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{"id":25174,"date":"2018-04-03T22:07:58","date_gmt":"2018-04-03T15:07:58","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=25174"},"modified":"2018-04-03T22:07:58","modified_gmt":"2018-04-03T15:07:58","slug":"chuong-6-bai-31-mot-so-hop-chat-quan-trong-cua-kim-loai-kiem-tho","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/chuong-6-bai-31-mot-so-hop-chat-quan-trong-cua-kim-loai-kiem-tho\/","title":{"rendered":"Ch\u01b0\u01a1ng 6 – B\u00e0i 31: M\u1ed9t s\u1ed1 h\u1ee3p ch\u1ea5t quan tr\u1ecdng c\u1ee7a kim lo\u1ea1i ki\u1ec1m th\u1ed5"},"content":{"rendered":"

B\u00e0i 1 (trang 167 sgk H\u00f3a 12 n\u00e2ng cao):\u00a0Ch\u1ea5t n\u00e0o sau \u0111\u00e2y kh\u00f4ng b\u1ecb ph\u00e2n h\u1ee7y khi nung n\u00f3ng?<\/strong><\/p>\n

A. Mg(NO3<\/sub>)2<\/sub><\/p>\n

B. CaCO3<\/sub><\/p>\n

C. CaSO4<\/sub><\/p>\n

D. Mg(OH)2<\/sub><\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

\u0110\u00e1p \u00e1n C<\/p>\n

B\u00e0i 2 (trang 167 sgk H\u00f3a 12 n\u00e2ng cao):\u00a0Theo thuy\u1ebft Br\u00f3n-stet, ion n\u00e0o sau \u0111\u00e2y (trong dung d\u1ecbch) c\u00f3 t\u00ednh l\u01b0\u1ee1ng t\u00ednh?<\/strong><\/p>\n

A. CO3<\/sub>2-<\/sup><\/p>\n

B. OH–<\/sup><\/p>\n

C. Ca2+<\/sup><\/p>\n

D. HCO3<\/sub>–<\/sup><\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

\u0110\u00e1p \u00e1n D<\/p>\n

B\u00e0i 3 (trang 167 sgk H\u00f3a 12 n\u00e2ng cao):\u00a0N\u01b0\u1edbc t\u1ef1 nhi\u00ean c\u00f3 ch\u1ee9a ion n\u00e0o d\u01b0\u1edbi \u0111\u00e2y \u0111\u01b0\u1ee3c g\u1ecdi l\u00e0 n\u01b0\u1edbc c\u00f3 t\u00ednh c\u1ee9ng t\u1ea1m th\u1eddi?<\/strong><\/p>\n

A. Ca2+<\/sup>, Mg2+<\/sup>, Cl–<\/sup><\/p>\n

B. Ca2+<\/sup>, Mg2+<\/sup>, SO4<\/sub>2-<\/sup>.<\/p>\n

C. Cl–<\/sup>, SO4<\/sub>2-<\/sup>, HCO3<\/sub>–<\/sup>\u00a0,Ca2+<\/sup>.<\/p>\n

D. HCO3<\/sub>–<\/sup>,Ca2+<\/sup>, Mg2+<\/sup>.<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

\u0110\u00e1p \u00e1n D<\/p>\n

\n
\n

B\u00e0i 4 (trang 167 sgk H\u00f3a 12 n\u00e2ng cao):\u00a0M\u1ed9t lo\u1ea1i n\u01b0\u1edbc c\u1ee9ng khi \u0111un s\u00f4i th\u00ec m\u1ea5t t\u00ednh c\u1ee9ng, trong lo\u1ea1i n\u01b0\u1edbc c\u1ee9ng n\u00e0y c\u00f3 h\u00f2a tan nh\u1eefng h\u1ee3p ch\u1ea5t n\u00e0o sau \u0111\u00e2y?<\/strong><\/p>\n

