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{"id":24522,"date":"2018-03-29T16:21:35","date_gmt":"2018-03-29T09:21:35","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=24522"},"modified":"2018-03-29T16:26:41","modified_gmt":"2018-03-29T09:26:41","slug":"chuong-3-bai-12-amino-axit","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/chuong-3-bai-12-amino-axit\/","title":{"rendered":"Ch\u01b0\u01a1ng 3 – B\u00e0i 10: Amino axit"},"content":{"rendered":"

B\u00e0i 1 (trang 48 SGK H\u00f3a 12):\u00a0\u1ee8ng v\u1edbi c\u00f4ng th\u1ee9c ph\u00e2n t\u1eed C4<\/sub>H9<\/sub>NO2<\/sub>\u00a0c\u00f3 bao nhi\u00eau amino axit l\u00e0 \u0111\u1ed3ng ph\u00e2n c\u1ea5u t\u1ea1o c\u1ee7a nhau?<\/strong><\/p>\n

A. 3.<\/p>\n

B. 4.<\/p>\n

C. 5.<\/p>\n

D. 6.<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

\u0110\u00e1p \u00e1n C.<\/p>\n

H2<\/sub>N – CH2<\/sub>\u00a0– CH2<\/sub>\u00a0– CH2<\/sub>\u00a0\u2013 COOH : axit 4 \u2013 aminobutanoic<\/p>\n

\"\"<\/p>\n

B\u00e0i 2 (trang 48 SGK H\u00f3a 12):\u00a0C\u00f3 3 ch\u1ea5t h\u1eefu c\u01a1: H2<\/sub>NCH2<\/sub>COOH, CH3<\/sub>CH2<\/sub>COOH, CH3<\/sub>[CH2<\/sub>]3<\/sub>NH2<\/sub><\/strong><\/p>\n

\u0110\u1ec3 nh\u1eadn ra dung d\u1ecbch c\u1ee7a c\u00e1c ch\u1ea5t tr\u00ean ch\u1ec9 c\u1ea7n d\u00f9ng thu\u1ed1c th\u1eed n\u00e0o sau \u0111\u00e2y?<\/p>\n

A. NaOH.<\/p>\n

B. HCl.<\/p>\n

C. CH3<\/sub>OH\/HCl.<\/p>\n

D. Qu\u1ef3 t\u00edm.<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

\u0110\u00e1p \u00e1n D.<\/p>\n

Cho qu\u1ef3 t\u00edm v\u00e0o 3 m\u1eabu th\u1eed, m\u1eabu th\u1eed n\u00e0o qu\u1ef3 t\u00edm c\u00f3 m\u00e0u \u0111\u1ecf l\u00e0 CH3<\/sub>CH2<\/sub>COOH, m\u1eabu th\u1eed n\u00e0o qu\u1ef3 t\u00edm c\u00f3 m\u00e0u xanh l\u00e0 CH3<\/sub>[CH2<\/sub>]3<\/sub>NH2<\/sub>, m\u1eabu th\u1eed m\u00e0 qu\u1ef3 t\u00edm kh\u00f4ng m\u00e0u l\u00e0 H2<\/sub>NCH2<\/sub>COOH<\/p>\n

B\u00e0i 3 (trang 48 SGK H\u00f3a 12):\u00a0Amino axit X c\u00f3 ph\u1ea7n tr\u0103m kh\u1ed1i l\u01b0\u1ee3ng c\u00e1c nguy\u00ean t\u1ed1 C, H, N l\u00e0 40,45%; 7,86%; 15,73%, c\u00f2n l\u1ea1i l\u00e0 oxi, v\u00e0 c\u00f4ng th\u1ee9c ph\u00e2n t\u1eed tr\u00f9ng v\u1edbi c\u00f4ng th\u1ee9c \u0111\u01a1n gi\u1ea3n nh\u1ea5t. X\u00e1c \u0111\u1ecbnh c\u00f4ng th\u1ee9c c\u1ea5u t\u1ea1o v\u00e0 g\u1ecdi t\u00ean c\u1ee7a X.<\/strong><\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

%O = 100% – (40,45% – 7,86% – 15,73%) = 35,96%<\/p>\n

C\u00f4ng th\u1ee9c c\u1ee7a X l\u00e0 CxHyOzNt. Ta c\u00f3 t\u1ec9 l\u1ec7: 12x \/ (%C) = y \/ (%H) = 16z \/ (%O) = 14t \/ (%N)<\/p>\n

