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{"id":24906,"date":"2018-03-31T12:10:52","date_gmt":"2018-03-31T05:10:52","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=24906"},"modified":"2018-03-31T12:10:52","modified_gmt":"2018-03-31T05:10:52","slug":"chuong-1-bai-1-dao-dong-dieu-hoa","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/chuong-1-bai-1-dao-dong-dieu-hoa\/","title":{"rendered":"Ch\u01b0\u01a1ng 1 – B\u00e0i 1: Dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a"},"content":{"rendered":"

B\u00e0i 1 (trang 9 SGK V\u1eadt L\u00fd 12):<\/b>\u00a0Ph\u00e1t bi\u1ec3u \u0111\u1ecbnh ngh\u0129a c\u1ee7a dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a.<\/span><\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

Dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a l\u00e0 dao \u0111\u1ed9ng trong \u0111\u00f3 li \u0111\u1ed9 c\u1ee7a v\u1eadt l\u00e0 m\u1ed9t h\u00e0m cosin (hay sin) c\u1ee7a th\u1eddi gian.<\/p>\n

B\u00e0i 2 (trang 9 SGK V\u1eadt L\u00fd 12):<\/b>\u00a0Vi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh c\u1ee7a dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a v\u00e0 gi\u1ea3i th\u00edch c\u00e1c \u0111\u1ea1i l\u01b0\u1ee3ng trong ph\u01b0\u01a1ng tr\u00ecnh.<\/span><\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

Ph\u01b0\u01a1ng tr\u00ecnh c\u1ee7a dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a x= Acos(\u03c9t + \u03c6)<\/p>\n

Trong \u0111\u00f3 :<\/p>\n

– x : li \u0111\u1ed9 c\u1ee7a dao \u0111\u1ed9ng (\u0111\u1ed9 l\u1ec7ch c\u1ee7a v\u1eadt kh\u1ecfi v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng) c\u00f3 \u0111\u01a1n v\u1ecb l\u00e0 centimet ho\u1eb7c m\u00e9t (cm ; m)<\/p>\n

– A : bi\u00ean \u0111\u1ed9 dao \u0111\u1ed9ng, c\u00f3 \u0111\u01a1n v\u1ecb l\u00e0 centimet ho\u1eb7c m\u00e9t (cm ; m)<\/p>\n

– \u03c9 : t\u1ea7n s\u1ed1 g\u00f3c c\u1ee7a dao \u0111\u1ed9ng c\u00f3 \u0111\u01a1n v\u1ecb l\u00e0 radian tr\u00ean gi\u00e2y (rad\/s)<\/p>\n

– (\u03c9t + \u03c6) : pha c\u1ee7a dao \u0111\u1ed9ng t\u1ea1i th\u1eddi \u0111i\u1ec3m t, c\u00f3 \u0111\u01a1n v\u1ecb l\u00e0 radian (rad)<\/p>\n

– \u03c6: pha ban \u0111\u1ea7u c\u1ee7a dao \u0111\u1ed9ng, c\u00f3 \u0111\u01a1n v\u1ecb l\u00e0 radian (rad)<\/p>\n

B\u00e0i 3 (trang 9 SGK V\u1eadt L\u00fd 12):<\/b>\u00a0M\u1ed1i li\u00ean h\u1ec7 gi\u1eefa dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a v\u00e0 chuy\u1ec3n \u0111\u1ed9ng tr\u00f2n \u0111\u1ec1u th\u1ec3 hi\u1ec7n \u1edf ch\u1ed7 n\u00e0o ?<\/span><\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

M\u1ed9t \u0111i\u1ec3m P dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a tr\u00ean m\u1ed9t \u0111o\u1ea1n th\u1eb3ng lu\u00f4n lu\u00f4n c\u00f3 th\u1ec3 \u0111\u01b0\u1ee3c coi l\u00e0 h\u00ecnh chi\u1ebfu c\u1ee7a m\u1ed9t \u0111i\u1ec3m M t\u01b0\u01a1ng \u1ee9ng chuy\u1ec3n \u0111\u1ed9ng tr\u00f2n \u0111\u1ec1u l\u00ean \u0111\u01b0\u1eddng k\u00ednh l\u00e0 \u0111o\u1ea1n th\u1eb3ng \u0111\u00f3.<\/p>\n