A. Ca(HCO3<\/sub>)2<\/sub>, MgCl2<\/sub>.<\/p>\n

B. Ca(HCO3<\/sub>)2<\/sub>, Mg(HCO3<\/sub>)2<\/sub><\/p>\n

C. Mg(HCO3<\/sub>)2<\/sub>, CaCl2<\/sub>.<\/p>\n

D. MgCl2<\/sub>, Ca2SO4<\/sub>.<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

\u0110\u00e1p \u00e1n D<\/p>\n

B\u00e0i 5 (trang 167 sgk H\u00f3a 12 n\u00e2ng cao):\u00a0Cho c\u00e1c ch\u1ea5t:<\/strong><\/p>\n

A. NaCl<\/strong><\/p>\n

B. Ca(OH)2<\/sub><\/strong><\/p>\n

C. Na2<\/sub>CO3<\/sub><\/strong><\/p>\n

D. HCl<\/strong><\/p>\n

E. BaCl2<\/sub><\/strong><\/p>\n

F. Na2<\/sub>SO4<\/sub><\/strong><\/p>\n

Nh\u1eefng ch\u1ea5t n\u00e0o c\u00f3 th\u1ec3<\/strong><\/p>\n

a. l\u00e0m m\u1ec1m n\u01b0\u1edbc c\u00f3 t\u00ednh c\u1ee9ng t\u1ea1m th\u1eddi.<\/strong><\/p>\n

b. l\u00e0m m\u1ec1m n\u01b0\u1edbc c\u00f3 t\u00ednh c\u1ee9ng v\u0129nh c\u1eedu.<\/strong><\/p>\n

Vi\u1ebft c\u00e1c ph\u01b0\u01a1ng tr\u00ecnh h\u00f3a h\u1ecdc.<\/strong><\/p>\n

L\u1eddi gi\u1ea3i:<\/strong><\/p>\n

a, \u0110\u00e1p \u00e1n B ho\u1eb7c C<\/p>\n

\u0110\u1ec3 l\u00e0m m\u1ec1m n\u01b0\u1edbc c\u1ee9ng t\u1ea1m th\u1eddi c\u00f3 th\u1ec3 d\u00f9ng Ca(OH)2<\/sub>\u00a0ho\u1eb7c Na2<\/sub>CO3<\/sub>\u00a0do ch\u00fang l\u00e0m k\u1ebft t\u1ee7a Ca2+<\/sup>\u00a0v\u00e0 Mg2+<\/sup>\u00a0d\u01b0\u1edbi d\u1ea1ng mu\u1ed1i cacbonat theo c\u00e1c ph\u01b0\u01a1ng tr\u00ecnh :<\/p>\n

Ca(OH)2<\/sub>\u00a0OH–<\/sup>\u00a0+ HCO3<\/sub>– \u2192 CO3<\/sub>2-<\/sup>\u00a0+H2<\/sub>O<\/p>\n

CO3<\/sub>2-<\/sup>\u00a0+ Mg2+<\/sup>\u00a0\u2192 MgCO3<\/sub>\u00a0\u2193<\/p>\n

CO3<\/sub>2-<\/sup>\u00a0+ Ca2+<\/sup>\u00a0\u2192 CaCO3<\/sub>\u00a0\u2193<\/p>\n

Na2<\/sub>CO3<\/sub>: CO3<\/sub>2-<\/sup>\u00a0+ Mg2+<\/sup>\u00a0\u2192 MgCO3<\/sub>\u00a0\u2193<\/p>\n

