B\u00e0i 1 (trang 52 sgk H\u00f3a 12 n\u00e2ng cao):\u00a0\u0110\u1ed1t ch\u00e1y m\u1ed9t h\u1ee3p ch\u1ea5t h\u1eefu c\u01a1 c\u00f3 6 nguy\u00ean t\u1eed cacbon trong ph\u00e2n t\u1eed thu \u0111\u01b0\u1ee3c h\u1ed7n h\u1ee3p s\u1ea3n ph\u1ea9m CO2<\/sub>\u00a0v\u00e0 n\u01b0\u1edbc theo t\u1ec9 l\u1ec7 mol 1:1. H\u1ee3p ch\u1ea5t \u0111\u00f3 c\u00f3 th\u1ec3 l\u00e0 h\u1ee3p ch\u1ea5t n\u00e0o trong c\u00e1c h\u1ee3p ch\u1ea5t d\u01b0\u1edbi \u0111\u00e2y. Bi\u1ebft r\u1eb1ng s\u1ed1 mol oxi ti\u00eau th\u1ee5 b\u1eb1ng s\u1ed1 mol CO2<\/sub>\u00a0thu \u0111\u01b0\u1ee3c?<\/strong><\/p>\n A. Glucoz\u01a1 C6<\/sub>H12<\/sub>O6<\/sub><\/p>\n B. Xiclohexanol C6<\/sub>H12<\/sub>O.<\/p>\n C. Axit hexanoic C5<\/sub>H11<\/sub>COOH<\/p>\n D. Hexanal.<\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n \u0110\u00e1p \u00e1n A<\/p>\n B\u00e0i 2 (trang 52 sgk H\u00f3a 12 n\u00e2ng cao):\u00a0Ghi \u0110 (\u0111\u00fang) ho\u1eb7c s (sai) v\u00e0o \u00f4 vu\u00f4ng \u1edf cu\u1ed1i m\u1ed7i n\u1ed9i dung sau:<\/strong><\/p>\n A. C\u00f3 th\u1ec3 ph\u00e2n bi\u1ec7t glucozo v\u00e0 fructozo b\u1eb1ng v\u1ecb gi\u00e1c<\/p>\n B. Dung d\u1ecbch mantozo c\u00f3 t\u00ednh kh\u1ee9 v\u00ec \u0111\u00e3 b\u1ecb th\u1ee7y ph\u00e2n th\u00e0nh glucozo<\/p>\n C. Tinh b\u1ed9t v\u00e0 xenlulozo kh\u00f4ng th\u1ec3 hi\u1ec7n t\u00ednh kh\u1eed v\u00ec trong ph\u00e2n t\u1eed h\u1ea7u nh\u01b0 kh\u00f4ng c\u00f3 nh\u00f3m -OH semiaxetal t\u1ef1 do.<\/p>\n D. Tinh b\u1ed9t c\u00f3 ph\u1ea3n \u1ee9ng m\u00e0u v\u1edbi iot v\u00ec c\u00f3 c\u1ea5u tr\u00fac v\u00f2ng xo\u1eafn.<\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n A – S<\/p>\n B – S<\/p>\n C- \u0110<\/p>\n D – \u0110<\/p>\n B\u00e0i 3 (trang 53 sgk H\u00f3a 12 n\u00e2ng cao):\u00a03. H\u00e3y vi\u1ebft c\u00f4ng th\u1ee9c ph\u00e2n t\u1eeb, c\u00f4ng th\u1ee9c c\u1ea5u t\u1ea1o thu g\u1ecdn (\u1edf d\u1ea1ng m\u1ea1ch h\u1edf v\u00e0 d\u1ea1ng m\u1ea1ch v\u00f2ng) c\u1ee7a glucozo, fructozo, saccarozo, mantozo, tinh b\u1ed9t v\u00e0 xenluloza.<\/strong><\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n C\u00f4ng th\u1ee9c ph\u00e2n t\u1eed, c\u00f4ng th\u1ee9c c\u1ea5u t\u1ea1o thu g\u1ecdn ( \u1edf d\u1ea1ng m\u1ea1ch h\u1edf v\u00e0 d\u1ea1ng m\u1ea1ch v\u00f2ng) c\u1ee7a glucozo, fructozo, saccarozo, mantozo, tinh b\u1ed9t v\u00e0 xenlulozo<\/p>\n <\/p>\n B\u00e0i 4 (trang 53 sgk H\u00f3a 12 n\u00e2ng cao):\u00a0Ph\u1ea7n l\u1edbn glucozo do c\u00e2y xanh t\u1ed5ng h\u1ee3p ra trong qu\u00e1 tr\u00ecnh quang h\u1ee3p l\u00e0 \u0111\u1ec3 t\u1ea1o ra xenluloz\u01a1. Bi\u1ebft r\u1eb1ng m\u1ed9t c\u00e2y b\u1ea1ch \u0111\u00e0n 5 tu\u00f4i c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng g\u1ed7 trung b\u00ecnh l\u00e0 100kg ch\u1ee9a 50% xenlulozo.<\/strong><\/p>\n a. T\u00ednh xem 1 ha r\u1eebng b\u1ea1ch \u0111\u00e0n 5 tu\u1ed5i m\u1eadt \u0111\u1ed9 1 c\u00e2y\/20m2<\/sup>\u00a0\u0111\u00e3 h\u1ea5p th\u1ee5 bao nhi\u00eau m3<\/sup>CO2<\/sub>\u00a0v\u00e0 gi\u1ea3i ph\u00f3ng ra bao nhi\u00eau m3<\/sup>\u00a0O2<\/sub>\u00a0\u0111\u1ec3 t\u1ea1o xenlulozo.