B\u00e0i 1 (trang 13 SGK V\u1eadt L\u00fd 12):<\/b>\u00a0Kh\u1ea3o s\u00e1t dao \u0111\u1ed9ng c\u1ee7a con l\u1eafc l\u00f2 xo n\u1eb1m ngang. T\u00ecm c\u00f4ng th\u1ee9c c\u1ee7a l\u1ef1c k\u00e9o v\u1ec1.<\/span><\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n X\u00e9t con l\u1eafc l\u00f2 xo nh\u01b0 h\u00ecnh v\u1ebd:<\/p>\n <\/p>\n Ch\u1ecdn h\u1ec7 tr\u1ee5c t\u1ecda \u0111\u1ed9 c\u00f3 Ox c\u00f3 g\u1ed1c t\u1ecda \u0111\u1ed9 O tr\u00f9ng v\u1edbi v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng, chi\u1ec1u d\u01b0\u01a1ng l\u00e0 chi\u1ec1u quy \u01b0\u1edbc (nh\u01b0 h\u00ecnh v\u1ebd).<\/p>\n T\u1eeb v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng O k\u00e9o v\u1eadt m cho l\u00f2 xo d\u00e3n ra m\u1ed9t \u0111o\u1ea1n nh\u1ecf r\u1ed3i bu\u00f4ng tay, v\u1eadt s\u1ebd dao \u0111\u1ed9ng tr\u00ean m\u1ed9t \u0111\u01b0\u1eddng th\u1eb3ng quanh v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng.<\/p>\n <\/p>\n B\u00e0i 2 (trang 13 SGK V\u1eadt L\u00fd 12):<\/b>\u00a0N\u00eau c\u00f4ng th\u1ee9c t\u00ednh chu k\u00ec c\u1ee7a con l\u1eafc l\u00f2 xo.<\/span><\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n C\u00f4ng th\u1ee9c chu k\u00ec con l\u1eafc l\u00f2 xo<\/p>\n <\/p>\n V\u1edbi : m : kh\u1ed1i l\u01b0\u1ee3ng qu\u1ea3 n\u1eb7ng (kg)<\/p>\n k : l\u00e0 \u0111\u1ed9 c\u1ee9ng c\u1ee7a l\u00f2 xo, c\u00f3 \u0111\u01a1n v\u1ecb l\u00e0 Niuton tr\u00ean m\u00e9t (N\/m)<\/p>\n T : l\u00e0 chu k\u00ec, c\u00f3 \u0111\u01a1n v\u1ecb l\u00e0 gi\u00e2y (s)<\/p>\n B\u00e0i 3 (trang 13 SGK V\u1eadt L\u00fd 12):<\/b>\u00a0Vi\u1ebft c\u00f4ng th\u1ee9c c\u1ee7a \u0111\u1ed9ng n\u0103ng, th\u1ebf n\u0103ng v\u00e0 c\u01a1 n\u0103ng c\u1ee7a con l\u1eafc l\u00f2 xo.<\/span><\/p>\n Khi con l\u1eafc l\u00f2 xo dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a th\u00ec \u0111\u1ed9ng n\u0103ng v\u00e0 th\u1ebf n\u0103ng c\u1ee7a con l\u1eafc bi\u1ebfn \u0111\u1ed5i qua l\u1ea1i nh\u01b0 th\u1ebf n\u00e0o?<\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n \u0110\u1ed9ng n\u0103ng :<\/p>\n <\/p>\n W\u0111<\/sub>\u00a0: \u0110\u1ed9ng n\u0103ng c\u1ee7a con l\u1eafc l\u00f2 xo (J)<\/p>\n m: kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a v\u1eadt (kg)<\/p>\n v: v\u1eadn t\u1ed1c c\u1ee7a v\u1eadt (m\/s)<\/p>\n Th\u1ebf n\u0103ng (Ch\u1ecdn g\u1ed1c th\u1ebf n\u0103ng \u0111\u00e0n h\u1ed3i t\u1ea1i v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng c\u1ee7a v\u1eadt)<\/p>\n <\/p>\n Wt<\/sub>: th\u1ebf n\u0103ng \u0111\u00e0n h\u1ed3i (J)<\/p>\n k: \u0111\u1ed9 c\u1ee9ng l\u00f2 xo (N\/m)<\/p>\n x: li \u0111\u1ed9 (m)<\/p>\n C\u01a1 n\u0103ng: B\u1eb1ng t\u1ed5ng \u0111\u1ed9ng n\u0103ng v\u00e0 th\u1ebf n\u0103ng<\/p>\n <\/p>\n Khi con l\u1eafc dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a, \u0111\u1ed9ng n\u0103ng t\u0103ng th\u00ec th\u1ebf n\u0103ng gi\u1ea3m v\u00e0 ng\u01b0\u1ee3c l\u1ea1i, \u0111\u1ed9ng n\u0103ng gi\u1ea3m th\u00ec th\u1ebf n\u0103ng t\u0103ng.