CO3<\/sub>2-<\/sup>\u00a0+ Ca2+<\/sup>\u00a0\u2192 CaCO3<\/sub>\u00a0\u2193<\/p>\n

b. \u0110\u00e1p \u00e1n C(ph\u1ea3n \u1ee9ng xem ph\u1ea7n a)<\/p>\n

B\u00e0i 6 (trang 167 sgk H\u00f3a 12 n\u00e2ng cao):\u00a0a. C\u00f3 4 ch\u1ea5t r\u1eafn \u0111\u1ef1ng trong 4 l\u1ecd ri\u00eang bi\u1ec7t: Na2<\/sub>CO3<\/sub>, CaCO3<\/sub>, Na2<\/sub>SO4<\/sub>. CaSO.2H2<\/sub>O. B\u1eb1ng c\u00e1ch n\u00e0o \u0111\u1ec3 nh\u1eadn bi\u1ebft 4 ch\u1ea5t, n\u1ebfu ta ch\u1ec9 d\u00f9ng n\u01b0\u1edbc v\u00e0 dung d\u1ecbch axit HCl.<\/strong><\/p>\n

b. C\u00f3 3 ch\u1ea5t r\u1eafn \u0111\u1ef1ng trong 3 l\u1ecd ri\u00eang bi\u1ec7t: NaCl, CaCl2<\/sub>\u00a0v\u00e0 MgCl2<\/sub>. H\u00e3y tr\u00ecnh b\u00e0y ph\u01b0\u01a1ng ph\u00e1p h\u00f3a h\u1ecdc \u0111\u1ec3 nh\u1eadn bi\u1ebft m\u1ed7i ch\u1ea5t (c\u00f3 \u0111\u1ee7 d\u1ee5ng c\u1ee5 v\u00e0 nh\u1eefng h\u00f3a ch\u1ea5t c\u1ea7n thi\u1ebft).<\/strong><\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

a, H\u00f2a tan 4 ch\u1ea5t v\u00e0o n\u01b0\u1edbc ta thu \u0111\u01b0\u1ee3c hai nh\u00f3m:<\/p>\n

– Nh\u00f3m tan nhi\u1ec1u trong n\u01b0\u1edbc c\u00f3 Na2<\/sub>CO3<\/sub>\u00a0v\u00e0 Na2<\/sub>SO4<\/sub>.<\/p>\n

– Nh\u00f3m \u00edt tan trong n\u01b0\u1edbc c\u00f3 CaCO3<\/sub>\u00a0v\u00e0 CaSO4<\/sub>.2H2<\/sub>O Nh\u1ecf dung d\u1ecbch HCl v\u00e0o t\u1eebng ch\u1ea5t thu\u1ed9c hai nh\u00f3m tr\u00ean<\/p>\n

– Nh\u1eadn ra Na2<\/sub>CO3<\/sub>\u00a0v\u00ec c\u00f3 kh\u00ed tho\u00e1t ra c\u00f2n Na2<\/sub>SO4<\/sub>\u00a0th\u00ec kh\u00f4ng<\/p>\n

Na2<\/sub>CO3<\/sub>\u00a0+ 2HCl \u2192 2NaCl + CO2<\/sub>\u00a0+ H2<\/sub>O<\/p>\n

– Nh\u1eadn ra CaCO3<\/sub>\u00a0v\u00ec c\u00f3 kh\u00ed c\u00f2n CaSO4<\/sub>.2H2<\/sub>O th\u00ec kh\u00f4ng<\/p>\n

CaCO3<\/sub>\u00a0+ 2HCl \u2192 CaCl2<\/sub>\u00a0+ CO2<\/sub>\u00a0+ H2<\/sub>O<\/p>\n

b, L\u1ea5y m\u1ed7i l\u1ecd m\u1ed9t \u00edt ch\u1ea5t r\u1eafn \u0111em h\u00f2a tan v\u00e0o n\u01b0\u1edbc, \u0111\u00e1nh s\u1ed1 r\u1ed3i chia l\u00e0m hai ph\u1ea7n<\/p>\n

Ph\u1ea7n 1: Nh\u00f2 t\u1eeb t\u1eeb dung d\u1ecbch NaOH v\u00e0o, nh\u1eadn ra \u1ed1ng \u0111\u1ef1ng MgCl2<\/sub>\u00a0v\u00ec c\u00f3 k\u1ebft t\u1ee7a<\/p>\n

