B\u00e0i 1 (trang 14 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0M\u1ed9t momen l\u1ef1c kh\u00f4ng \u0111\u1ed5i t\u00e1c d\u1ee5ng v\u00e0o m\u1ed9t v\u1eadt c\u00f3 tr\u1ee5c quay c\u1ed1 \u0111\u1ecbnh. Trong nh\u1eefng \u0111\u1ea1i l\u01b0\u1ee3ng d\u01b0\u1edbi \u0111\u00e2y, \u0111\u1ea1i l\u01b0\u1ee3ng n\u00e0o kh\u00f4ng ph\u1ea3i m\u1ed9t h\u1eb1ng s\u1ed1?<\/span><\/p>\nA. Momen qu\u00e1n t\u00ednh\u00a0\u00a0\u00a0B. Gia t\u1ed1c g\u00f3c<\/p>\n
C. Kh\u1ed1i l\u01b0\u1ee3ng.\u00a0\u00a0\u00a0D. T\u1ed1c \u0111\u1ed9 g\u00f3c.<\/p>\n
L\u1eddi gi\u1ea3i:<\/b><\/p>\n
Ch\u1ecdn D.<\/p>\n
Momen qu\u00e1n t\u00ednh v\u00e0 kh\u1ed1i l\u01b0\u1ee3ng l\u00e0 \u0111\u1ea1i l\u01b0\u1ee3ng kh\u00f4ng \u0111\u1ed5i v\u1edbi m\u1ed9t v\u1eadt. T\u1eeb ph\u01b0\u01a1ng tr\u00ecnh \u0111\u1ed9ng l\u1ef1c h\u1ecdc c\u01a1 b\u1ea3n c\u1ee7a v\u1eadt r\u1eafn M= l\u03b3 ta suy ra gia t\u1ed1c g\u00f3c \u03b3 kh\u00f4ng \u0111\u1ed5i.<\/p>\n
T\u1ed1c \u0111\u1ed9 g\u00f3c \u03c9 = \u03c9o<\/sub>\u00a0+ \u03b3t r\u00f5 r\u00e0ng bi\u1ebfn \u0111\u1ed5i theo th\u1eddi gian.<\/p>\nB\u00e0i 2 (trang 14 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0Hai ch\u1ea5t \u0111i\u1ec3m c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng 1kg v\u00e0 2kg \u0111\u01b0\u1ee3c g\u1eafn \u1edf hai \u0111\u1ea7u c\u1ee7a m\u00f4t thanh nh\u1eb9 c\u00f3 chi\u1ec1u d\u00e0i 1m. Momen qu\u00e1n t\u00ednh c\u1ee7a h\u1ec7 \u0111\u1ed1i v\u1edbi tr\u1ee5c quay \u0111i qua trung \u0111i\u1ec3m c\u1ee7a thanh v\u00e0 vu\u00f4ng g\u00f3c v\u1edbi thanh c\u00f3 g\u00eda tr\u1ecb.<\/span><\/p>\nA. 1,5 kg.m2<\/sup>.\u00a0\u00a0\u00a0B. 0,75 kg.m2<\/sup>.<\/p>\nC. 0,5 kg.m2<\/sup>.\u00a0\u00a0\u00a0D. 1,75 kg.m2<\/sup>.<\/p>\nL\u1eddi gi\u1ea3i:<\/b><\/p>\n
Ch\u1ecdn A.<\/p>\n
Momen qu\u00e1n t\u00ednh c\u1ee7a h\u1ec7 \u0111\u1ed1i v\u1edbi tr\u1ee5c quay \u0111i qua trung \u0111i\u1ec3m c\u1ee7a thanh v\u00e0 vu\u00f4ng g\u00f3c v\u1edbi thanh l = m1<\/sub>R1<\/sub>2<\/sup>\u00a0+ m2<\/sub>R2<\/sub>2<\/sup>\u00a0.<\/p>\nV\u1edbi R1<\/sub>\u00a0= R2<\/sub>\u00a0= 0,5R= 0,5m. Ta c\u00f3:<\/p>\nL = 1.0,25 + 2.0,25 = 0,75 kg.m2<\/sup><\/p>\nB\u00e0i 3 (trang 14 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0Momen qu\u00e1n t\u00ednh c\u1ee7a m\u1ed9t v\u1eadt r\u1eafn kh\u00f4ng ph\u1ee5 thu\u1ed9c v\u00e0o:<\/span><\/p>\nA. Kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a v\u1eadt\u00a0\u00a0\u00a0B. T\u1ed1c \u0111\u1ed9c g\u00f3c c\u1ee7a v\u1eadt<\/p>\n
