B\u00e0i 1 (trang 25 SGK V\u1eadt L\u00fd 12):<\/b>\u00a0N\u00eau c\u00e1ch bi\u1ec3u di\u1ec5n m\u1ed9t dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a b\u1eb1ng m\u1ed9t vecto quay.<\/span><\/p>\nL\u1eddi gi\u1ea3i:<\/b><\/p>\n
M\u1ed7i dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a x = Acos(\u03c9t + \u03c6) \u0111\u01b0\u1ee3c bi\u1ec3u di\u1ec5n b\u1eb1ng m\u1ed9t vecto quay. Vecto quay c\u00f3 \u0111\u1eb7c \u0111i\u1ec3m:<\/p>\n
C\u00f3 g\u1ed1c t\u1ea1i g\u1ed1c t\u1ecda \u0111\u1ed9 c\u1ee7a tr\u1ee5c Ox, c\u00f3 \u0111\u1ed9 d\u00e0i b\u1eb1ng bi\u00ean \u0111\u1ed9 dao \u0111\u1ed9ng A v\u00e0 h\u1ee3p v\u1edbi tr\u1ee5c Ox m\u1ed9t g\u00f3c b\u1eb1ng pha ban \u0111\u1ea7u \u03c6.<\/p>\n
B\u00e0i 2 (trang 25 SGK V\u1eadt L\u00fd 12)<\/b>: Tr\u00ecnh b\u00e0y ph\u01b0\u01a1ng ph\u00e1p gi\u1ea3n \u0111\u1ed3 Fre-nen \u0111\u1ec3 t\u00ecm dao \u0111\u1ed9ng t\u1ed5ng h\u1ee3p c\u1ee7a hai dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a c\u00f9ng ph\u01b0\u01a1ng, c\u00f9ng t\u1ea7n s\u1ed1.<\/span><\/p>\nL\u1eddi gi\u1ea3i:<\/b><\/p>\n
Gi\u1ea3 s\u1eed c\u1ea7n t\u1ed5ng h\u1ee3p hai dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a c\u00f9ng ph\u01b0\u01a1ng, c\u00f9ng t\u1ea7n s\u1ed1.<\/p>\n
x1<\/sub>\u00a0= A1<\/sub>cos(\u03c9t + \u03c61<\/sub>); \u00a0 \u00a0\u00a0\u00a0 x2<\/sub>\u00a0= A2<\/sub>cos(\u03c9t + \u03c62<\/sub>)<\/p>\nL\u1ea7n l\u01b0\u1ee3t v\u1ebd hai vecto quay A1<\/sub>, A2<\/sub>\u00a0bi\u1ec3u di\u1ec5n cho dao \u0111\u1ed9ng x1<\/sub>\u00a0v\u00e0 dao \u0111\u1ed9ng x2<\/sub>, l\u1ea7n l\u01b0\u1ee3t h\u1ee3p v\u1edbi tr\u1ee5c Ox nh\u1eefng g\u00f3c \u03c61, \u03c62. V\u1ebd vecto t\u1ed5ng h\u1ee3p c\u1ee7a hai vecto tr\u00ean. Vecto t\u1ed5ng h\u1ee3p l\u00e0 vecto quay bi\u1ec3u di\u1ec5n ph\u01b0\u01a1ng tr\u00ecnh c\u1ee7a dao \u0111\u1ed9ng t\u1ed5ng h\u1ee3p.<\/p>\nB\u00e0i 3 (trang 25 SGK V\u1eadt L\u00fd 12):<\/b>\u00a0N\u00eau \u1ea3nh h\u01b0\u1edfng c\u1ee7a \u0111\u1ed9 l\u1ec7ch pha (\u03c62<\/sub>\u00a0– \u03c61<\/sub>) \u0111\u1ebfn bi\u00ean \u0111\u1ed9 c\u1ee7a dao \u0111\u1ed9ng t\u1ed5ng h\u1ee3p trong c\u00e1c tr\u01b0\u1eddng h\u1ee3p:<\/span><\/p>\na) Hai dao \u0111\u1ed9ng th\u00e0nh ph\u1ea7n c\u00f9ng pha<\/p>\n
