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{"id":25189,"date":"2018-04-04T01:08:35","date_gmt":"2018-04-03T18:08:35","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=25189"},"modified":"2018-04-04T01:08:35","modified_gmt":"2018-04-03T18:08:35","slug":"chuong-5-bai-25-luyen-tap-su-dien-phan-su-an-mon-kim-loai-dieu-che-kim-loai","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/chuong-5-bai-25-luyen-tap-su-dien-phan-su-an-mon-kim-loai-dieu-che-kim-loai\/","title":{"rendered":"Ch\u01b0\u01a1ng 5 – B\u00e0i 25: Luy\u1ec7n t\u1eadp: S\u1ef1 \u0111i\u1ec7n ph\u00e2n – S\u1ef1 \u0103n m\u00f2n kim lo\u1ea1i – \u0110i\u1ec1u ch\u1ebf kim lo\u1ea1i"},"content":{"rendered":"

B\u00e0i 1 (trang 142 sgk H\u00f3a 12 n\u00e2ng cao):\u00a0Trong qu\u00e1 tr\u00ecnh \u0111i\u1ec7n ph\u00e2n dung d\u1ecbch Pb(NO3<\/sub>)2<\/sub>\u00a0v\u1edbi c\u00e1c \u0111i\u1ec7n c\u1ef1c tr\u01a1, ion Pb2+<\/sup>\u00a0di chuy\u1ec3n v\u1ec1<\/strong><\/p>\n

A. catot v\u00e0 b\u1ecb oxi h\u00f3a.<\/p>\n

B. anot v\u00e0 b\u1ecb oxi h\u00f3a.<\/p>\n

C. catot v\u00e0 b\u1ecb kh\u1eed.<\/p>\n

D. anot v\u00e0 b\u1ecb kh\u1eed.<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

\u0110\u00e1p \u00e1n C<\/p>\n

\n
\n

B\u00e0i 2 (trang 142 sgk H\u00f3a 12 n\u00e2ng cao):\u00a0Ph\u00e1t bi\u1ec3u n\u00e0o sau \u0111\u00e2y l\u00e0 kh\u00f4ng \u0111\u00fang?<\/strong><\/p>\n

A. \u0102n m\u00f2n kim lo\u1ea1i l\u00e0 s\u1ef1 ph\u00e1 h\u1ee7y kim lo\u1ea1i v\u00e0 h\u1ee3p kim d\u01b0\u1edbi t\u00e1c d\u1ee5ng c\u1ee7a m\u00f4i tr\u01b0\u1eddng xung quanh<\/p>\n

B. \u0102n m\u00f2n h\u00f3a h\u1ecdc l\u00e0 m\u1ed9t qu\u00e1 tr\u00ecnh h\u00f3a h\u1ecdc trong \u0111\u00f3 kim lo\u1ea1i b\u1ecb \u0103n m\u00f2n b\u1edfi c\u00e1c axit trong m\u00f4i tr\u01b0\u1eddng kh\u00f4ng kh\u00ed<\/p>\n

C. trong qu\u00e1 tr\u00ecnh \u0103n m\u00f2n kim lo\u1ea1i b\u1ecb oxi h\u00f3a th\u00e0nh ion c\u1ee7a n\u00f3<\/p>\n

D. \u0102n m\u00f2n kim lo\u1ea1i \u0111\u01b0\u1ee3c chia l\u00e0m 2 d\u1ea1ng \u0103n m\u00f2n h\u00f3a h\u1ecdc v\u00e0 \u0103n m\u00f2n \u0111i\u1ec7n h\u00f3a h\u1ecdc.<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

\u0110\u00e1p \u00e1n B<\/p>\n

\n
\n

B\u00e0i 3 (trang 143 sgk H\u00f3a 12 n\u00e2ng cao):\u00a0Ph\u1ea3n \u1ee9ng \u0111i\u1ec1u ch\u1ebf kim lo\u1ea1i n\u00e0o d\u01b0\u1edbi \u0111\u00e2y thu\u1ed9c ph\u01b0\u01a1ng ph\u00e1p nhi\u1ec7t luy\u1ec7n:<\/strong><\/p>\n