2NaOH + MgCl2<\/sub>\u00a0\u2192 Mg(OH)2<\/sub>\u00a0\u2193 + 2NaCl<\/p>\n

Ph\u1ea7n 2 : Lo\u1ea1i b\u1ecf \u1ed1ng nghi\u1ec7m MgCl2<\/sub>\u00a0\u0111\u00e3 nh\u1eadn ra, nh\u1ecf t\u1eeb t\u1eeb dung d\u1ecbch Na2<\/sub>CO3<\/sub>\u00a0v\u00e0o nh\u1eadn ra \u1ed1ng \u0111\u1ef1ng CaCl2<\/sub>\u00a0v\u00ec c\u00f3 k\u1ebft t\u1ee7a<\/p>\n

CaCl2<\/sub>\u00a0+ Na2<\/sub>CO3<\/sub>\u00a0\u2192 CaCO3<\/sub>\u00a0+ 2NaCl<\/p>\n

C\u00f2n l\u1ea1i l\u00e0 NaCl<\/p>\n

B\u00e0i 7 (trang 167 sgk H\u00f3a 12 n\u00e2ng cao):\u00a0Trong t\u1ef1 nhi\u00ean c\u00e1c nguy\u00ean t\u1ed1 magie v\u00e0 canxi c\u00f3 trong qu\u1eb7ng \u0111\u00f4l\u00f4mit: CaCO3<\/sub>.MgCO3<\/sub>. T\u1eeb qu\u1eb7ng n\u00e0y h\u00e3y tr\u00ecnh b\u00e0y ph\u01b0\u01a1ng ph\u00e1p \u0111i\u1ec1u ch\u1ebf:<\/p>\n

a. Hai ch\u1ea5t ri\u00eang bi\u1ec7t l\u00e0 CaCO3<\/sub>v\u00e0 MgCO3<\/sub>.<\/p>\n

b. Hai kim lo\u1ea1i ri\u00eang bi\u1ec7t l\u00e0 Ca v\u00e0 Mg.<\/p>\n

Vi\u1ebft c\u00e1c ph\u01b0\u01a1ng tr\u00ecnh h\u00f3a h\u1ecdc.<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

S\u01a1 \u0111\u1ed3 t\u00e1ch<\/p>\n

\"\"<\/p>\n

\n

CaCO3<\/sub>\u00a0+ 2HCl \u2192 CaCl2<\/sub>\u00a0+ CO2<\/sub>\u00a0+ 2H2<\/sub>O<\/p>\n

MgCO3<\/sub>\u00a0+ 2HCl \u2192 MgCl2<\/sub>\u00a0+ CO2<\/sub>\u00a0+ 2H2<\/sub>O<\/p>\n

MgCl2<\/sub>\u00a0+ 2NaOH \u2192 Mg(OH)2<\/sub>\u00a0\u2193 + 2NaCl<\/p>\n

– L\u1ecdc t\u00e1ch ph\u1ea7n kh\u00f4ng tan th\u00ec dung d\u1ecbch c\u00f2n ch\u1ee9a c\u00e1c ion Ca2+<\/sup>, Cl–<\/sup>, Na+<\/sup>, OH–<\/sup>\u00a0th\u00eam Na2<\/sub>CO3<\/sub>\u00a0v\u00e0o dung d\u1ecbch ta thu CaCO3<\/sub>\u00a0k\u1ebft t\u1ee7a<\/p>\n

Ca2+<\/sup>\u00a0+ CO3<\/sub>2<\/sup>\u00a0\u2192 CaCO3<\/sub><\/p>\n

CaCO3<\/sub>\u00a0+ 2HCl \u2192 CaCl2<\/sub>\u00a0+ CO2<\/sub>\u00a0+ 2H2<\/sub>O<\/p>\n

