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{"id":25162,"date":"2018-04-03T18:04:20","date_gmt":"2018-04-03T11:04:20","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=25162"},"modified":"2018-04-03T18:04:20","modified_gmt":"2018-04-03T11:04:20","slug":"chuong-3-bai-16-giao-thoa-song","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/chuong-3-bai-16-giao-thoa-song\/","title":{"rendered":"Ch\u01b0\u01a1ng 3 – B\u00e0i 16: Giao thoa s\u00f3ng"},"content":{"rendered":"

C\u00c2U H\u1eceI<\/strong><\/p>\n

C\u00e2u 1 (trang 88 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0H\u00e3y gi\u1ea3i th\u00edch hi\u1ec7n t\u01b0\u01a1ng t\u1ea1o th\u00e0nh v\u00e2n giao thoa tr\u00ean m\u1eb7t n\u01b0\u1edbc.<\/span><\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

Gi\u1ea3 s\u1eed Ph\u01b0\u01a1ng tr\u00ecnh dao \u0111\u1ed9ng: T\u1ea1i A: u = Acos2\u03c0ft<\/p>\n

Coi kho\u1ea3ng c\u00e1ch gi\u1eefa A, B l\u00e0 nh\u1ecf.<\/p>\n

S\u00f3ng t\u1ea1i M t\u1eeb A truy\u1ec1n \u0111\u1ebfn c\u00f3 d\u1ea1ng: uA<\/sub>\u00a0= Acos2\u03c0(t\/T – d1<\/sub>\/\u03b1)<\/p>\n

S\u00f3ng t\u1ea1i M t\u1eeb B truy\u1ec1n \u0111\u1ebfn c\u00f3 d\u1ea1ng: uB<\/sub>\u00a0= Acos2\u03c0(t\/T – d2<\/sub>\/\u03b1)<\/p>\n

T\u1ea1i \u0111i\u1ec3m M bi\u00ean \u0111\u1ed9 dao \u0111\u1ed9 dao \u0111\u1ed9ng t\u1ed5ng h\u1ee3p c\u00f3 d\u1ea1ng AM<\/sub>\u00a0= 2A|cos\u2061[\u2206\u03c6\/2]|, nh\u01b0 v\u1eady t\u00f9y theo hi\u1ec7u \u0111\u01b0\u1eddng \u0111i d1<\/sub>\u00a0– d2<\/sub>\u00a0m\u00e0 \u0111i\u1ec3m M l\u00e0 m\u1ed9t c\u1ef1c d\u1ea1i ho\u1eb7c c\u1ef1c ti\u1ec3u. Qu\u1ef9 t\u00edch \u0111i\u1ec3m \u0111\u00f3 l\u00e0 c\u00e1c \u0111\u01b0\u1eddng h\u00eaplbol<\/p>\n

C\u00e2u 2 (trang 88 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0Gi\u1ea3i th\u00edch v\u00ec sao hai s\u00f3ng m\u1eb7t n\u01b0\u1edbc xu\u1ea5t ph\u00e1t t\u1eeb ngu\u1ed3n k\u1ebft h\u1ee3p giao nhau l\u1ea1i kh\u00f4ng t\u1ea1o th\u00e0nh v\u00e2n giao thoa.<\/span><\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

Hai s\u00f3ng m\u1eb7t n\u01b0\u1edbc xu\u1ea5t ph\u00e1t t\u1eeb hai ngu\u1ed3n k\u1ebft h\u1ee3p giao v\u1edbi nhau l\u1ea1i kh\u00f4ng t\u1ea1o th\u00e0nh v\u00e2n giao thoa v\u00ec n\u1ebfn kh\u00f4ng ph\u1ea3i l\u00e0 s\u00f3ng k\u1ebft h\u1ee3p th\u00ec \u0111\u1ed9 l\u1ec7ch pha \u2206\u03c6 lu\u00f4n lu\u00f4n thay \u0111\u1ed5i n\u00ean v\u1ecb tr\u00ed c\u1ee7a c\u00e1c \u0111i\u1ec3m c\u1ef1c d\u1ea1i hay c\u1ef1c ti\u1ec3u lu\u00f4n bi\u1ebfn \u0111\u1ed5i v\u00ec v\u1eady kh\u00f4ng c\u00f3 v\u00e2n giao thoa c\u00f3 v\u1ecb tr\u00ed \u1ed5n \u0111\u1ecbnh.<\/p>\n