12x \/ (40,45%) = y \/ (7,86%) = 16z \/ (35,96%) = 14t \/ (15,73%)<\/p>\n

Ta c\u00f3 t\u1ec9 l\u1ec7: x : y : z : t = 3 : 7 : 2 : 1<\/p>\n

C\u00f4ng th\u1ee9c \u0111\u01a1n gi\u1ea3n : (C3<\/sub>H7<\/sub>O2<\/sub>N)n<\/sub>.<\/p>\n

V\u00ec c\u00f4ng th\u1ee9c ph\u00e2n t\u1eed tr\u00f9ng v\u1edbi c\u00f4ng th\u1ee9c \u0111\u01a1n gi\u1ea3n n\u00ean<\/p>\n

C\u00f4ng th\u1ee9c ph\u00e2n t\u1eed C3<\/sub>H7<\/sub>O2<\/sub>N<\/p>\n

C\u00f4ng th\u1ee9c c\u1ea5u t\u1ea1o CH3<\/sub>-CH(NH2<\/sub>)-COOH Axit \u03b1-amino propanoic<\/p>\n

B\u00e0i 4 (trang 48 SGK H\u00f3a 12):\u00a0Vi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh h\u00f3a h\u1ecdc c\u1ee7a c\u00e1c ph\u1ea3n \u1ee9ng gi\u1eefa axit 2-aminopropanoic v\u1edbi NaOH, H2<\/sub>SO4<\/sub>; CH3<\/sub>OH khi c\u00f3 m\u1eb7t kh\u00ed HCl b\u00e3o h\u00f2a.<\/strong><\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

CH3<\/sub>-CH(NH2<\/sub>)-COOH + NaOH \u2192 CH3<\/sub>-CH(NH2<\/sub>)-COONa + H2<\/sub>O.<\/p>\n

CH3<\/sub>-CH(NH2<\/sub>)-COOH + H2<\/sub>SO4<\/sub>\u00a0\u2192 CH3<\/sub>-CH(NH3<\/sub>HSO4<\/sub>)-COOH .<\/p>\n

CH3<\/sub>-CH(NH2<\/sub>)-COOH + CH3<\/sub>OH \u2192 CH3<\/sub>-CH(NH2<\/sub>)-COOCH3<\/sub>\u00a0+ H2<\/sub>O.<\/p>\n

B\u00e0i 5 (trang 48 SGK H\u00f3a 12):\u00a0Vi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh h\u00f3a h\u1ecdc ph\u1ea3n \u1ee9ng tr\u00f9ng ng\u01b0ng c\u00e1c amino axit sau:<\/strong><\/p>\n

a) Axit 7 \u2013 aminoheptanoic<\/p>\n

b) Axit 10- amino\u0111ecanoic<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

Axit 7-aminoheptanoic<\/p>\n

\"\"<\/p>\n

Axit 10-amino\u0111ecanoic<\/p>\n

\"\"<\/p>\n

B\u00e0i 6 (trang 48 SGK H\u00f3a 12):\u00a0Este A \u0111\u01b0\u1ee3c \u0111i\u1ec1u ch\u1ebf t\u1eeb amino axit B (ch\u1ec9 ch\u1ee9a C, H, N, O) v\u00e0 ancol metylic. T\u1ec9 kh\u1ed1i h\u01a1i c\u1ee7a A so v\u1edbi H2<\/sub>\u00a0l\u00e0 44,5. \u0110\u1ed1t ch\u00e1y ho\u00e0n to\u00e0n 8,9 gam este A thu \u0111\u01b0\u1ee3c 13,2 gam CO2<\/sub>, 6,3 gam H2<\/sub>O v\u00e0 1,12 l\u00edt N2<\/sub>(\u0111o \u1edf \u0111ktc). X\u00e1c \u0111\u1ecbnh c\u00f4ng th\u1ee9c ph\u00e2n t\u1eed v\u00e0 c\u00f4ng th\u1ee9c c\u1ea5u t\u1ea1o c\u1ee7a A v\u00e0 B.<\/strong><\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

