B\u00e0i 1 (trang 85 SGK V\u1eadt L\u00fd 12):<\/b>\u00a0C\u00f4ng su\u1ea5t \u0111i\u1ec7n ti\u00eau th\u1ee5 trong m\u1ed9t m\u1ea1ch \u0111i\u1ec7n xoay chi\u1ec1u ph\u1ee5 thu\u1ed9c nh\u1eefng \u0111\u1ea1i l\u01b0\u1ee3ng n\u00e0o?<\/span><\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n C\u00f4ng su\u1ea5t t\u1ecfa nhi\u1ec7t P ph\u1ee5 thu\u1ed9c v\u00e0o h\u1ec7 s\u1ed1 c\u00f4ng su\u1ea5t.<\/p>\n M\u00e0 h\u1ec7 s\u1ed1 c\u00f4ng su\u1ea5t cos \u03c6 = R\/Z, do \u0111\u00f3 P ph\u1ee5 thu\u1ed9c v\u00e0o Z v\u00e0 R.<\/p>\n B\u00e0i 2 (trang 85 SGK V\u1eadt L\u00fd 12):<\/b>\u00a0H\u00e3y ch\u1ecdn c\u00e2u \u0111\u00fang.<\/span><\/p>\n H\u1ec7 s\u1ed1 c\u00f4ng su\u1ea5t c\u1ee7a m\u1ed9t m\u1ea1ch \u0111i\u1ec7n xoay chi\u1ec1u b\u1eb1ng:<\/p>\n <\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n Ch\u1ecdn \u0111\u00e1p \u00e1n C.<\/p>\n <\/p>\n B\u00e0i 3 (trang 85 SGK V\u1eadt L\u00fd 12):<\/b>\u00a0H\u00e3y ch\u1ecdn c\u00e2u \u0111\u00fang.<\/span><\/p>\n H\u1ec7 s\u1ed1 c\u00f4ng su\u1ea5t trong m\u1ea1ch \u0111i\u1ec7n xoay chi\u1ec1u g\u1ed3m R, L, C m\u1eafc n\u1ed1i ti\u1ebfp v\u1edbi ZL<\/sub>\u00a0= ZC<\/sub>:<\/p>\n A. b\u1eb1ng 0<\/p>\n B. b\u1eb1ng 1<\/p>\n C. ph\u1ee5 thu\u1ed9c R<\/p>\n D. ph\u1ee5 thu\u1ed9c ZC<\/sub>\/ZL<\/sub><\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n Ch\u1ecdn \u0111\u00e1p \u00e1n B.<\/p>\n <\/p>\n B\u00e0i 4 (trang 85 SGK V\u1eadt L\u00fd 12):<\/b>\u00a0H\u00e3y ch\u1ecdn c\u00e2u \u0111\u00fang.<\/span><\/p>\n M\u1ea1ch \u0111i\u1ec7n xoay chi\u1ec1u n\u1ed1i ti\u1ebfp R = 10\u03a9; ZL<\/sub>\u00a0= 8\u03a9; ZC<\/sub>\u00a0= 6\u03a9 v\u1edbi t\u1ea7n s\u1ed1 f. Gi\u00e1 tr\u1ecb c\u1ee7a t\u1ea7n s\u1ed1 \u0111\u1ec3 h\u1ec7 s\u1ed1 c\u00f4ng su\u1ea5t b\u1eb1ng 1:<\/p>\n A. l\u00e0 m\u1ed9t s\u1ed1 < f<\/p>\n B. l\u00e0 m\u1ed9t s\u1ed1 > f<\/p>\n C. l\u00e0 m\u1ed9t s\u1ed1 = f<\/p>\n D. kh\u00f4ng t\u1ed3n t\u1ea1i<\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n Ch\u1ecdn \u0111\u00e1p \u00e1n A. Ta c\u00f3<\/p>\n B\u00e0i 5 (trang 85 SGK V\u1eadt L\u00fd 12):<\/b>\u00a0Cho m\u1ea1ch \u0111i\u1ec7n tr\u00ean h\u00ecnh 15.2, trong \u0111\u00f3 L l\u00e0 m\u1ed9t cu\u1ed9n c\u1ea3m thu\u1ea7n, \u0111i\u1ec7n \u00e1p hai \u0111\u1ea7u m\u1ea1ch uPQ<\/sub>\u00a0= 60\u221a2cos100\u03c0t (V), c\u00e1c \u0111i\u1ec7n \u00e1p hi\u1ec7u d\u1ee5ng UPN<\/sub>\u00a0= UNQ<\/sub>\u00a0= 60V. H\u1ec7 s\u1ed1 c\u00f4ng su\u1ea5t c\u1ee7a m\u1ea1ch l\u00e0 bao nhi\u00eau ?<\/span><\/p>\n <\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n Ch\u1ecdn \u0111\u00e1p \u00e1n A. Ta c\u00f3:<\/p>\n <\/p>\n B\u00e0i 6 (trang 4 SGK V\u1eadt L\u00fd 12):<\/b>\u00a0M\u1ea1ch \u0111i\u1ec7n xoay chi\u1ec1u n\u1ed1i ti\u1ebfp g\u1ed3m c\u00f3:<\/span><\/p>\n <\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n <\/p>\n","protected":false},"excerpt":{"rendered":" B\u00e0i 1 (trang 85 SGK V\u1eadt L\u00fd 12):\u00a0C\u00f4ng su\u1ea5t \u0111i\u1ec7n ti\u00eau th\u1ee5 trong m\u1ed9t m\u1ea1ch \u0111i\u1ec7n xoay chi\u1ec1u ph\u1ee5 thu\u1ed9c nh\u1eefng \u0111\u1ea1i l\u01b0\u1ee3ng n\u00e0o? L\u1eddi gi\u1ea3i: C\u00f4ng su\u1ea5t t\u1ecfa nhi\u1ec7t P ph\u1ee5 thu\u1ed9c v\u00e0o h\u1ec7 s\u1ed1 c\u00f4ng su\u1ea5t. M\u00e0 h\u1ec7 s\u1ed1 c\u00f4ng su\u1ea5t cos \u03c6 = R\/Z, do \u0111\u00f3 P ph\u1ee5 thu\u1ed9c v\u00e0o Z v\u00e0 […]<\/p>\n","protected":false},"author":3,"featured_media":24804,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1303],"tags":[1428,1427],"yoast_head":"\n