B\u00e0i 4 (trang 259 sgk H\u00f3a 12 n\u00e2ng cao):\u00a0H\u00f3a h\u1ecdc \u0111\u00e3 g\u00f3p ph\u1ea7n gi\u1ea3i quy\u1ebft v\u1ea5n \u0111\u1ec1 nhi\u00ean li\u1ec7u v\u00e0 n\u0103ng l\u01b0\u1ee3ng: c\u1ee7a nh\u00e2n lo\u1ea1i trong t\u01b0\u01a1ng lai nh\u01b0 th\u1ebf n\u00e0o?<\/strong><\/p>\nL\u1eddi gi\u1ea3i:<\/b><\/p>\n
H\u00f3a h\u1ecdc \u0111\u00e3 g\u00f3p ph\u1ea7n gi\u1ea3i quy\u1ebft v\u1ea5n \u0111\u1ec1 nhi\u00ean li\u1ec7u v\u00e0 n\u0103ng l\u01b0\u1ee3ng<\/p>\n
– S\u1ea3n xu\u1ea5t CH4 b\u1eb1ng h\u1ea7m biogas hay b\u1eb1ng ph\u1ea3n \u1ee9ng Fischer-Trop<\/p>\n
– S\u1ea3n xu\u1ea5t kh\u00ed than kh\u00f4 v\u00e0 kh\u00ed than \u01b0\u1edbt t\u1eeb than \u0111\u00e1 v\u00e0 n\u01b0\u1edbc<\/p>\n
– S\u1ea3n xu\u1ea5t c\u00e1c v\u1eadt li\u1ec7u chuy\u00ean d\u1ee5ng cho c\u00e1c nh\u00e0 m\u00e1y l\u1ecdc h\u00f3a d\u1ea7u, \u0111i\u1ec7n h\u1ea1t nh\u00e2n<\/p>\n
– S\u1ea3n xu\u1ea5t c\u00e1c v\u1eadt li\u1ec7u chuy\u00ean d\u1ee5ng cho pin m\u1eb7t tr\u1eddi, thi\u1ebft b\u1ecb \u0111un n\u01b0\u1edbc n\u00f3ng m\u1eb7t tr\u1eddi, s\u1ea3n xu\u1ea5t c\u00e1c lo\u1ea1i acquy<\/p>\n
– S\u1eed d\u1ee5ng c\u00e1c ngu\u1ed3n n\u0103ng l\u01b0\u1ee3ng trong c\u00f4ng nghi\u1ec7p h\u00f3a h\u1ecdc m\u1ed9t c\u00e1ch ti\u1ebft ki\u1ec7m hi\u1ec7u qu\u1ea3<\/p>\n
B\u00e0i 5 (trang 259 sgk H\u00f3a 12 n\u00e2ng cao):\u00a0H\u00e3y k\u1ec3 3 th\u00ed d\u1ee5 v\u1ec1 3 lo\u1ea1i v\u1eadt li\u1ec7u h\u00f3a h\u1ecdc \u0111\u01b0\u1ee3c d\u00f9ng trong \u0111\u1eddi s\u1ed1ng v\u00e0 s\u1ea3n xu\u1ea5t<\/strong><\/p>\nL\u1eddi gi\u1ea3i:<\/b><\/p>\n
V\u1eadt li\u1ec7u h\u00f3a h\u1ecdc d\u00f9ng trong s\u1ea3n xu\u1ea5t v\u00e0 \u0111\u1eddi s\u1ed1ng : Cao su, c\u00e1c v\u1eadt li\u1ec7u h\u1ee3p kim , t\u01a1 , s\u1ee3i, …<\/p>\n
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B\u00e0i 6 (trang 259 sgk H\u00f3a 12 n\u00e2ng cao):\u00a0Nhi\u1ec1u lo\u1ea1i s\u1ea3n ph\u1ea9m h\u00f3a h\u1ecdc \u0111\u01b0\u1ee3c s\u1ea3n xu\u1ea5t t\u1eeb mu\u1ed1i \u0103n trong n\u01b0\u1edbc bi\u1ec3n nh\u01b0: HCl, n\u01b0\u1edbc Gia-ven, NaOH, NaCO3<\/sub><\/strong><\/p>\na. H\u00e3y Vi\u1ebft c\u00e1c ph\u01b0\u01a1ng tr\u00ecnh h\u00f3a h\u1ecdc bi\u1ec3u di\u1ec5n c\u00e1c quy tr\u00ecnh s\u1ea3n xu\u1ea5t \u0111\u00f3.<\/p>\n
b. T\u00ednh kh\u1ed1i l\u01b0\u1ee3ng NaCl c\u1ea7n thi\u1ebft \u0111\u1ec3 s\u1ea3n xu\u1ea5t 15 t\u1ea5n NaOH. Bi\u1ebft hi\u1ec7u su\u1ea5t c\u1ee7a qu\u00e1 tr\u00ecnh l\u00e0 80%.<\/p>\n
