \n

    D)<\/span>38,76%.<\/b><\/p>\n<\/li>\n<\/ul>\n<\/div>\n<\/div>\n<\/div>\n

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    \n
    \n
    2. <\/span><\/span>Cho 7,65 gam h\u1ed7n h\u1ee3p X g\u1ed3m Al v\u00e0 Al2O3 (trong \u0111\u00f3 Al chi\u1ebfm 60% kh\u1ed1i l\u01b0\u1ee3ng) tan ho\u00e0n to\u00e0n trong dung d\u1ecbch Y g\u1ed3m H2SO4v\u00e0 NaNO3, thu \u0111\u01b0\u1ee3c dung d\u1ecbch Z ch\u1ec9 ch\u1ee9a 3 mu\u1ed1i trung h\u00f2a v\u00e0 m gam h\u1ed7n h\u1ee3p kh\u00ed T (trong T c\u00f3 0,015 mol H2). Cho dung d\u1ecbch BaCl2 d\u01b0 v\u00e0o Z \u0111\u1ebfn khi c\u00e1c ph\u1ea3n \u1ee9ng x\u1ea3y ra ho\u00e0n to\u00e0n, thu \u0111\u01b0\u1ee3c 93,2 gam k\u1ebft t\u1ee7a. C\u00f2n n\u1ebfu cho Z ph\u1ea3n \u1ee9ng v\u1edbi NaOH th\u00ec l\u01b0\u1ee3ng NaOH ph\u1ea3n \u1ee9ng t\u1ed1i \u0111a l\u00e0 0,935 mol. Gi\u00e1 tr\u1ecb c\u1ee7a m g\u1ea7n gi\u00e1 tr\u1ecb n\u00e0o nh\u1ea5t sau \u0111\u00e2y?<\/b><\/h5>\n<\/div>\n
    \n
      \n
    • \n

      A)<\/span>1,0.<\/b><\/b><\/p>\n<\/li>\n

    • \n

      B)<\/span>2,5.<\/b><\/b><\/p>\n<\/li>\n

    • \n

      C)<\/span>1,5.<\/b><\/b><\/p>\n<\/li>\n

    • \n

      D)<\/span>3,0.<\/b><\/b><\/p>\n<\/li>\n<\/ul>\n<\/div>\n<\/div>\n<\/div>\n

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      \n
      \n
      3. <\/span><\/span>\u0110un h\u1ed7n h\u1ee3p etylen glicol v\u00e0 axit cacboxylic X (ph\u00e2n t\u1eed ch\u1ec9 c\u00f3 nh\u00f3m -COOH) v\u1edbi x\u00fac t\u00e1c H2SO4 \u0111\u1eb7c, thu \u0111\u01b0\u1ee3c h\u1ed7n h\u1ee3p s\u1ea3n ph\u1ea9m h\u1eefu c\u01a1, trong \u0111\u00f3 c\u00f3 ch\u1ea5t h\u1eefu c\u01a1 Y m\u1ea1ch h\u1edf. \u0110\u1ed1t ch\u00e1y ho\u00e0n to\u00e0n 3,95 gam Y c\u1ea7n 4,00 gam O2, thu \u0111\u01b0\u1ee3c CO2v\u00e0 H2O theo t\u1ec9 l\u1ec7 mol t\u01b0\u01a1ng \u1ee9ng 2 : 1. Bi\u1ebft Y c\u00f3 c\u00f4ng th\u1ee9c ph\u00e2n t\u1eed tr\u00f9ng v\u1edbi c\u00f4ng th\u1ee9c \u0111\u01a1n gi\u1ea3n nh\u1ea5t, Y ph\u1ea3n \u1ee9ng \u0111\u01b0\u1ee3c v\u1edbi NaOH theo t\u1ec9 l\u1ec7 mol t\u01b0\u01a1ng \u1ee9ng 1 : 2. Ph\u00e1t bi\u1ec3u n\u00e0o sau \u0111\u00e2y sai?<\/b><\/h5>\n<\/div>\n
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      • \n

        A)<\/span> T\u1ed5ng s\u1ed1 nguy\u00ean t\u1eed hi\u0111ro trong hai ph\u00e2n t\u1eed X, Y b\u1eb1ng 8.<\/b><\/b><\/p>\n<\/li>\n