\"\"<\/p>\n

mO<\/sub>\u00a0= 8,9-(3,6+0,7+1,4)= 3,2(g)<\/p>\n

G\u1ecdi c\u00f4ng th\u1ee9c c\u1ee7a A l\u00e0 Cx<\/sub>Hy<\/sub>Oz<\/sub>Nt<\/sub>. Ta c\u00f3 t\u1ec9 l\u1ec7<\/p>\n

x: y :z : t =3,6\/12 : 0,7\/1 : 3,2\/16 : 1,4\/14 = 0,3: 0,7 : 0,2 : 0,1 = 3: 7 : 2 : 1<\/p>\n

C\u00f4ng th\u1ee9c \u0111\u01a1n gi\u1ea3n : C3<\/sub>H7<\/sub>O2<\/sub>N<\/p>\n

C\u00f4ng th\u1ee9c ph\u00e2n t\u1eed (C3<\/sub>H7<\/sub>O2<\/sub>N)n<\/p>\n

Ta c\u00f3 89n = 89 \u2192 n=1<\/p>\n

C\u00f4ng th\u1ee9c ph\u00e2n t\u1eed C3<\/sub>H7<\/sub>O2<\/sub>N<\/p>\n

A l\u00e0 este c\u1ee7a r\u01b0\u1ee3u metylic n\u00ean c\u00f3 c\u00f4ng th\u1ee9c c\u1ea5u t\u1ea1o l\u00e0 H2<\/sub>N-CH2<\/sub>-COOCH3<\/sub><\/p>\n

C\u00f4ng th\u1ee9c c\u1ea5u t\u1ea1o c\u1ee7a B l\u00e0 H2<\/sub>N- CH2<\/sub>-COOH<\/p>\n

<\/div>\n","protected":false},"excerpt":{"rendered":"

