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{"id":24305,"date":"2018-03-28T22:46:54","date_gmt":"2018-03-28T15:46:54","guid":{"rendered":"https:\/\/lop12.edu.vn\/?p=24305"},"modified":"2018-03-28T22:46:54","modified_gmt":"2018-03-28T15:46:54","slug":"chuong-7-bai-35-dong-va-hop-chat-cua-dong","status":"publish","type":"post","link":"https:\/\/lop12.edu.vn\/chuong-7-bai-35-dong-va-hop-chat-cua-dong\/","title":{"rendered":"Ch\u01b0\u01a1ng 7 – B\u00e0i 35: \u0110\u1ed3ng v\u00e0 h\u1ee3p ch\u1ea5t c\u1ee7a \u0111\u1ed3ng"},"content":{"rendered":"

B\u00e0i 1 (trang 158 SGK H\u00f3a 12):\u00a0C\u1ea5u h\u00ecnh electron c\u1ee7a Cu2+<\/sup>\u00a0l\u00e0 :<\/strong><\/p>\n

A. [Ar]3d7<\/sup>.<\/p>\n

B. [Ar]3d8<\/sup>.<\/p>\n

C. [Ar]3d9<\/sup>.<\/p>\n

D. [Ar]3d10<\/sup>.<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

\u0110\u00e1p \u00e1n C.<\/p>\n

B\u00e0i 2 (trang 159 SGK H\u00f3a 12):\u00a0Cho 19,2g kim lo\u1ea1i M t\u00e1c d\u1ee5ng v\u1edbi dung d\u1ecbch HNO3<\/sub>lo\u00e3ng d\u01b0 thu \u0111\u01b0\u1ee3c 4,48 l\u00edt kh\u00ed duy nh\u1ea5t NO(\u0111ktc). Kim lo\u1ea1i M l\u00e0:<\/strong><\/p>\n

A. Mg.<\/p>\n

\n

B. Cu.<\/p>\n

C. Fe.<\/p>\n

D. Zn.<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

\u0110\u00e1p \u00e1n B.<\/p>\n

Ta c\u00f3 nNO<\/sub>\u00a0= 4,48 \/ 22,4 = 0,2 mol.<\/p>\n

3M + 4HNO3<\/sub>\u00a0\u2192 3M(NO3<\/sub>)n<\/sub>\u00a0+ nNO + 2H2<\/sub>O.<\/p>\n

nM<\/sub>\u00a0= 0,6 \/ n.<\/p>\n

MM<\/sub>\u00a0= 32n.<\/p>\n

=> n=2 => M = Cu.<\/p>\n

B\u00e0i 3 (trang 159 SGK H\u00f3a 12):\u00a0Cho 7,68 gam Cu t\u00e1c d\u1ee5ng h\u1ebft v\u1edbi dung d\u1ecbch HNO3<\/sub>lo\u00e3ng th\u1ea5y c\u00f3 kh\u00ed NO tho\u00e1t ra. Kh\u1ed1i l\u01b0\u1ee3ng mu\u1ed1i nitrat sinh ra trong dung d\u1ecbch l\u00e0 :<\/strong><\/p>\n

A. 21,56 gam.<\/p>\n

B. 21,65 gam.<\/p>\n

C. 22,56 gam.<\/p>\n

D. 22,65 gam.<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

\u0110\u00e1p \u00e1n C.<\/p>\n

nCu<\/sub>\u00a0= 0,12 mol.<\/p>\n

nCu(NO3)2<\/sub>\u00a0= nCu<\/sub>\u00a0= 0,12 mol.<\/p>\n

mCu(NO3)2<\/sub>\u00a0= 0,12 x 188 = 22,56.<\/p>\n

B\u00e0i 4 (trang 159 SGK H\u00f3a 12):\u00a0\u0110\u1ed1t 12,8 gam Cu trong kh\u00f4ng kh\u00ed, h\u00f2a tan ch\u1ea5t r\u1eafn thu \u0111\u01b0\u1ee3c trong dung d\u1ecbch HNO3<\/sub>\u00a00,5M th\u1ea5y tho\u00e1t ra 448ml kh\u00ed NO duy nh\u1ea5t (\u0111ktc).<\/strong><\/p>\n

a) Vi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh ph\u1ea3n \u1ee9ng h\u00f3a h\u1ecdc x\u1ea3y ra.<\/p>\n

