https://dashboard.mempawahkab.go.id/wp-content/plugins/ https://www.kungfuology.com/mt-static/ https://pgsd.fkip.unsulbar.ac.id/wp-content/server/https://www.kungfuology.com/home/plugins/ https://land.ubiz.ua/assets/img/ https://sentraki.polimarin.ac.id/js/slot-dana/ https://qml.cvc.uab.es/responsivl/slot-gacor/ https://sentraki.polimarin.ac.id/public/js/ https://fh.uki.ac.id/nul/slot-pulsa/ https://ncc.potensi-utama.ac.id/wp-content/plugins/ https://pgsd.fkip.unsulbar.ac.id/wp-includes/qris/ https://aktasidangmd.gkjw.or.id/aset/css/ https://simpenmas.untirta.ac.id/plugins/slot-dana/
{"id":24542,"date":"2018-03-29T16:37:09","date_gmt":"2018-03-29T09:37:09","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=24542"},"modified":"2018-03-29T16:37:09","modified_gmt":"2018-03-29T09:37:09","slug":"chuong-2-bai-7-luyen-tap-cau-tao-va-tinh-chat-cua-cacbohidrat","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/chuong-2-bai-7-luyen-tap-cau-tao-va-tinh-chat-cua-cacbohidrat\/","title":{"rendered":"Ch\u01b0\u01a1ng 2 – B\u00e0i 7: Luy\u1ec7n t\u1eadp: C\u1ea5u t\u1ea1o v\u00e0 t\u00ednh ch\u1ea5t c\u1ee7a cacbohi\u0111rat"},"content":{"rendered":"

B\u00e0i 1 (trang 36 SGK H\u00f3a 12):\u00a0\u0110\u1ec3 ph\u00e2n bi\u1ec7t dung d\u1ecbch glucoz\u01a1, dung d\u1ecbch saccaroz\u01a1 v\u00e0 andehit axetic c\u00f3 th\u1ec3 d\u00f9ng ch\u1ea5t n\u00e0o trong s\u1ed1 c\u00e1c ch\u1ea5t sau \u0111\u00e2y l\u00e0m thu\u1ed1c th\u1eed?<\/strong><\/p>\n

A. Cu(OH)2<\/sub>\u00a0v\u00e0 AgNO3<\/sub>\/NH3<\/sub>.<\/p>\n

B. N\u01b0\u1edbc brom v\u00e0 NaOH.<\/p>\n

C. HNO3<\/sub>\u00a0v\u00e0 AgNO3<\/sub>\/NH3<\/sub>.<\/p>\n

D. AgNO3<\/sub>\/NH3<\/sub>\u00a0v\u00e0 NaOH.<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

\u0110\u00e1p \u00e1n A. Cu(OH)2<\/sub>\u00a0v\u00e0 AgNO3<\/sub>\/NH3<\/sub>.<\/p>\n

\"\"<\/p>\n

PTHH:<\/p>\n

2C6<\/sub>H12<\/sub>O6<\/sub>\u00a0+ Cu(OH)2<\/sub>\u00a0\u2192 (C6<\/sub>H12<\/sub>O6<\/sub>)2<\/sub>Cu + 2H2<\/sub>O<\/p>\n

2C22<\/sub>H22<\/sub>O11<\/sub>\u00a0+ Cu(OH)2<\/sub>\u00a0\u2192 (C22<\/sub>H22<\/sub>O11<\/sub>)2<\/sub>Cu + 2H2<\/sub>O<\/p>\n