A. C + ZnO \u2192 Zn + CO<\/p>\n

B. Al2<\/sub>O3<\/sub>\u00a0\u2192 2Al + 3\/2 O2<\/sub><\/p>\n

C. MgCl2<\/sub>\u00a0\u2192 Mg + Cl2<\/sub><\/p>\n

D. Zn + 2AgNO3<\/sub>\u00a0\u2192 Zn(NO3<\/sub>)2<\/sub>\u00a0+ 2Ag<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

\u0110\u00e1p \u00e1n A<\/p>\n

\n
\n

B\u00e0i 4 (trang 143 sgk H\u00f3a 12 n\u00e2ng cao):\u00a0T\u1eeb MgCO3\u00a0\u0111i\u1ec1u ch\u1ebf Mg. T\u1eeb CuS \u0111i\u1ec1u ch\u1ebf Cu. T\u1eeb K2SO4\u00a0\u0111i\u1ec1u ch\u1ebf K (c\u00e1c ch\u1ea5t trung gian t\u00f9y \u00fd ch\u1ecdn)<\/strong><\/p>\n

L\u1eddi gi\u1ea3i:<\/strong><\/p>\n

T\u1eeb MgCO3<\/sub>\u00a0\u2192 Mg<\/p>\n

MgCO3<\/sub>\u00a0+ 2HCl \u2192 MgCl2<\/sub>\u00a0+ CO2<\/sub>\u00a0+ H2<\/sub>O (1)<\/p>\n

MgCl\u00a0\u0111pnc<\/sup>\u00a0\u2192 Mg + Cl2<\/sub>\u00a0(2)<\/p>\n

* T\u1eeb CuS \u2192 Cu<\/p>\n

2CuS + 3O2<\/sub>\u00a0to<\/sup>\u00a0\u2192 2CuO + 2SO2<\/sub>\u00a0(1)<\/p>\n

H2<\/sub>\u00a0+ CuO\u00a0to<\/sup>\u00a0\u2192 Cu + H2<\/sub>O (2)<\/p>\n

*T\u1eeb K2<\/sub>SO4<\/sub>\u00a0\u2192 K<\/p>\n

K2<\/sub>SO4<\/sub>\u00a0+ BaCl2<\/sub>\u00a0\u2192 BaSO4<\/sub>\u00a0\u2193 + 2KCl (1)<\/p>\n

2KCl\u00a0\u0111pnc<\/sup>\u00a0\u2192 2K + Cl2<\/sub>\u00a0(2)<\/p>\n

B\u00e0i 5 (trang 143 sgk H\u00f3a 12 n\u00e2ng cao):\u00a0Khi nung 23,2 gam sunfua c\u1ee7a m\u1ed9t kim lo\u1ea1i h\u00f3a tr\u1ecb hai trong kh\u00f4ng kh\u00ed r\u1ed3i l\u00e0m ngu\u1ed9i s\u1ea3n ph\u1ea9m thu \u0111\u01b0\u1ee3c m\u1ed9t ch\u00e2t l\u1ecfng v\u00e0 m\u1ed9t ch\u1ea5t kh\u00ed. L\u01b0\u1ee3ng s\u1ea3n ph\u1ea9m kh\u00ed n\u00e0y l\u00e0m m\u1ea5t m\u00e0u 25,4 gam iot. X\u00e1c \u0111\u1ecbnh t\u00ean kim lo\u1ea1i \u0111\u00f3.<\/strong><\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

G\u1ecdi kim lo\u1ea1i h\u00f3a tr\u1ecb hai l\u00e0 M => Mu\u1ed1i l\u00e0 MS nung trong kh\u00f4ng kh\u00ed \u0111\u01b0\u1ee3c m\u1ed9t ch\u1ea5t kh\u00ed l\u00e0 SO2<\/sub>\u00a0v\u00e0 m\u1ed9t ch\u1ea5t l\u1ecfng SO2<\/sub>\u00a0ph\u1ea3n \u1ee9ng v\u1edbi I2<\/sub>\u00a0theo ph\u01b0\u01a1ng tr\u00ecnh<\/p>\n