\n

b) T\u00ednh th\u1ec3 t\u00edch t\u1ed1i thi\u1ec3u dung d\u1ecbch HNO3<\/sub>\u00a0c\u1ea7n d\u00f9ng \u0111\u1ec3 h\u00f2a tan ch\u1ea5t r\u1eafn.<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

a) 2Cu + O2<\/sub>\u00a0\u2192 2CuO (1)<\/p>\n

3CuO + 8HNO3<\/sub>\u00a0\u2192 3Cu(NO3<\/sub>)2<\/sub>\u00a0+ 2NO + H2<\/sub>O (2)<\/p>\n

CuO + 2HNO3<\/sub>\u00a0\u2192 Cu(NO3<\/sub>)2<\/sub>\u00a0+ 2H2<\/sub>O (3)<\/p>\n

b) nCu<\/sub>\u00a0= 0,2 (mol) ; nNO<\/sub>\u00a0= 0,02 (mol)<\/p>\n

T\u1eeb (2) => nCu(d\u01b0)<\/sub>\u00a0= nNO<\/sub>\u00a0= 0,03 (mol) ; nHNO3<\/sub>\u00a0= 4nNO<\/sub>\u00a0= 0,08 (mol).<\/p>\n

T\u1eeb (1) => nCuO<\/sub>\u00a0= nCu(ph\u1ea3n \u1ee9ng)<\/sub>\u00a0= 0,2 – 0,03 = 0,17 (mol).<\/p>\n

T\u1eeb (3) => nHNO3<\/sub>\u00a0= 2nCuO<\/sub>\u00a0= 0,34 (mol).<\/p>\n

V\u1eady th\u1ec3 t\u00edch dung d\u1ecbch HNO3<\/sub>\u00a0c\u1ea7n d\u00f9ng l\u00e0 : (O,34 + 0,08) \/ 0,5 = 0,84 (l\u00edt).<\/p>\n

B\u00e0i 5 (trang 159 SGK H\u00f3a 12):\u00a0H\u00f2a tan 58g mu\u1ed1i CuSO4<\/sub>.5H2<\/sub>O v\u00e0o n\u01b0\u1edbc \u0111\u01b0\u1ee3c 500ml dung d\u1ecbch A.<\/strong><\/p>\n

a) X\u00e1c \u0111\u1ecbnh n\u1ed3ng \u0111\u1ed9 mol c\u1ee7a dung d\u1ecbch A.<\/p>\n

b) Cho d\u1ea7n d\u1ea7n b\u1ed9t s\u1eaft v\u00e0o 50ml dung d\u1ecbch A, khu\u1ea9y nh\u1eb9 cho t\u1edbi khi dung d\u1ecbch h\u1ebft m\u00e0u xanh. T\u00ednh l\u01b0\u1ee3ng s\u1eaft \u0111\u00e3 tham gia ph\u1ea3n \u1ee9ng.<\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

nCuSO4<\/sub>\u00a0= nCuSO4.5H2O<\/sub>\u00a0= 58 \/ 250 = 0,232 mol.<\/p>\n

CCuSO4<\/sub>\u00a0= 0,232 \/ 0,5 = 0,464M.<\/p>\n

Fe + CuSO4<\/sub>\u00a0\u2192 FeSO4<\/sub>\u00a0+ Cu.<\/p>\n

nFe<\/sub>= nCuSO4<\/sub>\u00a0= 0,232 mol.<\/p>\n

mFe<\/sub>\u00a0= 0,232 x 56 = 12,992g.<\/p>\n

B\u00e0i 6 (trang 159 SGK H\u00f3a 12):\u00a0M\u1ed9t thanh \u0111\u1ed3ng n\u1eb7ng 140,8 gam sau khi \u0111\u00e3 ng\u00e2m trong dung d\u1ecbch AgNO3<\/sub>\u00a0c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng l\u00e0 171,2 gam. T\u00ednh th\u1ec3 t\u00edch dung d\u1ecbch AgNO3<\/sub>32% (D= 1,2g\/ml) \u0111\u00e3 t\u00e1c d\u1ee5ng v\u1edbi thanh \u0111\u1ed3ng.<\/strong><\/p>\n