\"\"<\/p>\n

B\u00e0i 2 (trang 37 SGK H\u00f3a 12):\u00a0Khi \u0111\u1ed1t ch\u00e1y ho\u00e0n to\u00e0n m\u1ed9t h\u1ee3p ch\u1ea5t h\u1eefu c\u01a1 thu \u0111\u01b0\u1ee3c h\u1ed7n h\u1ee3p kh\u00ed CO2<\/sub>\u00a0v\u00e0 h\u01a1i n\u01b0\u1edbc c\u00f3 t\u1ec9 l\u1ec7 m\u1ecdt l\u00e0 1:1. Ch\u1ea5t n\u00e0y c\u00f3 th\u1ec3 l\u00ean men r\u01b0\u1ee3u. \u0110\u00f3 l\u00e0 ch\u1ea5t n\u00e0o trong s\u1ed1 c\u00e1c ch\u1ea5t d\u01b0\u1edbi \u0111\u00e2y?<\/strong><\/p>\n

A. Axit axetic<\/p>\n

B. Glucoz\u01a1<\/p>\n

C. Saccaroz\u01a1<\/p>\n

D. Fructoz\u01a1<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

\u0110\u00e1p \u00e1n B. Glucoz\u01a1<\/p>\n

Khi \u0111\u1ed1t ch\u00e1y: nCO2<\/sub>= nH2O<\/sub>\u00a0\u2192 h\u1ee3p ch\u1ea5t \u0111\u00f3 ph\u1ea3i l\u00e0 cacbohidrat<\/p>\n

M\u00e0 ch\u1ea5t n\u00e0y c\u00f3 th\u1ec3 l\u00ean men r\u01b0\u1ee3u \u2192 ch\u1ea5t \u0111\u00f3 ph\u1ea3i l\u00e0 gluczo<\/p>\n

PTHH:<\/p>\n

\"\"<\/p>\n

B\u00e0i 3 (trang 37 SGK H\u00f3a 12):\u00a0Tr\u00ecnh b\u00e0y ph\u01b0\u01a1ng ph\u00e1p h\u00f3a h\u1ecdc ph\u00e2n bi\u1ec7t c\u00e1c dung d\u1ecbch ri\u00eang bi\u1ec7t trong m\u1ed7i nh\u00f3m ch\u1ea5t sau:<\/strong><\/p>\n

a. Glucoz\u01a1, glixerol, andehit axetic.<\/p>\n

b. Glucoz\u01a1, saccaroz\u01a1, glixerol.<\/p>\n

c. Saccaroz\u01a1, andehit axetic, h\u1ed3 tinh b\u1ed9t.<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

Tr\u00ecnh b\u00e0y ph\u01b0\u01a1ng ph\u00e1p h\u00f3a h\u1ecdc ph\u00e2n bi\u1ec7t c\u00e1c nh\u00f3m ch\u1ea5t sau trong dung d\u1ecbch<\/p>\n

a. Glucozo, glixerol, andehit axetic.<\/p>\n

\"\"<\/p>\n

PTHH:<\/p>\n

\"\"<\/p>\n

b. Glucoz\u01a1, saccaroz\u01a1, glixerol.<\/p>\n

\"\"<\/p>\n

PTHH:<\/p>\n

\"\"<\/p>\n

Khi \u0111un n\u00f3ng saccarozo trong m\u00f4i tr\u01b0\u1eddng axit, saccarozo s\u1ebd b\u1ecb th\u1ee7y ph\u00e2n th\u00e0nh glucozo<\/p>\n

c. Saccaroz\u01a1, andehit axetic, h\u1ed3 tinh b\u1ed9t<\/p>\n

\"\"<\/p>\n

PTHH:<\/p>\n

\"\"<\/p>\n

B\u00e0i 4 (trang 37 SGK H\u00f3a 12):\u00a0T\u1eeb m\u1ed9t t\u1ea5n b\u1ed9t s\u1eafn ch\u1ee9a 20% t\u1ea1p ch\u1ea5t tr\u01a1, c\u00f3 th\u1ec3 s\u1ea3n xu\u1ea5t \u0111\u01b0\u1ee3c bao nhi\u00eau gam glucozo, n\u1ebfu hi\u1ec7u su\u1ea5t c\u1ee7a qu\u00e1 tr\u00ecnh s\u1ea3n xu\u1ea5t l\u00e0 75%<\/strong><\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