SO2<\/sub>\u00a0+ I2<\/sub>\u00a0+ 2H2<\/sub>O \u2192 H2<\/sub>SO4<\/sub>\u00a0+ 2HI<\/p>\n

(23,2 : 0,1).nSO2<\/sub>\u00a0= nI2<\/sub>\u00a0= nS<\/sub>\u00a0= nMS<\/sub>\u00a0= 25,4 : 254 = 0,1 mol => MMS<\/sub>\u00a0= 23,2 : 0,1 = 232 = M + 32<\/p>\n

=> M = 200. M l\u00e0 th\u1ee7y ng\u00e2n Hg<\/p>\n

B\u00e0i 6 (trang 143 sgk H\u00f3a 12 n\u00e2ng cao):\u00a0\u0110i\u1ec7n ph\u00e2n 100 ml m\u1ed9t dung d\u1ecbch c\u00f3 h\u00f2a tan 13,5 gam CuCl v\u00e0 14,9 gam KCl (c\u00f3 m\u00e0ng ng\u0103n v\u00e0 \u0111i\u1ec7n c\u1ef1c tr\u01a1)<\/strong><\/p>\n

a) Tr\u00ecnh b\u00e0y s\u01a1 \u0111\u1ed3 v\u00e0 vi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh h\u00f3a h\u1ecdc c\u1ee7a ph\u1ea3n \u1ee9ng \u0111i\u1ec7n ph\u00e2n c\u00f3 th\u1ec3 x\u1ea3y ra.<\/strong><\/p>\n

b) H\u00e3y cho bi\u1ebft ch\u1ea5t n\u00e0o c\u00f2n l\u1ea1i trong dung d\u1ecbch \u0111i\u1ec7n ph\u00e2n. Bi\u1ebft th\u1eddi gian \u0111i\u1ec7n ph\u00e2n l\u00e0 2 gi\u1edd, c\u01b0\u1eddng \u0111\u1ed9 d\u00f2ng \u0111i\u1ec7n 5,1 ampe.<\/strong><\/p>\n

c) H\u00e3y x\u00e1c \u0111\u1ecbnh n\u1ed3ng \u0111\u1ed9 c\u00e1c ch\u1ea5t c\u00f3 trong dung d\u1ecbch sau \u0111i\u1ec7n ph\u00e2n. Bi\u1ebft r\u1eb1ng dung d\u1ecbch sau \u0111i\u1ec7n ph\u00e2n \u0111\u00e3 \u0111\u01b0\u1ee3c pha lo\u00e3ng cho \u0111\u1ee7 200 ml.<\/strong><\/p>\n

L\u1eddi gi\u1ea3i:<\/strong><\/p>\n

nCuCl2<\/sub>\u00a0= 13,5 : 135 = 0,1 mol ; nKCl<\/sub>\u00a0= 14,9 : 74,5 = 0,2 mol => nCl–<\/sup>\u00a0<\/sub>= 0,4 mol; nCu2+<\/sup>\u00a0<\/sub>= 0,1 mol<\/p>\n

\"\"<\/p>\n

Ph\u01b0\u01a1ng tr\u00ecnh \u0111i\u1ec7n ph\u00e2n : CuCl2<\/sub>\u00a0\u2192 Cu + Cl2<\/sub><\/p>\n

2KCl + 2H2<\/sub>O \u2192 2KOH + H2<\/sub>\u00a0+ Cl2<\/sub><\/p>\n

Kh\u1ed1i l\u01b0\u1ee3ng clo tho\u00e1t ra m = (71.5,1.7200) : (96500.2) = 13,5 gam<\/p>\n

=> nCl<\/sub>\u00a0= 0,19 mol => Cl–<\/sup>\u00a0c\u00f2n d\u01b0<\/p>\n

\"\"<\/p>\n

H\u1ebft Cu2+<\/sup>\u00a0: 2H2<\/sub>O + 2e \u2192 H2<\/sub>\u00a0+ 2OH–<\/sup>\u00a0(dd)<\/p>\n