B\u00e0i 4 (trang 9 SGK V\u1eadt L\u00fd 12):<\/b>\u00a0N\u00eau \u0111\u1ecbnh ngh\u0129a chu k\u00ec v\u00e0 t\u1ea7n s\u1ed1 c\u1ee7a dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a.<\/span><\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

Chu k\u00ec T c\u1ee7a dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a l\u00e0 kho\u1ea3ng th\u1eddi gian \u0111\u1ec3 v\u1eadt th\u1ef1c hi\u1ec7n \u0111\u01b0\u1ee3c m\u1ed9t dao \u0111\u1ed9ng to\u00e0n ph\u1ea7n. \u0110\u01a1n v\u1ecb c\u1ee7a chu k\u00ec l\u00e0 gi\u00e2y (s).<\/p>\n

T\u1ea7n s\u1ed1 f c\u1ee7a dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a l\u00e0 s\u1ed1 l\u1ea7n dao \u0111\u1ed9ng to\u00e0n ph\u1ea7n th\u1ef1c hi\u1ec7n \u0111\u01b0\u1ee3c trong m\u1ed9t gi\u00e2y. \u0110\u01a1n v\u1ecb c\u1ee7a t\u1ea7n s\u1ed1 l\u00e0 h\u00e9c (Hz).<\/p>\n

B\u00e0i 5 (trang 9 SGK V\u1eadt L\u00fd 12):<\/b>\u00a0Gi\u1eefa chu k\u00ec, t\u1ea7n s\u1ed1 v\u00e0 t\u1ea7n s\u1ed1 g\u00f3c c\u00f3 m\u1ed1i li\u00ean h\u1ec7 nh\u01b0 th\u1ebf n\u00e0o ?<\/span><\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

Gi\u1eefa chu k\u00ec T, t\u1ea7n s\u1ed1 f v\u00e0 t\u1ea7n s\u1ed1 g\u00f3c \u03c9 li\u00ean h\u1ec7 v\u1edbi nhau b\u1edfi h\u1ec7 th\u1ee9c<\/p>\n

\"\"<\/p>\n

v\u1edbi \u03c9 l\u00e0 t\u1ea7n s\u1ed1 g\u00f3c, \u0111\u01a1n v\u1ecb l\u00e0 radian tr\u00ean gi\u00e2y (rad\/s)<\/p>\n

B\u00e0i 6 (trang 9 SGK V\u1eadt L\u00fd 12):<\/b>\u00a0M\u1ed9t v\u1eadt dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a theo ph\u01b0\u01a1ng tr\u00ecnh x= Acos(\u03c9t + \u03c6).<\/span><\/p>\n

a) L\u1eadp c\u00f4ng th\u1ee9c t\u00ednh v\u1eadn t\u1ed1c v\u00e0 gia t\u1ed1c c\u1ee7a v\u1eadt.<\/p>\n

b) \u1ede v\u1ecb tr\u00ed n\u00e0o th\u00ec v\u1eadn t\u1ed1c b\u1eb1ng 0 ? \u1ede v\u1ecb tr\u00ed n\u00e0o th\u00ec gia t\u1ed1c b\u1eb1ng 0 ?<\/p>\n

c) \u1ede v\u1ecb tr\u00ed n\u00e0o th\u00ec v\u1eadn t\u1ed1c c\u00f3 \u0111\u1ed9 d\u00e0i c\u1ef1c \u0111\u1ea1i ? \u1ede v\u1ecb tr\u00ed n\u00e0o th\u00ec gia t\u1ed1c c\u00f3 \u0111\u1ed9 l\u1edbn c\u1ef1c \u0111\u1ea1i ?<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

a) C\u00f4ng th\u1ee9c v\u1eadn t\u1ed1c v = x'(t) = – \u03c9Asin(\u03c9t + \u03c6)<\/p>\n

C\u00f4ng th\u1ee9c gia t\u1ed1c a = v'(t) = – \u03c92<\/sup>Acos(\u03c9t + \u03c6) hay a = – \u03c92<\/sup>x<\/p>\n

b) T\u1ea1i v\u1ecb tr\u00ed bi\u00ean x = \u00b1A th\u00ec v\u1eadn t\u1ed1c b\u1eb1ng kh\u00f4ng.<\/p>\n