<\/p>\n b. N\u1ebfu d\u00f9ng to\u00e0n b\u1ed9 g\u1ed7 t\u1eeb 1 ha b\u1ea1ch \u0111\u00e0n n\u00f3i tr\u00ean \u0111\u1ec3 s\u1ea3n xu\u1ea5t gi\u1ea5y (gi\u1ea3 s\u1eed ch\u1ee9a 95% xenlulozo v\u00e0 5% ph\u1ee5 gia) th\u00ec s\u1ebd thu \u0111\u01b0\u1ee3c bao nhi\u00eau t\u1ea5n gi\u1ea5y, bi\u1ebft r\u1eb1ng hi\u1ec7u su\u1ea5t chung c\u1ee7a qu\u00e1 tr\u00ecnh l\u00e0 80% tinh theo l\u01b0\u1ee3ng xenlulozo ban \u0111\u1ea7u.<\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n a. 1 ha = 10000 m2<\/sup>. M\u1eadt \u0111\u1ed9 b\u1ea1ch \u0111\u00e0n 20m2<\/sup>\/c\u00e2y, m\u1ed7i c\u00e2y c\u00f3 50 kg xenlulozo n\u00ean t\u1ed5ng kh\u1ed1i l\u01b0\u1ee3ng xenlulozo t\u1ed5ng h\u1ee3p \u0111\u01b0\u1ee3c l\u00e0 : 50.10000 \/20 = 25000 (kg)<\/p>\n Ph\u1ea3n \u1ee9ng quang h\u1ee3p<\/p>\n 6nCO2<\/sub>\u00a0+ 5nH2<\/sub>O \u2192 (C6<\/sub>H10<\/sub>O5<\/sub>)n<\/sub>\u00a0+ 6nO2<\/sub><\/p>\n Th\u1ec3 t\u00edch CO2<\/sub>\u00a0= th\u1ec3 t\u00edch O2<\/sub>\u00a0= V m3<\/sup><\/p>\n => V = (25000 x 6 x 22,4n):(0,162n x 1000) = 20740,740 (m3<\/sup>)<\/p>\n b. kh\u1ed1i l\u01b0\u1ee3ng gi\u1ea5y s\u1ea3n xu\u1ea5t t\u1eeb 1 ha b\u1ea1ch \u0111\u00e0n tr\u00ean l\u00e0 : 25 : 95 . 100 \u2248 26,32 (t\u1ea5n)<\/p>\n B\u00e0i 5 (trang 53 sgk H\u00f3a 12 n\u00e2ng cao):\u00a0T\u00ednh kh\u1ed1i l\u01b0\u1ee3ng ancol etvlic thu \u0111\u01b0\u1ee3c t\u1eeb:<\/strong><\/p>\n a. M\u1ed9t t\u1ea5n ng\u00f4 ch\u1ee9a 65% tinh b\u1ed9t, hi\u1ec7u su\u1ea5t c\u1ea3 qu\u00e1 tr\u00ecnh \u0111\u1ea1t 80%.<\/strong><\/p>\n b. M\u1ed9t t\u1ea5n m\u00f9n c\u01b0a ch\u1ee9a 50% xenlulozo, hi\u1ec7u su\u1ea5t c\u1ea3 qu\u00e1 tr\u00ecnh \u0111\u1ea1t 70%.<\/strong><\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n S\u01a1 \u0111\u1ed3 \u0111i\u1ec1u ch\u1ebf etanol t\u1eeb xenlulozo<\/p>\n <\/p>\n a. mtinh b\u1ed9t<\/sub>\u00a0= 1.65:100 = 0,65 t\u1ea5n = 650 kg<\/p>\n kh\u1ed1i l\u01b0\u1ee3ng etanol thu \u0111\u01b0\u1ee3c v\u1edbi hi\u1ec7u su\u1ea5t 80% l\u00e0 :<\/p>\n 650.(92n : 162n).(80 : 100) = 295,3 kg<\/p>\n b. mxenlulozo<\/sub>\u00a0= 50:100.1 = 0,5 t\u1ea5n = 500 kg<\/p>\n Kh\u1ed1i l\u01b0\u1ee3ng etanol thu \u0111\u01b0\u1ee3c v\u1edbi hi\u1ec7u su\u1ea5t 70% l\u00e0 :<\/p>\n 500. (92n : 162n).(70 : 100) = 198,8 kg<\/p>\n <\/p>\n","protected":false},"excerpt":{"rendered":" B\u00e0i 1 (trang 52 sgk H\u00f3a 12 n\u00e2ng cao):\u00a0\u0110\u1ed1t ch\u00e1y m\u1ed9t h\u1ee3p ch\u1ea5t h\u1eefu c\u01a1 c\u00f3 6 nguy\u00ean t\u1eed cacbon trong ph\u00e2n t\u1eed thu \u0111\u01b0\u1ee3c h\u1ed7n h\u1ee3p s\u1ea3n ph\u1ea9m CO2\u00a0v\u00e0 n\u01b0\u1edbc theo t\u1ec9 l\u1ec7 mol 1:1. H\u1ee3p ch\u1ea5t \u0111\u00f3 c\u00f3 th\u1ec3 l\u00e0 h\u1ee3p ch\u1ea5t n\u00e0o trong c\u00e1c h\u1ee3p ch\u1ea5t d\u01b0\u1edbi \u0111\u00e2y. Bi\u1ebft r\u1eb1ng s\u1ed1 mol […]<\/p>\n","protected":false},"author":3,"featured_media":25434,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1306],"tags":[1436,1435],"yoast_head":"\n