C\u00c2U H\u1eceI<\/strong><\/p>\n C\u00e2u 1 (trang 241 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0Tr\u00ecnh b\u00e0y hai ti\u00ean \u0111\u1ec1 c\u1ee7a Bo.<\/span><\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n Xem m\u1ee5c 1 ph\u1ea7n KTCB.<\/p>\n C\u00e2u 2 (trang 241 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0M\u00f4 t\u1ea3 quang ph\u1ed5 v\u1ea1ch c\u1ee7a hidro v\u00e0 gi\u1ea3i th\u00edch s\u1ef1 t\u1ea1o th\u00e0nh c\u00e1c d\u00e3y quang ph\u1ed5.<\/span><\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n Xem m\u1ee5c 2 ph\u1ea7n KTCB.<\/p>\n B\u00c0I T\u1eacP<\/strong><\/p>\n B\u00e0i 1 (trang 241 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0Tr\u1ea1ng th\u00e1i d\u1eebng c\u1ee7a m\u1ed9t nguy\u00ean t\u1eed l\u00e0<\/span><\/p>\n A. Tr\u1ea1ng th\u00e1i \u0111\u1ee9ng y\u00ean c\u1ee7a nguy\u00ean t\u1eed.<\/p>\n B. Tr\u1ea1ng th\u00e1i chuy\u1ec3n \u0111\u1ed9ng \u0111\u1ec1u c\u1ee7a nguy\u00ean t\u1eed.<\/p>\n C. Tr\u1ea1ng th\u00e1i trong \u0111\u00f3 m\u1ecdi electron c\u1ee7a nguy\u00ean t\u1eed \u0111\u1ec1u kh\u00f4ng chuy\u1ec3n \u0111\u1ed9ng \u0111\u1ed1i v\u1edbi h\u1ea1t nh\u00e2n.<\/p>\n D. M\u1ed9t trong s\u1ed1 c\u00e1c tr\u1ea1ng th\u00e1i c\u00f3 n\u0103ng l\u01b0\u1ee3ng x\u00e1c \u0111\u1ecbnh, m\u00e0 nguy\u00ean t\u1eed c\u00f3 th\u1ec3 t\u1ed3n t\u1ea1i.<\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n Ch\u1ecdn D<\/p>\n B\u00e0i 2 (trang 241 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0\u1ede tr\u1ea1ng th\u00e1i d\u1eebng, nguy\u00ean t\u1eed<\/span><\/p>\n A. Kh\u00f4ng b\u1ee9c x\u1ea1 v\u00e0 kh\u00f4ng h\u1ea5p th\u1ee5 n\u0103ng l\u01b0\u1ee3ng.<\/p>\n B. Kh\u00f4ng b\u1ee9c x\u1ea1, nh\u01b0ng c\u00f3 th\u1ec3 h\u1ea5p th\u1ee5 n\u0103ng l\u01b0\u1ee3ng.<\/p>\n C. Kh\u00f4ng h\u1ea5p th\u1ee5, nh\u01b0ng c\u00f3 th\u1ec3 b\u1ee9c x\u1ea1 n\u0103ng l\u01b0\u1ee3ng.<\/p>\n D. V\u1eabn c\u00f3 th\u1ec3 h\u1eadp th\u1ee5 v\u00e0 b\u1ee9c x\u1ea1 n\u0103ng l\u01b0\u1ee3ng.<\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n Ch\u1ecdn A<\/p>\n B\u00e0i 4 (trang 241 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0B\u01b0\u1edbc s\u00f3ng c\u1ee7a v\u1ea1ch quang ph\u1ed5 th\u1ee9 nh\u1ea5t trong d\u00e3y Lai \u2013 man l\u00e0 \u03bb0<\/sub>\u00a0= 122 nm c\u1ee7a hai v\u1ea1ch H\u03b1<\/sub>,H\u03b2<\/sub>\u00a0l\u1ea7n l\u01b0\u1ee3t l\u00e0 \u03bb1<\/sub>\u00a0= 0,656 \u03bcm v\u00e0 \u03bb2<\/sub>\u00a0= 0,486 \u03bcm. H\u00e3y t\u00ednh b\u01b0\u1edbc s\u00f3ng hai v\u1ea1ch ti\u1ebfp theo trong d\u00e3y Lai \u2013 man v\u00e0 v\u1ea1ch \u0111\u1ea7u ti\u00ean trong d\u00e3y Pa \u2013 sen.<\/span><\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n V\u1ebd s\u01a1 \u0111\u1ed3 chuy\u1ec3n m\u1ee9c n\u0103ng l\u01b0\u1ee3ng (h\u00ecnh 7.3)<\/p>\n <\/p>\n Theo s\u01a1 \u0111\u1ed3 h\u00ecnh 7.3 ta th\u1ea5y:<\/p>\n hf0<\/sub>\u00a0= E1<\/sub>\u00a0– E0<\/sub>; hf1<\/sub>\u00a0= E2<\/sub>\u00a0– E1<\/sub><\/p>\n hf2<\/sub>\u00a0= E3<\/sub>\u00a0– E1<\/sub><\/p>\n V\u1ea1ch \u03bb02<\/sub>\u00a0c\u00f3 t\u1ea7n s\u1ed1 f0<\/sub>2. T\u00ednh theo c\u00f4ng th\u1ee9c:<\/p>\n hf0<\/sub>\u00a0= E2<\/sub>\u00a0– E0<\/sub>\u00a0= hf1<\/sub>\u00a0+ hf0<\/sub><\/p>\n C\u1ed9ng v\u1ebf v\u1edbi v\u1ebf (1) v\u00e0 (2). Do \u0111\u00f3:<\/p>\n <\/p>\n \u03bb01<\/sub>\u00a0= 103 nm<\/p>\n T\u01b0\u01a1ng t\u1ef1, ta c\u00f3:<\/p>\n <\/p>\n \u03bb02<\/sub>\u00a0= 97,5 nm<\/p>\n B\u01b0\u1edbc s\u00f3ng \u03bb23<\/sub>\u00a0c\u1ee7a v\u1ea1ch \u0111\u1ea7u ti\u00ean trong d\u00e3y Pa \u2013 sen, \u0111\u01b0\u1ee3c t\u00ednh theo c\u00f4ng th\u1ee9c:<\/p>\n <\/p>\n L\u1ea5y (3) tr\u1eeb (2) , ta \u0111\u01b0\u1ee3c : hf23<\/sub>\u00a0= hf2<\/sub>\u00a0– hf1<\/sub>\u00a0hay l\u00e0:<\/p>\n <\/p>\n T\u1eeb \u0111\u00f3:<\/p>\n <\/p>\n C\u00c2U H\u1eceI C\u00e2u 1 (trang 241 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):\u00a0Tr\u00ecnh b\u00e0y hai ti\u00ean \u0111\u1ec1 c\u1ee7a Bo. L\u1eddi gi\u1ea3i: Xem m\u1ee5c 1 ph\u1ea7n KTCB. C\u00e2u 2 (trang 241 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):\u00a0M\u00f4 t\u1ea3 quang ph\u1ed5 v\u1ea1ch c\u1ee7a hidro v\u00e0 gi\u1ea3i th\u00edch s\u1ef1 t\u1ea1o th\u00e0nh c\u00e1c d\u00e3y quang ph\u1ed5. L\u1eddi gi\u1ea3i: Xem m\u1ee5c […]<\/p>\n","protected":false},"author":3,"featured_media":25007,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1304],"tags":[1432,1431],"yoast_head":"\n