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{"id":24598,"date":"2018-03-29T17:13:53","date_gmt":"2018-03-29T10:13:53","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=24598"},"modified":"2018-03-29T17:13:53","modified_gmt":"2018-03-29T10:13:53","slug":"chuong-1-bai-2-lipit","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/chuong-1-bai-2-lipit\/","title":{"rendered":"Ch\u01b0\u01a1ng 1- B\u00e0i 2: Lipit"},"content":{"rendered":"

B\u00e0i 1 (trang 11 SGK H\u00f3a 12):<\/b>\u00a0Ch\u1ea5t b\u00e9o l\u00e0 g\u00ec? D\u1ea7u \u0103n v\u00e0 m\u1ee1 \u0111\u1ed9ng v\u1eadt c\u00f3 \u0111i\u1ec3m g\u00ec kh\u00e1c nhau v\u1ec1 c\u1ea5u t\u1ea1o v\u00e0 t\u00ednh ch\u1ea5t v\u1eadt l\u00ed? Cho v\u00ed d\u1ee5 minh h\u1ecda?<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

– Ch\u1ea5t b\u00e9o l\u00e0 trieste c\u1ee7a glixerol v\u00e0 c\u00e1c axit b\u00e9o, g\u1ecdi chung l\u00e0 triglixerit.<\/p>\n

C\u00f4ng th\u1ee9c c\u1ea5u t\u1ea1o chung c\u1ee7a ch\u1ea5t b\u00e9o l\u00e0:<\/p>\n

\"\"<\/p>\n

trong \u0111\u00f3 R1<\/sub>, R2<\/sub>, R3<\/sub>\u00a0l\u00e0 g\u1ed1c axit, c\u00f3 th\u1ec3 gi\u1ed1ng nhau ho\u1eb7c kh\u00e1c nhau.<\/p>\n

– D\u1ea7u \u0103n v\u00e0 m\u1ee1 \u0111\u1ed9ng v\u1eadt \u0111\u1ec1u l\u00e0 este c\u1ee7a glixerol v\u00e0 c\u00e1c axit b\u00e9o. Ch\u00fang kh\u00e1c nhau \u1edf ch\u1ed7:<\/p>\n

+ D\u1ea7u \u0103n th\u00e0nh ph\u1ea7n l\u00e0 c\u00e1c axit b\u00e9o c\u00f3 g\u1ed1c hi\u0111rocacbon kh\u00f4ng no, ch\u00fang \u1edf tr\u1ea1ng th\u00e1i l\u1ecfng.<\/p>\n

V\u00ed d\u1ee5: (C17<\/sub>H33<\/sub>COO)3<\/sub>C3<\/sub>H5<\/sub><\/p>\n

+ M\u1ee1 \u0111\u1ed9ng v\u1eadt th\u00e0nh ph\u1ea7n l\u00e0 c\u00e1c axit b\u00e9o c\u00f3 g\u1ed1c hi\u0111rocacbon no, ch\u00fang \u1edf tr\u1ea1ng th\u00e1i r\u1eafn.<\/p>\n

V\u00ed d\u1ee5: (C17<\/sub>H35<\/sub>COO)3<\/sub>C3<\/sub>H5<\/sub><\/p>\n

B\u00e0i 2 (trang 11 SGK H\u00f3a 12):\u00a0Ph\u00e1t bi\u1ec3u n\u00e0o sau \u0111\u00e2y l\u00e0\u00a0kh\u00f4ng\u00a0\u0111\u00fang?<\/strong><\/p>\n

A. Ch\u1ea5t b\u00e9o kh\u00f4ng tan trong n\u01b0\u1edbc.<\/p>\n

B. Ch\u1ea5t b\u00e9o kh\u00f4ng tan trong n\u01b0\u1edbc, nh\u1eb9 h\u01a1n n\u01b0\u1edbc nh\u01b0ng tan nhi\u1ec1u trong dung m\u00f4i h\u1eefu c\u01a1.<\/p>\n

