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{"id":25255,"date":"2018-04-04T17:26:06","date_gmt":"2018-04-04T10:26:06","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=25255"},"modified":"2018-04-04T17:26:06","modified_gmt":"2018-04-04T10:26:06","slug":"chuong-2-bai-7-con-lac-don-con-lac-vat-li","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/chuong-2-bai-7-con-lac-don-con-lac-vat-li\/","title":{"rendered":"Ch\u01b0\u01a1ng 2 – B\u00e0i 7: Con l\u1eafc \u0111\u01a1n. Con l\u1eafc v\u1eadt l\u00ed"},"content":{"rendered":"

C\u00c2U H\u1eceI<\/strong><\/p>\n

C\u00e2u 1 (trang 40 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0Dao \u0111\u1ed9ng c\u1ee7a v\u1eadt n\u1eb7ng trong con l\u1eafc l\u00f2 xo l\u00e0 dao \u0111\u1ed9ng t\u1ecbnh ti\u1ebfn: v\u1eadt n\u1eb7ng chuy\u1ec3n \u0111\u1ed9ng t\u1ecbnh ti\u1ebfn theo Ph\u01b0\u01a1ng tr\u00ecnh d\u1ea1ng sin, v\u00e0o m\u1ed9t th\u1eddi \u0111i\u1ec3m \u0111\u00e3 cho c\u1ee7a v\u1eadt n\u1eb7ng c\u00f3 c\u00f9ng v\u1eadn t\u1ed1c v\u00e0 gia t\u1ed1c. Dao \u0111\u1ed9ng c\u1ee7a con l\u1eafc v\u1eadt l\u00fd c\u00f3 ph\u1ea3i dao \u0111\u1ed9ng t\u00ednh ti\u1ebfn kh\u00f4ng? N\u1ebfu kh\u00f4ng th\u00ec dao \u0111\u1ed9ng n\u00e0o kh\u00e1c dao \u0111\u1ed9ng t\u1ecbnh ti\u1ebfn th\u1ebf n\u00e0o?<\/span><\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

Dao \u0111\u1ed9ng c\u1ee7a con l\u1eafc v\u1eadt l\u00ed kh\u00f4ng ph\u1ea3i l\u00e0 dao \u0111\u1ed9ng t\u1ecbnh ti\u1ebfn m\u00e0 l\u00e0 dao \u0111\u1ed9ng quay, trong \u0111\u00f3 c\u00e1c \u0111\u1ea1i l\u01b0\u1ee3ng c\u00e1c \u0111\u1ea1i l\u01b0\u1ee3ng \u0111\u1eb7c tr\u01b0ng cho chuy\u1ec3n \u0111\u1ed9ng quay th\u00ec nh\u01b0 nhau cho m\u1ecdi \u0111i\u1ec3m, v\u00ed d\u1ee5 nh\u01b0 g\u00f3c quay \u03c6, t\u1ed1c \u0111\u1ed9 g\u00f3c \u03c9, gia t\u1ed1c g\u00f3c \u03b3…<\/p>\n

C\u00e2u 2 (trang 40 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0\u0110\u1ed1i chi\u1ebfu dao \u0111\u1ed9ng c\u1ee7a con l\u1eafc \u0111\u01a1n v\u1edbi dao \u0111\u1ed9ng c\u1ee7a con l\u1eafc l\u00f2 xo. Tr\u1ea3 l\u1eddi c\u00e1c c\u00e2u h\u1ecfi sau \u0111\u1ed1i v\u1edbi t\u1eebng con l\u1eafc:<\/span><\/p>\n

a) L\u1ef1c k\u00e9o v\u1ec1 c\u00f3 ph\u1ee5 thu\u1ed9c kh\u1ed1i l\u01b0\u1ee3ng v\u1eadt n\u1eb7ng kh\u00f4ng?<\/p>\n

b) Gia t\u1ed1c c\u1ee7a v\u1eadt n\u1eb7ng ph\u1ee5 thu\u1ed9c kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a n\u00f3 kh\u00f4ng?<\/p>\n

c) T\u1ea7n s\u1ed1 g\u00f3c ph\u1ee5 thu\u1ed9c kh\u1ed1i l\u01b0\u1ee3ng v\u1eadt n\u1eb7ng?<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n\n\n\n\n\n\n
\u0110\u1ea1i l\u01b0\u1ee3ng<\/td>\nCon l\u1eafc l\u00f2 xo<\/td>\nCon l\u1eafc \u0111\u01a1n<\/td>\n<\/tr>\n
L\u1ef1c k\u00e9o v\u1ec1 F<\/td>\nF = -kx kh\u00f4ng ph\u1ee5 thu\u1ed9c kh\u1ed1i l\u01b0\u1ee3ng m<\/td>\nF = -m(g\/l)x c\u00f3 ph\u1ee5 thu\u1ed9c v\u00e0o kh\u1ed1i l\u01b0\u1ee3ng m.<\/td>\n<\/tr>\n
Gia t\u1ed1c a<\/td>\na = -(k\/m)x c\u00f3 ph\u1ee5 thu\u1ed9c v\u00e0o m.<\/td>\na = (g\/l)s kh\u00f4ng ph\u1ee5 thu\u1ed9c v\u00e0o m<\/td>\n<\/tr>\n
T\u1ea7n s\u1ed1 g\u00f3c \u03c9<\/td>\n\u03c9 = \u221a(k\/m) c\u00f3 ph\u1ee5 thu\u1ed9c v\u00e0o m<\/td>\n\u03c9 = \u221a(g\/l) kh\u00f4ng ph\u1ee5 thu\u1ed9c v\u00e0o m<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