L\u1eddi gi\u1ea3i:<\/b><\/p>\n
a) T\u1eeb mu\u1ed1i \u0103n \u2192 HCl , n\u01b0\u1edbc Giaven, NaOH, Na2<\/sub>CO3<\/sub><\/p>\n2NaCl + 2H2<\/sub>O (\u0111pdd) \u2192 2NaOH + H2<\/sub>\u00a0+ Cl2<\/sub><\/p>\nH2<\/sub>\u00a0+ Cl2<\/sub>\u00a0(as) \u2192 2HCl<\/p>\nCl2<\/sub>\u00a0+ 2NaOH \u2192 NaCl + NaClO + H2<\/sub>O<\/p>\nCO2<\/sub>\u00a0+ NaOH \u2192 NaHCO3<\/sub><\/p>\n2NaHCO3<\/sub>\u00a0(to)\u2192 Na2<\/sub>CO3<\/sub>\u00a0+ CO2<\/sub>\u00a0+ H2<\/sub>O<\/p>\nb) 2NaCl + 2H2<\/sub>O (\u0111pdd) \u2192 2NaOH + H2<\/sub>\u00a0+ Cl2<\/sub><\/p>\nTheo pt: 2.58,5 gam \u2192 2.40 gam<\/p>\n
V\u1eady 21,9375 t\u1ea5n \u2192 15 t\u1ea5n<\/p>\n
V\u1edbi hi\u1ec7u su\u1ea5t 80% th\u00ec kh\u1ed1i l\u01b0\u1ee3ng NaCl c\u1ea7n l\u1ea5y l\u00e0 :<\/p>\n
21,9375 x 100 : 80 = 27,422 t\u1ea5n<\/p>\n
B\u00e0i 7 (trang 259 sgk H\u00f3a 12 n\u00e2ng cao):\u00a0Metan l\u00e0 th\u00e0nh ph\u1ea7n ch\u1ee7 y\u1ebfu c\u1ee7a kh\u00ed thi\u00ean nhi\u00ean, T\u00ednh th\u1ec3 t\u00edch kh\u00ed thi\u00ean nhi\u00ean \u1edf \u0111ktc ch\u1ee9a 92% metan c\u1eb1n thi\u1ebft \u0111\u1ec3 s\u1ea3n xu\u1ea5t 10 t\u1ea5n nh\u1ef1a phenol foman\u0111ehit (nov\u01a1iac).<\/strong><\/p>\nL\u1eddi gi\u1ea3i:<\/b><\/p>\n
S\u01a1 \u0111\u1ed3<\/p>\n
![\"\"](\"https:\/\/lop12.edu.vn\/wp-content\/uploads\/2018\/03\/bai-7-trang-259-sgk-hoa-12-nang-cao.png\")
<\/p>\n
T\u1ee9c l\u00e0: 7n mol CH4<\/sub>\u00a0\u2192 106n gam polime<\/p>\n0,660377.106 mol \u21d0 10 t\u1ea5n = 107<\/sup>\u00a0gam<\/p>\nVkh\u00ed<\/sub>\u00a0CH4<\/sub>\u00a0= 0,660377.106<\/sup>.22,4 = 14,8.106<\/sup>\u00a0l\u00edt<\/p>\n=> Vkh\u00ed thi\u00ean nhi\u00ean<\/sub>\u00a0= 14,8.106<\/sup>.100\/92 = 16,08.106<\/sup>\u00a0l\u00edt = 16080 m3<\/p>\n <\/p>\n<\/div>\n<\/div>\n
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B\u00e0i 1 (trang 259 sgk H\u00f3a 12 n\u00e2ng cao):\u00a0Nhi\u00ean li\u1ec7u n\u00e0o sau \u0111\u00e2y thu\u1ed9c lo\u1ea1i nhi\u00ean li\u1ec7u s\u1ea1ch \u0111ang \u0111\u01b0\u1ee3c nghi\u00ean c\u1ee9u \u0111\u1ec3 s\u1eed d\u1ee5ng thay th\u1ebf m\u1ed9t s\u1ed1 nhi\u00ean li\u1ec7u kh\u00e1c g\u00e2y \u00f4 nhi\u1ec5m m\u00f4i tr\u01b0\u1eddng? A. Than \u0111\u00e1 B. X\u0103ng d\u1ea7u C. Kh\u00ed butan (gaz) D. Kh\u00ed hi\u0111ro L\u1eddi gi\u1ea3i: \u0110\u00e1p \u00e1n D […]<\/p>\n","protected":false},"author":3,"featured_media":24699,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1306],"tags":[1429,1430],"yoast_head":"\n
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