B\u00e0i 1 (trang 36 SGK H\u00f3a 12):\u00a0\u0110\u1ec3 ph\u00e2n bi\u1ec7t dung d\u1ecbch glucoz\u01a1, dung d\u1ecbch saccaroz\u01a1 v\u00e0 andehit axetic c\u00f3 th\u1ec3 d\u00f9ng ch\u1ea5t n\u00e0o trong s\u1ed1 c\u00e1c ch\u1ea5t sau \u0111\u00e2y l\u00e0m thu\u1ed1c th\u1eed?<\/strong><\/p>\n A. Cu(OH)2<\/sub>\u00a0v\u00e0 AgNO3<\/sub>\/NH3<\/sub>.<\/p>\n B. N\u01b0\u1edbc brom v\u00e0 NaOH.<\/p>\n C. HNO3<\/sub>\u00a0v\u00e0 AgNO3<\/sub>\/NH3<\/sub>.<\/p>\n D. AgNO3<\/sub>\/NH3<\/sub>\u00a0v\u00e0 NaOH.<\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n \u0110\u00e1p \u00e1n A. Cu(OH)2<\/sub>\u00a0v\u00e0 AgNO3<\/sub>\/NH3<\/sub>.<\/p>\n <\/p>\n PTHH:<\/p>\n 2C6<\/sub>H12<\/sub>O6<\/sub>\u00a0+ Cu(OH)2<\/sub>\u00a0\u2192 (C6<\/sub>H12<\/sub>O6<\/sub>)2<\/sub>Cu + 2H2<\/sub>O<\/p>\n 2C22<\/sub>H22<\/sub>O11<\/sub>\u00a0+ Cu(OH)2<\/sub>\u00a0\u2192 (C22<\/sub>H22<\/sub>O11<\/sub>)2<\/sub>Cu + 2H2<\/sub>O<\/p>\n <\/p>\n B\u00e0i 2 (trang 37 SGK H\u00f3a 12):\u00a0Khi \u0111\u1ed1t ch\u00e1y ho\u00e0n to\u00e0n m\u1ed9t h\u1ee3p ch\u1ea5t h\u1eefu c\u01a1 thu \u0111\u01b0\u1ee3c h\u1ed7n h\u1ee3p kh\u00ed CO2<\/sub>\u00a0v\u00e0 h\u01a1i n\u01b0\u1edbc c\u00f3 t\u1ec9 l\u1ec7 m\u1ecdt l\u00e0 1:1. Ch\u1ea5t n\u00e0y c\u00f3 th\u1ec3 l\u00ean men r\u01b0\u1ee3u. \u0110\u00f3 l\u00e0 ch\u1ea5t n\u00e0o trong s\u1ed1 c\u00e1c ch\u1ea5t d\u01b0\u1edbi \u0111\u00e2y?<\/strong><\/p>\n A. Axit axetic<\/p>\n B. Glucoz\u01a1<\/p>\n C. Saccaroz\u01a1<\/p>\n D. Fructoz\u01a1<\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n \u0110\u00e1p \u00e1n B. Glucoz\u01a1<\/p>\n Khi \u0111\u1ed1t ch\u00e1y: nCO2<\/sub>= nH2O<\/sub>\u00a0\u2192 h\u1ee3p ch\u1ea5t \u0111\u00f3 ph\u1ea3i l\u00e0 cacbohidrat<\/p>\n M\u00e0 ch\u1ea5t n\u00e0y c\u00f3 th\u1ec3 l\u00ean men r\u01b0\u1ee3u \u2192 ch\u1ea5t \u0111\u00f3 ph\u1ea3i l\u00e0 gluczo<\/p>\n PTHH:<\/p>\n <\/p>\n B\u00e0i 3 (trang 37 SGK H\u00f3a 12):\u00a0Tr\u00ecnh b\u00e0y ph\u01b0\u01a1ng ph\u00e1p h\u00f3a h\u1ecdc ph\u00e2n bi\u1ec7t c\u00e1c dung d\u1ecbch ri\u00eang bi\u1ec7t trong m\u1ed7i nh\u00f3m ch\u1ea5t sau:<\/strong><\/p>\n a. Glucoz\u01a1, glixerol, andehit axetic.<\/p>\n b. Glucoz\u01a1, saccaroz\u01a1, glixerol.