B\u00e0i 1 (trang 48 SGK H\u00f3a 12):\u00a0\u1ee8ng v\u1edbi c\u00f4ng th\u1ee9c ph\u00e2n t\u1eed C4H9NO2\u00a0c\u00f3 bao nhi\u00eau amino axit l\u00e0 \u0111\u1ed3ng ph\u00e2n c\u1ea5u t\u1ea1o c\u1ee7a nhau? A. 3. B. 4. C. 5. D. 6. L\u1eddi gi\u1ea3i: \u0110\u00e1p \u00e1n C. H2N – CH2\u00a0– CH2\u00a0– CH2\u00a0\u2013 COOH : axit 4 \u2013 aminobutanoic B\u00e0i 2 (trang 48 SGK H\u00f3a 12):\u00a0C\u00f3 […]<\/p>\n","protected":false},"author":3,"featured_media":24523,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1305],"tags":[1419,1420],"yoast_head":"\nCh\u01b0\u01a1ng 3 - B\u00e0i 10: Amino axit<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/chuong-3-bai-12-amino-axit\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Ch\u01b0\u01a1ng 3 - B\u00e0i 10: Amino axit\" \/>\n<meta property=\"og:description\" content=\"B\u00e0i 1 (trang 48 SGK H\u00f3a 12):\u00a0\u1ee8ng v\u1edbi c\u00f4ng th\u1ee9c ph\u00e2n t\u1eed C4H9NO2\u00a0c\u00f3 bao nhi\u00eau amino axit l\u00e0 \u0111\u1ed3ng ph\u00e2n c\u1ea5u t\u1ea1o c\u1ee7a nhau? A. 3. B. 4. C. 5. D. 6. L\u1eddi gi\u1ea3i: \u0110\u00e1p \u00e1n C. H2N – CH2\u00a0– CH2\u00a0– CH2\u00a0\u2013 COOH : axit 4 \u2013 aminobutanoic B\u00e0i 2 (trang 48 SGK H\u00f3a 12):\u00a0C\u00f3 […]\" \/>\n<meta property=\"og:url\" content=\"https:\/\/lop12.edu.vn\/chuong-3-bai-12-amino-axit\/\" \/>\n<meta property=\"og:site_name\" content=\"Lop12.edu.vn - C\u1ed9ng \u0111\u1ed3ng h\u1ecdc sinh l\u1edbp 12 l\u1edbn nh\u1ea5t t\u1ea1i Vi\u1ec7t Nam\" \/>\n<meta property=\"article:published_time\" content=\"2018-03-29T09:21:35+00:00\" \/>\n<meta property=\"article:modified_time\" content=\"2018-03-29T09:26:41+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/lop12.edu.vn\/wp-content\/uploads\/2018\/03\/bai-1-trang-48-sgk-hoa-12.png\" \/>\n\t<meta property=\"og:image:width\" content=\"506\" \/>\n\t<meta property=\"og:image:height\" content=\"426\" \/>\n\t<meta property=\"og:image:type\" content=\"image\/png\" \/>\n<meta name=\"author\" content=\"H\u00e0 Trang\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"H\u00e0 Trang\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"3 minutes\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"WebPage\",\"@id\":\"https:\/\/lop12.edu.vn\/chuong-3-bai-12-amino-axit\/\",\"url\":\"https:\/\/lop12.edu.vn\/chuong-3-bai-12-amino-axit\/\",\"name\":\"Ch\u01b0\u01a1ng 3 - B\u00e0i 10: Amino axit\",\"isPartOf\":{\"@id\":\"https:\/\/lop12.edu.vn\/#website\"},\"datePublished\":\"2018-03-29T09:21:35+00:00\",\"dateModified\":\"2018-03-29T09:26:41+00:00\",\"author\":{\"@id\":\"https:\/\/lop12.edu.vn\/#\/schema\/person\/2da855e5d06b553ac0065157cc261a45\"},\"breadcrumb\":{\"@id\":\"https:\/\/lop12.edu.vn\/chuong-3-bai-12-amino-axit\/#breadcrumb\"},\"inLanguage\":\"en-US\",\"potentialAction\":[{\"@type\":\"ReadAction\",\"target\":[\"https:\/\/lop12.edu.vn\/chuong-3-bai-12-amino-axit\/\"]}]},{\"@type\":\"BreadcrumbList\",\"@id\":\"https:\/\/lop12.edu.vn\/chuong-3-bai-12-amino-axit\/#breadcrumb\",\"itemListElement\":[{\"@type\":\"ListItem\",\"position\":1,\"name\":\"Home\",\"item\":\"https:\/\/lop12.edu.vn\/\"},{\"@type\":\"ListItem\",\"position\":2,\"name\":\"Ch\u01b0\u01a1ng 3 – B\u00e0i 10: Amino axit\"}]},{\"@type\":\"WebSite\",\"@id\":\"https:\/\/lop12.edu.vn\/#website\",\"url\":\"https:\/\/lop12.edu.vn\/\",\"name\":\"Lop12.edu.vn - C\u1ed9ng \u0111\u1ed3ng h\u1ecdc sinh l\u1edbp 12\",\"description\":\"\",\"potentialAction\":[{\"@type\":\"SearchAction\",\"target\":{\"@type\":\"EntryPoint\",\"urlTemplate\":\"https:\/\/lop12.edu.vn\/?s={search_term_string}\"},\"query-input\":\"required name=search_term_string\"}],\"inLanguage\":\"en-US\"},{\"@type\":\"Person\",\"@id\":\"https:\/\/lop12.edu.vn\/#\/schema\/person\/2da855e5d06b553ac0065157cc261a45\",\"name\":\"H\u00e0 Trang\",\"image\":{\"@type\":\"ImageObject\",\"inLanguage\":\"en-US\",\"@id\":\"https:\/\/lop12.edu.vn\/#\/schema\/person\/image\/\",\"url\":\"https:\/\/secure.gravatar.com\/avatar\/545a8100db1147f314111301d261dc33?s=96&d=mm&r=g\",\"contentUrl\":\"https:\/\/secure.gravatar.com\/avatar\/545a8100db1147f314111301d261dc33?s=96&d=mm&r=g\",\"caption\":\"H\u00e0 Trang\"},\"url\":\"https:\/\/lop12.edu.vn\/author\/trangvth2\/\"}]}<\/script>\n<!-- \/ Yoast SEO plugin. -->","yoast_head_json":{"title":"Ch\u01b0\u01a1ng 3 - B\u00e0i 10: Amino axit","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/lop12.edu.vn\/chuong-3-bai-12-amino-axit\/","og_locale":"en_US","og_type":"article","og_title":"Ch\u01b0\u01a1ng 3 - B\u00e0i 10: Amino axit","og_description":"B\u00e0i 1 (trang 48 SGK H\u00f3a 12):\u00a0\u1ee8ng v\u1edbi c\u00f4ng th\u1ee9c ph\u00e2n t\u1eed C4H9NO2\u00a0c\u00f3 bao nhi\u00eau amino axit l\u00e0 \u0111\u1ed3ng ph\u00e2n c\u1ea5u t\u1ea1o c\u1ee7a nhau? 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