<\/p>\n B\u00e0i 4 (trang 13 SGK V\u1eadt L\u00fd 12):<\/b>\u00a0Ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang. C\u00f4ng th\u1ee9c t\u00ednh chu k\u00ec dao \u0111\u1ed9ng c\u1ee7a con l\u1eafc l\u00f2 xo l\u00e0:<\/span><\/p>\n <\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n Ch\u1ecdn \u0111\u00e1p \u00e1n D.<\/p>\n B\u00e0i 5 (trang 13 SGK V\u1eadt L\u00fd 12):<\/b>\u00a0M\u1ed9t con l\u1eafc l\u00f2 xo dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a. L\u00f2 xo c\u00f3 \u0111\u1ed9 c\u1ee9ng k = 40 N\/m. Khi v\u1eadt m c\u1ee7a con l\u1eafc \u0111i qua v\u1ecb tr\u00ed c\u00f3 li \u0111\u1ed9 x = – 2cm th\u00ec th\u1ebf n\u0103ng c\u1ee7a con l\u1eafc l\u00e0 bao nhi\u00eau?<\/span><\/p>\n A. \u2013 0,016 J<\/p>\n B. \u2013 0,008 J<\/p>\n C. 0,016 J<\/p>\n D. 0,008 J<\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n Th\u1ebf n\u0103ng<\/p>\n <\/p>\n Ch\u1ecdn \u0111\u00e1p \u00e1n D.<\/p>\n B\u00e0i 6 (trang 13 SGK V\u1eadt L\u00fd 12):<\/b>\u00a0M\u1ed9t con l\u1eafc l\u00f2 xo g\u1ed3m m\u1ed9t kh\u1ed1i l\u01b0\u1ee3ng m = 0,4 kg v\u00e0 m\u1ed9t l\u00f2 xo c\u00f3 \u0111\u1ed9 c\u1ee9ng k = 80 N\/m. Con l\u1eafc dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a v\u1edbi bi\u00ean \u0111\u1ed9 b\u1eb1ng 0,1 m. H\u1ecfi t\u1ed1c \u0111\u1ed9 c\u1ee7a con l\u1eafc khi qua v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng?<\/span><\/p>\n A. 0 m\/s<\/p>\n B. 1,4 m\/s<\/p>\n C. 2,0 m\/s<\/p>\n D. 3,4 m\/s<\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n T\u1ed1c \u0111\u1ed9 c\u1ee7a con l\u1eafc qua v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng l\u00e0 c\u1ef1c \u0111\u1ea1i<\/p>\n Ta c\u00f3 vmax<\/sub>\u00a0= \u03c9A v\u1edbi<\/p>\n <\/p>\n Ch\u1ecdn \u0111\u00e1p \u00e1n B.<\/p>\n B\u00e0i 1 (trang 13 SGK V\u1eadt L\u00fd 12):\u00a0Kh\u1ea3o s\u00e1t dao \u0111\u1ed9ng c\u1ee7a con l\u1eafc l\u00f2 xo n\u1eb1m ngang. T\u00ecm c\u00f4ng th\u1ee9c c\u1ee7a l\u1ef1c k\u00e9o v\u1ec1. L\u1eddi gi\u1ea3i: X\u00e9t con l\u1eafc l\u00f2 xo nh\u01b0 h\u00ecnh v\u1ebd: Ch\u1ecdn h\u1ec7 tr\u1ee5c t\u1ecda \u0111\u1ed9 c\u00f3 Ox c\u00f3 g\u1ed1c t\u1ecda \u0111\u1ed9 O tr\u00f9ng v\u1edbi v\u1ecb tr\u00ed c\u00e2n b\u1eb1ng, chi\u1ec1u d\u01b0\u01a1ng […]<\/p>\n","protected":false},"author":3,"featured_media":24896,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1303],"tags":[1428,1427],"yoast_head":"\n