B\u00e0i 1 (trang 273 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0Ph\u00f3ng x\u1ea1 l\u00e0 hi\u1ec7n t\u01b0\u1ee3ng m\u1ed9t h\u1ea1t nh\u00e2n<\/span><\/p>\nA. Ph\u00e1t ra m\u1ed9t b\u1ee9c x\u1ea1 \u0111i\u1ec7n t\u1eeb.<\/p>\n
B. T\u1ef1 ph\u00e1t ph\u00f3ng ra c\u00e1c tia \u03b1, \u03b2, \u03b3 nh\u01b0ng kh\u00f4ng thay \u0111\u1ed5i h\u1ea1t nh\u00e2n.<\/p>\n
C. T\u1ef1 ph\u00f3ng ra tia ph\u00f3ng x\u1ea1 v\u00e0 bi\u1ebfn th\u00e0nh m\u1ed9t h\u1ea1t nh\u00e2n kh\u00e1c.<\/p>\n
D. Ph\u00f3ng ra c\u00e1c tia ph\u00f3ng x\u1ea1, khi b\u1ecb b\u1eafn ph\u00e1 b\u1eb1ng nh\u1eefng h\u1ea1t chuy\u1ec3n \u0111\u1ed9ng v\u1edbi t\u1ed1c \u0111\u1ed9 l\u1edbn.<\/p>\n
L\u1eddi gi\u1ea3i:<\/b><\/p>\n
Ch\u1ecdn C<\/p>\n
L\u1eddi gi\u1ea3i:<\/b><\/p>\n
Xem m\u1ee5c 4 ph\u1ea7n KTCB.<\/p>\n
B\u00e0i 2 (trang 273 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0Cho c\u00e1c tia anpha, beta v\u00e0 gamma bay qua kho\u1ea3ng kh\u00f4ng gian gi\u1eefa hai b\u1ea3n c\u1ef1c c\u1ee7a m\u1ed9t t\u1ee5 \u0111i\u1ec7n th\u00ec<\/span><\/p>\nA. Tia anpha l\u1ec7ch nhi\u1ec1u h\u01a1n c\u1ea3, sau \u0111\u1ebfn tia beta v\u00e0 tia gamma.<\/p>\n
B. Tia anpha l\u1ec7ch v\u1ec1 ph\u00e1i b\u1ea3n d\u01b0\u01a1ng, tia gamma l\u1ec7ch v\u1ec1 ph\u00e1i b\u1ea3n \u00e2m c\u1ee7a t\u1ee5 \u0111i\u1ec7n.<\/p>\n
C. Tia gamma kh\u00f4ng b\u1ecb l\u1ec7ch.<\/p>\n
D. Tia b\u00eata kh\u00f4ng b\u1ecb l\u1ec7ch.<\/p>\n
L\u1eddi gi\u1ea3i:<\/b><\/p>\n
Ch\u1ecdn C<\/p>\n
B\u00e0i 3 (trang 273 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0Chu k\u00ec b\u00e1n r\u00e3 c\u1ee7a m\u1ed9t ch\u1ea5t ph\u00f3ng x\u1ea1 l\u00e0 kho\u1ea3ng th\u1eddi gian \u0111\u1ec3<\/span><\/p>\nA. Qu\u00e1 tr\u00ecnh ph\u00f3ng x\u1ea1 l\u1ea1i l\u1eb7p l\u1ea1i nh\u01b0 l\u00fac ban \u0111\u1ea7u.<\/p>\n
B. M\u1ed9t n\u1eeda s\u1ed1 nguy\u00ean t\u1eed ch\u1ea5t \u1ea5y bi\u1ebfn th\u00e0nh ch\u1ea5t kh\u00e1c.<\/p>\n
C. Kh\u1ed1i l\u01b0\u1ee3ng ch\u1ea5t \u1ea5y gi\u1ea3m m\u1ed9t ph\u1ea7n nh\u1ea5t \u0111\u1ecbnh, t\u00f9y thu\u1ed9c v\u00e0o c\u1ea5u t\u1ea1o c\u1ee7a n\u00f3.<\/p>\n
D. M\u1ed9t n\u1eeda s\u1ed1 nguy\u00ean t\u1eed ch\u1ea5t \u1ea5y h\u1ebft kh\u1ea3 n\u0103ng ph\u00f3ng x\u1ea1.<\/p>\n