\n
B\u00c0I T\u1eacP<\/strong><\/div>\n
<\/div>\n
\n

B\u00e0i 1 (trang 89 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0\u0110i\u1ec1u ki\u1ec7n c\u00f3 giao thoa s\u00f3ng l\u00e0<\/span><\/p>\n

A. Hai s\u00f3ng chuy\u1ec3n \u0111\u1ed9ng ng\u01b0\u1ee3c chi\u1ec1u giao nhau.<\/p>\n

B. Hai s\u00f3ng c\u00f9ng t\u1ea7n s\u1ed1 v\u00e0 c\u00f3 \u0111\u1ed9 l\u1ec7ch pha kh\u00f4ng \u0111\u1ed5i giao nhau.<\/p>\n

C. Hai s\u00f3ng c\u00f3 c\u00f9ng b\u01b0\u1edbc s\u00f3ng giao nhau.<\/p>\n

D. Hai s\u00f3ng c\u00f3 c\u00f9ng bi\u00ean \u0111\u1ed9, c\u00f9ng t\u1ed1c \u0111\u1ed9 giao nhau.<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

Ch\u1ecdn B<\/p>\n

B\u00e0i 2 (trang 89 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0Hai s\u00f3ng k\u1ebft h\u1ee3p l\u00e0<\/span><\/p>\n

A. Hai d\u00f3ng chuy\u1ec3n \u0111\u1ed9ng c\u00f9ng chi\u1ec1u v\u1edbi t\u1ed1c \u0111\u1ed9<\/p>\n

B. Hai s\u00f3ng lu\u00f4n \u0111i k\u00e8m v\u1edbi nhau.<\/p>\n

C. Hai s\u00f3ng c\u00f3 c\u00f9ng t\u1ea7n s\u1ed1 v\u00e0 c\u00f3 \u0111\u1ed9 l\u1ec7ch pha kh\u00f4ng \u0111\u1ed5i theo th\u1eddi gian<\/p>\n

D. Hai s\u00f3ng c\u00f9ng b\u01b0\u1edbc s\u00f3ng v\u00e0 c\u00f3 \u0111\u1ed9 l\u1ec7ch pha bi\u1ebfn th\u00e0nh tu\u1ea7n ho\u00e0n.<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

Ch\u1ecdn C<\/p>\n

B\u00e0i 3 (trang 89 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0Khi m\u1ed9t s\u00f3ng m\u1eb7t n\u01b0\u1edbc g\u1eb7p m\u1ed9t khe ch\u1eafn h\u1eb9p c\u00f3 k\u00edch th\u01b0\u1edbc nh\u1ecf h\u01a1n b\u01b0\u1edbc s\u00f3ng th\u00ec<\/span><\/p>\n

