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{"id":24319,"date":"2018-03-28T23:04:37","date_gmt":"2018-03-28T16:04:37","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=24319"},"modified":"2018-03-28T23:04:37","modified_gmt":"2018-03-28T16:04:37","slug":"chuong-7-bai-31-sat","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/chuong-7-bai-31-sat\/","title":{"rendered":"Ch\u01b0\u01a1ng 7 – B\u00e0i 31: S\u1eaft"},"content":{"rendered":"

B\u00e0i 1 (trang 141 SGK H\u00f3a 12):\u00a0C\u00e1c kim lo\u1ea1i n\u00e0o sau \u0111\u00e2y \u0111\u1ec1u ph\u1ea3n \u1ee9ng v\u1edbi dung d\u1ecbch CuCl2<\/sub>?<\/strong><\/p>\n

A. Na, Mg, Ag.<\/p>\n

B. Fe, Na, Mg.<\/p>\n

C. Ba, Mg, Hg.<\/p>\n

D. Na, Ba, Ag.<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

\u0110\u00e1p \u00e1n B.<\/p>\n

B\u00e0i 2 (trang 141 SGK H\u00f3a 12):\u00a0C\u1ea5u h\u00ecnh electron n\u00e0o sau \u0111\u00e2y l\u00e0 c\u1ee7a Fe3+<\/sup>\u00a0?<\/strong><\/p>\n

A. [Ar]3d6<\/sup>.<\/p>\n

B. [Ar]3d5<\/sup>.<\/p>\n

C. [Ar]3d4<\/sup>.<\/p>\n

D. [Ar]3d3<\/sup>.<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

\u0110\u00e1p \u00e1n B.<\/p>\n

B\u00e0i 3 (trang 141 SGK H\u00f3a 12):\u00a0Cho 3,52 gam m\u1ed9t kim lo\u1ea1i t\u00e1c d\u1ee5ng h\u1ebft v\u1edbi dung d\u1ecbch H2<\/sub>SO4<\/sub>\u00a0lo\u00e3ng, thu \u0111\u01b0\u1ee3c 6,84 gam mu\u1ed1i sunfat. Kim lo\u1ea1i \u0111\u00f3 l\u00e0<\/strong><\/p>\n

A. Mg.<\/p>\n

B. Zn.<\/p>\n

C. Fe.<\/p>\n

D. Al.<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

\u0110\u00e1p \u00e1n C.<\/p>\n

\"\"<\/p>\n

B\u00e0i 4 (trang 141 SGK H\u00f3a 12):\u00a0Ng\u00e2m m\u1ed9t l\u00e1 kim lo\u1ea1i c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng 50 gam trong dung d\u1ecbch HCl. Sau khi thu \u0111\u01b0\u1ee3c 336ml kh\u00ed H2<\/sub>\u00a0(\u0111ktc) th\u00ec kh\u1ed1i l\u01b0\u1ee3ng l\u00e1 kim lo\u1ea1i gi\u1ea3m 1,68 %. Kim lo\u1ea1i \u0111\u00f3 l\u00e0 :<\/strong><\/p>\n

A. Zn.<\/p>\n

B. Fe.<\/p>\n

C. Al.<\/p>\n

D. Ni.<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

\u0110\u00e1p \u00e1n B.<\/p>\n

\"\"<\/p>\n

B\u00e0i 5 (trang 141 SGK H\u00f3a 12):\u00a0H\u1ed7n h\u1ee3p A ch\u1ee9a Fe v\u00e0 kim lo\u1ea1i M c\u00f3 h\u00f3a tr\u1ecb kh\u00f4ng \u0111\u1ed5i trong m\u1ecdi h\u1ee3p ch\u1ea5t. T\u1ec9 l\u1ec7 s\u1ed1 mol c\u1ee7a M v\u00e0 E trong h\u1ed7n h\u1ee3p l\u00e0 1 : 3. Cho 19,2 gam h\u1ed7n h\u1ee3p A tan h\u1ebft v\u00e0o dung d\u1ecbch HCl thu \u0111\u01b0\u1ee3c 8,96 l\u00edt kh\u00ed H2<\/sub>\u00a0Cho 19,2 gam h\u1ed7n h\u1ee3p A t\u00e1c d\u1ee5ng h\u1ebft v\u1edbi Cl2<\/sub>\u00a0th\u00ec c\u1ea7n d\u00f9ng 13,32 l\u00edt kh\u00ed Cl2<\/sub>. X\u00e1c \u0111\u1ecbnh kim lo\u1ea1i M v\u00e0 ph\u1ea7n tr\u0103m kh\u1ed1i l\u01b0\u1ee3ng c\u00e1c kim lo\u1ea1i trong h\u1ed7n h\u1ee3p A. C\u00e1c th\u1ec3 t\u00edch kh\u00ed \u0111o \u1edf \u0111ktc.<\/strong><\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

G\u1ecdi h\u00f3a tr\u1ecb c\u1ee7a M l\u00e0 n<\/p>\n

x l\u00e0 s\u1ed1 mol Fe v\u00e0 y l\u00e0 s\u1ed1 mol M<\/p>\n

ta c\u00f3: y\/x= 1\/3<\/p>\n

S\u1ed1 mol H2<\/sub>\u00a0l\u00e0 nH2<\/sub>= 8,96\/22,4=0,4 (mol)<\/p>\n

S\u1ed1 mol Cl2<\/sub>\u00a0l\u00e0 nCl2<\/sub>\u00a0= 12,32\/22,4=0,55 (mol)<\/p>\n

C\u00e1c PTHH:<\/p>\n

\"\"<\/p>\n

Theo b\u00e0i ra ta c\u00f3 h\u1ec7 ph\u01b0\u01a1ng tr\u00ecnh<\/p>\n

\"\"<\/p>\n

V\u1eady M l\u00e0 Mg<\/p>\n

Th\u00e0nh ph\u1ea7n % theo kh\u1ed1i l\u01b0\u1ee3ng<\/p>\n

\"\"<\/p>\n

 <\/p>\n

<\/div>\n","protected":false},"excerpt":{"rendered":"

B\u00e0i 1 (trang 141 SGK H\u00f3a 12):\u00a0C\u00e1c kim lo\u1ea1i n\u00e0o sau \u0111\u00e2y \u0111\u1ec1u ph\u1ea3n \u1ee9ng v\u1edbi dung d\u1ecbch CuCl2? A. Na, Mg, Ag. B. Fe, Na, Mg. C. Ba, Mg, Hg. D. Na, Ba, Ag. L\u1eddi gi\u1ea3i: \u0110\u00e1p \u00e1n B. B\u00e0i 2 (trang 141 SGK H\u00f3a 12):\u00a0C\u1ea5u h\u00ecnh electron n\u00e0o sau \u0111\u00e2y l\u00e0 c\u1ee7a Fe3+\u00a0? 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L\u1eddi gi\u1ea3i: \u0110\u00e1p \u00e1n B. B\u00e0i 2 (trang 141 SGK H\u00f3a 12):\u00a0C\u1ea5u h\u00ecnh electron n\u00e0o sau \u0111\u00e2y l\u00e0 c\u1ee7a Fe3+\u00a0? 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