C\u00e2u 9:<\/b>\u00a0H\u1ea1t anpha c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng 6,64.1027<\/sup>\u00a0kg chuy\u1ec3n \u0111\u1ed9ng tr\u00f2n \u0111\u1ec1u trong t\u1eeb tr\u01b0\u1eddng \u0111\u1ec1u c\u00f3 c\u1ea3m \u1ee9ng t\u1eeb B = 0,5T. Bi\u1ebft b\u00e1n k\u00ednh qu\u1ef9 \u0111\u1ea1o l\u00e0 0,5 m. T\u1ed1c \u0111\u1ed9 c\u1ee7a h\u1ea1t l\u00e0<\/p>\n A. 3,8.107<\/sup>\u00a0m\/s\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 7,6.107<\/sup>\u00a0m\/s<\/p>\n C. 1,9.107<\/sup>\u00a0m\/s\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 3,8.106<\/sup>m\/s<\/p>\n C\u00e2u 10:<\/b>Sau th\u1eddi gian 1 n\u0103m, s\u1ed1 h\u1ea1t nh\u00e2n nguy\u00ean t\u1eed c\u1ee7a m\u1ed9t ch\u1ea5t ph\u00f3ng x\u1ea1 gi\u1ea3m \u0111i 7 l\u1ea7n. Chu k\u00ec b\u00e1n r\u00e3 c\u1ee7a ch\u1ea5t ph\u00f3ng x\u1ea1 n\u00e0y l\u00e0<\/p>\n <\/p>\n C\u00e2u 11:<\/b>\u00a0Urani\u00a092<\/sub>234<\/sup>U ph\u00f3ng x\u1ea1 c\u00f3 chu k\u00ec b\u00e1n r\u00e3 T = 4,5 t\u1ec9 n\u0103m, nh\u00e2n con l\u00e0 ch\u1ec9\u00a082<\/sub>206<\/sup>Pb. Gi\u1ea3 s\u1eed khi h\u00ecnh th\u00e0nh, qu\u1eb7ng kh\u00f4ng c\u00f3 nguy\u00ean t\u1eed ch\u00ec ; hi\u1ec7n nay, trong qu\u1eb7ng c\u00f3 1 g urani v\u00e0 0,01 g ch\u00ec. Tu\u1ed5i c\u1ee7a qu\u1eb7ng l\u00e0<\/p>\n A. 74,6 tri\u1ec7u n\u0103m\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 7,46 tri\u1ec7u n\u0103m<\/p>\n C. 45,2 tri\u1ec7u n\u0103m\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 4,52 tri\u1ec7u n\u0103m<\/p>\n C\u00e2u 12:<\/b>\u00a0H\u1ea1t nh\u00e2n X trong ph\u1ea3n \u1ee9ng X + \u03b1 \u2192 n +\u00a06<\/sub>12<\/sup>C l\u00e0<\/p>\n A. 3<\/sub>6<\/sup>Li\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 4<\/sub>9<\/sup>Be<\/p>\n C. 5<\/sub>10<\/sup>Bo\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 67<\/sub>14<\/sup>N<\/p>\n C\u00e2u 13:<\/b>\u00a0Bi\u1ebft kh\u1ed1i l\u01b0\u1ee3ng c\u00e1c h\u1ea1t l\u00e0 : mp<\/sub>\u00a0= 1,007276 u, mn<\/sub>\u00a0= 1,008670 u, m\u03b1<\/sub>\u00a0= 4,0015 u, 1 u = 930 MeV\/c2<\/sup>. N\u0103ng l\u01b0\u1ee3ng t\u1ecfa ra khi c\u00f3 5,6 dm3<\/sup>\u00a0kh\u00ed heli \u1edf \u0111i\u1ec1u ki\u1ec7n chu\u1ea9n t\u1ea1o th\u00e0nh t\u1eeb c\u00e1c nucl\u00f4n l\u00e0<\/p>\n A. 6,8.1011<\/sup>\u00a0J\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 2,7.1012<\/sup>\u00a0J<\/p>\n C. 4,5.1011<\/sup>\u00a0J\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 8,5.1013<\/sup>\u00a0J<\/p>\n C\u00e2u 14:<\/b>\u00a0Cho urani ph\u00f3ng x\u1ea1 \u03b1 theo ph\u01b0\u01a1ng tr\u00ecnh:\u00a092<\/sub>234<\/sup>U \u2192\u03b1+90<\/sub>230<\/sup>Th. Theo ph\u01b0\u01a1ng tr\u00ecnh n\u00e0y ta t\u00ednh \u0111\u01b0\u1ee3c \u0111\u1ed9ng n\u0103ng c\u1ee7a h\u1ea1t \u03b1 l\u00e0 13,91 MeV. \u0110\u00f3 l\u00e0 do c\u00f3 ph\u00f3ng x\u1ea1 \u03b3 k\u00e8m theo ph\u00f3ng x\u1ea1 \u03b1. B\u01b0\u1edbc s\u00f3ng c\u1ee7a b\u1ee9c x\u1ea1 \u03b3 l\u00e0<\/p>\n A. 1,37 pm\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 1,54 pm<\/p>\n C. 13,7 pm\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 2,62 pm<\/p>\n C\u00e2u 15:<\/b>\u00a0H\u1ea1t \u03b1 c\u00f3 \u0111\u1ed9ng n\u0103ng W\u0111\u03b1<\/sub>\u00a0= 4,32 MeV \u0111\u1eadp v\u00e0o h\u1ea1t nh\u00e2n nh\u00f4m g\u00e2y ra ph\u1ea3n \u1ee9ng : \u03b1+13<\/sub>27<\/sup>Al\u219215<\/sub>30<\/sup>P+n. Bi\u1ebft ph\u1ea3n \u1ee9ng n\u00e0y thu n\u0103ng l\u01b0\u1ee3ng 2,7 MeV v\u00e0 gi\u1ea3 thi\u1ebft hai h\u1ea1t sinh ra sau ph\u1ea3n \u1ee9ng c\u00f3 c\u00f9ng t\u1ed1c \u0111\u1ed9. \u0110\u1ed9ng n\u0103ng c\u1ee7a n\u01a1tron l\u00e0<\/p>\n A. 4,52 MeV\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 7,02 MeV<\/p>\n C. 0,226 MeV\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 6,78 MeV<\/p>\n H\u01b0\u1edbng d\u1eabn gi\u1ea3i v\u00e0 \u0111\u00e1p \u00e1n<\/b><\/p>\n C\u00e2u 9:<\/b>\u00a0C<\/p>\n <\/p>\n C\u00e2u 10:<\/b>\u00a0B<\/p>\n <\/p>\n C\u00e2u 13:<\/b>\u00a0A<\/p>\n <\/p>\n C\u00e2u 14:<\/b>\u00a0A<\/p>\n <\/p>\n C\u00e2u 15:<\/b>\u00a0C<\/p>\n <\/p>\n","protected":false},"excerpt":{"rendered":" C\u00e2u 9:\u00a0H\u1ea1t anpha c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng 6,64.1027\u00a0kg chuy\u1ec3n \u0111\u1ed9ng tr\u00f2n \u0111\u1ec1u trong t\u1eeb tr\u01b0\u1eddng \u0111\u1ec1u c\u00f3 c\u1ea3m \u1ee9ng t\u1eeb B = 0,5T. Bi\u1ebft b\u00e1n k\u00ednh qu\u1ef9 \u0111\u1ea1o l\u00e0 0,5 m. T\u1ed1c \u0111\u1ed9 c\u1ee7a h\u1ea1t l\u00e0 A. 3,8.107\u00a0m\/s\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 7,6.107\u00a0m\/s C. 1,9.107\u00a0m\/s\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D. 3,8.106m\/s C\u00e2u 10:Sau th\u1eddi gian 1 n\u0103m, s\u1ed1 h\u1ea1t nh\u00e2n nguy\u00ean t\u1eed c\u1ee7a […]<\/p>\n","protected":false},"author":3,"featured_media":25721,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[158],"tags":[1443,1442],"yoast_head":"\n\n\n
\n C\u00e2u<\/td>\n 9<\/td>\n 10<\/td>\n 11<\/td>\n 12<\/td>\n 13<\/td>\n 14<\/td>\n 15<\/td>\n<\/tr>\n \n \u0110\u00e1p \u00e1n<\/td>\n C<\/td>\n B<\/td>\n A<\/td>\n B<\/td>\n A<\/td>\n A<\/td>\n C<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n