 <\/p>\n

B\u00c0I T\u1eacP<\/strong><\/p>\n

B\u00e0i 1 (trang 40 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0Chu k\u00ec dao \u0111\u1ed9ng nh\u1ecf con l\u1eafc \u0111\u01a1n ph\u1ee5 thu\u1ed9c:<\/span><\/p>\n

A. Kh\u1ed1i l\u01b0\u1ee3ng con l\u1eafc<\/p>\n

B. Tr\u1ecdng l\u01b0\u01a1ng con l\u1eafc<\/p>\n

C. T\u1ec9 s\u1ed1 c\u1ee7a tr\u1ecdng l\u01b0\u1ee3ng v\u00e0 kh\u1ed9i l\u01b0\u1ee3ng c\u1ee7a con l\u1eafc<\/p>\n

D. kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a con l\u1eafc.<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

Ch\u1ecdn C<\/p>\n

V\u00ec T = 2\u03c0\u221a(l\/g) m\u00e0 t\u1ec9 s\u1ed1 p\/m = g<\/p>\n

n\u00ean chu k\u00ec T t\u1ef7 l\u1ec7 ngh\u1ecbch v\u1edbi \u221ag n\u00ean c\u00f9ng t\u1ef7 l\u1ec7 ngh\u1ecbch v\u1edbi t\u1ef7 s\u1ed1 p\/m<\/p>\n

B\u00e0i 2 (trang 40 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0Chu k\u00ec c\u1ee7a con l\u1eafc v\u1eadt l\u00fd \u0111\u01b0\u1ee3c x\u00e1c \u0111\u1ecbnh b\u1eb1ng c\u00f4ng th\u1ee9c.<\/span><\/p>\n

\"\"<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

Ch\u1ecdn B.<\/p>\n

B\u00e0i 3 (trang 40 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0T\u00ecm chi\u1ec1u d\u00e0i c\u1ee7a con l\u1eafc \u0111\u01a1n c\u00f3 chu k\u00ec 1s \u1edf n\u01a1i c\u00f3 gia t\u1ed1c tr\u1ecdng tr\u01b0\u1eddng g = 9,81 m\/<\/span>s2<\/sup><\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

T\u1eeb c\u00f4ng th\u1ee9c:<\/p>\n

\"\"<\/p>\n

B\u00e0i 4 (trang 40 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0\u1ede n\u01a1i m\u00e0 con l\u1eafc \u0111\u01a1n \u0111\u1ebfm gi\u00e2y (t\u1ee9c l\u00e0 c\u00f3 chu k\u00ec 2s) c\u00f3 \u0111\u1ed9 d\u00e0i 1 m th\u00ec con l\u1eafc \u0111\u01a1n c\u00f3 \u0111\u1ed9 d\u00e0i 3m dao \u0111\u1ed9ng v\u1edbi chu k\u00ec b\u1eb1ng bao nhi\u00eau?<\/span><\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

T\u1eeb c\u00f4ng th\u1ee9c T = 2 \u03c0 \u221a(l\/g) ta suy ra:<\/p>\n

\"\"<\/p>\n

B\u00e0i 5 (trang 40 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0M\u1ed9t v\u1eadt r\u1eafn c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng m = 1,5 kg c\u00f3 th\u1ec3 quay quanh m\u1ed9t tr\u1ee5c n\u1eb1m ngang. D\u01b0\u1edbi t\u00e1c d\u1ee5ng c\u1ee7a tr\u1ecdng l\u1ef1c, v\u1eadt dao \u0111\u1ed9ng nh\u1ecf v\u1edbi chu k\u00ec T = 0,5s. kho\u1ea3ng c\u00e1ch t\u1eeb tr\u1ee5c quay \u0111\u1ebfn tr\u1ecdng t\u00e2m c\u1ee7a v\u1eadt l\u00e0 d = 10cm. T\u00ednh momen qu\u00e1n t\u00ednh c\u1ee7a v\u1eadt \u0111\u1ed1i v\u1edbi tr\u1ee5c quay (l\u1ea5y g = 10 m\/s2<\/sup>).<\/span><\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

T\u1eeb c\u00f4ng th\u1ee9c:<\/p>\n

\"\"<\/p>\n

Suy ra r\u1eb1ng:<\/p>\n

\"\"<\/p>\n

V\u1edbi T = 0,5s th\u00ec:<\/p>\n

\"\"<\/p>\n

\n
<\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"

C\u00c2U H\u1eceI C\u00e2u 1 (trang 40 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):\u00a0Dao \u0111\u1ed9ng c\u1ee7a v\u1eadt n\u1eb7ng trong con l\u1eafc l\u00f2 xo l\u00e0 dao \u0111\u1ed9ng t\u1ecbnh ti\u1ebfn: v\u1eadt n\u1eb7ng chuy\u1ec3n \u0111\u1ed9ng t\u1ecbnh ti\u1ebfn theo Ph\u01b0\u01a1ng tr\u00ecnh d\u1ea1ng sin, v\u00e0o m\u1ed9t th\u1eddi \u0111i\u1ec3m \u0111\u00e3 cho c\u1ee7a v\u1eadt n\u1eb7ng c\u00f3 c\u00f9ng v\u1eadn t\u1ed1c v\u00e0 gia t\u1ed1c. Dao \u0111\u1ed9ng […]<\/p>\n","protected":false},"author":3,"featured_media":25256,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1304],"tags":[1432,1431],"yoast_head":"\nCh\u01b0\u01a1ng 2 - B\u00e0i 7: Con l\u1eafc \u0111\u01a1n. Con l\u1eafc v\u1eadt l\u00ed<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/chuong-2-bai-7-con-lac-don-con-lac-vat-li\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Ch\u01b0\u01a1ng 2 - B\u00e0i 7: Con l\u1eafc \u0111\u01a1n. 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