      • \n

        B)<\/span> X c\u00f3 \u0111\u1ed3ng ph\u00e2n h\u00ecnh h\u1ecdc.<\/b><\/b><\/p>\n<\/li>\n

      • \n

        C)<\/span> Y kh\u00f4ng c\u00f3 ph\u1ea3n \u1ee9ng tr\u00e1ng b\u1ea1c.<\/b><\/b><\/p>\n<\/li>\n

      • \n

        D)<\/span> Y tham gia \u0111\u01b0\u1ee3c ph\u1ea3n \u1ee9ng c\u1ed9ng v\u1edbi Br2 theo t\u1ec9 l\u1ec7 mol t\u01b0\u01a1ng \u1ee9ng 1 : 2.<\/b><\/b><\/p>\n<\/li>\n<\/ul>\n<\/div>\n<\/div>\n<\/div>\n

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        4. <\/span><\/span>Cho 0,7 mol h\u1ed7n h\u1ee3p T g\u1ed3m hai peptit m\u1ea1ch h\u1edf l\u00e0 X (x mol) v\u00e0 Y (y mol), \u0111\u1ec1u t\u1ea1o b\u1edfi glyxin v\u00e0 alanin. \u0110un n\u00f3ng 0,7 mol T trong l\u01b0\u1ee3ng d\u01b0 dung d\u1ecbch NaOH th\u00ec c\u00f3 3,8 mol NaOH ph\u1ea3n \u1ee9ng v\u00e0 thu \u0111\u01b0\u1ee3c dung d\u1ecbch ch\u1ee9a m gam mu\u1ed1i. M\u1eb7t kh\u00e1c, n\u1ebfu \u0111\u1ed1t ch\u00e1y ho\u00e0n to\u00e0n x mol X ho\u1eb7c y mol Y th\u00ec \u0111\u1ec1u thu \u0111\u01b0\u1ee3c c\u00f9ng s\u1ed1 mol CO2. Bi\u1ebft t\u1ed5ng s\u1ed1 nguy\u00ean t\u1eed oxi trong hai ph\u00e2n t\u1eed X v\u00e0 Y l\u00e0 13, trong X v\u00e0 Y \u0111\u1ec1u c\u00f3 s\u1ed1 li\u00ean k\u1ebft peptit kh\u00f4ng nh\u1ecf h\u01a1n 4. Gi\u00e1 tr\u1ecb c\u1ee7a m l\u00e0<\/b><\/h5>\n<\/div>\n
        \n
          \n
        • \n

          A)<\/span>396,6.<\/b><\/b><\/p>\n<\/li>\n

        • \n

          B)<\/span>409,2.<\/b><\/b><\/p>\n<\/li>\n

        • \n

          C)<\/span>399,4.<\/b><\/b><\/p>\n<\/li>\n

        • \n

          D)<\/span>340,8.<\/b><\/b><\/p>\n<\/li>\n<\/ul>\n<\/div>\n<\/div>\n<\/div>\n

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          5. <\/span><\/span>X l\u00e0 dung d\u1ecbch HCl n\u1ed3ng \u0111\u1ed9 x mol\/l. Y l\u00e0 dung d\u1ecbch Na2CO3 n\u1ed3ng \u0111\u1ed9 y mol\/l. Nh\u1ecft\u1eeb t\u1eeb100 ml X v\u00e0o 100 ml Y, sau c\u00e1c ph\u1ea3n \u1ee9ng thu \u0111\u01b0\u1ee3c V1 l\u00edt CO2 (\u0111ktc). Nh\u1ecf t\u1eeb t\u1eeb 100 ml Y v\u00e0o 100 ml X, sau ph\u1ea3n \u1ee9ng thu \u0111\u01b0\u1ee3c V2 l\u00edt CO2(\u0111ktc). Bi\u1ebft t\u1ec9 l\u1ec7 V1: V2= 4 : 7. T\u1ec9 l\u1ec7x : y b\u1eb1ng<\/b><\/h5>\n<\/div>\n
          \n
            \n
          • \n

