B\u00e0i 1 (trang 197 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0\u0110\u1ec3 hai s\u00f3ng \u00e1nh s\u00e1ng k\u1ebft h\u1ee3p c\u00f3 b\u01b0\u1edbc s\u00f3ng \u03bb t\u0103ng c\u01b0\u1eddng l\u1eabn nhau khi giao thoa v\u1edbi nhau th\u00ec \u0111\u01b0\u1eddng \u0111i c\u1ee7a ch\u00fang ph\u1ea3i.<\/span><\/p>\nA. b\u1eb1ng 0<\/p>\n
B. b\u1eb1ng k \u03bb (k = 0; \u00b11; \u00b12; \u2026)<\/p>\n
C. b\u1eb1ng (k-1\/2)\u03bb (v\u1edbi k = 0; \u00b11; \u00b12,…<\/p>\n
D. b\u1eb1ng (k\u03bb-\u03bb\/4)\u03bb (v\u1edbi k = 0,1,2,…<\/p>\n
L\u1eddi gi\u1ea3i:<\/b><\/p>\n
Ch\u1ecdn B<\/p>\n
B\u00e0i 2 (trang 197 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0Kho\u1ea3ng c\u00e1ch I gi\u1eefa hai v\u00e2n s\u00e1ng, ho\u1eb7c hai v\u00e2n t\u1ed1i li\u00ean ti\u1ebfp trong h\u1ec7 v\u00e2n giao thoa, \u1edf th\u00ed nghi\u1ec7m hai khi Y-\u00e2ng, \u0111\u01b0\u1ee3c t\u00ednh theo c\u00f4ng th\u1ee9c n\u00e0o sau \u0111\u00e2y?<\/span><\/p>\n![\"\u0110\u1ec3](\"http:\/\/vietjack.com\/giai-ly-12-nang-cao\/images\/bai-2-trang-197-sgk-vat-ly-12-nang-cao.PNG\")
<\/p>\n
L\u1eddi gi\u1ea3i:<\/b><\/p>\n
Ch\u1ecdn B.<\/p>\n
B\u00e0i 3 (trang 197 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0S\u1ef1 ph\u1ee5 thu\u1ed9c c\u1ee7a chi\u1ebft su\u1ea5t v\u00e0o b\u01b0\u1edbc s\u00f3ng.<\/span><\/p>\nA. X\u1ea3y ra v\u1edbi m\u1ecdi ch\u1ea5t r\u1eafn, l\u1ecfng, ho\u1eb7c kh\u00ed.<\/p>\n
B. Ch\u1ec9 x\u1ea3y ra v\u1edbi ch\u1ea5t r\u1eafn, v\u00e0 ch\u1ea5t l\u1ecfng.<\/p>\n
C. Ch\u1ec9 x\u1ea3y ra v\u1edbi ch\u1ea5t r\u1eafn.<\/p>\n
D. l\u00e0 hi\u1ec7n t\u01b0\u1ee3ng \u0111\u1eb7c tr\u01b0ng c\u1ee7a th\u1ee7y t\u00ednh.<\/p>\n
L\u1eddi gi\u1ea3i:<\/b><\/p>\n
Ch\u1ecdn A.<\/p>\n
B\u00e0i 4 (trang 197 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0Trong th\u00ed nghi\u1ec7m v\u1ec1 giao thoa \u00e1nh s\u00e1ng, tr\u00ean m\u00e0n \u1ea3nh ng\u01b0\u1eddi ta \u0111o \u0111\u01b0\u1ee3c kho\u1ea3ng c\u00e1ch t\u1eeb v\u00e2n s\u00e1ng th\u1ee9 t\u01b0 \u0111\u1ebfn v\u00e2n s\u00e1ng th\u1ee9 m\u01b0\u1eddi \u1edf c\u00f9ng m\u1ed9t b\u00ean c\u1ee7a v\u00e2n s\u00e1ng trung t\u00e2m l\u00e0 2,4 nm. Cho bi\u1ebft kho\u1ea3ng c\u00e1ch gi\u1eefa hai khe l\u00e0 1 mm, v\u00e0 m\u00e0n \u1ea3nh c\u00e1ch hai khe 1m .<\/span><\/p>\na) T\u00ednh b\u01b0\u1edbc s\u00f3ng \u00e1nh s\u00e1ng. \u00c1nh s\u00e1ng \u0111\u00f3 c\u00f3 m\u00e0u g\u00ec?<\/p>\n
b) N\u1ebfu d\u00f9ng \u00e1nh s\u00e1ng \u0111\u00f3 c\u00f3 b\u01b0\u1edbc s\u00f3ng 0,70\u03bcm th\u00ec kho\u1ea3ng c\u00e1ch t\u1eeb v\u00e2n s\u00e1ng th\u1ee9 t\u01b0 \u0111\u1ebfn v\u00e2n s\u00e1ng th\u1ee9 10 \u1edf c\u00f9ng m\u1ed9t b\u00ean v\u00e2n s\u00e1ng trung t\u00e2m l\u00e0 bao nhi\u00eau?<\/p>\n