Kh\u1ed1i l\u01b0\u1ee3ng tinh b\u1ed9t trong 1 t\u1ea5n b\u1ed9t s\u1eafn c\u00f3 ch\u1ee9a 20% t\u1ea1p ch\u1ea5t tr\u01a1 l\u00e0 :<\/p>\n

m = 1 . 80 \/ 100 = 0,8 (t\u1ea5n)<\/p>\n

(C6<\/sub>H10<\/sub>O5<\/sub>)n<\/sub>\u00a0+ nH2<\/sub>O \u2192 nC6<\/sub>H12<\/sub>O6<\/sub><\/p>\n

n(C6H10O5)n<\/sub>\u00a0= 0,8 \/162n.<\/p>\n

Hi\u1ec7u su\u1ea5t 75% n\u00ean kh\u1ed1i l\u01b0\u1ee3ng glucoz\u01a1 thu \u0111\u01b0\u1ee3c l\u00e0 :<\/p>\n

mC6H12O6<\/sub>\u00a0= (0,8 . 180n)\/162n . 75\/ 100=0,67 (t\u1ea5n)<\/p>\n

B\u00e0i 5 (trang 37 SGK H\u00f3a 12):\u00a0T\u00ednh kh\u1ed1i l\u01b0\u1ee3ng glucoz\u01a1 t\u1ea1o th\u00e0nh khi th\u1ee7y ph\u00e2n:<\/strong><\/p>\n

a. 1kg b\u1ed9t g\u1ea1o c\u00f3 80% tinh b\u1ed9t, c\u00f2n l\u1ea1i l\u00e0 t\u1ea1p ch\u1ea5t tr\u01a1.<\/p>\n

b. 1kg m\u00f9n c\u01b0a c\u00f3 50% xenluloz\u01a1, c\u00f2n l\u1ea1i l\u00e0 t\u1ea1p ch\u1ea5t tr\u01a1.<\/p>\n

c. 1kg saccaroz\u01a1.<\/p>\n

Gi\u1ea3 thi\u1ebft c\u00e1c ph\u1ea3n \u1ee9ng x\u1ea3y ra ho\u00e0n to\u00e0n<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

\"\"<\/p>\n

B\u00e0i 6 (trang 37 SGK H\u00f3a 12):\u00a0\u0110\u1ed1t ch\u00e1y ho\u00e0n to\u00e0n 16,2 gam m\u1ed9t cacbohidrat X thu 13,44 l\u00edt kh\u00ed CO2<\/sub>\u00a0(\u0111ktc) v\u00e0 9,0 gam H2<\/sub>O<\/strong><\/p>\n

\n

a. T\u00ecm c\u00f4ng th\u1ee9c \u0111\u01a1n gi\u1ea3n nh\u1ea5t c\u1ee7a X, X thu\u1ed9c lo\u1ea1i cacbohi\u0111rat n\u00e0o \u0111\u00e3 h\u1ecdc?<\/p>\n

b. \u0110ung 16,2 gam X trong dung d\u1ecbch axit thu \u0111\u01b0\u1ee3c dung d\u1ecbch Y. Cho Y t\u00e1c d\u1ee5ng v\u1edbi l\u01b0\u1ee3ng d\u01b0 dung d\u1ecbch AgNO3<\/sub>\/NH3<\/sub>\u00a0thu \u0111\u01b0\u1ee3c bao nhi\u00eau gam Ag. Gi\u1ea3 s\u1eed hi\u1ec7u su\u1ea5t c\u1ee7a qu\u00e1 tr\u00ecnh l\u00e0 80%.<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

mc<\/sub>\u00a0= 12 . 13,44 \/ 22,4 = 7,2(g)<\/p>\n

mH<\/sub>\u00a0= (2 x 9) \/ 18 = 1(g)<\/p>\n

mO<\/sub>\u00a0= 16,2 – 7,2 – 1 = 8(g)<\/p>\n

G\u1ecdi c\u00f4ng th\u1ee9c t\u1ed5ng qu\u00e1t Cx<\/sub>Hy<\/sub>Oz<\/sub>.<\/p>\n