C. D\u1ea7u \u0103n v\u00e0 m\u1ee1 b\u00f4i tr\u01a1n c\u00f3 c\u00f9ng th\u00e0nh ph\u1ea7n nguy\u00ean t\u1ed1.<\/p>\n

D. Ch\u1ea5t b\u00e9o l\u00e0 este c\u1ee7a glixerol v\u00e0 c\u00e1c axit cacboxylic m\u1ea1ch cacbon d\u00e0i, kh\u00f4ng ph\u00e2n nh\u00e1nh.<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

– \u0110\u00e1p \u00e1n C.<\/p>\n

– B\u1edfi v\u00ec: D\u1ea7u \u0103n l\u00e0 ch\u1ea5t b\u00e9o, c\u00f2n m\u1ee1 b\u00f4i tr\u01a1n l\u00e0 c\u00e1c hi\u0111rocacbon.<\/p>\n

B\u00e0i 3 (trang 11 SGK H\u00f3a 12):\u00a0Trong th\u00e0nh ph\u1ea7n c\u1ee7a m\u1ed9t s\u1ed1 lo\u1ea1i s\u01a1n c\u00f3 trieste c\u1ee7a glixerol v\u1edbi axit linoleic C17<\/sub>H31<\/sub>COOH v\u00e0 axit linolenic C17<\/sub>H29<\/sub>COOH. Vi\u1ebft c\u00f4ng th\u1ee9c c\u1ea5u t\u1ea1o thu g\u1ecdn c\u1ee7a c\u00e1c trieste c\u00f3 th\u1ec3 c\u00f3 c\u1ee7a hai axit tr\u00ean v\u1edbi glixerol.<\/strong><\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

\"\"<\/p>\n

B\u00e0i 4 (trang 11 SGK H\u00f3a 12):\u00a0Trong ch\u1ea5t b\u00e9o lu\u00f4n c\u00f3 m\u1ed9t l\u01b0\u1ee3ng nh\u1ecf axit t\u1ef1 do. S\u1ed1 miligam KOH d\u00f9ng trung h\u00f2a l\u01b0\u1ee3ng axit t\u1ef1 do trong 1 gam ch\u1ea5t b\u00e9o g\u1ecdi l\u00e0 ch\u1ec9 s\u1ed1 axit c\u1ee7a ch\u1ea5t b\u00e9o. \u0110\u1ec3 trung h\u00f2a 2,8 gam ch\u1ea5t b\u00e9o c\u1ea7n 3,0 ml dung d\u1ecbch KOH 0,1 M. T\u00ednh ch\u1ec9 s\u1ed1 axit c\u1ee7a m\u1eabu ch\u1ea5t b\u00e9o tr\u00ean.<\/strong><\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

S\u1ed1 mol KOH l\u00e0: nKOH<\/sub>\u00a0= 0,003. 0,1 = 0,0003 (mol)<\/p>\n

Kh\u1ed1i l\u01b0\u1ee3ng KOH c\u1ea7n d\u00f9ng l\u00e0 mKOH<\/sub>\u00a0= 0,0003.56 = 0,0168 (g) = 16,8 (mg)<\/p>\n

Trung h\u00f2a 2,8 gam ch\u1ea5t b\u00e9o c\u1ea7n 16,8 mg KOH<\/p>\n

=> Trung h\u00f2a 1 gam ch\u1ea5t b\u00e9o c\u1ea7n x mg KOH<\/p>\n

=> x = 16,8 \/ 2,8 = 6<\/p>\n

V\u1eady ch\u1ec9 s\u1ed1 axit c\u1ee7a m\u1eabu ch\u1ea5t b\u00e9o tr\u00ean l\u00e0 6.<\/p>\n