            A)<\/span>11 : 7.<\/b><\/b><\/p>\n<\/li>\n

          • \n

            B)<\/span>11 : 4.<\/b><\/b><\/p>\n<\/li>\n

          • \n

            C)<\/span>7 : 5.<\/b><\/b><\/p>\n<\/li>\n

          • \n

            D)<\/span>7 : 3.<\/b><\/b><\/p>\n<\/li>\n<\/ul>\n<\/div>\n<\/div>\n<\/div>\n

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            6. <\/span><\/span>Cho 7,65 gam h\u1ed7n h\u1ee3p X g\u1ed3m Al v\u00e0 Al2O3(trong \u0111\u00f3 Al chi\u1ebfm 60% kh\u1ed1i l\u01b0\u1ee3ng) tan ho\u00e0n to\u00e0n trong dung d\u1ecbch Y g\u1ed3m H2SO4 v\u00e0 NaNO3, thu \u0111\u01b0\u1ee3c dung d\u1ecbch Z ch\u1ec9 ch\u1ee9a 3 mu\u1ed1i trung h\u00f2a v\u00e0 m gam h\u1ed7n h\u1ee3p kh\u00ed T (trong T c\u00f3 0,015 mol H2). Cho dung d\u1ecbch BaCl2 d\u01b0 v\u00e0o Z \u0111\u1ebfn khi c\u00e1c ph\u1ea3n \u1ee9ng x\u1ea3y ra ho\u00e0n to\u00e0n, thu \u0111\u01b0\u1ee3c 93,2 gam k\u1ebft t\u1ee7a. C\u00f2n n\u1ebfu cho Z ph\u1ea3n \u1ee9ng v\u1edbi NaOH th\u00ec l\u01b0\u1ee3ng NaOH ph\u1ea3n \u1ee9ng t\u1ed1i \u0111a l\u00e0 0,935 mol. Gi\u00e1 tr\u1ecb c\u1ee7a m g\u1ea7n gi\u00e1 tr\u1ecb n\u00e0o nh\u1ea5t sau \u0111\u00e2y?<\/b><\/h5>\n<\/div>\n
            \n
              \n
            • \n

              A)<\/span>2,5.<\/b><\/b><\/p>\n<\/li>\n

            • \n

              B)<\/span>3,0.<\/b><\/b><\/p>\n<\/li>\n

            • \n

              C)<\/span>1,0.<\/b><\/b><\/p>\n<\/li>\n

            • \n

              D)<\/span>1,5.<\/b><\/b><\/p>\n<\/li>\n<\/ul>\n<\/div>\n<\/div>\n<\/div>\n

              \n
              \n
              \n
              7. <\/span><\/span>H\u1ed7n h\u1ee3p X g\u1ed3m hai ch\u1ea5t h\u1eefu c\u01a1no, m\u1ea1ch h\u1edf (\u0111\u1ec1u ch\u1ee9a C, H, O), trong ph\u00e2n t\u1eed m\u1ed7i ch\u1ea5t c\u00f3 hai nh\u00f3m ch\u1ee9c trong s\u1ed1 c\u00e1c nh\u00f3m -OH, -CHO, -COOH. Cho m gam X ph\u1ea3n \u1ee9ng ho\u00e0n to\u00e0n v\u1edbi l\u01b0\u1ee3ng d\u01b0 dung d\u1ecbch AgNO3 trong NH3, thu \u0111\u01b0\u1ee3c 4,05 gam Ag v\u00e0 1,86 gam m\u1ed9t mu\u1ed1i amoni h\u1eefu c\u01a1. Cho to\u00e0n b\u1ed9 l\u01b0\u1ee3ng mu\u1ed1i amoni h\u1eefu c\u01a1 n\u00e0y v\u00e0o dung d\u1ecbch NaOH (d\u01b0, \u0111un n\u00f3ng), thu \u0111\u01b0\u1ee3c 0,02 mol NH3. Gi\u00e1 tr\u1ecb c\u1ee7a m l\u00e0<\/b><\/h5>\n<\/div>\n
              \n
                \n
              • \n

