B\u00e0i 1 (trang 79 SGK V\u1eadt L\u00fd 12):<\/b>\u00a0Ph\u00e1t bi\u1ec3u \u0111\u1ecbnh lu\u1eadt \u00d4m \u0111\u1ed1i v\u1edbi m\u1ea1ch \u0111i\u1ec7n xoay chi\u1ec1u c\u00f3 R, L, C m\u1eafc n\u1ed1i ti\u1ebfp.<\/span><\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n \u0110\u1ecbnh lu\u1eadt \u00d4m c\u1ee7a d\u00f2ng \u0111i\u1ec7n xoay chi\u1ec1u c\u1ee7a \u0111o\u1ea1n m\u1ea1ch R, L, C m\u1eafc n\u1ed1i ti\u1ebfp: “C\u01b0\u1eddng \u0111\u1ed9 hi\u1ec7u d\u1ee5ng trong m\u1ea1ch R, L, C m\u1eafc n\u1ed1i ti\u1ebfp c\u00f3 gi\u00e1 tr\u1ecb b\u1eb1ng th\u01b0\u01a1ng s\u1ed1 c\u1ee7a \u0111i\u1ec7n \u00e1p hi\u1ec7u d\u1ee5ng gi\u1eefa hai \u0111\u1ea7u m\u1ea1ch v\u00e0 t\u1ed5ng tr\u1edf c\u1ee7a m\u1ea1ch.”<\/p>\n B\u00e0i 2 (trang 79 SGK V\u1eadt L\u00fd 12):<\/b>\u00a0D\u00f2ng n\u00e0o c\u00f3 c\u1ed9t A t\u01b0\u01a1ng \u1ee9ng v\u1edbi d\u00f2ng n\u00e0o \u1edf c\u1ed9t B?<\/span><\/p>\n <\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n K\u1ebft c\u1ed9t A t\u01b0\u01a1ng \u1ee9ng c\u1ed9t B.<\/p>\n 1 \u2013 e)<\/p>\n 2 \u2013 c)<\/p>\n 3 \u2013 a)<\/p>\n 4 \u2013 a)<\/p>\n 5 \u2013 c)<\/p>\n 6 \u2013 f)<\/p>\n B\u00e0i 3 (trang 79 SGK V\u1eadt L\u00fd 12):<\/b>Trong m\u1ea1ch \u0111i\u1ec7n xoay chi\u1ec1u n\u1ed1i ti\u1ebfp, c\u1ed9ng h\u01b0\u1edfng l\u00e0 g\u00ec? \u0110\u1eb7c tr\u01b0ng c\u1ee7a c\u1ed9ng h\u01b0\u1edfng?<\/span><\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n C\u1ed9ng h\u01b0\u1edfng \u0111i\u1ec7n l\u00e0 hi\u1ec7n t\u01b0\u1ee3ng trong m\u1ea1ch R, L, C m\u1eafc n\u1ed1i ti\u1ebfp c\u00f3 ZL<\/sub>\u00a0= ZC<\/sub>\u00a0hay \u03c92<\/sup>LC = 1.<\/p>\n \u0110\u1eb7c \u0111i\u1ec3m: T\u1ed5ng tr\u1edf m\u1ea1ch Z = R l\u00e0 nh\u1ecf nh\u1ea5t v\u00e0 I = U\/R l\u00e0 l\u1edbn nh\u1ea5t.<\/p>\n D\u00f2ng \u0111i\u1ec7n i c\u00f9ng pha v\u1edbi \u0111i\u1ec7n \u00e1p u<\/p>\n U = UR<\/sub><\/p>\n UL<\/sub>\u00a0= UC<\/sub><\/p>\n B\u00e0i 4 (trang 79 SGK V\u1eadt L\u00fd 12):<\/b>\u00a0M\u1ea1ch \u0111i\u1ec7n xoay chi\u1ec1u g\u1ed3m c\u00f3 R = 20\u03a9 …<\/span><\/p>\n <\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n M\u1ea1ch R n\u1ed1i ti\u1ebfp t\u1ee5 \u0111i\u1ec7n th\u00ec i s\u1edbm pha so v\u1edbi u m\u1ed9t g\u00f3c \u03c6. Ta c\u00f3 u = 60 \u221a2cos100\u03c0t \u21d2 i = I0 cos(100\u03c0t + \u03c6i)<\/p>\n <\/div>\n B\u00e0i 5 (trang 79 SGK V\u1eadt L\u00fd 12):<\/b>\u00a0M\u1ea1ch \u0111i\u1ec7n xoay chi\u1ec1u g\u1ed3m c\u00f3 R = 30\u03a9 …<\/span><\/p>\n <\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n M\u1ea1ch R n\u1ed1i ti\u1ebfp v\u1edbi cu\u1ed9n c\u1ea3m th\u00ec i tr\u1ec5 pha so v\u1edbi u m\u1ed9t g\u00f3c \u03c6.<\/p>\n Ta c\u00f3 u = 120\u221a2cos100\u03c0t (V). \u21d2 i = I0<\/sub>\u00a0cos(100\u03c0t + \u03c6i)<\/p>\n <\/div>\n<\/div>\n B\u00e0i 1 (trang 79 SGK V\u1eadt L\u00fd 12):\u00a0Ph\u00e1t bi\u1ec3u \u0111\u1ecbnh lu\u1eadt \u00d4m \u0111\u1ed1i v\u1edbi m\u1ea1ch \u0111i\u1ec7n xoay chi\u1ec1u c\u00f3 R, L, C m\u1eafc n\u1ed1i ti\u1ebfp. L\u1eddi gi\u1ea3i: \u0110\u1ecbnh lu\u1eadt \u00d4m c\u1ee7a d\u00f2ng \u0111i\u1ec7n xoay chi\u1ec1u c\u1ee7a \u0111o\u1ea1n m\u1ea1ch R, L, C m\u1eafc n\u1ed1i ti\u1ebfp: “C\u01b0\u1eddng \u0111\u1ed9 hi\u1ec7u d\u1ee5ng trong m\u1ea1ch R, L, C m\u1eafc n\u1ed1i […]<\/p>\n","protected":false},"author":3,"featured_media":24814,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1303],"tags":[1428,1427],"yoast_head":"\n