CaCl2<\/sub>\u00a0\u0111pnc<\/sup>\u2192 Ca + Cl2<\/sub><\/p>\n

Mg(OH)2<\/sub>\u00a0+ 2HCl \u2192 MgCl2<\/sub>\u00a0+ 2H2<\/sub>O<\/p>\n

MgCl2<\/sub>\u00a0+ Na2<\/sub>CO3<\/sub>\u00a0\u2192 MgCO3<\/sub>\u00a0+ 2NaCl<\/p>\n

MgCl2<\/sub>\u00a0\u0111pnc<\/sup>\u2192 Mg + Cl2<\/sub><\/p>\n

B\u00e0i 8 (trang 168 sgk H\u00f3a 12 n\u00e2ng cao):\u00a0D\u1ef1a v\u00e0o b\u1ea3ng t\u00ednh tan c\u1ee7a m\u1ed9t s\u1ed1 h\u1ee3p ch\u1ea5t kim lo\u1ea1i ki\u1ec1m th\u1ed5 (xem ph\u1ea7n t\u01b0 li\u1ec7u), h\u00e3v x\u00e9t xem ph\u1ea3n \u1ee9ng n\u00e0o sau \u0111\u00e2y x\u1ea3y ra:<\/strong><\/p>\n

Mg(OH)2<\/sub>\u00a0+ Ca2+<\/sup>\u00a0\u2192 Ca(OH)2<\/sub>\u00a0+ Mg2+<\/sup>.<\/p>\n

Ca(OH)2<\/sub>\u00a0+ Mg2+<\/sup>\u00a0\u2192 Mg(OH)2<\/sub>\u00a0+ Ca2+<\/sup><\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

Ph\u1ea3n \u1ee9ng x\u1ea3y ra l\u00e0 :<\/p>\n

Ca(OH)2<\/sub>\u00a0+ Mg2+<\/sup>\u00a0\u2192 Mg(OH)2<\/sub>\u00a0+ Ca2+<\/sup><\/p>\n

\u0110\u1ed9 tan c\u1ee7a Ca(OH)2<\/sub>\u00a0l\u00e0 16.10-4<\/sup>\u00a0mol\/100 g H2<\/sub>O c\u00f2n Mg(OH)2<\/sub>\u00a0l\u00e0 0,2.10-4<\/sup>\u00a0mol\/100g H2<\/sub>O<\/p>\n

=> Ph\u1ea3n \u1ee9ng di\u1ec5n ra do t\u1ea1o ch\u1ea5t Mg(OH)2<\/sub>\u00a0l\u00e0 ch\u1ea5t \u00edt tan trong n\u01b0\u1edbc h\u01a1n nhi\u1ec1u so v\u1edbi Ca(OH)2<\/sub><\/p>\n

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\n

B\u00e0i 9 (trang 168 sgk H\u00f3a 12 n\u00e2ng cao):\u00a0Cho 10 l\u00edt (\u0111ktc) h\u1ed7n h\u1ee3p kh\u00ed g\u1ed3m N2<\/sub>\u00a0v\u00e0 CO2\u00a0<\/sub>t\u00e1c d\u1ee5ng v\u1edbi 2 l\u00edt dung d\u1ecbch Ca(OH)2<\/sub>\u00a00,02 mol\/l, thu \u0111\u01b0\u1ee3c 1 gam ch\u1ea5t k\u1ebft t\u1ee7a. H\u00e3y x\u00e1c \u0111\u1ecbnh th\u00e0nh ph\u1ea7n % theo th\u1ec3 t\u00edch c\u1ee7a m\u1ed7i kh\u00ed trong h\u1ed7n h\u1ee3p ban \u0111\u1ea7u?<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

CO2<\/sub>\u00a0+ Ca(OH)2<\/sub>\u00a0\u2192 CaCO3<\/sub>\u00a0\u2193 + H2<\/sub>O (1)<\/p>\n

N\u1ebfu d\u01b0 CO2<\/sub>\u00a0d\u01b0 : CO2<\/sub>\u00a0+ CaCO3<\/sub>\u00a0+ H2<\/sub>O \u2192 Ca(HCO3<\/sub>)2<\/sub>\u00a0(2)<\/p>\n