Ch\u1ea5t c\u00f2n l\u1ea1i sau \u0111i\u1ec7n ph\u00e2n l\u00e0 K+<\/sup>\u00a00,2 mol; Cl–<\/sup>\u00a0d\u01b0 0,02 mol; OH–<\/sup>\u00a0d\u01b0 0,18 mol<\/p>\n

=> KOH 0,18 mol; KCl 0,02 mol<\/p>\n

c. CM KOH<\/sub>\u00a0= 0,18 : 0,2 = 0,9M.<\/p>\n

CM KCl<\/sub>\u00a0= 0,02 : 0,2 = 0,1M<\/p>\n

B\u00e0i 7 (trang 143 sgk H\u00f3a 12 n\u00e2ng cao):\u00a0Th\u1ef1c hi\u1ec7n s\u1ef1 \u0111i\u1ec7n ph\u00e2n dung d\u1ecbch CuSO4<\/sub>\u00a0v\u1edbi m\u1ed9t \u0111i\u1ec7n c\u1ef1c b\u1eb1ng graphit v\u00e0 m\u1ed9t \u0111i\u1ec7n c\u1ef1c b\u1eb1ng \u0111\u1ed3ng.<\/strong><\/p>\n

Th\u00ed nghi\u1ec7m 1: Ng\u01b0\u1eddi ta n\u1ed1i \u0111i\u1ec7n c\u1ef1c graphit v\u1edbi c\u1ef1c d\u01b0\u01a1ng v\u00e0 \u0111i\u1ec7n c\u1ef1c \u0111\u1ed3ng n\u1ed1i v\u1edbi c\u1ef1c \u00e2m c\u1ee7a ngu\u1ed3n \u0111i\u1ec7n.<\/p>\n

Th\u00ed nghi\u1ec7m 2: \u0110\u1ea3o l\u1ea1i, ng\u01b0\u1eddi ta n\u1ed1i \u0111i\u1ec7n c\u1ef1c graphit v\u1edbi c\u1ef1c \u00e2m v\u00e0 \u0111i\u1ec7n c\u1ef1c \u0111\u1ed3ng r\u1ed3i v\u1edbi c\u1ef1c d\u01b0\u01a1ng c\u1ee7a ngu\u1ed3n \u0111i\u1ec7n.<\/p>\n

1) H\u00e3y m\u00f4 t\u1ea3 hi\u1ec7n t\u01b0\u1ee3ng quan s\u00e1t \u0111\u01b0\u1ee3c v\u00e0 cho bi\u1ebft ph\u1ea3n \u1ee9ng x\u1ea3y ra \u1edf m\u1ed7i \u0111i\u1ec7n c\u1ef1c trong c\u00e1c th\u00ed nghi\u1ec7m tr\u00ean.<\/p>\n

2) H\u00e3y so s\u00e1nh \u0111\u1ed9 pH c\u1ee7a dung d\u1ecbch trong hai th\u00ed nghi\u1ec7m tr\u00ean.<\/p>\n

3) H\u00e3y so s\u00e1nh n\u1ed3ng \u0111\u1ed9 ion Cu2+<\/sup>\u00a0trong dung d\u1ecbch sau hai th\u00ed nghi\u1ec7m<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

1, Th\u00ed nghi\u1ec7m 1 :<\/p>\n

\"\"<\/p>\n

Ph\u01b0\u01a1ng tr\u00ecnh \u0111i\u1ec7n ph\u00e2n<\/p>\n

2Cu2+<\/sup>\u00a0+ 2H2<\/sub>O\u00a0\u0111pdd<\/sup>\u2192 2Cu + 4H+<\/sup>\u00a0+O2<\/sub><\/p>\n

Hi\u1ec7n t\u01b0\u1ee3ng : Kim lo\u1ea1i \u0111\u1ed3ng b\u00e1m v\u00e0o catot b\u1eb1ng \u0111\u1ed3ng<\/p>\n