L\u1eadp t\u1ec9 l\u1ec7:<\/p>\n

x: y : z= 7,2\/12 : 1\/1 : 8\/16<\/p>\n

x: y : z = 0,6 : 1 : 0,5<\/p>\n

x : y : z = 6 : 10 : 5<\/p>\n

c\u00f4ng th\u1ee9c \u0111\u01a1n gi\u1ea3n C6<\/sub>H10<\/sub>O5<\/sub><\/p>\n

c\u00f4ng th\u1ee9c ph\u00e2n t\u1eed (C6<\/sub>H10<\/sub>O5<\/sub>)n<\/p>\n

X: l\u00e0 polisaccarit<\/p>\n

\"\"<\/p>\n

Kh\u1ed1i l\u01b0\u1ee3ng glucozo l\u00e0<\/p>\n

\"\"<\/p>\n

S\u1ed1 mol glucozo l\u00e0 n = 18\/180 = 0,1 (mol)<\/p>\n

\"\"<\/p>\n

Kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a Ag m =0,2.108 = 21,6 (g)<\/p>\n

V\u00ec h = 80% n\u00ean kh\u1ed1i l\u01b0\u1ee3ng Ag th\u1ef1c t\u1ebf thu \u0111\u01b0\u1ee3c l\u00e0<\/p>\n

m= 21,6.80% =17,28 (g)<\/p>\n<\/div>\n","protected":false},"excerpt":{"rendered":"