* Tr\u01b0\u1eddng h\u1ee3p 1 : N\u1ebfu CO2<\/sub>\u00a0kh\u00f4ng d\u01b0 :<\/p>\n

nCO2<\/sub>\u00a0= nCaCO3<\/sub>\u00a0= 1 : 100 = 0,01 mol => VCO2<\/sub>\u00a0= 0,01 . 22,4 = 0,224 (l\u00edt)<\/p>\n

=> %(V) CO2<\/sub>\u00a0= 0,224 : 10 . 100 = 2,24%<\/p>\n

%(V)N2<\/sub>\u00a0= 100 \u2013 2,24 = 97,76%<\/p>\n

*Tr\u01b0\u1eddng h\u1ee3p 2 : N\u1ebfu CO2<\/sub>\u00a0d\u01b0, x\u1ea3y ra ph\u01b0\u01a1ng tr\u00ecnh s\u1ed1 2<\/p>\n

nCa(OH)2<\/sub>\u00a0= 2.0,02 = 0,04 mol<\/p>\n

Theo (1) nCO2<\/sub>\u00a0= nCa(OH)2<\/sub>\u00a0= nCaCO3<\/sub>\u00a0= 0,04 mol<\/p>\n

Nh\u01b0ng theo \u0111\u1ec1 b\u00e0i ch\u1ec9 thu \u0111\u01b0\u1ee3c 0,01 mol k\u1ebft t\u1ee7a => c\u00f3 0,03 mol k\u1ebft t\u1ee7a b\u1ecb h\u00f2a tan theo ph\u01b0\u01a1ng tr\u00ecnh (2)<\/p>\n

nCO2<\/sub>\u00a0= nCaCO3<\/sub>\u00a0tan ra = 0,03<\/p>\n

T\u1ed5ng s\u1ed1 mol CO2<\/sub>\u00a0= 0,04 + 0,03 = 0,07 (mol)<\/p>\n

=> VCO2<\/sub>\u00a0= 0,07.22,4 = 1,568 l\u00edt<\/p>\n

=> %(V) CO2<\/sub>\u00a0= 1,568 : 10 . 100 = 15,68%<\/p>\n

%(V)N2<\/sub>\u00a0= 100 \u2013 15,68 = 84,32%<\/p>\n

B\u00e0i 10 (trang 168 sgk H\u00f3a 12 n\u00e2ng cao):\u00a0C\u00f3 ba c\u1ed1c \u0111\u1ef1ng l\u1ea7n l\u01b0\u1ee3t: n\u01b0\u1edbc m\u01b0a, n\u01b0\u1edbc c\u00f3 t\u00ednh c\u1ee9ng t\u1ea1m th\u1eddi, n\u01b0\u1edbc c\u00f3 t\u00ednh c\u1ee9ng v\u0129nh c\u1eedu. H\u00e3y nh\u1eadn bi\u1ebft n\u01b0\u1edbc \u0111\u1ef1ng trong m\u1ed7i c\u1ed1c b\u1eb1ng ph\u01b0\u01a1ng ph\u00e1p h\u00f3a h\u1ecdc. Vi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh ph\u1ea3n \u1ee9ng.<\/strong><\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

\u0110un n\u00f3ng 3 c\u1ed1c , c\u1ed1c c\u00f3 k\u1ebft t\u1ee7a xu\u1ea5t hi\u1ec7n l\u00e0 c\u1ed1c c\u00f3 ch\u1ee9a n\u01b0\u1edbc c\u1ee9ng t\u1ea1m th\u1eddi<\/p>\n

Ca(HCO3<\/sub>)2<\/sub>\u00a0to<\/sup>\u00a0\u2192 CO2<\/sub>\u00a0+ CaCO3<\/sub>\u00a0+ H2<\/sub>O<\/p>\n