b) Hai dao \u0111\u1ed9ng th\u00e0nh ph\u1ea7n ng\u01b0\u1ee3c pha<\/p>\n
c) Hai dao \u0111\u1ed9ng th\u00e0nh ph\u1ea7n c\u00f3 pha vu\u00f4ng g\u00f3c<\/p>\n
![\"\"](\"https:\/\/lop12.edu.vn\/wp-content\/uploads\/2018\/03\/1-630.png\")
<\/p>\n
L\u1eddi gi\u1ea3i:<\/b><\/p>\n
Bi\u00ean \u0111\u1ed9 dao \u0111\u1ed9ng t\u1ed5ng h\u1ee3p ph\u1ee5 thu\u1ed9c v\u00e0o \u0111\u1ed9 l\u1ec7ch pha \u0394\u03c6 = \u03c62<\/sub>\u00a0– \u03c61<\/sub><\/p>\nBi\u00ean \u0111\u1ed9 dao \u0111\u1ed9ng t\u1ed5ng h\u1ee3p ph\u1ee5 thu\u1ed9c v\u00e0o \u0111\u1ed9 l\u1ec7ch pha \u0394\u03c6 = \u03c62<\/sub>\u00a0– \u03c61<\/sub><\/p>\nN\u1ebfu hai dao \u0111\u1ed9ng th\u00e0nh ph\u1ea7n ng\u01b0\u1ee3c pha: \u0394\u03c6 = \u03c62<\/sub>\u00a0– \u03c61<\/sub>\u00a0= (2n + 1)\u03c0 (n = 0, \u00b11,\u00b12,\u2026) th\u00ec bi\u00ean \u0111\u1ed9 dao \u0111\u1ed9ng t\u1ed5ng h\u1ee3p l\u00e0 nh\u1ecf nh\u1ea5t A = |A1<\/sub>-A2<\/sub>\u00a0|<\/p>\nN\u1ebfu hai dao \u0111\u1ed9ng th\u00e0nh ph\u1ea7n c\u00f3 pha vu\u00f4ng g\u00f3c \u0394\u03c6 = \u03c62<\/sub>\u00a0– \u03c61<\/sub>\u00a0= \u00b1\u03c0\/2+2n\u03c0 (n = 0, \u00b11,\u00b12,\u2026) th\u00ec bi\u00ean \u0111\u1ed9 dao \u0111\u1ed9ng t\u1ed5ng h\u1ee3p<\/p>\n![\"\"](\"https:\/\/lop12.edu.vn\/wp-content\/uploads\/2018\/03\/2-407.png\")
<\/p>\n
B\u00e0i 4 (trang 25 SGK V\u1eadt L\u00fd 12):<\/b>\u00a0Ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang. Hai dao \u0111\u1ed9ng l\u00e0 ng\u01b0\u1ee3c pha khi:<\/span><\/p>\nA. \u03c62<\/sub>\u00a0– \u03c61<\/sub>\u00a0= 2n\u03c0 ; \u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0 B. \u03c62<\/sub>\u00a0– \u03c61<\/sub>\u00a0= n\u03c0<\/p>\nC. \u03c62<\/sub>\u00a0– \u03c61<\/sub>\u00a0= (2n – 1)\u03c0 ; \u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0 D. \u03c62<\/sub>\u00a0– \u03c61<\/sub>\u00a0= (2n + 1)\u03c0<\/p>\nL\u1eddi gi\u1ea3i:<\/b><\/p>\n
Ch\u1ecdn \u0111\u00e1p \u00e1n D.<\/p>\n
\n
\n
B\u00e0i 5 (trang 25 SGK V\u1eadt L\u00fd 12)<\/b>\u00a0X\u00e9t m\u1ed9t vecto quay …<\/span><\/p>\n![\"\"](\"https:\/\/lop12.edu.vn\/wp-content\/uploads\/2018\/03\/1-631.png\")
\nH\u1ecfi vecto quay OM bi\u1ec3u di\u1ec5n ph\u01b0\u01a1ng tr\u00ecnh c\u1ee7a dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a n\u00e0o?<\/p>\n
