C\u00e2u 1 (trang 17 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0Ph\u00e1t bi\u1ec3u \u0111\u1ecbnh lu\u1eadt b\u1ea3o to\u00e0n momen \u0111\u1ed9ng l\u01b0\u1ee3ng.<\/span><\/p>\nL\u1eddi gi\u1ea3i:<\/b><\/p>\n
N\u1ebfu t\u1ed5ng c\u00e1c momen l\u1ef1c t\u00e1c d\u1ee5ng l\u00ean m\u1ed9t v\u1eadt r\u1eafn (hay h\u1ec7 v\u1eadt) \u0111\u1ed1i v\u1edbi m\u1ed9t tr\u1ee5c b\u1eb1ng kh\u00f4ng th\u00ec t\u1ed5ng momen \u0111\u1ed9ng l\u01b0\u1ee3ng c\u1ee7a v\u1eadt (hay h\u1ec7 v\u1eadt) \u0111\u1ed1i v\u1edbi tr\u1ee5c \u0111\u00f3 \u0111\u01b0\u1ee3c b\u1ea3o to\u00e0n.<\/p>\n
C\u00e2u 2 (trang 17 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0C\u00e1c v\u1eadn \u0111\u1ed9ng vi\u00ean nh\u1ea3y c\u1ea7u khi nh\u1ea3y t\u1eeb v\u00e1n c\u1ea7u xu\u1ed1ng n\u01b0\u1edbc c\u00f3 \u0111\u1ed9ng t\u00e1c “b\u00f3 g\u1ed1i” th\u1eadt ch\u1eb7t l\u00fac \u1edf tr\u00ean kh\u00f4ng. Gi\u1ea3i th\u00edch t\u1ea1i sao l\u00e0m nh\u01b0 th\u1ebf l\u1ea1i t\u0103ng t\u1ed1c \u0111\u1ed9 quay.<\/span><\/p>\nL\u1eddi gi\u1ea3i:<\/b><\/p>\n
Momen \u0111\u1ed9ng l\u01b0\u1ee3ng c\u1ee7a ng\u01b0\u1eddi L = I\u03c9. Khi b\u00f3 g\u1ed1i th\u00ec momen qu\u00e1n t\u00ednh c\u1ee7a ng\u01b0\u1eddi \u0111\u00f3 gi\u1ea3m, theo \u0111\u1ecbnh lu\u1eadt b\u1ea3o to\u00e0n momen \u0111\u1ed9ng l\u01b0\u1ee3ng t\u1ed1c \u0111\u1ed9 g\u00f3c \u03c9 ph\u1ea3i t\u0103ng, \u0111\u00e2y l\u00e0 \u0111\u1ed9ng t\u00e1c bi\u1ec3u di\u1ec5n xoay ng\u01b0\u1eddi tr\u00ean kh\u00f4ng. Khi g\u1ea7n ti\u1ebfp n\u01b0\u1edbc, ng\u01b0\u1eddi \u0111\u00f3 ph\u1ea3i du\u1ed7i th\u1eb3ng ng\u01b0\u1eddi ra. Momen qu\u00e1n t\u00ednh t\u0103ng th\u00ec t\u1ed1c \u0111\u1ed9 g\u00f3c \u03c9 gi\u1ea3m l\u00e0m ng\u01b0\u1eddi \u0111\u00f3 ng\u1eebng quay v\u00e0 lao m\u00ecnh v\u00e0o trong n\u01b0\u1edbc.<\/p>\n
B\u00c0I T\u1eacP<\/p>\n
B\u00e0i 1 (trang 17 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0M\u1ed9t v\u1eadt c\u00f3 momem qu\u00e1n t\u00ednh \u0111\u1ed1i v\u1edbi tr\u1ee5c quay c\u1ed1 \u0111\u1ecbnh l\u00e0 0,72 kg.m2<\/sup>\u00a0quay \u0111\u1ec1u 10 v\u00f2ng trong 1,8 s. Momen \u0111\u1ed9ng l\u01b0\u1ee3ng c\u1ee7a v\u1eadt c\u00f3 \u0111\u1ed9 l\u1edbn b\u1eb1ng<\/span><\/p>\nA. 4 kg.m2<\/sup>\/s B. 8 kg.m2<\/sup>\/s<\/p>\nC. 13 kg.m2<\/sup>\/s D. 25 kg.m2<\/sup>\/s<\/p>\nL\u1eddi gi\u1ea3i:<\/b><\/p>\n
Ch\u1ecdn D<\/p>\n
+ T\u1ed1c \u0111\u1ed9 g\u00f3c \u03c9 = 2\u03c0n = 2\u03c0.10\/1,8 =3 5 rad\/s<\/p>\n
