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{"id":24964,"date":"2018-04-02T13:15:42","date_gmt":"2018-04-02T06:15:42","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=24964"},"modified":"2018-04-02T13:15:42","modified_gmt":"2018-04-02T06:15:42","slug":"chuong-9-bai-52-cau-tao-cua-hat-nhan-nguyen-tu-do-hut-khoi","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/chuong-9-bai-52-cau-tao-cua-hat-nhan-nguyen-tu-do-hut-khoi\/","title":{"rendered":"Ch\u01b0\u01a1ng 9 – B\u00e0i 52: C\u1ea5u t\u1ea1o c\u1ee7a h\u1ea1t nh\u00e2n nguy\u00ean t\u1eed. \u0110\u1ed9 h\u1ee5t kh\u1ed1i"},"content":{"rendered":"

C\u00c2U H\u1eceI<\/strong><\/p>\n

C\u00e2u 1 (trang 265 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0H\u1ea1t nh\u00e2n nguy\u00ean t\u1eed \u0111\u01b0\u1ee3c c\u1ea5u t\u1ea1o nh\u01b0 th\u1ebf n\u00e0o ?<\/span><\/p>\n

H\u00e3y n\u00eau c\u1ea5u t\u1ea1o h\u1ea1t nh\u00e2n c\u1ee7a c\u00e1c nguy\u00ean t\u1eed\u00a08<\/sub>16<\/sup>O v\u00e0\u00a092<\/sub>238<\/sup>U.<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

Xem m\u1ee5c 1 ph\u1ea7n KTCB.<\/p>\n

+ c\u1ea5u t\u1ea1o h\u1ea1t nh\u00e2n c\u1ee7a c\u00e1c nguy\u00ean t\u1eed\u00a08<\/sub>16<\/sup>O l\u00e0 c\u00f3 8 proton v\u00e0 8 n\u01a1tr\u00f4n.<\/p>\n

+ c\u1ea5u t\u1ea1o h\u1ea1t nh\u00e2n c\u1ee7a c\u00e1c nguy\u00ean t\u1eed\u00a092<\/sub>238<\/sup>U l\u00e0 c\u00f3 92 prot\u00f4n v\u00e0 238 \u2013 92 = 146 n\u01a1tr\u00f4n.<\/p>\n

C\u00e2u 2 (trang 265 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0\u0110\u1ed3ng v\u1ecb l\u00e0 g\u00ec? Cho v\u00ed d\u1ee5.<\/span><\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

C\u00e1c nguy\u00ean t\u1eed m\u00e0 h\u1ea1t nh\u00e2n c\u00f3 c\u00f9ng s\u1ed1 proton Z (c\u0169ng v\u1ecb tr\u00ed trong b\u1ea3ng tu\u1ea7n ho\u00e0n), nh\u01b0ng kh\u00e1c s\u1ed1 n\u01a1tr\u00f4n N, g\u1ecdi l\u00e0 c\u00e1c \u0111\u1ed3ng v\u1ecb.<\/p>\n

C\u00e2u 3 (trang 265 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0N\u00eau c\u00e1c \u0111\u01a1n v\u1ecb d\u00f9ng \u0111\u1ec3 \u0111o kh\u1ed1i l\u01b0\u1ee3ng nguy\u00ean t\u1eed trong v\u1eadt l\u00ed h\u1ea1t nh\u00e2n.<\/span><\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

Xem m\u1ee5c 3 ph\u1ea7n KTCB.<\/p>\n

C\u00e2u 4 (trang 265 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0\u0110\u1ed9 h\u1ee5t kh\u1ed1i v\u00e0 n\u0103ng l\u01b0\u1ee3ng li\u00ean k\u1ebft c\u1ee7a h\u1ea1t nh\u00e2n l\u00e0 g\u00ec? Ch\u00fang c\u00f3 li\u00ean quan th\u1ebf n\u00e0o v\u1edbi s\u1ef1 b\u1ec1n v\u1eefng c\u1ee7a h\u1ea1t nh\u00e2n ?<\/span><\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

Xem m\u1ee5c 4 ph\u1ea7n KTCB.<\/p>\n

B\u00c0I T\u1eacP<\/strong><\/p>\n

B\u00e0i 1 (trang 266 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0H\u1ea1t nh\u00e2n nguy\u00ean t\u1eed \u0111\u01b0\u1ee3c c\u1ea5u t\u1ea1o b\u1edfi<\/span><\/p>\n