![\"\"](\"https:\/\/lop12.edu.vn\/wp-content\/uploads\/2018\/03\/2-408.png\")
<\/div>\n
\n
L\u1eddi gi\u1ea3i:<\/b><\/p>\n
Ch\u1ecdn \u0111\u00e1p \u00e1n B.<\/p>\n
B\u00e0i 6 (trang 25 SGK V\u1eadt L\u00fd 12):<\/b>\u00a0Cho hai dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a c\u00f9ng ph\u01b0\u01a1ng, c\u00f9ng t\u1ea7n s\u1ed1 g\u00f3c \u03c9 = 5\u03c0 rad\/s, v\u1edbi c\u00e1c bi\u00ean \u0111\u1ed9 :<\/span><\/p>\n![\"\"](\"https:\/\/lop12.edu.vn\/wp-content\/uploads\/2018\/03\/1-632.png\")
<\/p>\n
T\u00ecm ph\u01b0\u01a1ng tr\u00ecnh dao \u0111\u1ed9ng t\u1ed5ng h\u1ee3p c\u1ee7a hai dao \u0111\u1ed9ng tr\u00ean.<\/p>\n
L\u1eddi gi\u1ea3i:<\/b><\/p>\n
![\"\"](\"https:\/\/lop12.edu.vn\/wp-content\/uploads\/2018\/03\/2-409.png\")
<\/p>\n
H\u00ecnh tr\u00ean bi\u1ec3u di\u1ec5n hai vecto x1m<\/sub>\u00a0v\u00e0 x2m<\/sub>\u00a0\u0111\u1ed9 l\u1edbn l\u1ea7n l\u01b0\u1ee3t l\u00e0<\/p>\n![\"\"](\"https:\/\/lop12.edu.vn\/wp-content\/uploads\/2018\/03\/3-211.png\")
<\/p>\n
h\u1ee3p v\u1edbi tr\u1ee5c Ox l\u1ea7n l\u01b0\u1ee3t c\u00e1c g\u00f3c 90o<\/sup>\u00a0v\u00e0 150o<\/sup>.<\/p>\nTa c\u00f3 c\u00f4ng th\u1ee9c :<\/p>\n
![\"\"](\"https:\/\/lop12.edu.vn\/wp-content\/uploads\/2018\/03\/4-124.png\")
<\/p>\n
Theo h\u00ecnh v\u1ebd ch\u1ecdn \u03c6 = 0,73\u03c0<\/p>\n
V\u1eady ph\u01b0\u01a1ng tr\u00ecnh t\u1ed5ng h\u1ee3p l\u00e0: x = 2,3cos(5\u03c0t + 0,73\u03c0) (cm)<\/p>\n<\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"
B\u00e0i 1 (trang 25 SGK V\u1eadt L\u00fd 12):\u00a0N\u00eau c\u00e1ch bi\u1ec3u di\u1ec5n m\u1ed9t dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a b\u1eb1ng m\u1ed9t vecto quay. L\u1eddi gi\u1ea3i: M\u1ed7i dao \u0111\u1ed9ng \u0111i\u1ec1u h\u00f2a x = Acos(\u03c9t + \u03c6) \u0111\u01b0\u1ee3c bi\u1ec3u di\u1ec5n b\u1eb1ng m\u1ed9t vecto quay. Vecto quay c\u00f3 \u0111\u1eb7c \u0111i\u1ec3m: C\u00f3 g\u1ed1c t\u1ea1i g\u1ed1c t\u1ecda \u0111\u1ed9 c\u1ee7a tr\u1ee5c Ox, c\u00f3 \u0111\u1ed9 […]<\/p>\n","protected":false},"author":3,"featured_media":24865,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1303],"tags":[1428,1427],"yoast_head":"\n
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