A. S\u00f3ng v\u1eabn ti\u1ebfp t\u1ee5c truy\u1ec1n th\u1eb3ng khe.<\/p>\n

B. S\u00f3ng g\u1eb7p khe b\u1ecb ph\u1ea3n x\u1ea1 l\u1ea1i<\/p>\n

C. S\u00f3ng truy\u1ec1n qua khe gi\u1ed1ng nh\u01b0 khe l\u00e0 m\u1ed9t t\u00e2m ph\u00e1t s\u00f3ng m\u1edbi.<\/p>\n

D. S\u00f3ng g\u1eb7p khe s\u1ebd dung l\u1ea1i.<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

Ch\u1ecdn C<\/p>\n

B\u00e0i 4 (trang 89 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0Trong m\u1ed9t th\u00ed nghi\u1ec7m t\u1ea1o v\u00e2n thoa tr\u00ean s\u00f3ng n\u01b0\u1edbc, ng\u01b0\u1eddi ta \u0111\u00f9ng hai ngu\u1ed3n dao \u0111\u1ed9ng pha c\u00f3 t\u1ea7n s\u1ed1 50 Hz v\u00e0 \u0111o \u0111\u01b0\u1ee3c kho\u1ea3ng c\u00e1ch gi\u1eefa hai v\u00e2n c\u1ef1c ti\u1ec3u li\u00ean ti\u1ebfp n\u1eb1m tr\u00ean \u0111\u01b0\u1eddng n\u1ed1i li\u1ec1n t\u00e2m dao \u0111\u1ed9ng l\u00e0 2 mm. T\u00ecm b\u01b0\u1edbc s\u00f3ng v\u00e0 t\u1ed1c \u0111\u1ed9 truy\u1ec1n s\u00f3ng.<\/span><\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

T\u01b0\u01a1ng t\u1ef1 nh\u01b0 s\u00f3ng d\u1eebng. Tr\u00ean \u0111\u01b0\u1eddng n\u1ed1i li\u00ean t\u00e2m dao \u0111\u1ed9ng v\u00e2n l\u1ed1i \u1ee9ng v\u1edbi b\u1ee5ng s\u00f3ng, v\u00e2n l\u00f5m \u1ee9ng v\u1edbi n\u00fat s\u00f3ng. Kho\u1ea3ng c\u00e1ch gi\u1eefa hai v\u00e2n l\u1ed3i li\u00ean ti\u1ebfp l\u00e0 kho\u1ea3ng c\u00e1ch gi\u1eefa hai b\u1ee5ng, b\u1eb1ng n\u1eeda b\u01b0\u1edbc s\u00f3ng. Do \u0111\u00f3 b\u01b0\u1edbc s\u00f3ng c\u00f3 \u0111\u1ed9 d\u00e0i l\u00e0:<\/p>\n

\u03b1 – 2d = 2.2 = 4mm<\/p>\n

T\u1ed1c \u0111\u1ed9 truy\u1ec1n s\u00f3ng v = f\u03b1 = 4.50 = 200 cm\/s = 0,2 m\/s<\/p>\n<\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"

C\u00c2U H\u1eceI C\u00e2u 1 (trang 88 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):\u00a0H\u00e3y gi\u1ea3i th\u00edch hi\u1ec7n t\u01b0\u01a1ng t\u1ea1o th\u00e0nh v\u00e2n giao thoa tr\u00ean m\u1eb7t n\u01b0\u1edbc. L\u1eddi gi\u1ea3i: Gi\u1ea3 s\u1eed Ph\u01b0\u01a1ng tr\u00ecnh dao \u0111\u1ed9ng: T\u1ea1i A: u = Acos2\u03c0ft Coi kho\u1ea3ng c\u00e1ch gi\u1eefa A, B l\u00e0 nh\u1ecf. S\u00f3ng t\u1ea1i M t\u1eeb A truy\u1ec1n \u0111\u1ebfn c\u00f3 d\u1ea1ng: uA\u00a0= […]<\/p>\n","protected":false},"author":3,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1304],"tags":[1434,1433],"yoast_head":"\nCh\u01b0\u01a1ng 3 - B\u00e0i 16: Giao thoa s\u00f3ng<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/chuong-3-bai-16-giao-thoa-song\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Ch\u01b0\u01a1ng 3 - B\u00e0i 16: Giao thoa s\u00f3ng\" \/>\n<meta property=\"og:description\" content=\"C\u00c2U H\u1eceI C\u00e2u 1 (trang 88 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):\u00a0H\u00e3y gi\u1ea3i th\u00edch hi\u1ec7n t\u01b0\u01a1ng t\u1ea1o th\u00e0nh v\u00e2n giao thoa tr\u00ean m\u1eb7t n\u01b0\u1edbc. L\u1eddi gi\u1ea3i: Gi\u1ea3 s\u1eed Ph\u01b0\u01a1ng tr\u00ecnh dao \u0111\u1ed9ng: T\u1ea1i A: u = Acos2\u03c0ft Coi kho\u1ea3ng c\u00e1ch gi\u1eefa A, B l\u00e0 nh\u1ecf. 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