B\u00e0i 1 (trang 36 SGK H\u00f3a 12):\u00a0\u0110\u1ec3 ph\u00e2n bi\u1ec7t dung d\u1ecbch glucoz\u01a1, dung d\u1ecbch saccaroz\u01a1 v\u00e0 andehit axetic c\u00f3 th\u1ec3 d\u00f9ng ch\u1ea5t n\u00e0o trong s\u1ed1 c\u00e1c ch\u1ea5t sau \u0111\u00e2y l\u00e0m thu\u1ed1c th\u1eed? A. Cu(OH)2\u00a0v\u00e0 AgNO3\/NH3. B. N\u01b0\u1edbc brom v\u00e0 NaOH. C. HNO3\u00a0v\u00e0 AgNO3\/NH3. D. AgNO3\/NH3\u00a0v\u00e0 NaOH. L\u1eddi gi\u1ea3i: \u0110\u00e1p \u00e1n A. Cu(OH)2\u00a0v\u00e0 AgNO3\/NH3. PTHH: 2C6H12O6\u00a0+ […]<\/p>\n","protected":false},"author":3,"featured_media":24543,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1305],"tags":[1419,1420],"yoast_head":"\nCh\u01b0\u01a1ng 2 - B\u00e0i 7: Luy\u1ec7n t\u1eadp: C\u1ea5u t\u1ea1o v\u00e0 t\u00ednh ch\u1ea5t c\u1ee7a cacbohi\u0111rat<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/chuong-2-bai-7-luyen-tap-cau-tao-va-tinh-chat-cua-cacbohidrat\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Ch\u01b0\u01a1ng 2 - B\u00e0i 7: Luy\u1ec7n t\u1eadp: C\u1ea5u t\u1ea1o v\u00e0 t\u00ednh ch\u1ea5t c\u1ee7a cacbohi\u0111rat\" \/>\n<meta property=\"og:description\" content=\"B\u00e0i 1 (trang 36 SGK H\u00f3a 12):\u00a0\u0110\u1ec3 ph\u00e2n bi\u1ec7t dung d\u1ecbch glucoz\u01a1, dung d\u1ecbch saccaroz\u01a1 v\u00e0 andehit axetic c\u00f3 th\u1ec3 d\u00f9ng ch\u1ea5t n\u00e0o trong s\u1ed1 c\u00e1c ch\u1ea5t sau \u0111\u00e2y l\u00e0m thu\u1ed1c th\u1eed? A. Cu(OH)2\u00a0v\u00e0 AgNO3\/NH3. B. N\u01b0\u1edbc brom v\u00e0 NaOH. C. HNO3\u00a0v\u00e0 AgNO3\/NH3. D. AgNO3\/NH3\u00a0v\u00e0 NaOH. L\u1eddi gi\u1ea3i: \u0110\u00e1p \u00e1n A. Cu(OH)2\u00a0v\u00e0 AgNO3\/NH3. PTHH: 2C6H12O6\u00a0+ […]\" \/>\n<meta property=\"og:url\" content=\"https:\/\/lop12.edu.vn\/chuong-2-bai-7-luyen-tap-cau-tao-va-tinh-chat-cua-cacbohidrat\/\" \/>\n<meta property=\"og:site_name\" content=\"Lop12.edu.vn - C\u1ed9ng \u0111\u1ed3ng h\u1ecdc sinh l\u1edbp 12 l\u1edbn nh\u1ea5t t\u1ea1i Vi\u1ec7t Nam\" \/>\n<meta property=\"article:published_time\" content=\"2018-03-29T09:37:09+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/lop12.edu.vn\/wp-content\/uploads\/2018\/03\/bai-1-trang-36-sgk-hoa-12.png\" \/>\n\t<meta property=\"og:image:width\" content=\"624\" \/>\n\t<meta property=\"og:image:height\" content=\"185\" \/>\n\t<meta property=\"og:image:type\" content=\"image\/png\" \/>\n<meta name=\"author\" content=\"H\u00e0 Trang\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"H\u00e0 Trang\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"4 minutes\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"WebPage\",\"@id\":\"https:\/\/lop12.edu.vn\/chuong-2-bai-7-luyen-tap-cau-tao-va-tinh-chat-cua-cacbohidrat\/\",\"url\":\"https:\/\/lop12.edu.vn\/chuong-2-bai-7-luyen-tap-cau-tao-va-tinh-chat-cua-cacbohidrat\/\",\"name\":\"Ch\u01b0\u01a1ng 2 - B\u00e0i 7: Luy\u1ec7n t\u1eadp: C\u1ea5u t\u1ea1o v\u00e0 t\u00ednh ch\u1ea5t c\u1ee7a