C\u00c2U H\u1eceI<\/strong><\/p>\n C\u00e2u 1 (trang 225 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0M\u00f4 t\u1ea3 kh\u00e1i qu\u00e1t s\u01a1 \u0111\u1ed3 th\u00ed nghi\u1ec7m v\u1edbi t\u1ebf b\u00e0o quang \u0111i\u1ec7n. V\u1ebd \u0111\u1eb7c tuy\u1ebfn v\u00f4n-ampe c\u1ee7a t\u1ebf b\u00e0o quang \u0111i\u1ec7n.<\/span><\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n Xem m\u1ee5c 1 ph\u1ea7n KTCB.<\/p>\n C\u00e2u 2 (trang 225 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0Tr\u00ecnh b\u00e0y c\u00e1c k\u1ebft lu\u1eadn ch\u00ednh r\u00fat ra t\u1eeb k\u1ebft qu\u1ea3 th\u00ed nghi\u1ec7m.<\/span><\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n Xem m\u1ee5c 2 ph\u1ea7n KTCB.<\/p>\n C\u00e2u 3 (trang 225 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0Ph\u00e1t bi\u1ec3u c\u00e1c \u0111\u1ecbnh lu\u1eadt quang \u0111i\u1ec7n.<\/span><\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n Xem m\u1ee5c 3 ph\u1ea7n KTCB.<\/p>\n B\u00c0I T\u1eacP<\/strong><\/p>\n B\u00e0i 1 (trang 225 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0N\u1ebfu chi\u1ebfu m\u1ed9t chum tia h\u1ed3ng ngo\u1ea1i v\u00e0o t\u1ea5m k\u1ebdm t\u00edch \u0111i\u1ec7n \u00e2m, th\u00ec.<\/span><\/p>\n A. T\u1ea5m k\u1ebdm m\u1ea5t d\u1ea7n \u0111i\u1ec7n t\u00edch d\u01b0\u01a1ng.<\/p>\n B. T\u1ea5m k\u1ebdm m\u1ea5t d\u1ea7n \u0111i\u1ec7n t\u00edch \u00e2m.<\/p>\n C. T\u1ea5n k\u1ebdm tr\u1edf n\u00ean trung h\u00f2a \u0111i\u1ec7n.<\/p>\n D. \u0110i\u1ec7n t\u00edch \u00e2m c\u1ee7a t\u1ea5m k\u1ebdm kh\u00f4ng \u0111\u1ed5i.<\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n Ch\u1ecdn D<\/p>\n B\u00e0i 2 (trang 225 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0Gi\u1edbi h\u1ea1n quang \u0111i\u1ec7n c\u1ee7a m\u1ed7i kim lo\u1ea1i l\u00e0<\/span><\/p>\n A. B\u01b0\u1edbc s\u00f3ng c\u1ee7a \u00e1nh s\u00e1ng k\u00edch th\u00edch chi\u1ebfu v\u00e0o kim lo\u1ea1i g\u00e2y ra hi\u1ec7n t\u01b0\u1ee3ng quang \u0111i\u1ec7n.<\/p>\n B. C\u00f4ng tho\u00e1t c\u1ee7a c\u00e1c electron \u1edf b\u1ec1 m\u1eb7t kim lo\u1ea1i \u0111\u00f3.<\/p>\n C. B\u01b0\u1edbc s\u00f3ng gi\u1edbi h\u1ea1n c\u1ee7a \u00e1nh s\u00e1ng k\u00edch th\u00edch \u0111\u1ec3 g\u00e2y ra hi\u1ec7n t\u01b0\u1ee3ng quang \u0111i\u1ec7n kim lo\u1ea1i \u0111\u00f3.<\/p>\n D. Hi\u1ec7u \u0111i\u1ec7n th\u1ebf h\u00e3m.<\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n Ch\u1ecdn C<\/p>\n B\u00e0i 3 (trang 225 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0\u0110\u1ec3 g\u00e2y \u0111\u01b0\u1ee3c hi\u1ec7u \u1ee9ng quang \u0111i\u1ec7n, b\u1ee9c x\u1ea1 r\u1ecdi v\u00e0o kim lo\u1ea1i ph\u1ea3i th\u1ecfa m\u00e3n \u0111i\u1ec1u ki\u1ec7n n\u00e0o sau \u0111\u00e2y?