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{"id":24951,"date":"2018-04-02T13:02:41","date_gmt":"2018-04-02T06:02:41","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=24951"},"modified":"2018-04-02T13:02:41","modified_gmt":"2018-04-02T06:02:41","slug":"chuong-9-bai-56-phan-ung-phan-hach","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/chuong-9-bai-56-phan-ung-phan-hach\/","title":{"rendered":"Ch\u01b0\u01a1ng 9 – B\u00e0i 56: Ph\u1ea3n \u1ee9ng ph\u00e2n h\u1ea1ch"},"content":{"rendered":"

C\u00c2U H\u1eceI<\/strong><\/p>\n

C\u00e2u 1 (trang 287 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0Ph\u1ea3n \u1ee9ng ph\u00e2n h\u1ea1ch l\u00e0 g\u00ec?<\/span><\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

Xem m\u1ee5c 1 ph\u1ea7n KTCB.<\/p>\n

C\u00e2u 2 (trang 287 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0Ph\u1ea3n \u1ee9ng ph\u00e2n h\u1ea1ch d\u00e2y chuy\u1ec1n l\u00e0 g\u00ec? V\u1edbi \u0111i\u1ec1u ki\u1ec7n n\u00e0o th\u00ec n\u00f3 x\u1ea3y ra?<\/span><\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

Xem m\u1ee5c 2, ph\u1ea7n KTCB.<\/p>\n

C\u00e2u 3 (trang 287 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0N\u00eau c\u00e1c b\u1ed9 ph\u1eadn ch\u00ednh c\u1ee7a nh\u00e0 m\u00e1y \u0111i\u1ec7n h\u1ea1t nh\u00e2n.<\/span><\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

Xem m\u1ee5c 3, ph\u1ea7n KTCB.<\/p>\n

B\u00c0I T\u1eacP<\/strong><\/p>\n

B\u00e0i 1 (trang 287 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0S\u1ef1 ph\u00e2n h\u1ea1ch l\u00e0 s\u1ef1 v\u1ee1 m\u1ed9t h\u1ea1t nh\u00e2n n\u1eb7ng.<\/span><\/p>\n

A. Th\u01b0\u1eddng x\u1ea3y ra m\u1ed9t c\u00e1ch t\u1ef1 ph\u00e1t th\u00e0nh nhi\u1ec1u h\u1ea1t nh\u00e2n nh\u1eb9 h\u01a1n.<\/p>\n

B. Th\u00e0nh hai h\u1ea1t nh\u00e2n nh\u1eb9 h\u01a1n, do h\u1ea5p th\u1ee5 m\u1ed9t notron.<\/p>\n

C. Th\u00e0nh hai h\u1ea1t nh\u00e2n nh\u1eb9 h\u01a1n v\u00e0 v\u00e0i notron, sau khi h\u1ea5p th\u1ee5 m\u1ed9t notron ch\u1eadm.<\/p>\n

D. Th\u00e0nh hai h\u1ea1t nh\u00e2n nh\u1eb9 h\u01a1n, th\u01b0\u1eddng x\u1ea3y ra m\u1ed9t c\u00e1ch t\u1ef1 ph\u00e1t.<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

Ch\u1ecdn C.<\/p>\n

B\u00e0i 2 (trang 287 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0\u0110\u1ed3ng v\u1ecb c\u00f3 th\u1ec3 ph\u00e2n h\u1ea1ch khi h\u1ea5p th\u1ee5 m\u1ed9t notron ch\u1eadm l\u00e0<\/span><\/p>\n

A.\u00a092<\/sub>228<\/sup>U\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0B.\u00a092<\/sub>234<\/sup>U\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0C.\u00a092<\/sub>235<\/sup>U\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0D.\u00a092<\/sub>239<\/sup>U<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