cacbohi\u0111rat\",\"isPartOf\":{\"@id\":\"https:\/\/lop12.edu.vn\/#website\"},\"datePublished\":\"2018-03-29T09:37:09+00:00\",\"dateModified\":\"2018-03-29T09:37:09+00:00\",\"author\":{\"@id\":\"https:\/\/lop12.edu.vn\/#\/schema\/person\/2da855e5d06b553ac0065157cc261a45\"},\"breadcrumb\":{\"@id\":\"https:\/\/lop12.edu.vn\/chuong-2-bai-7-luyen-tap-cau-tao-va-tinh-chat-cua-cacbohidrat\/#breadcrumb\"},\"inLanguage\":\"en-US\",\"potentialAction\":[{\"@type\":\"ReadAction\",\"target\":[\"https:\/\/lop12.edu.vn\/chuong-2-bai-7-luyen-tap-cau-tao-va-tinh-chat-cua-cacbohidrat\/\"]}]},{\"@type\":\"BreadcrumbList\",\"@id\":\"https:\/\/lop12.edu.vn\/chuong-2-bai-7-luyen-tap-cau-tao-va-tinh-chat-cua-cacbohidrat\/#breadcrumb\",\"itemListElement\":[{\"@type\":\"ListItem\",\"position\":1,\"name\":\"Home\",\"item\":\"https:\/\/lop12.edu.vn\/\"},{\"@type\":\"ListItem\",\"position\":2,\"name\":\"Ch\u01b0\u01a1ng 2 – B\u00e0i 7: Luy\u1ec7n t\u1eadp: C\u1ea5u t\u1ea1o v\u00e0 t\u00ednh ch\u1ea5t c\u1ee7a cacbohi\u0111rat\"}]},{\"@type\":\"WebSite\",\"@id\":\"https:\/\/lop12.edu.vn\/#website\",\"url\":\"https:\/\/lop12.edu.vn\/\",\"name\":\"Lop12.edu.vn - C\u1ed9ng \u0111\u1ed3ng h\u1ecdc sinh l\u1edbp 12\",\"description\":\"\",\"potentialAction\":[{\"@type\":\"SearchAction\",\"target\":{\"@type\":\"EntryPoint\",\"urlTemplate\":\"https:\/\/lop12.edu.vn\/?s={search_term_string}\"},\"query-input\":\"required name=search_term_string\"}],\"inLanguage\":\"en-US\"},{\"@type\":\"Person\",\"@id\":\"https:\/\/lop12.edu.vn\/#\/schema\/person\/2da855e5d06b553ac0065157cc261a45\",\"name\":\"H\u00e0 Trang\",\"image\":{\"@type\":\"ImageObject\",\"inLanguage\":\"en-US\",\"@id\":\"https:\/\/lop12.edu.vn\/#\/schema\/person\/image\/\",\"url\":\"https:\/\/secure.gravatar.com\/avatar\/545a8100db1147f314111301d261dc33?s=96&d=mm&r=g\",\"contentUrl\":\"https:\/\/secure.gravatar.com\/avatar\/545a8100db1147f314111301d261dc33?s=96&d=mm&r=g\",\"caption\":\"H\u00e0 Trang\"},\"url\":\"https:\/\/lop12.edu.vn\/author\/trangvth2\/\"}]}<\/script>\n<!-- \/ Yoast SEO plugin. -->","yoast_head_json":{"title":"Ch\u01b0\u01a1ng 2 - B\u00e0i 7: Luy\u1ec7n t\u1eadp: C\u1ea5u t\u1ea1o v\u00e0 t\u00ednh ch\u1ea5t c\u1ee7a cacbohi\u0111rat","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/lop12.edu.vn\/chuong-2-bai-7-luyen-tap-cau-tao-va-tinh-chat-cua-cacbohidrat\/","og_locale":"en_US","og_type":"article","og_title":"Ch\u01b0\u01a1ng 2 - B\u00e0i 7: Luy\u1ec7n t\u1eadp: C\u1ea5u t\u1ea1o v\u00e0 t\u00ednh ch\u1ea5t c\u1ee7a cacbohi\u0111rat","og_description":"B\u00e0i 1 (trang 36 SGK H\u00f3a 12):\u00a0\u0110\u1ec3 ph\u00e2n bi\u1ec7t dung d\u1ecbch glucoz\u01a1, dung d\u1ecbch saccaroz\u01a1 v\u00e0 andehit axetic c\u00f3 th\u1ec3 d\u00f9ng ch\u1ea5t n\u00e0o trong s\u1ed1 c\u00e1c ch\u1ea5t sau \u0111\u00e2y l\u00e0m thu\u1ed1c th\u1eed? A. Cu(OH)2\u00a0v\u00e0 AgNO3\/NH3. B. N\u01b0\u1edbc brom v\u00e0 NaOH. C. HNO3\u00a0v\u00e0 AgNO3\/NH3. D. AgNO3\/NH3\u00a0v\u00e0 NaOH. L\u1eddi gi\u1ea3i: \u0110\u00e1p \u00e1n A. Cu(OH)2\u00a0v\u00e0 AgNO3\/NH3. PTHH: 2C6H12O6\u00a0+ […]","og_url":"https:\/\/lop12.edu.vn\/chuong-2-bai-7-luyen-tap-cau-tao-va-tinh-chat-cua-cacbohidrat\/","og_site_name":"Lop12.edu.vn - C\u1ed9ng \u0111\u1ed3ng h\u1ecdc sinh l\u1edbp 12 l\u1edbn nh\u1ea5t t\u1ea1i Vi\u1ec7t Nam","article_published_time":"2018-03-29T09:37:09+00:00","og_image":[{"width":624,"height":185,"url":"https:\/\/lop12.edu.vn\/wp-content\/uploads\/2018\/03\/bai-1-trang-36-sgk-hoa-12.png","type":"image\/png"}],"author":"H\u00e0 