– C\u00f3 kh\u00ed tho\u00e1t ra \u1edf anot b\u1eb1ng graphit<\/p>\n

– M\u00e0u xanh c\u1ee7a dung d\u1ecbch nh\u1ea1t d\u1ea7n<\/p>\n

Th\u00ed nghi\u1ec7m 2 :<\/p>\n

\"\"<\/p>\n

Ph\u01b0\u01a1ng tr\u00ecnh \u0111i\u1ec7n ph\u00e2n<\/p>\n

Cu2+<\/sup>dd<\/sub>\u00a0+ Cuanot<\/sub>\u00a0\u2192 Cucatot<\/sub>\u00a0+ Cu2+<\/sup>dd<\/sub><\/p>\n

Hi\u1ec7n t\u01b0\u1ee3ng :<\/p>\n

– Kim lo\u1ea1i \u0111\u1ed3ng b\u00e1m v\u00e0o catot b\u1eb1ng graphit<\/p>\n

– Anot b\u1eb1ng \u0111\u1ed3ng tan ra<\/p>\n

– M\u00e0u xanh c\u1ee7a dung d\u1ecbch kh\u00f4ng \u0111\u1ed5i<\/p>\n

2. N\u1ed3ng \u0111\u1ed9 H+<\/sup>\u00a0\u1edf th\u00ed nghi\u1ec7m 1 l\u1edbn h\u01a1n th\u00ed nghi\u1ec7m 2 => pHTN1<\/sub>\u00a0< pHTN2<\/sub><\/p>\n

3. N\u1ed3ng \u0111\u1ed9 Cu2+<\/sup>\u00a0\u1edf th\u00ed nghi\u1ec7m 1 gi\u1ea3m , \u1edf th\u00ed nghi\u1ec7m 2 kh\u00f4ng \u0111\u1ed5i .<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"

B\u00e0i 1 (trang 142 sgk H\u00f3a 12 n\u00e2ng cao):\u00a0Trong qu\u00e1 tr\u00ecnh \u0111i\u1ec7n ph\u00e2n dung d\u1ecbch Pb(NO3)2\u00a0v\u1edbi c\u00e1c \u0111i\u1ec7n c\u1ef1c tr\u01a1, ion Pb2+\u00a0di chuy\u1ec3n v\u1ec1 A. catot v\u00e0 b\u1ecb oxi h\u00f3a. B. anot v\u00e0 b\u1ecb oxi h\u00f3a. C. catot v\u00e0 b\u1ecb kh\u1eed. D. anot v\u00e0 b\u1ecb kh\u1eed. L\u1eddi gi\u1ea3i: \u0110\u00e1p \u00e1n C B\u00e0i 2 (trang 142 […]<\/p>\n","protected":false},"author":3,"featured_media":25190,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1306],"tags":[1436,1435],"yoast_head":"\nCh\u01b0\u01a1ng 5 - B\u00e0i 25: Luy\u1ec7n t\u1eadp: S\u1ef1 \u0111i\u1ec7n ph\u00e2n - S\u1ef1 \u0103n m\u00f2n kim lo\u1ea1i - \u0110i\u1ec1u ch\u1ebf kim lo\u1ea1i<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/chuong-5-bai-25-luyen-tap-su-dien-phan-su-an-mon-kim-loai-dieu-che-kim-loai\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Ch\u01b0\u01a1ng 5 - B\u00e0i 25: Luy\u1ec7n t\u1eadp: S\u1ef1 \u0111i\u1ec7n ph\u00e2n - S\u1ef1 \u0103n m\u00f2n kim lo\u1ea1i - \u0110i\u1ec1u ch\u1ebf kim lo\u1ea1i\" \/>\n<meta property=\"og:description\" content=\"B\u00e0i 1 (trang 142 sgk H\u00f3a 12 n\u00e2ng cao):\u00a0Trong qu\u00e1 tr\u00ecnh \u0111i\u1ec7n ph\u00e2n dung d\u1ecbch Pb(NO3)2\u00a0v\u1edbi c\u00e1c \u0111i\u1ec7n c\u1ef1c tr\u01a1, ion Pb2+\u00a0di chuy\u1ec3n v\u1ec1 A. catot v\u00e0 b\u1ecb oxi h\u00f3a. B. anot v\u00e0 b\u1ecb oxi h\u00f3a. C. catot v\u00e0 b\u1ecb kh\u1eed. D. anot v\u00e0 b\u1ecb kh\u1eed. 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