<\/span><\/p>\n A. T\u1ea7n s\u1ed1 l\u1edbn h\u01a1n m\u1ed9t t\u1ea7n s\u1ed1 n\u00e0o \u0111\u00f3.<\/p>\n B. T\u1ea7n s\u1ed1 nh\u1ecf h\u01a1n m\u1ed9t t\u1ea7n s\u1ed1 n\u00e0o \u0111\u00f3.<\/p>\n C. B\u01b0\u1edbc s\u00f3ng nh\u1ecf h\u01a1n gi\u1edbi h\u1ea1n quang \u0111i\u1ec7n.<\/p>\n D. B\u01b0\u1edbc s\u00f3ng l\u1edbn h\u01a1n gi\u1edbi h\u1ea1n quang \u0111i\u1ec7n.<\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n Ch\u1ecdn C<\/p>\n B\u00e0i 4 (trang 225 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0V\u1edbi m\u1ed9t b\u1ee9c x\u1ea1 c\u00f3 b\u01b0\u1edbc s\u00f3ng th\u00edch h\u1ee3p th\u00ec c\u01b0\u1eddng \u0111\u1ed9 d\u00f2ng quang \u0111i\u1ec7n b\u00e3o h\u00f2a.<\/span><\/p>\n A. Tri\u1ec7t ti\u00eau, khi c\u01b0\u1eddng \u0111\u1ed9 chum s\u00e1ng k\u00edch th\u00edch nh\u1ecf h\u01a1n m\u1ed9t gi\u00e1 tr\u1ecb gi\u1edbi h\u1ea1n.<\/p>\n B. T\u1ec9 l\u1ec7 v\u1edbi b\u00ecnh ph\u01b0\u01a1ng c\u01b0\u1eddng \u0111\u1ed9 chum s\u00e1ng.<\/p>\n C. T\u1ec9 l\u1ec7 v\u1edbi c\u0103n b\u1eadc hai c\u1ee7a c\u01b0\u1eddng \u0111\u1ed9 chum s\u00e1ng.<\/p>\n D. T\u1ec9 l\u1ec7 thu\u1eadn v\u1edbi c\u01b0\u1eddng \u0111\u1ed9 ch\u00f9m s\u00e1ng.<\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n Ch\u1ecdn D.<\/p>\n B\u00e0i 5 (trang 225 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0T\u00ednh v\u1eadn t\u1ed1c ban \u0111\u1ea7u c\u1ef1c \u0111\u1ea1i c\u1ee7a electron quang \u0111i\u1ec7n, bi\u1ebft r\u1eb1ng hi\u1ec7u \u0111i\u1ec7n th\u1ebf h\u00e3m b\u1eb1ng 1,8V.<\/span><\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n \u00c1p d\u1ee5ng c\u00f4ng th\u1ee9c:<\/p>\n <\/p>\n Ta c\u00f3 :<\/p>\n <\/p>\n Thay s\u1ed1 ta \u0111\u01b0\u1ee3c v0 max<\/sub>\u00a0= 7,98.106<\/sup>\u00a0m\/s.<\/p>\n C\u00c2U H\u1eceI C\u00e2u 1 (trang 225 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):\u00a0M\u00f4 t\u1ea3 kh\u00e1i qu\u00e1t s\u01a1 \u0111\u1ed3 th\u00ed nghi\u1ec7m v\u1edbi t\u1ebf b\u00e0o quang \u0111i\u1ec7n. V\u1ebd \u0111\u1eb7c tuy\u1ebfn v\u00f4n-ampe c\u1ee7a t\u1ebf b\u00e0o quang \u0111i\u1ec7n. L\u1eddi gi\u1ea3i: Xem m\u1ee5c 1 ph\u1ea7n KTCB. C\u00e2u 2 (trang 225 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):\u00a0Tr\u00ecnh b\u00e0y c\u00e1c k\u1ebft lu\u1eadn ch\u00ednh […]<\/p>\n","protected":false},"author":3,"featured_media":25025,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1304],"tags":[1432,1431],"yoast_head":"\n