+ Momen \u0111\u1ed9ng l\u01b0\u1ee3ng: L = I\u03c9 = 0,72.35 = 25 kg.m2<\/sup>\/s<\/p>\nB\u00e0i 2 (trang 17 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0Hai \u0111\u0129a tr\u00f2n c\u00f3 momen qu\u00e1n t\u00ednh I1<\/sub>\u00a0v\u00e0 I2<\/sub>\u00a0\u0111ang quay \u0111\u1ed3ng tr\u1ee5c v\u00e0 c\u00f9ng chi\u1ec1u v\u1edbi t\u1ed1c \u0111\u1ed9 g\u00f3c \u03c91<\/sub>\u00a0v\u00e0 \u03c92<\/sub>(H\u00ecnh 3.3). Ma s\u00e1t \u1edf tr\u1ee5c quay nh\u1ecf kh\u00f4ng \u0111\u00e1ng k\u1ec3. Sau \u0111\u00f3 cho hai \u0111\u0129a d\u00ednh v\u00e0o nhau, h\u1ec7 hai \u0111\u0129a quay v\u1edbi t\u1ed1c \u0111\u1ed9 g\u00f3c \u03c9 c\u00f3 \u0111\u1ed9 l\u1edbn \u0111\u01b0\u1ee3c x\u00e1c \u0111\u1ecbnh b\u1eb1ng c\u00f4ng th\u1ee9c.<\/span><\/p>\n![\"\"](\"https:\/\/lop12.edu.vn\/wp-content\/uploads\/2018\/04\/1-58.png\")
<\/p>\n
L\u1eddi gi\u1ea3i:<\/b><\/p>\n
Ch\u1ecdn B<\/p>\n
\u00c1p d\u1ee5ng \u0111\u1ecbnh lu\u1eadt \u1ea3o to\u00e0n momem \u0111\u1ed9ng l\u01b0\u1ee3ng: l1<\/sub>\u03c91<\/sub>\u00a0+ l2<\/sub>\u03c92<\/sub>= (l1<\/sub>\u00a0+ l2<\/sub>)\u03c9. Suy ra :<\/p>\n![\"\"](\"https:\/\/lop12.edu.vn\/wp-content\/uploads\/2018\/04\/2-22.png\")
<\/p>\n
B\u00e0i 4 (trang 17 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0M\u1ed9t \u0111\u0129a tr\u00f2n \u0111\u1ed3ng ch\u1ea5t c\u00f3 b\u00e1n k\u00ednh R = 0,5m. Kh\u1ed1i l\u01b0\u1ee3ng m =1kg quay \u0111\u1ec1u v\u1edbi t\u1ed1c \u0111\u1ed9 g\u00f3c \u03c9 = 6 rad\/s quanh m\u1ed9t tr\u1ee5c th\u1eb3ng \u0111\u1ee9ng \u0111i qua t\u00e2m c\u1ee7a \u0111\u0129a. T\u00ednh momen \u0111\u1ed9ng l\u01b0\u1ee3ng c\u1ee7a \u0111\u0129a \u0111\u1ed1i v\u1edbi tr\u1ee5c quay \u0111\u00f3.<\/span><\/p>\nL\u1eddi gi\u1ea3i:<\/b><\/p>\n
– Momen qu\u00e1n t\u00ednh c\u1ee7a \u0111\u0129a: l = (1\/2)mR2<\/sup>\u00a0= 0,5. 1.0,52<\/sup>\u00a0= 0,125 kg.m2<\/sup><\/p>\n– Momem \u0111\u1ed9ng l\u01b0\u1ee3ng: M = l\u03c9 = 0,125.6 = 0,75 kg.m2<\/sup>\/s.<\/p>\n","protected":false},"excerpt":{"rendered":"C\u00c2U H\u1eceI C\u00e2u 1 (trang 17 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):\u00a0Ph\u00e1t bi\u1ec3u \u0111\u1ecbnh lu\u1eadt b\u1ea3o to\u00e0n momen \u0111\u1ed9ng l\u01b0\u1ee3ng. L\u1eddi gi\u1ea3i: N\u1ebfu t\u1ed5ng c\u00e1c momen l\u1ef1c t\u00e1c d\u1ee5ng l\u00ean m\u1ed9t v\u1eadt r\u1eafn (hay h\u1ec7 v\u1eadt) \u0111\u1ed1i v\u1edbi m\u1ed9t tr\u1ee5c b\u1eb1ng kh\u00f4ng th\u00ec t\u1ed5ng momen \u0111\u1ed9ng l\u01b0\u1ee3ng c\u1ee7a v\u1eadt (hay h\u1ec7 v\u1eadt) \u0111\u1ed1i v\u1edbi tr\u1ee5c […]<\/p>\n","protected":false},"author":3,"featured_media":25332,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1304],"tags":[1432,1431],"yoast_head":"\n
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