B\u00e0i 5 (trang 12 SGK H\u00f3a 12):\u00a0T\u1ed5ng s\u1ed1 miligam KOH \u0111\u1ec3 trung h\u00f2a h\u1ebft l\u01b0\u1ee3ng axit t\u1ef1 do v\u00e0 x\u00e0 ph\u00f2ng h\u00f3a h\u1ebft l\u01b0\u1ee3ng este trong 1 gam ch\u1ea5t b\u00e9o g\u1ecdi l\u00e0 ch\u1ec9 s\u1ed1 x\u00e0 ph\u00f2ng h\u00f3a c\u1ee7a ch\u1ea5t b\u00e9o. T\u00ednh ch\u1ec9 s\u1ed1 x\u00e0 ph\u00f2ng h\u00f3a c\u1ee7a m\u1eabu ch\u1ea5t b\u00e9o c\u00f3 ch\u1ec9 s\u1ed1 axit b\u1eb1ng 7 ch\u1ee9a tristearoylglixerol c\u00f2n l\u1eabn m\u1ed9t l\u01b0\u1ee3ng axit stearic.<\/strong><\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

Ch\u1ec9 s\u1ed1 axit c\u1ee7a m\u1eabu ch\u1ea5t b\u00e9o tristearoylglixerol tr\u00ean l\u00e0 7.<\/p>\n

Ph\u01b0\u01a1ng tr\u00ecnh h\u00f3a h\u1ecdc<\/p>\n

(C17<\/sub>H35<\/sub>COO)3<\/sub>C3<\/sub>H5<\/sub>\u00a0+ 3KOH \u2192 3C17<\/sub>H35<\/sub>COOK + C3<\/sub>H5<\/sub>(OH)3<\/sub><\/p>\n

n(C17H35COO)3C3H5<\/sub>\u00a0= 1\/890 mol.<\/p>\n

nKOH<\/sub>\u00a0= 3\/890 .<\/p>\n

S\u1ed1 mg KOH tham gia x\u00e0 ph\u00f2ng h\u00f3a = (3x 56 x 103<\/sup>)\/ 890 \u2248 188,8 mg<\/p>\n

Ch\u1ec9 s\u1ed1 x\u00e0 ph\u00f2ng h\u00f3a c\u1ee7a ch\u1ea5t b\u00e9o tristearoylixerol l\u00e0 188,8 + 7,0 = 195,8.<\/p>\n

 <\/p>\n","protected":false},"excerpt":{"rendered":"

B\u00e0i 1 (trang 11 SGK H\u00f3a 12):\u00a0Ch\u1ea5t b\u00e9o l\u00e0 g\u00ec? D\u1ea7u \u0103n v\u00e0 m\u1ee1 \u0111\u1ed9ng v\u1eadt c\u00f3 \u0111i\u1ec3m g\u00ec kh\u00e1c nhau v\u1ec1 c\u1ea5u t\u1ea1o v\u00e0 t\u00ednh ch\u1ea5t v\u1eadt l\u00ed? Cho v\u00ed d\u1ee5 minh h\u1ecda? L\u1eddi gi\u1ea3i: – Ch\u1ea5t b\u00e9o l\u00e0 trieste c\u1ee7a glixerol v\u00e0 c\u00e1c axit b\u00e9o, g\u1ecdi chung l\u00e0 triglixerit. C\u00f4ng th\u1ee9c c\u1ea5u t\u1ea1o […]<\/p>\n","protected":false},"author":3,"featured_media":24599,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1305],"tags":[1419,1420],"yoast_head":"\nCh\u01b0\u01a1ng 1- B\u00e0i 2: Lipit<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/chuong-1-bai-2-lipit\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Ch\u01b0\u01a1ng 1- B\u00e0i 2: Lipit\" \/>\n<meta property=\"og:description\" content=\"B\u00e0i 1 (trang 11 SGK H\u00f3a 12):\u00a0Ch\u1ea5t b\u00e9o l\u00e0 g\u00ec? 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