A. Pr\u00f4t\u00f4n.<\/p>\n

B. N\u01a1tr\u00f4n.<\/p>\n

C. Pr\u00f4t\u00f4n v\u00e0 n\u01a1tr\u00f4n.<\/p>\n

D. Pr\u00f4t\u00f4n, n\u01a1tr\u00f4n v\u00e0 electron.<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

Ch\u1ecdn C<\/p>\n

B\u00e0i 2 (trang 266 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0\u0110\u1ed3ng v\u1ecb l\u00e0 nh\u1eefng nguy\u00ean t\u1eed m\u00e0 h\u1ea1t nh\u00e2n ch\u1ee9a<\/span><\/p>\n

A. C\u00f9ng s\u1ed1 proton Z, nh\u01b0ng s\u1ed1 n\u01a1tr\u00f4n N kh\u00e1c nhau.<\/p>\n

B. C\u00f9ng s\u1ed1 n\u01a1tr\u00f4n N, nh\u01b0ng s\u1ed1 proton Z kh\u00e1c nhau.<\/p>\n

C. C\u00f9ng s\u1ed1 nuclon A, nh\u01b0ng s\u1ed1 proton Z v\u00e0 s\u1ed1 notron N kh\u00e1c nhau.<\/p>\n

D. C\u00f9ng s\u1ed1 proton Z v\u00e0 s\u1ed1 notron N.<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

Ch\u1ecdn A<\/p>\n

B\u00e0i 3 (trang 266 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0\u0110\u01a1n v\u1ecb kh\u1ed1i l\u01b0\u1ee3ng nguy\u00ean t\u1eed l\u00e0<\/span><\/p>\n

A. Kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a h\u1ea1t nh\u00e2n nguy\u00ean t\u1eed hidro.<\/p>\n

B. Kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a m\u1ed9t nguy\u00ean t\u1eed hidro.<\/p>\n

C. Kh\u1ed1i l\u01b0\u1ee3ng b\u1eb1ng 1\/12 l\u1ea7n kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a \u0111\u1ed3ng v\u1ecb\u00a06<\/sub>12<\/sup>C c\u1ee7a nguy\u00ean t\u1eed cacbon.<\/p>\n

D. Kh\u1ed1i l\u01b0\u1ee3ng b\u1eb1ng 1\/12 l\u1ea7n kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a \u0111\u1ed3ng v\u1ecb c\u1ee7a nguy\u00ean t\u1eed oxi.<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

Ch\u1ecdn C<\/p>\n

B\u00e0i 4 (trang 266 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0N\u0103ng l\u01b0\u1ee3ng li\u00ean k\u1ebft ri\u00eang c\u1ee7a m\u1ed9t h\u1ea1t nh\u00e2n.<\/span><\/p>\n

A. C\u00f3 th\u1ec3 \u00e2m ho\u1eb7c d\u01b0\u01a1ng.<\/p>\n

B. C\u00e0ng l\u1edbn, th\u00ec h\u1ea1t nh\u00e2n c\u00e0ng b\u1ec1n.<\/p>\n

C. C\u00e0ng nh\u1ecf, th\u00ec h\u1ea1t nh\u00e2n c\u00e0ng b\u1ec1n.<\/p>\n

D. C\u00f3 th\u1ec3 tri\u1ec7t ti\u00eau, \u0111\u1ed1i v\u1edbi m\u1ed9t s\u1ed1 h\u1ea1t nh\u00e2n \u0111\u1eb7c bi\u1ec7t .<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

Ch\u1ecdn B<\/p>\n

B\u00e0i 5 (trang 266 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0H\u1ea1t nh\u00e2n doteri c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng 2,0136 u. T\u00ednh n\u0103ng l\u01b0\u1ee3ng li\u00ean k\u1ebft c\u1ee7a n\u00f3.<\/span><\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

2,3 MeV.<\/p>\n

\u0110\u1ed9 h\u1ee5t kh\u1ed1i: \u2206m = {Zmp<\/sub>\u00a0+ (A-Z) mn<\/sub>\u00a0} – mhn<\/sub>\u00a0= mp<\/sub>\u00a0+ mn<\/sub>\u00a0– mhn<\/sub><\/p>\n