                A)<\/span>1,50.<\/b><\/b><\/p>\n<\/li>\n

              • \n

                B)<\/span>2,98.<\/b><\/b><\/p>\n<\/li>\n

              • \n

                C)<\/span>1,22.<\/b><\/b><\/p>\n<\/li>\n

              • \n

                D)<\/span>1,24.<\/b><\/b><\/p>\n<\/li>\n<\/ul>\n<\/div>\n<\/div>\n<\/div>\n

                \n
                \n
                \n
                8. <\/span><\/span>H\u1ed7n h\u1ee3p T g\u1ed3m hai ancol \u0111\u01a1n ch\u1ee9c l\u00e0 X v\u00e0 Y (MX< MY), \u0111\u1ed3ng \u0111\u1eb3ng k\u1ebf ti\u1ebfp c\u1ee7a nhau. \u0110un n\u00f3ng 27,2 gam T v\u1edbi H2SO4 \u0111\u1eb7c, thu \u0111\u01b0\u1ee3c h\u1ed7n h\u1ee3p c\u00e1c ch\u1ea5t h\u1eefu c\u01a1 Z g\u1ed3m: 0,08 mol ba ete (c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng 6,76 gam) v\u00e0 m\u1ed9t l\u01b0\u1ee3ng ancol d\u01b0. \u0110\u1ed1t ch\u00e1y ho\u00e0n to\u00e0n Z c\u1ea7n v\u1eeba \u0111\u1ee7 43,68 l\u00edt O2 (\u0111ktc). Hi\u1ec7u su\u1ea5t ph\u1ea3n \u1ee9ng t\u1ea1o ete c\u1ee7a X v\u00e0 Y l\u1ea7n l\u01b0\u1ee3t l\u00e0<\/b><\/h5>\n<\/div>\n
                \n
                  \n
                • \n

                  A)<\/span>20% v\u00e0 40%.<\/b><\/b><\/p>\n<\/li>\n

                • \n

                  B)<\/span>40% v\u00e0 30%.<\/b><\/b><\/p>\n<\/li>\n

                • \n

                  C)<\/span>30% v\u00e0 30%.<\/b><\/b><\/p>\n<\/li>\n

                • \n

                  D)<\/span>50% v\u00e0 20%.<\/b><\/b><\/p>\n<\/li>\n<\/ul>\n

                  H\u1ed3ng H\u1ea1nh<\/strong><\/p>\n

                  (Ngu\u1ed3n B\u1ed9 GD-\u0110T)<\/em><\/p>\n<\/div>\n<\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"

                  \u0110\u1ec1 thi THPT qu\u1ed1c gia H\u00f3a h\u1ecdc th\u01b0\u1eddng c\u00f3 50 c\u00e2u h\u1ecfi. M\u1ee9c \u0111\u1ed9 c\u00e2u h\u1ecfi s\u1ebd t\u0103ng d\u1ea7n t\u1eeb d\u1ec5 \u0111\u1ebfn kh\u00f3. Nh\u1eefng c\u00e2u h\u1ecfi kh\u00f3 th\u01b0\u1eddng l\u00e0 nh\u1eefng c\u00e2u \u0111\u1ec3 ph\u00e2n lo\u1ea1i th\u00ed sinh kh\u00e1 – gi\u1ecfi. D\u01b0\u1edbi \u0111\u00e2y l\u00e0 nh\u1eefng d\u1ea1ng c\u00e2u h\u1ecfi kh\u00f3 m\u00e0 th\u00ed sinh s\u1ebd g\u1eb7p trong \u0111\u1ec1 thi […]<\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[159],"tags":[],"yoast_head":"\nNh\u1eefng c\u00e2u h\u1ecfi kh\u00f3 trong \u0111\u1ec1 thi H\u00f3a<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/nhung-cau-hoi-kho-trong-de-thi-hoa-2\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Nh\u1eefng c\u00e2u h\u1ecfi kh\u00f3 trong \u0111\u1ec1 thi H\u00f3a\" \/>\n<meta property=\"og:description\" content=\"\u0110\u1ec1 thi THPT qu\u1ed1c gia H\u00f3a h\u1ecdc th\u01b0\u1eddng c\u00f3 50 c\u00e2u h\u1ecfi. M\u1ee9c \u0111\u1ed9 c\u00e2u h\u1ecfi s\u1ebd t\u0103ng d\u1ea7n t\u1eeb d\u1ec5 \u0111\u1ebfn kh\u00f3. Nh\u1eefng c\u00e2u h\u1ecfi kh\u00f3 th\u01b0\u1eddng l\u00e0 nh\u1eefng c\u00e2u \u0111\u1ec3 ph\u00e2n lo\u1ea1i th\u00ed sinh kh\u00e1 – gi\u1ecfi. 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