Mg(HCO3<\/sub>)2<\/sub>\u00a0to<\/sup>\u00a0\u2192 CO2<\/sub>\u00a0+ MgCO3<\/sub>\u00a0+ H2<\/sub>O<\/p>\n

Nh\u1ecf dung d\u1ecbch Na2CO3<\/sub>\u00a0v\u00e0o hai m\u1eabu n\u01b0\u1edbc c\u00f2n l\u1ea1i, c\u1ed1c c\u00f3 k\u1ebft t\u1ee7a xu\u1ea5t hi\u1ec7n l\u00e0 c\u1ed1c n\u01b0\u1edbc c\u1ee9ng v\u0129nh c\u1eedu, c\u00f2n l\u1ea1i l\u00e0 n\u01b0\u1edbc m\u01b0a (n\u01b0\u1edbc m\u1ec1m)<\/p>\n

CO3<\/sub>2-<\/sup>\u00a0+ Mg2+<\/sup>\u00a0\u2192 MgCO3<\/sub>\u00a0\u2193<\/p>\n

CO3<\/sub>2-<\/sup>\u00a0+ Ca2+<\/sup>\u00a0\u2192 CaCO3<\/sub>\u00a0\u2193<\/p>\n<\/div>\n<\/div>\n

\n
<\/div>\n<\/div>\n<\/div>\n<\/div>\n
\n
<\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"

B\u00e0i 1 (trang 167 sgk H\u00f3a 12 n\u00e2ng cao):\u00a0Ch\u1ea5t n\u00e0o sau \u0111\u00e2y kh\u00f4ng b\u1ecb ph\u00e2n h\u1ee7y khi nung n\u00f3ng? A. Mg(NO3)2 B. CaCO3 C. CaSO4 D. Mg(OH)2 L\u1eddi gi\u1ea3i: \u0110\u00e1p \u00e1n C B\u00e0i 2 (trang 167 sgk H\u00f3a 12 n\u00e2ng cao):\u00a0Theo thuy\u1ebft Br\u00f3n-stet, ion n\u00e0o sau \u0111\u00e2y (trong dung d\u1ecbch) c\u00f3 t\u00ednh l\u01b0\u1ee1ng t\u00ednh? A. […]<\/p>\n","protected":false},"author":3,"featured_media":25176,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1306],"tags":[1436,1435],"yoast_head":"\nCh\u01b0\u01a1ng 6 - B\u00e0i 31: M\u1ed9t s\u1ed1 h\u1ee3p ch\u1ea5t quan tr\u1ecdng c\u1ee7a kim lo\u1ea1i ki\u1ec1m th\u1ed5<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/chuong-6-bai-31-mot-so-hop-chat-quan-trong-cua-kim-loai-kiem-tho\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Ch\u01b0\u01a1ng 6 - B\u00e0i 31: M\u1ed9t s\u1ed1 h\u1ee3p ch\u1ea5t quan tr\u1ecdng c\u1ee7a kim lo\u1ea1i ki\u1ec1m th\u1ed5\" \/>\n<meta property=\"og:description\" content=\"B\u00e0i 1 (trang 167 sgk H\u00f3a 12 n\u00e2ng cao):\u00a0Ch\u1ea5t n\u00e0o sau \u0111\u00e2y kh\u00f4ng b\u1ecb ph\u00e2n h\u1ee7y khi nung n\u00f3ng? A. Mg(NO3)2 B. CaCO3 C. CaSO4 D. Mg(OH)2 L\u1eddi gi\u1ea3i: \u0110\u00e1p \u00e1n C B\u00e0i 2 (trang 167 sgk H\u00f3a 12 n\u00e2ng cao):\u00a0Theo thuy\u1ebft Br\u00f3n-stet, ion n\u00e0o sau \u0111\u00e2y (trong dung d\u1ecbch) c\u00f3 t\u00ednh l\u01b0\u1ee1ng t\u00ednh? A. 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