Trang","twitter_card":"summary_large_image","twitter_misc":{"Written by":"H\u00e0 Trang","Est. reading time":"4 minutes"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"WebPage","@id":"https:\/\/lop12.edu.vn\/chuong-2-bai-7-luyen-tap-cau-tao-va-tinh-chat-cua-cacbohidrat\/","url":"https:\/\/lop12.edu.vn\/chuong-2-bai-7-luyen-tap-cau-tao-va-tinh-chat-cua-cacbohidrat\/","name":"Ch\u01b0\u01a1ng 2 - B\u00e0i 7: Luy\u1ec7n t\u1eadp: C\u1ea5u t\u1ea1o v\u00e0 t\u00ednh ch\u1ea5t c\u1ee7a cacbohi\u0111rat","isPartOf":{"@id":"https:\/\/lop12.edu.vn\/#website"},"datePublished":"2018-03-29T09:37:09+00:00","dateModified":"2018-03-29T09:37:09+00:00","author":{"@id":"https:\/\/lop12.edu.vn\/#\/schema\/person\/2da855e5d06b553ac0065157cc261a45"},"breadcrumb":{"@id":"https:\/\/lop12.edu.vn\/chuong-2-bai-7-luyen-tap-cau-tao-va-tinh-chat-cua-cacbohidrat\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/lop12.edu.vn\/chuong-2-bai-7-luyen-tap-cau-tao-va-tinh-chat-cua-cacbohidrat\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/lop12.edu.vn\/chuong-2-bai-7-luyen-tap-cau-tao-va-tinh-chat-cua-cacbohidrat\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/lop12.edu.vn\/"},{"@type":"ListItem","position":2,"name":"Ch\u01b0\u01a1ng 2 – B\u00e0i 7: Luy\u1ec7n t\u1eadp: C\u1ea5u t\u1ea1o v\u00e0 t\u00ednh ch\u1ea5t c\u1ee7a cacbohi\u0111rat"}]},{"@type":"WebSite","@id":"https:\/\/lop12.edu.vn\/#website","url":"https:\/\/lop12.edu.vn\/","name":"Lop12.edu.vn - C\u1ed9ng \u0111\u1ed3ng h\u1ecdc sinh l\u1edbp 12","description":"","potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/lop12.edu.vn\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"en-US"},{"@type":"Person","@id":"https:\/\/lop12.edu.vn\/#\/schema\/person\/2da855e5d06b553ac0065157cc261a45","name":"H\u00e0 Trang","image":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/lop12.edu.vn\/#\/schema\/person\/image\/","url":"https:\/\/secure.gravatar.com\/avatar\/545a8100db1147f314111301d261dc33?s=96&d=mm&r=g","contentUrl":"https:\/\/secure.gravatar.com\/avatar\/545a8100db1147f314111301d261dc33?s=96&d=mm&r=g","caption":"H\u00e0 Trang"},"url":"https:\/\/lop12.edu.vn\/author\/trangvth2\/"}]}},"_links":{"self":[{"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/posts\/24542"}],"collection":[{"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/users\/3"}],"replies":[{"embeddable":true,"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/comments?post=24542"}],"version-history":[{"count":2,"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/posts\/24542\/revisions"}],"predecessor-version":[{"id":24557,"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/posts\/24542\/revisions\/24557"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/media\/24543"}],"wp:attachment":[{"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/media?parent=24542"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/categories?post=24542"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/lop12.edu.vn\/wp-json\/wp\/v2\/tags?post=24542"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}