L\u1eddi gi\u1ea3i:<\/b><\/p>\n
a) T\u1eeb v\u00e2n s\u00e1ng b\u1eadc 4 \u0111\u1ebfn v\u00e2n s\u00e1ng b\u1eadc 10 c\u00f3 6 kho\u1ea3ng v\u00e2n. Suy ra : 6i = 2,4 mm, I = 0,4 mm. \u00c1p d\u1ee5ng c\u00f4ng th\u1ee9c:<\/p>\n
![\"\"](\"https:\/\/lop12.edu.vn\/wp-content\/uploads\/2018\/04\/1-16.png\")
<\/p>\n
Thay s\u1ed1 (ch\u00fa \u00fd \u0111\u1ed5i \u0111\u01a1n v\u1ecb), ta \u0111\u01b0\u1ee3c \u03bb=0,40\u03bcm. \u0110\u00f3 l\u00e0 b\u01b0\u1edbc s\u00f3ng c\u1ee7a \u00e1nh s\u00e1ng t\u00edm.<\/p>\n
b) Thay \u03bb = 0,70 \u03bcm v\u00e0o c\u00f4ng th\u1ee9c t\u00ednh i. Sau \u0111\u00f3 t\u00ecm kho\u1ea3ng c\u00e1ch b\u1eb1ng 6i. Do \u0111\u00f3, t\u00ednh \u0111\u01b0\u1ee3c kho\u1ea3ng c\u00e1ch b\u1eb1ng 4,2 mm.<\/p>\n
B\u00e0i 5 (trang 197 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0Hai khe Y-\u00e2ng c\u00e1ch nhau 3 mm \u0111\u01b0\u1ee3c chi\u1ebfu s\u00e1ng b\u1eb1ng \u00e1nh s\u00e1ng \u0111\u01a1n s\u1eafc c\u00f3 b\u01b0\u1edbc s\u00f3ng 0,60 \u03bcm. C\u00e1c v\u00e2n giao thoa \u0111\u01b0\u1ee3c h\u1ee9ng tr\u00ean m\u00e0n c\u00e1ch hai khe 2m. h\u00e3y x\u00e1c \u0111\u1ecbnh t\u00ednh ch\u1ea5t c\u1ee7a v\u00e2n giao thoa t\u1ea1i \u0111i\u1ec3m M c\u00e1ch v\u00e2n s\u00e1ng trung t\u00e2m 1,2 mm v\u00e0 t\u1ea1i \u0111i\u1ec3m N c\u00e1ch v\u00e2n s\u00e1ng trung t\u00e2m 1,8 mm.<\/span><\/p>\nL\u1eddi gi\u1ea3i:<\/b><\/p>\n
Tr\u01b0\u1edbc h\u1ebft t\u00ednh kho\u1ea3ng v\u00e2n :<\/p>\n
![\"\"](\"https:\/\/lop12.edu.vn\/wp-content\/uploads\/2018\/04\/1-17.png\")
<\/p>\n
Nh\u1eadn x\u00e9t:<\/p>\n
+ 1,2 mm = 3i; suy ra t\u1ea1i M c\u00f3 v\u00e2n s\u00e1ng b\u1eadc 3.<\/p>\n
+ 1,8 mm = (4+1\/2)i; suy ra t\u1ea1i N c\u00f3 v\u00e2n t\u1ed1i th\u1ee9 5.<\/p>\n<\/div>\n
<\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"
C\u00c2U H\u1eceI C\u00e2u 1 (trang 197 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):\u00a0Thi\u1ebft l\u1eadp c\u00f4ng th\u1ee9c t\u00ednh kho\u1ea3ng v\u00e2n. L\u1eddi gi\u1ea3i: V\u1ecb tr\u00ed v\u00e2n s\u00e1ng b\u1eadc k: V\u1ecb tr\u00ed v\u00e2n s\u00e1ng b\u1eadc k \u2013 1: Kho\u1ea3ng v\u00e2n i l\u00e0 : C\u00e2u 2 (trang 197 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):\u00a0Tr\u00ecnh b\u00e0y ph\u01b0\u01a1ng ph\u00e1p giao thoa \u0111\u1ec3 […]<\/p>\n","protected":false},"author":3,"featured_media":25039,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1304],"tags":[1432,1431],"yoast_head":"\n
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