<\/p>\n c. Saccaroz\u01a1, andehit axetic, h\u1ed3 tinh b\u1ed9t.<\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n Tr\u00ecnh b\u00e0y ph\u01b0\u01a1ng ph\u00e1p h\u00f3a h\u1ecdc ph\u00e2n bi\u1ec7t c\u00e1c nh\u00f3m ch\u1ea5t sau trong dung d\u1ecbch<\/p>\n a. Glucozo, glixerol, andehit axetic.<\/p>\n <\/p>\n PTHH:<\/p>\n <\/p>\n b. Glucoz\u01a1, saccaroz\u01a1, glixerol.<\/p>\n <\/p>\n PTHH:<\/p>\n <\/p>\n Khi \u0111un n\u00f3ng saccarozo trong m\u00f4i tr\u01b0\u1eddng axit, saccarozo s\u1ebd b\u1ecb th\u1ee7y ph\u00e2n th\u00e0nh glucozo<\/p>\n c. Saccaroz\u01a1, andehit axetic, h\u1ed3 tinh b\u1ed9t<\/p>\n <\/p>\n PTHH:<\/p>\n <\/p>\n B\u00e0i 4 (trang 37 SGK H\u00f3a 12):\u00a0T\u1eeb m\u1ed9t t\u1ea5n b\u1ed9t s\u1eafn ch\u1ee9a 20% t\u1ea1p ch\u1ea5t tr\u01a1, c\u00f3 th\u1ec3 s\u1ea3n xu\u1ea5t \u0111\u01b0\u1ee3c bao nhi\u00eau gam glucozo, n\u1ebfu hi\u1ec7u su\u1ea5t c\u1ee7a qu\u00e1 tr\u00ecnh s\u1ea3n xu\u1ea5t l\u00e0 75%<\/strong><\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n Kh\u1ed1i l\u01b0\u1ee3ng tinh b\u1ed9t trong 1 t\u1ea5n b\u1ed9t s\u1eafn c\u00f3 ch\u1ee9a 20% t\u1ea1p ch\u1ea5t tr\u01a1 l\u00e0 :<\/p>\n m = 1 . 80 \/ 100 = 0,8 (t\u1ea5n)<\/p>\n (C6<\/sub>H10<\/sub>O5<\/sub>)n<\/sub>\u00a0+ nH2<\/sub>O \u2192 nC6<\/sub>H12<\/sub>O6<\/sub><\/p>\n n(C6H10O5)n<\/sub>\u00a0= 0,8 \/162n.<\/p>\n Hi\u1ec7u su\u1ea5t 75% n\u00ean kh\u1ed1i l\u01b0\u1ee3ng glucoz\u01a1 thu \u0111\u01b0\u1ee3c l\u00e0 :<\/p>\n mC6H12O6<\/sub>\u00a0= (0,8 . 180n)\/162n . 75\/ 100=0,67 (t\u1ea5n)<\/p>\n B\u00e0i 5 (trang 37 SGK H\u00f3a 12):\u00a0T\u00ednh kh\u1ed1i l\u01b0\u1ee3ng glucoz\u01a1 t\u1ea1o th\u00e0nh khi th\u1ee7y ph\u00e2n:<\/strong><\/p>\n a. 1kg b\u1ed9t g\u1ea1o c\u00f3 80% tinh b\u1ed9t, c\u00f2n l\u1ea1i l\u00e0 t\u1ea1p ch\u1ea5t tr\u01a1.<\/p>\n b. 1kg m\u00f9n c\u01b0a c\u00f3 50% xenluloz\u01a1, c\u00f2n l\u1ea1i l\u00e0 t\u1ea1p ch\u1ea5t tr\u01a1.<\/p>\n c. 1kg saccaroz\u01a1.<\/p>\n Gi\u1ea3 thi\u1ebft c\u00e1c ph\u1ea3n \u1ee9ng x\u1ea3y ra ho\u00e0n to\u00e0n<\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n <\/p>\n B\u00e0i 6 (trang 37 SGK H\u00f3a 12):\u00a0\u0110\u1ed1t ch\u00e1y ho\u00e0n to\u00e0n 16,2 gam m\u1ed9t cacbohidrat X thu 13,44 l\u00edt kh\u00ed CO2<\/sub>\u00a0(\u0111ktc) v\u00e0 9,0 gam H2<\/sub>O<\/strong><\/p>\n a. T\u00ecm c\u00f4ng th\u1ee9c \u0111\u01a1n gi\u1ea3n nh\u1ea5t c\u1ee7a X, X thu\u1ed9c lo\u1ea1i cacbohi\u0111rat n\u00e0o \u0111\u00e3 h\u1ecdc?