B\u00e0i 4 (trang 104 sgk H\u00f3a 12 n\u00e2ng cao):\u00a0a. Ph\u00e2n t\u1eed polime c\u00f3 nh\u1eefng d\u1ea1ng m\u1ea1ch n\u00e0o? L\u1ea5y th\u00ed d\u1ee5?<\/strong><\/p>\n

b. V\u00ec sao amilozo tan \u0111\u01b0\u1ee3c m\u1ed9t l\u01b0\u1ee3ng \u0111\u00e1ng k\u1ec3 trong n\u01b0\u1edbc c\u00f2n tinh b\u1ed9t v\u00e0 xenlulozo th\u00ec kh\u00f4ng<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

a. C\u00f3 3 d\u1ea1ng c\u1ea5u tr\u00fac c\u01a1 b\u1ea3n ph\u00e2n t\u1eed polime :<\/p>\n

– D\u1ea1ng m\u1ea1ch kh\u00f4ng ph\u00e2n nh\u00e1nh : PE, PVC, polimebutadien, amilozo<\/p>\n

– D\u1ea1ng m\u1ea1ch ph\u00e2n nh\u00e1nh : amilopectin<\/p>\n

– D\u1ea1ng m\u1ea1ch kh\u00f4ng gian : cao su l\u01b0u h\u00f3a<\/p>\n

b. D\u1ea1ng amilozo tan nhi\u1ec1u trong n\u01b0\u1edbc h\u01a1n d\u1ea1ng amilopectin v\u00ec c\u1ea5u tr\u00fac h\u00f3a h\u1ecdc kh\u00f4ng ph\u00e2n nh\u00e1nh, \u0111\u1ed3ng th\u1eddi s\u1ed1 l\u01b0\u1ee3ng m\u1eaft x\u00edch trong ph\u00e2n t\u1eed nh\u1ecf h\u01a1n<\/p>\n

B\u00e0i 5 (trang 104 sgk H\u00f3a 12 n\u00e2ng cao):\u00a0a. Cho th\u00ed d\u1ee5 v\u1ec1 c\u00e1c lo\u1ea1i polime c\u00f3 t\u00ednh d\u1ebbo, t\u00ednh \u0111\u00e0n h\u1ed3i v\u00e0 t\u00ednh dai b\u1ec1n c\u00f3 th\u1ec3 k\u00e9o th\u00e0nh t\u01a1<\/strong><\/p>\n

b. Cho th\u00ed d\u1ee5 v\u1ec1 c\u00e1c ph\u1ea3n \u1ee9ng c\u1eaft m\u1ea1ch, gi\u1eef nguy\u00ean m\u1ea1ch v\u00e0 t\u0103ng m\u1ea1ch polime.<\/strong><\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

a. Polime c\u00f3 t\u00ednh d\u1ebbo: PE, PVC, poli(metylmetacrylat)<\/p>\n

Polime c\u00f3 t\u00ednh \u0111\u00e0n h\u1ed3i : cao su thi\u00ean nhi\u00ean, sao su buna<\/p>\n

Polime c\u00f3 t\u00ednh dai, b\u1ec1n : nilon \u2013 6,6; t\u01a1 lapsan ,…<\/p>\n

b. Ph\u1ea3n \u1ee9ng c\u1eaft m\u1ea1ch<\/p>\n

<\/p>\n

Ph\u1ea3n \u1ee9ng gi\u1eef nguy\u00ean m\u1ea1ch<\/p>\n

<\/p>\n

Ph\u1ea3n \u1ee9ng t\u0103ng m\u1ea1ch (SGK-T90)<\/p>\n

<\/p>\n

B\u00e0i 6 (trang 104 sgk H\u00f3a 12 n\u00e2ng cao):\u00a0\u0110\u1ec3 s\u1ea3n xu\u1ea5t polime clorin, ng\u01b0\u1eddi ta clo h\u00f3a PVC b\u1eb1ng clo. S\u1ea3n ph\u1ea9m thu \u0111\u01b0\u1ee3c ch\u1ee9a 66,7% clo.<\/strong><\/p>\n

– T\u00ednh xem trung b\u00ecnh m\u1ed7i ph\u00e2n t\u1eed clo t\u00e1c d\u1ee5ng v\u1edbi m\u1ea5y m\u1eaft x\u00edch \u2013CH_{2<\/sub>CHCl- trong ph\u00e2n t\u1eed PVC? Gi\u1ea3 thi\u1ebft r\u1eb1ng h\u1ec7 s\u1ed1 polime h\u00f3a l\u00e0 n kh\u00f4ng thay \u0111\u1ed5i sau ph\u1ea3n \u1ee9ng<\/strong><\/p>\n}

– Vi\u1ebft c\u00f4ng th\u1ee9c c\u1ea5u t\u1ea1o m\u1ed9t \u0111o\u1ea1n ph\u00e2n t\u1eed polime peclorovinyl \u0111\u00e3 cho \u1edf tr\u00ean.<\/strong><\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

S\u1ed1 m\u1eaft x\u00edch \u2013CH_{2<\/sub>-CHCl- ph\u1ea3n \u1ee9ng v\u1edbi 1 ph\u00e2n t\u1eed Cl l\u00e0 x. Ta c\u00f3 ph\u01b0\u01a1ng tr\u00ecnh:<\/p>\n}

<\/p>\n

%Cl ={ [35,5.(x + 1)].100}:(62,5.x + 34,5) = 66,7%<\/p>\n

\u2192 53,22(x + 1) = 62,5x + 34,5 => x = 2<\/p>\n

V\u1eady trung b\u00ecnh 1 ph\u00e2n t\u1eed clo t\u00e1c d\u1ee5ng v\u1edbi 2 m\u1eaft x\u00edch \u2013CH_{2<\/sub>-CHCl-<\/p>\n}

– M\u1ed9t \u0111o\u1ea1n m\u1ea1ch t\u01a1 clorin<\/p>\n

<\/p>\n<\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"

B\u00e0i 1 (trang 103 sgk H\u00f3a 12 n\u00e2ng cao):\u00a0\u0110i\u1ec1n v\u00e0o ch\u1ed7 tr\u1ed1ng \u1edf cu\u1ed1i m\u1ed7i c\u00e2u sau ch\u1eef \u0110 n\u1ebfu ph\u00e1t bi\u1ec3u \u0111\u00f3 \u0111\u00fang, ch\u1eef S n\u1ebfu ph\u00e1t bi\u1ec3u \u0111\u00f3 sai A. Polipeptit l\u00e0 polime B. Protein l\u00e0 polime C. Protein l\u00e0 h\u1ee3p ch\u1ea5t cao ph\u00e2n t\u1eed D. Poliamit c\u00f3 ch\u1ee9a c\u00e1c li\u00ean k\u1ebft peptit […]<\/p>\n","protected":false},"author":3,"featured_media":25210,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1306],"tags":[1436,1435],"yoast_head":"\n