L\u1eddi gi\u1ea3i:<\/b><\/p>\n

Kh\u1ed1i l\u01b0\u1ee3ng thanh \u0111\u1ed3ng t\u0103ng l\u00e0 \u0394m = 171,2 \u2013 140,8 = 30,4 (g)<\/p>\n

Cu+ 2AgNO3<\/sub>\u00a0\u2192 Cu(NO3<\/sub>)2<\/sub>\u00a0+ 2Ag<\/p>\n

G\u1ecdi x l\u00e0 s\u1ed1 mol Cu ph\u1ea3n \u1ee9ng<\/p>\n

Ta c\u00f3 \u0394m = mAg<\/sub>\u00a0– mCu<\/sub>\u00a0= 2 x 108x – 64x<\/p>\n

30,4 = 152x \u2192 x = 0,2 (mol)<\/p>\n

Kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a AgNO3<\/sub>\u00a0l\u00e0 mAgNO3<\/sub>= 0,2 x 2 x 170 = 68(g)<\/p>\n

Th\u1ec3 t\u00edch dung d\u1ecbch AgNO3<\/sub>\u00a0l\u00e0 VAgNO3<\/sub>\u00a0= 68 x 100 \/ 32 x 1,2 = 177,08(ml)<\/p>\n

<\/div>\n
<\/div>\n<\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"

B\u00e0i 1 (trang 158 SGK H\u00f3a 12):\u00a0C\u1ea5u h\u00ecnh electron c\u1ee7a Cu2+\u00a0l\u00e0 : A. [Ar]3d7. B. [Ar]3d8. C. [Ar]3d9. D. [Ar]3d10. L\u1eddi gi\u1ea3i: \u0110\u00e1p \u00e1n C. B\u00e0i 2 (trang 159 SGK H\u00f3a 12):\u00a0Cho 19,2g kim lo\u1ea1i M t\u00e1c d\u1ee5ng v\u1edbi dung d\u1ecbch HNO3lo\u00e3ng d\u01b0 thu \u0111\u01b0\u1ee3c 4,48 l\u00edt kh\u00ed duy nh\u1ea5t NO(\u0111ktc). Kim lo\u1ea1i M l\u00e0: […]<\/p>\n","protected":false},"author":3,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_mi_skip_tracking":false,"tdm_status":"","tdm_grid_status":""},"categories":[1305],"tags":[1419,1420],"yoast_head":"\nCh\u01b0\u01a1ng 7 - B\u00e0i 35: \u0110\u1ed3ng v\u00e0 h\u1ee3p ch\u1ea5t c\u1ee7a \u0111\u1ed3ng<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/lop12.edu.vn\/chuong-7-bai-35-dong-va-hop-chat-cua-dong\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Ch\u01b0\u01a1ng 7 - B\u00e0i 35: \u0110\u1ed3ng v\u00e0 h\u1ee3p ch\u1ea5t c\u1ee7a \u0111\u1ed3ng\" \/>\n<meta property=\"og:description\" content=\"B\u00e0i 1 (trang 158 SGK H\u00f3a 12):\u00a0C\u1ea5u h\u00ecnh electron c\u1ee7a Cu2+\u00a0l\u00e0 : A. [Ar]3d7. B. [Ar]3d8. C. [Ar]3d9. D. [Ar]3d10. L\u1eddi gi\u1ea3i: \u0110\u00e1p \u00e1n C. B\u00e0i 2 (trang 159 SGK H\u00f3a 12):\u00a0Cho 19,2g kim lo\u1ea1i M t\u00e1c d\u1ee5ng v\u1edbi dung d\u1ecbch HNO3lo\u00e3ng d\u01b0 thu \u0111\u01b0\u1ee3c 4,48 l\u00edt kh\u00ed duy nh\u1ea5t NO(\u0111ktc). 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