L\u1eddi gi\u1ea3i:<\/b><\/p>\n
Ch\u1ecdn B<\/p>\n
B\u00e0i 4 (trang 273 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0Ch\u1ea5t ph\u00f3ng x\u1ea1 p\u00f4l\u00f4ni\u00a084<\/sub>210<\/sup>Po ph\u00f3ng ra tia \u03b1 v\u00e0 bi\u1ebfn th\u00e0nh ch\u00ec\u00a082<\/sub>206<\/sup>Po. H\u1ecfi trong 0,168 g poloni c\u00f3 bao nhi\u00eau nguy\u00ean t\u1eed b\u1ecb ph\u00e2n r\u00e3 sau 414 ng\u00e0y \u0111\u00eam v\u00e0 x\u00e1c \u0111\u1ecbnh l\u01b0\u1ee3ng ch\u00ec \u0111\u01b0\u1ee3c t\u1ea1o th\u00e0nh trong kho\u1ea3ng th\u1eddi gian n\u00f3i tr\u00ean. Cho bi\u1ebft chu k\u00ec b\u00e1n r\u00e3 c\u1ee7a poloni l\u00e0 138 ng\u00e0y.<\/span><\/p>\nL\u1eddi gi\u1ea3i:<\/b><\/p>\n
H\u1ecdc sinh t\u1ef1 l\u00e0m.<\/p>\n
B\u00e0i 5 (trang 273 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0T\u00ednh kh\u1ed1i l\u01b0\u1ee3ng poloni Po210<\/sup>\u00a0c\u00f3 \u0111\u1ed9 ph\u00f3ng x\u1ea1 1 Ci.<\/span><\/p>\nL\u1eddi gi\u1ea3i:<\/b><\/p>\n
Ch\u1ea5t ph\u00f3ng x\u1ea1 poloni\u00a084<\/sub>210<\/sup>Po c\u00f3 chu k\u00ec b\u00e1n r\u00e3 l\u00e0 138 ng\u00e0y. G\u1ecdi N l\u00e0 s\u1ed1 h\u1ea1t Po \u0111\u1ec3 c\u00f3 \u0111\u1ed9 ph\u00f3ng x\u1ea1 1Ci ta c\u00f3: H = 1Ci = 3,7.1010<\/sup>\u00a0Bq.<\/p>\nM\u1eb7t kh\u00e1c:<\/p>\n
![\"\"](\"https:\/\/lop12.edu.vn\/wp-content\/uploads\/2018\/04\/1-3.png\")
<\/p>\n
N = 6,37.1017<\/sup>\u00a0nguy\u00ean t\u1eed.<\/p>\nKh\u1ed1i l\u01b0\u1ee3ng:<\/p>\n
![\"\"](\"https:\/\/lop12.edu.vn\/wp-content\/uploads\/2018\/04\/2-1.png\")
<\/p>\n","protected":false},"excerpt":{"rendered":"
C\u00c2U H\u1eceI C\u00e2u 1 (trang 272 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):\u00a0S\u1ef1 ph\u00f3ng x\u1ea1 l\u00e0 g\u00ec? N\u00eau c\u00e1c tia ph\u00f3ng x\u1ea1 v\u00e0 b\u1ea3n ch\u1ea5t c\u1ee7a ch\u00fang. L\u1eddi gi\u1ea3i: Xem m\u1ee5c 1 v\u00e0 2 ph\u1ea7n KTCB. C\u00e2u 2 (trang 272 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):\u00a0Chu k\u00ec b\u00e1n r\u00e3 c\u1ee7a c\u00e1c ch\u1ea5t ph\u00f3ng x\u1ea1 l\u00e0 g\u00ec? […]<\/p>\n","protected":false},"author":3,"featured_media":24961,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1304],"tags":[1432,1431],"yoast_head":"\n
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