<\/p>\n b. \u0110ung 16,2 gam X trong dung d\u1ecbch axit thu \u0111\u01b0\u1ee3c dung d\u1ecbch Y. Cho Y t\u00e1c d\u1ee5ng v\u1edbi l\u01b0\u1ee3ng d\u01b0 dung d\u1ecbch AgNO3<\/sub>\/NH3<\/sub>\u00a0thu \u0111\u01b0\u1ee3c bao nhi\u00eau gam Ag. Gi\u1ea3 s\u1eed hi\u1ec7u su\u1ea5t c\u1ee7a qu\u00e1 tr\u00ecnh l\u00e0 80%.<\/p>\n L\u1eddi gi\u1ea3i:<\/b><\/p>\n mc<\/sub>\u00a0= 12 . 13,44 \/ 22,4 = 7,2(g)<\/p>\n mH<\/sub>\u00a0= (2 x 9) \/ 18 = 1(g)<\/p>\n mO<\/sub>\u00a0= 16,2 – 7,2 – 1 = 8(g)<\/p>\n G\u1ecdi c\u00f4ng th\u1ee9c t\u1ed5ng qu\u00e1t Cx<\/sub>Hy<\/sub>Oz<\/sub>.<\/p>\n L\u1eadp t\u1ec9 l\u1ec7:<\/p>\n x: y : z= 7,2\/12 : 1\/1 : 8\/16<\/p>\n x: y : z = 0,6 : 1 : 0,5<\/p>\n x : y : z = 6 : 10 : 5<\/p>\n c\u00f4ng th\u1ee9c \u0111\u01a1n gi\u1ea3n C6<\/sub>H10<\/sub>O5<\/sub><\/p>\n c\u00f4ng th\u1ee9c ph\u00e2n t\u1eed (C6<\/sub>H10<\/sub>O5<\/sub>)n<\/p>\n X: l\u00e0 polisaccarit<\/p>\n <\/p>\n Kh\u1ed1i l\u01b0\u1ee3ng glucozo l\u00e0<\/p>\n <\/p>\n S\u1ed1 mol glucozo l\u00e0 n = 18\/180 = 0,1 (mol)<\/p>\n <\/p>\n Kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a Ag m =0,2.108 = 21,6 (g)<\/p>\n V\u00ec h = 80% n\u00ean kh\u1ed1i l\u01b0\u1ee3ng Ag th\u1ef1c t\u1ebf thu \u0111\u01b0\u1ee3c l\u00e0<\/p>\n m= 21,6.80% =17,28 (g)<\/p>\n<\/div>\n","protected":false},"excerpt":{"rendered":" B\u00e0i 1 (trang 36 SGK H\u00f3a 12):\u00a0\u0110\u1ec3 ph\u00e2n bi\u1ec7t dung d\u1ecbch glucoz\u01a1, dung d\u1ecbch saccaroz\u01a1 v\u00e0 andehit axetic c\u00f3 th\u1ec3 d\u00f9ng ch\u1ea5t n\u00e0o trong s\u1ed1 c\u00e1c ch\u1ea5t sau \u0111\u00e2y l\u00e0m thu\u1ed1c th\u1eed? A. Cu(OH)2\u00a0v\u00e0 AgNO3\/NH3. B. N\u01b0\u1edbc brom v\u00e0 NaOH. C. HNO3\u00a0v\u00e0 AgNO3\/NH3. D. AgNO3\/NH3\u00a0v\u00e0 NaOH. L\u1eddi gi\u1ea3i: \u0110\u00e1p \u00e1n A. Cu(OH)2\u00a0v\u00e0 AgNO3\/NH3. PTHH: 2C6H12O6\u00a0+ […]<\/p>\n","protected":false},"author":3,"featured_media":24543,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1305],"tags":[1419,1420],"yoast_head":"\n