C. Kh\u00edch th\u01b0\u1edbc v\u00e0 h\u00ecnh d\u1ea1ng c\u1ee7a v\u1eadt\u00a0\u00a0\u00a0D. V\u1ecb tr\u00ed tr\u1ee9c quay c\u1ee7a v\u1eadt<\/p>\n
L\u1eddi gi\u1ea3i:<\/b><\/p>\n
Ch\u1ecdn B<\/p>\n
B\u00e0i 4 (trang 14 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0Ph\u00e1t bi\u1ec3u n\u00e0o sau \u0111\u1ea1y kh\u00f4ng \u0111\u00fang v\u1edbi chuy\u1ec3n \u0111\u1ed9ng quay \u0111\u1ec1u c\u1ee7a v\u1eadt r\u1eafn quanh m\u1ed9t tr\u1ee5c?<\/span><\/p>\nA. T\u1ed1c \u0111\u1ed9 g\u00f3c l\u00e0 m\u1ed9t h\u00e0m b\u1eadc nh\u1ea5t \u0111\u1ed1i v\u1edbi th\u1eddi gian<\/p>\n
B. Gia t\u1ed1c g\u00f3c c\u1ee7a v\u1eadt b\u1eb1ng 0.<\/p>\n
C. Trong nh\u1eefng kho\u1ea3ng th\u1eddi gian b\u1eb1ng nhau, v\u1eadt quay \u0111\u01b0\u1ee3c nh\u1ee9ng g\u00f3c b\u1eb1ng nhau.<\/p>\n
D. Ph\u01b0\u01a1ng tr\u00ecnh chuy\u1ec3n \u0111\u1ed9ng l\u00e0 m\u1ed9t h\u00e0m b\u1eadc nh\u1ea5t \u0111\u1ed1i v\u1edbi th\u1eddi gian.<\/p>\n
L\u1eddi gi\u1ea3i:<\/b><\/p>\n
Ch\u1ecdn A.<\/p>\n
Quay \u0111\u1ec1u th\u00ec \u03c9 = h\u1eb1ng s\u1ed1, v\u1eady c\u00e2u A sai<\/p>\n
B\u00e0i 5 (trang 14 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0M\u1ed9t c\u1eadu b\u00e9 \u0111\u1ea9y m\u1ed9t chi\u1ebfc \u0111u quay c\u00f3 \u0111\u01b0\u1eddng k\u00ednh 4m v\u1edbi m\u1ed9t l\u1ef1c 60N \u0111\u1eb7t t\u1ea1i v\u00e0nh c\u1ee7a chi\u1ebfc \u0111u theo ph\u01b0\u01a1ng ti\u1ebfp tuy\u1ebfn. Momen l\u1ef1c t\u00e1c d\u1ee5ng v\u00e0o \u0111u quay c\u00f3 gi\u00e1 tr\u1ecb:<\/span><\/p>\nA. 30 N.m\u00a0\u00a0\u00a0B. 15 N.m<\/p>\n
C. 240 N.m\u00a0\u00a0\u00a0D. 120 N.m<\/p>\n
L\u1eddi gi\u1ea3i:<\/b><\/p>\n
Ch\u1ecdn D.<\/p>\n
M = F.d = 60.2 = 120 N.m<\/p>\n
\n
<\/div>\n<\/div>\n
\n
<\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"
C\u00c2U H\u1eceI C\u00e2u 1 (trang 13 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):\u00a0Vi\u1ebft bi\u1ec3u th\u1ee9c v\u00e0 n\u00eau \u00fd ngh\u0129a c\u1ee7a momen qu\u00e1n t\u00ednh c\u1ee7a m\u1ed9t v\u1eadt r\u1eafn \u0111\u1ed1i v\u1edbi chuy\u1ec3n \u0111\u1ed9ng quay L\u1eddi gi\u1ea3i: + Bi\u1ec3u th\u1ee9c: + \u00dd ngh\u0129a: momen qu\u00e1n t\u00ednh c\u1ee7a v\u1eadt r\u1eafn \u0111\u1ed1i v\u1edbi m\u1ed9t tr\u1ee5c \u0111\u1eb7c tr\u01b0ng cho m\u1ee9c qu\u00e1n t\u00ednh […]<\/p>\n","protected":false},"author":3,"featured_media":25336,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1304],"tags":[1432,1431],"yoast_head":"\n
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