N\u0103ng l\u01b0\u1ee3ng li\u00ean k\u1ebft : \u2206E = \u2206m.c2<\/sup>\u00a0= 2,3 MeV<\/p>\n

B\u00e0i 6 (trang 266 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0H\u1ea1t nh\u00e2n \u03b1 c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng 4,0015 u. t\u00ednh n\u0103ng l\u01b0\u1ee3ng t\u1ecfa ra khi t\u1ea1o th\u00e0nh 1 mol heli. Cho bi\u1ebft s\u1ed1 Avogadro NA<\/sub>\u00a0=6,022.10(-23)<\/sup>\u00a0mol(-1)<\/sup>.<\/span><\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

M\u1ed9t h\u1ea1t nh\u00e2n heli khi li\u00ean k\u1ebft c\u00f3 \u0111\u1ed9 h\u1ee5t kh\u1ed1i:<\/p>\n

\u2206m = {Zmp<\/sub>\u00a0+ (A-Z)mn<\/sub>\u00a0} – mhn<\/sub><\/p>\n

= 2mp<\/sub>\u00a0+ 2mn<\/sub>\u00a0– mhn<\/sub><\/p>\n

= 2.1,007276u + 2.1,008665u – 4,0015u<\/p>\n

= 0,030382u<\/p>\n

N\u0103ng l\u01b0\u1ee3ng li\u00ean k\u1ebft :<\/p>\n

\u2206E = \u2206m.c2<\/sup>\u00a0= 0,030382.931,5 MeV<\/p>\n

= 28,300833 MeV<\/p>\n

N\u0103ng l\u01b0\u1ee3ng t\u1ecfa ra khi t\u1ea1o th\u00e0nh m\u1ed9t mol heli:<\/p>\n

E =170,4.1023<\/sup>\u00a0MeV = 2,7.1012<\/sup>\u00a0J.<\/p>\n","protected":false},"excerpt":{"rendered":"

C\u00c2U H\u1eceI C\u00e2u 1 (trang 265 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):\u00a0H\u1ea1t nh\u00e2n nguy\u00ean t\u1eed \u0111\u01b0\u1ee3c c\u1ea5u t\u1ea1o nh\u01b0 th\u1ebf n\u00e0o ? H\u00e3y n\u00eau c\u1ea5u t\u1ea1o h\u1ea1t nh\u00e2n c\u1ee7a c\u00e1c nguy\u00ean t\u1eed\u00a0816O v\u00e0\u00a092238U. L\u1eddi gi\u1ea3i: Xem m\u1ee5c 1 ph\u1ea7n KTCB. + c\u1ea5u t\u1ea1o h\u1ea1t nh\u00e2n c\u1ee7a c\u00e1c nguy\u00ean t\u1eed\u00a0816O l\u00e0 c\u00f3 8 proton v\u00e0 8 […]<\/p>\n","protected":false},"author":3,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1304],"tags":[1432,1431],"yoast_head":"\nCh\u01b0\u01a1ng 9 - B\u00e0i 52: C\u1ea5u t\u1ea1o c\u1ee7a h\u1ea1t nh\u00e2n nguy\u00ean t\u1eed. \u0110\u1ed9 h\u1ee5t kh\u1ed1i<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/chuong-9-bai-52-cau-tao-cua-hat-nhan-nguyen-tu-do-hut-khoi\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Ch\u01b0\u01a1ng 9 - B\u00e0i 52: C\u1ea5u t\u1ea1o c\u1ee7a h\u1ea1t nh\u00e2n nguy\u00ean t\u1eed. \u0110\u1ed9 h\u1ee5t kh\u1ed1i\" \/>\n<meta property=\"og:description\" content=\"C\u00c2U H\u1eceI C\u00e2u 1 (trang 265 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):\u00a0H\u1ea1t nh\u00e2n nguy\u00ean t\u1eed \u0111\u01b0\u1ee3c c\u1ea5u t\u1ea1o nh\u01b0 th\u1ebf n\u00e0o ? H\u00e3y n\u00eau c\u1ea5u t\u1ea1o h\u1ea1t nh\u00e2n c\u1ee7a c\u00e1c nguy\u00ean t\u1eed\u00a0816O v\u00e0\u00a092238U. 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