T\u1ea1i v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng x = 0 th\u00ec gia t\u1ed1c b\u1eb1ng kh\u00f4ng.<\/p>\n

c) T\u1ea1i v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng x = 0, v\u1eadn t\u1ed1c c\u1ef1c \u0111\u1ea1i.<\/p>\n

T\u1ea1i v\u1ecb tr\u00ed bi\u00ean x = \u00b1A, gia t\u1ed1c c\u00f3 \u0111\u1ed9 l\u1edbn c\u1ef1c \u0111\u1ea1i.<\/p>\n

B\u00e0i 7 (trang 9 SGK V\u1eadt L\u00fd 12):<\/b>\u00a0M\u1ed9t v\u1eadt dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a c\u00f3 qu\u1ef9 \u0111\u1ea1o l\u00e0 m\u1ed9t \u0111o\u1ea1n th\u1eb3ng d\u00e0i 12cm. Bi\u00ean \u0111\u1ed9 dao \u0111\u1ed9ng c\u1ee7a v\u1eadt l\u00e0 bao nhi\u00eau?<\/span><\/p>\n

A. 12cm ; \u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0 B. \u2013 12cm<\/p>\n

C. 6cm ; \u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0 D. \u2013 6cm<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

– Ch\u1ecdn\u00a0C<\/b><\/p>\n

– Bi\u00ean \u0111\u1ed9 dao \u0111\u1ed9ng c\u1ee7a v\u1eadt l\u00e0:<\/p>\n

\"\"<\/p>\n

B\u00e0i 8 (trang 9 SGK V\u1eadt L\u00fd 12):<\/b>\u00a0M\u1ed9t v\u1eadt chuy\u1ec3n \u0111\u1ed9ng tr\u00f2n \u0111\u1ec1u v\u1edbi v\u1eadn t\u1ed1c g\u00f3c l\u00e0 \u03c0 (rad\/s). H\u00ecnh chi\u1ebfu c\u1ee7a v\u1eadt tr\u00ean m\u1ed9t \u0111\u01b0\u1eddng k\u00ednh dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a v\u1edbi t\u1ea7n s\u1ed1 g\u00f3c, chu k\u00ec v\u00e0 t\u1ea7n s\u1ed1 b\u1eb1ng bao nhi\u00eau?<\/span><\/p>\n

A. \u03c0 rad\/s; 2s; 0,5 Hz ; \u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0 B. 2\u03c0 rad\/s; 0,5 s; 2 Hz<\/p>\n

C. 2\u03c0 rad\/s; 1s; 1Hz ; \u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0 D. \u03c0\/2 rad\/s; 4s; 0,25 Hz<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

Ch\u1ecdn \u0111\u00e1p \u00e1n A.<\/p>\n

V\u1eadn t\u1ed1c g\u00f3c \u03c9 = \u03c0 rad\/s<\/p>\n

=> T\u1ea7n s\u1ed1 g\u00f3c c\u1ee7a dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a t\u01b0\u01a1ng \u1ee9ng l\u00e0 \u03c9 = \u03c0 (rad\/s)<\/p>\n

\"\"<\/p>\n

B\u00e0i 9 (trang 9 SGK V\u1eadt L\u00fd 12):<\/b>\u00a0Cho ph\u01b0\u01a1ng tr\u00ecnh c\u1ee7a dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a x = – 5cos(4\u03c0t) (cm). Bi\u00ean \u0111\u1ed9 v\u00e0 pha ban \u0111\u1ea7u c\u1ee7a dao \u0111\u1ed9ng l\u00e0 bao nhi\u00eau?<\/span><\/p>\n

A. 5cm; 0 rad ; \u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0 B. 5 cm; 4\u03c0 rad<\/p>\n

C. 5 cm; (4\u03c0t) rad ; \u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0 D. 5cm; \u03c0 rad<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

– Ch\u1ecdn\u00a0D<\/b><\/p>\n

– Ta c\u00f3: x = -5cos(4\u03c0t) = 5cos(4\u03c0t + \u03c0)<\/p>\n

Bi\u00ean \u0111\u1ed9 c\u1ee7a dao \u0111\u1ed9ng A = 5cm.<\/p>\n

Pha ban \u0111\u1ea7u c\u1ee7a dao \u0111\u1ed9ng \u03c6 = \u03c0 (rad).<\/p>\n

B\u00e0i 10 (trang 9 SGK V\u1eadt L\u00fd 12):<\/b>\u00a0Ph\u01b0\u01a1ng tr\u00ecnh c\u1ee7a dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a l\u00e0<\/span><\/p>\n