Ch\u1ecdn C.<\/p>\n

B\u00e0i 3 (trang 287 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0G\u1ecdi k l\u00e0 h\u1ec7 s\u1ed1 nh\u00e2n notron, th\u00ec \u0111i\u1ec1u ki\u1ec7n c\u1ea7n v\u00e0 \u0111\u1ee7 \u0111\u1ec3 ph\u1ea3n \u1ee9ng d\u00e2y chuy\u1ec1n c\u00f3 th\u1ec3 x\u1ea3y ra m\u00e0.<\/span><\/p>\n

A. k < 1\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0B. k = 1\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0C. k > 1\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0D. k \u2265 1.<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

Ch\u1ecdn D.<\/p>\n

B\u00e0i 4 (trang 287 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):<\/b>\u00a0X\u00e9t ph\u1ea3n \u1ee9ng ph\u00e2n h\u1ea1ch urani U235<\/sup>\u00a0c\u00f3 ph\u01b0\u01a1ng tr\u00ecnh:<\/span><\/p>\n

\"\"<\/p>\n

T\u00ednh n\u0103ng l\u01b0\u1ee3ng m\u00e0 m\u1ed9t ph\u00e2n h\u1ea1ch t\u1ecfa ra.<\/p>\n

Cho bi\u1ebft :mU<\/sub>\u00a0= 234,99u; mMo<\/sub>\u00a0= 94,88u; mLa<\/sub>\u00a0= 138,87u. B\u1ecf qua kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a electron.<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

Ta c\u00f3:<\/p>\n

Q = (M0<\/sub>\u00a0– M)c2<\/sup>\u00a0v\u1edbi M0<\/sub>\u00a0= m(U) + m(n)<\/p>\n

= 234,99 + 1,01 = 236u<\/p>\n

M = m(M0<\/sub>\u00a0) + m(La) + 2m(n) = 235,77u.<\/p>\n

T\u1eeb \u0111\u00f3 : Q = 0,23u.c2<\/sup>\u00a0= 214 MeV.<\/p>\n

\n
<\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"

C\u00c2U H\u1eceI C\u00e2u 1 (trang 287 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):\u00a0Ph\u1ea3n \u1ee9ng ph\u00e2n h\u1ea1ch l\u00e0 g\u00ec? L\u1eddi gi\u1ea3i: Xem m\u1ee5c 1 ph\u1ea7n KTCB. C\u00e2u 2 (trang 287 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):\u00a0Ph\u1ea3n \u1ee9ng ph\u00e2n h\u1ea1ch d\u00e2y chuy\u1ec1n l\u00e0 g\u00ec? V\u1edbi \u0111i\u1ec1u ki\u1ec7n n\u00e0o th\u00ec n\u00f3 x\u1ea3y ra? L\u1eddi gi\u1ea3i: Xem m\u1ee5c 2, ph\u1ea7n […]<\/p>\n","protected":false},"author":3,"featured_media":24952,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1304],"tags":[1432,1431],"yoast_head":"\nCh\u01b0\u01a1ng 9 - B\u00e0i 56: Ph\u1ea3n \u1ee9ng ph\u00e2n h\u1ea1ch<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/chuong-9-bai-56-phan-ung-phan-hach\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Ch\u01b0\u01a1ng 9 - B\u00e0i 56: Ph\u1ea3n \u1ee9ng ph\u00e2n h\u1ea1ch\" \/>\n<meta property=\"og:description\" content=\"C\u00c2U H\u1eceI C\u00e2u 1 (trang 287 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):\u00a0Ph\u1ea3n \u1ee9ng ph\u00e2n h\u1ea1ch l\u00e0 g\u00ec? L\u1eddi gi\u1ea3i: Xem m\u1ee5c 1 ph\u1ea7n KTCB. C\u00e2u 2 (trang 287 sgk V\u1eadt L\u00ed 12 n\u00e2ng cao):\u00a0Ph\u1ea3n \u1ee9ng ph\u00e2n h\u1ea1ch d\u00e2y chuy\u1ec1n l\u00e0 g\u00ec? V\u1edbi \u0111i\u1ec1u ki\u1ec7n n\u00e0o th\u00ec n\u00f3 x\u1ea3y ra? 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