\"\"<\/p>\n

H\u00e3y cho bi\u1ebft bi\u00ean \u0111\u1ed9, pha ban \u0111\u1ea7u, v\u00e0 pha \u1edf th\u1eddi \u0111i\u1ec3m t c\u1ee7a dao \u0111\u1ed9ng.<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

Bi\u00ean \u0111\u1ed9 c\u1ee7a dao \u0111\u1ed9ng: A = 2 (cm)<\/p>\n

Pha ban \u0111\u1ea7u c\u1ee7a dao \u0111\u1ed9ng:<\/p>\n

\"\"<\/p>\n

Pha \u1edf th\u1eddi \u0111i\u1ec3m t c\u1ee7a dao \u0111\u1ed9ng:<\/p>\n

\"\"<\/p>\n

B\u00e0i 11 (trang 9 SGK V\u1eadt L\u00fd 12):<\/b>\u00a0M\u1ed9t v\u1eadt dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a ph\u1ea3i m\u1ea5t 0,25s \u0111\u1ec3 \u0111i t\u1eeb \u0111i\u1ec3m c\u00f3 v\u1eadn t\u1ed1c b\u1eb1ng kh\u00f4ng t\u1edbi \u0111i\u1ec3m ti\u1ebfp theo c\u0169ng nh\u01b0 v\u1eady. Kho\u1ea3ng c\u00e1ch gi\u1eefa hai \u0111i\u1ec3m l\u00e0 36cm. T\u00ednh:<\/span><\/p>\n

a) Chu k\u00ec<\/p>\n

b) T\u1ea7n s\u1ed1<\/p>\n

c) Bi\u00ean \u0111\u1ed9.<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

a) V\u1eadt \u0111i t\u1eeb \u0111i\u1ec3m c\u00f3 v\u1eadn t\u1ed1c b\u1eb1ng kh\u00f4ng t\u1edbi th\u1eddi \u0111i\u1ec3m ti\u1ebfp theo c\u0169ng c\u00f3 v\u1eadn t\u1ed1c b\u1eb1ng kh\u00f4ng, c\u00f3 ngh\u0129a l\u00e0 v\u1eadt \u0111i t\u1eeb v\u1ecb tr\u00ed bi\u00ean n\u00e0y t\u1edbi v\u1ecb tr\u00ed bi\u00ean kia m\u1ea5t kho\u1ea3ng th\u1eddi gian l\u00e0 n\u1eeda chu k\u00ec.<\/p>\n

\"\"<\/p>\n

\n
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B\u00e0i 1 (trang 9 SGK V\u1eadt L\u00fd 12):\u00a0Ph\u00e1t bi\u1ec3u \u0111\u1ecbnh ngh\u0129a c\u1ee7a dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a. L\u1eddi gi\u1ea3i: Dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a l\u00e0 dao \u0111\u1ed9ng trong \u0111\u00f3 li \u0111\u1ed9 c\u1ee7a v\u1eadt l\u00e0 m\u1ed9t h\u00e0m cosin (hay sin) c\u1ee7a th\u1eddi gian. B\u00e0i 2 (trang 9 SGK V\u1eadt L\u00fd 12):\u00a0Vi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh c\u1ee7a dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a […]<\/p>\n","protected":false},"author":3,"featured_media":24907,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1303],"tags":[1428,1427],"yoast_head":"\nCh\u01b0\u01a1ng 1 - B\u00e0i 1: Dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/chuong-1-bai-1-dao-dong-dieu-hoa\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Ch\u01b0\u01a1ng 1 - B\u00e0i 1: Dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a\" \/>\n<meta property=\"og:description\" content=\"B\u00e0i 1 (trang 9 SGK V\u1eadt L\u00fd 12):\u00a0Ph\u00e1t bi\u1ec3u \u0111\u1ecbnh ngh\u0129a c\u1ee7a dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a. L\u1eddi gi\u1ea3i: Dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a l\u00e0 dao \u0111\u1ed9ng trong \u0111\u00f3 li \u0111\u1ed9 c\u1ee7a v\u1eadt l\u00e0 m\u1ed9t h\u00e0m cosin (hay sin) c\u1ee7a th\u1eddi gian. 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